Download University Physics Mastering Physics Ch 33 34...
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5/16/12
MasteringPhysics: MasteringPhysics: Scores
Chapter 33/34 Assignment Due: 11:00pm on Monday, May 7, 2012 Note: To understand how points are aw arded, read your instructor's Grading Policy. [Sw itch to Standard Assignment View ]
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Exercise 33.15 A ray of light is incident on a plane surface separating two sheets of glass with refractive indexes 1.66 and 1.61. The angle of incidence is 60.5 , and the ray originates in the glass with 1.66 . Part A Compute the angle of refraction. ANSWER:
= 63.8 Correct
Exercise 33.23 A ray of light in diamond (index of refraction 2.42) is incident on an interface with air. Part A What is the largest angle the ray can make with the normal and not be totally reflected back into the diamond? ANSWER:
= 24.4 Correct
Exercise 33.24 A beam of light strikes a sheet of glass at an angle of 57.0 with the normal in air. You observe that red light makes an angle of 38.1 with the normal in the glass, while violet light makes a 36.7 angle. Part A What are the indexes of refraction of this glass for these colors of light? Answer in the order indicated. Separate your answers with a comma. ANSWER:
= 1.36,1.40 Correct
Part B session.masteringphysics.com/myct/scores
1/8
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What are the speeds of red and violet light in the glass? Answer in the order indicated. Separate your answers with a comma. ANSWER:
8 8 = 2.21×10 ,2.14×10 Correct
Exercise 33.31 Unpolarized light of intensity 23.2
is incident on two polarizing filters. The axis of the first
filter is at an angle of 23.0 counterclockwise from the vertical (viewed in the direction the light is traveling) and the axis of the second filter is at 59.2 counterclockwise from the vertical. Part A What is the intensity of the light after it has passed through the second polarizer? ANSWER:
= 7.55 Correct
Problem 33.46 After a long day of driving you take a late-night swim in a motel swimming pool. When you go to your room, you realize that you have lost your room key in the pool. You borrow a powerful flashlight and walk around the pool, shining the light into it. The light shines on the key, which is lying on the bottom of the pool, when the flashlight is held 1.2 above the water surface and is directed at the surface a horizontal distance of 1.5
from the edge .
Part A If the water here is 4.0
deep, how far is the key from the edge of the pool?
Express your answer using two significant figures. ANSWER: session.masteringphysics.com/myct/scores
2/8
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4.4 Correct
Problem 33.47 You sight along the rim of a glass with vertical sides so that the top rim is lined up with the opposite edge of the bottom (see the figure (a)). The glass is a thin-walled hollow cylinder 16.0 high with a top and bottom of the glass diameter of 8.0 . While you keep your eye in the same position, a friend fills the glass with a transparent liquid, and you then see a dime that is lying at the center of the bottom of the glass (see the figure(b)).
Part A What is the index of refraction of the liquid? Express your answer using two significant figures. ANSWER:
= 1.8 Correct
Exercise 34.9 A coin is placed next to the convex side of a thin spherical glass shell having a radius of curvature of 19.0 . An image of the 1.5 tall coin is formed 6.50 behind the glass shell. Part A Where is the coin located? ANSWER:
20.6 Correct
from the vertex
Part B Determine the size of the image. ANSWER: session.masteringphysics.com/myct/scores
= 0.474 Correct 3/8
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Part C Determine the orientation of the image. ANSWER:
inverted erect Correct
Part D Determine the nature (real or virtual) of the image. ANSWER:
real virtual Correct
Exercise 34.14 A spherical, concave, shaving mirror has a radius of curvature of 32.9
.
Part A What is the magnification of a person's face when it is 12.7
to the left of the vertex of the
mirror? ANSWER:
= 4.39 Correct
Part B Where is the image? ANSWER:
= -55.7 Correct
Part C Is the image real or virtual? ANSWER:
real virtual
session.masteringphysics.com/myct/scores
4/8
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Correct
Exercise 34.18 The left end of a long glass rod
in diameter has a convex hemispherical surface
in radius. The refractive index of the glass is
. Distances are measured from the vertex of the
hemispherical surface (to the right is positive for image distances). Part A Determine the position of the image if an object is placed in air on the axis of the rod at the infinitely far distance to the left of the vertex of the curved end. ANSWER:
= 8.00 Correct
Part B Determine the position of the image if an object is placed in air on the axis of the rod at the distance of to the left of the vertex of the curved end. ANSWER:
= 13.7 Correct
Part C Determine the position of the image if an object is placed in air on the axis of the rod at the distance of to the left of the vertex of the curved end. ANSWER:
= -5.33 Correct
Exercise 34.25 A converging meniscus lens (see Fig.34.32a in the textbook) with a refractive index of 1.52 has spherical surfaces whose radii are 7.00 and 4.00 . Part A What is the position of the image if an object is placed 23.0 ANSWER:
to the left of the lens?
= 81.7 Correct
Part B session.masteringphysics.com/myct/scores
5/8
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What is the magnification? ANSWER:
= -3.55 Correct
Exercise 34.29 A double-convex thin lens has surfaces with equal radii of curvature of magnitude 3.00
.
Looking through this lens, you observe that it forms an image of a very distant tree at a distance of 1.56 from the lens. Part A What is the index of refraction of the lens? ANSWER:
= 1.96 Correct
Exercise 34.55 The Yerkes refracting telescope of the University of Chicago has an objective 1.02 with an
in diameter
number of 19.0. (This is the largest-diameter refracting telescope in the world.)
Part A What is its focal length? ANSWER:
= 19.4 Correct
Problem 34.65 A concave mirror is to form an image of the filament of a headlight lamp on a screen 8.50 the mirror. The filament is 7.50
tall, and the image is to be 36.0
from
tall.
Part A How far in front of the vertex of the mirror should the filament be placed? ANSWER:
= 0.177 Correct
Part B session.masteringphysics.com/myct/scores
6/8
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What should be the radius of curvature of the mirror? ANSWER:
= 0.347 Correct
Problem 34.89 Two thin lenses with focal lengths of magnitude 15.0 converging, are placed 12.00
apart. An object 5.00
, the first diverging and the second tall is placed 5.50
to the left of the
first (diverging) lens. Part A Where is the image formed by the first lens located? ANSWER:
= -4.02 Correct
Part B How far from the object is the final image formed? ANSWER:
= 252 Correct
Part C Is the final image real or virtual? ANSWER:
real virtual Correct
Part D What is the height of the final image? ANSWER:
= 5.36 Correct
Part E Is the final image erect or inverted? ANSWER:
session.masteringphysics.com/myct/scores
erect 7/8
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inverted Correct
Score Summary: Your score on this assignment is 100%. You received 28 out of a possible total of 28 points.
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