A. WALL THICKNESS Grade SMYS of Line Pipe Wall Thickness Calculated tmin = P x D / (2x Sx Fx E x T) + A
X60 60200 15.5
psi mm
415 MPa 0.610 inch
15.9 58
mm
0.626 inch
B. EQUIVALENT STRESS CHECK FOR CORRODED PIPE CONDITION Wall thickness (t) Hoop Stress = Sh = PD/2t
14.4 201.6
mm MPa
B.1 Restrained Pipe (Underground) Thermal Stress = ST = a (Ti - Td) E Longitudinal Stress due to pressure = SP = 0.3 Sh
-125.9 60.5
MPa MPa
-65.5 OK
MPa
267.1 241.1 267.1
MPa MPa MPa
Longitudinal Stress, SL SL = SP + ST + SB + SX
S tmin t
≤
0.9 x SMYS = 374 MPa
Without considering SB (Bending stress) and SX (Axial stress due to external loading): SL = SP + ST Longitudinal Stress check : hence SL ≤ 0.9 x SMYS Equivalent Stress, SE SE1 = | Sh - SL | SE2 = [ Sh2 + SL2 - Sh SL ]1/2 SE = Max (SE1, SE2) Equivalent Stress check :
≤
0.9 x SMYS = 374 MPa SE ≤ 0.9 x SMYS
SE1 SE2 SE hence
OK
B.2 Unrestrained Pipe (Aboveground) Longitudinal Stress due to pressure = SP = 0.5 Sh
100.8
MPa
Longitudinal Stress, SL SL = SP +SB + SX ≤ 0.75 x SMYS = 312 MPa Without considering SB (Bending stress) and SX (Axial stress due to external loading): SL = SP SL ≤ 0.75 x SMYS Longitudinal Stress check : hence
100.8 OK
MPa
C. MINIMUM BENDING RADIUS Minimum bending radius for underground section is calculated from maximum margin of bending stress, based on Max (SE1, SE2) = 0.9 x SMYS. Hence, bending stress SB = -106.5 MPa R (Minimum Bend Radius) = E D / (2 |Sb|) 889 m D. CHECK ON THINNING DUE TO COLD BENDS: BEND RADIUS = 40 D
Inner bend radius divided by diameter, (n) As per PD 8010-1:2004, % of Wall thinning = 50 / (n+1) Pipe thk. before bending = cal thk/(1-thinning %) Available thickness for bending (= Selected thk) Adequacy Check (Pipe thk before bending < Available thk)
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