Unidad 2 - Tarea 3 - Identificación Del Diseño Experimental

August 15, 2022 | Author: Anonymous | Category: N/A
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C@LNKNBNDK@R ^ BM_MBS@_ÈRSNBMR

=- Mk Mkt` t`ss c` im r` r`mi minz nzmb mbnò nòk k c` c`ii mkíi mkíins nsns ns c` vmrn vmrnmk mkzm zm pmrm pmrm bumi bumiqu qun` n`rr cns` cns`ýd ýd `xp`rnh`ktmi, ´quî tnpd c` pru`oms c`o`k s`r mpinbmcms4 ´^ buíi`s sdk ims enpòt`sns mpinbmcms `k bmcm pru`om4 Hîtdcd mi`mtdrnd (msngkmbnòk mi mzmr), s` msngkm `i trmtmhn`ktd m bmcm ukncmc `xp`rnh`ktmi h`cnmkt` uk sdrt`d d pdr h`cnd c` ukm tmoim c` köh`rds mi`mtdrnds (Omcnn `t mi., ?117g). Im enpòt`sns kuim c` ims pru`oms mi`mtdrnms pr`cnb` qu` kd `xnst`k `l`btds cnl`r`kbnmi`s r`sp`btd c`i trmtmhn`ktd pmrm bmcm ukncmc `xp`rnh`ktmi (suf`tds, …), y ids vmidr`s c` ims pru`oms `stmcèstnbms s` bdksngu`k pdr p`rhutmbnòk c` ids cmtds qu` s` dot`kcrèmk `k msngkmbndk`s mit`rkmtnvms (omfd im enpòt`sns kuim).

?- _`m _`minb inb`` im r`pr` r`pr`s`kt s`ktmbn mbnòk òk c`i hdc hdc`id `id `stm `stmcès cèstnb tnbd, d, ims enp enpòt`s òt`sns ns y im `strub `strubturm turm mpinbmcm mi Cns`ýd Bdhpi`tmh`kt` mi Mzmr (CBM). BDHQM_MBNÒK C@ 3 LÒ_HPIMR C@ @KGD_C@ @K B@_CDR @i `qunpd c` c`smrrdiid ` nkkdvmbnòk qu` id bdhpdk`k zddt`bknstms ` nkg`kn`rds c` minh`k minh`ktds tds c` ukm `hpr `hpr`sm `sm c` b`rc b`rcds ds (`kgdr (`kgdrc`) c`) `vm `vmiöm iöm `i `l`btd c` bumtrd lòrhuim lòrhuimss c` `kgdrc` (L=, L?, L2, L3), sdor` `i p`sd lnkmi c` ids b`rcds (`kt`kcn`kcd qu` m hmydr p`sd `k ids b`rcds im lòrhuim c` `kgdrc` r`minzmcm `s hís `lnbn`kt`). @k prnh`rm nkstmkbnm, im `strmt`gnm `xp`rnh`ktmi `s mpinbmr bumtrd v`b`s ims bumtrd lòrhuims c` `kgdrc` `k drc`k bdhpi`tmh`kt` mi mi`mtdrnd (ims =< pru`oms mi mzmr). Ids p`sds (jg) dot`kncds c` ids b`rcds `k im nkv`stngmbnòk s` hu`strmk `k im sngun`kt` tmoim.

 

LD_HPIMR C@ @KGD_C@ B@_CDR L=

L?

L2

L3

?,0<

?,7

?,>=

2,1?

?,2?

?,5?

?,>2

2,==

?,33 ?,0

?,77 ?,53

?,>0 ?,>5

2,15 ?,>>

R` Ldrhuim `i nkt`rrdgmkt` c`i prdoi`hm c` nkv`stngmbnòk. ´Buíi `s im lòrhuim bdk im qu` s` dotn`k` hmydr gmkmkbnm c` p`sd `k ids b`rcds4

Ldrhui` ims enpòt`sns bdrr`spdkcn`kt`s (ngumicmc y mit`rkm).

 E 1 8  P = 8 P ? 8 P 2 8 P 3 8 P 

R` c`o` tdhmr ukm c`bnsnòk sn mb`ptmr d r`bemzmr im enpòt`sns c` ngumicmc

 

Ims h`cncms c` ims cnstrnoubndk`s c` ims vmrnmoi`s bumktntmtnvms `k bmcm ukd c` ids grupds nkc`p`kcn`kt`s sdk ngumi`s.

 E = 8  P n ≡ P  f

Cdkc` E 1 sdk ids bumtrd trmtmhn`ktds dos`rvmcds y  E = `s im enpòt`sns mit`rkm Migukm c` ims h`cnms c` ims cnstrnoubndk`s c` ims vmrnmoi`s bumktntmtnvms `k bmcm ukd c` ids grupds nkc`p`kcn`kt`s `s cnl`r`kt`. Bdkk `st Bd `stdd s` ousbm ousbm bdk bdktr trms mstm tmrr qu` kd `xn `xnst st`` cn cnl`r l`r`kb `kbnm nm `k `ktr tr`` id idss bu bumt mtrd rd tr trmt mtmh mhn` n`kt ktds ds dos`rvmcds, lr`kt` m im mit`rkmtnvm c` qu` mi h`kds ukd c` `stds trmtmhn`ktds `s cnl`r`kt` c` dtrd.

R` r`minzm ids bíibuids bdrr`spdkcn`kt`s mi mkíinsns c` vmrnmkzm y s` `imodrm im tmoim MKD\M, y pmrtnr c` ids brnt`rnds c`i r`suitmcd c`i vmidr ‒ Q y LD (sdk cds brnt`rnds cnl`r`kt`s), ´qu` s` pdcrèm bdkbiunr bdk r`sp`btd m ims enpòt`sns pimkt`mcms4

 

L= ?,0<

L? ?,7

L2 ?,>=

L3 2,1?

??,,23?3 ?,0

??,,57?7 ?,53

??,,>>20 ?,>5

22,,=1=5 ?,>>

RB S 8?3,=2 + 21,>3 + 23,35=>

05,5>55 @ktr` grupds 1,517
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