Titration Questions Set 1

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Chemistry Titration Questions Set 1 Question 1 Write a balanced equation between each a) Sodium hydroxide, NaOH and Hydrochloric acid, HCl b) Sodium hydroxide and Sulfuric acid, H2SO4 c) Potassium hydroxide, KOH and Nitric acid, HNO3 d) Sodium hydroxide and Ethanoic acid, CH3COOH e) Sodium hydroxide and Ethanedioic acid HOOCCH2COOH f) Barium hydroxide, Ba(OH)2 and nitric acid, HNO3 g) Barium hydroxide, Ba(OH)2 and ethanoic acid, CH3COOH h) Nitric acid solution and Sodium carbonate solution, Na2CO3 i) Hydrochloric acid solution and Calcium carbonate solid, CaCO3 j) Nitric acid solution and Sodium hydrogen carbonate, NaHCO3

Question 2

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Calculate moles of a) HNO3 in 25.0 cm3 nitric acid HNO3 solution 0.150 moldm-3 b) HCl in 15.0 cm3 hydrochloric acid 1.00 moldm-3 c) NaOH in 250 cm3 of sodium hydroxide solution 0.200 moldm-3

Question 3 Calculate mass of a) HNO3 in 25.0cm3 nitric acid HNO3 solution 0.150 moldm-3 H=1.00 N=14.0 O=16.0

b) HCl in 15.0 cm3 hydrochloric acid 1.00 moldm-3 H=1.00 Cl=35.5

c) NaOH in 250 cm3 of sodium hydroxide solution 0.200 moldm-3 Na=23.0

O=16.0

H=1.0

Question 4 Calculate the concentration in moldm-3 for each solution

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a) HNO3 concentration 45.0 gdm-3 H=1.00 N=14.0 O=16.0

b) HCl concentration 3.65 gdm-3 H=1.00 Cl=35.5

c) NaOH concentration 4.40 gdm-3 Na=23.0

O=16.0

H=1.0

Question 5 Calculate the concentration in gdm-3 for each solution a) HNO3 concentration 0.150 moldm-3 H=1.00 N=14.0 O=16.0

b) HCl concentration 1.50 moldm-3 H=1.00 Cl=35.5

c) NaOH concentration 0.200 moldm-3 Na=23.0

O=16.0

H=1.0

Question 6 FA 1 : HCl solution FA 2: NaOH solution 4.00 gdm-3

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Equation for reaction: HCl + NaCl  NaCl + H2O 25.0 cm3 of solution FA 1 required exactly 23.00 cm3 of FA 2 solution for complete reaction. Determine a) Concentration of NaOH in moldm-3 Na=23.0 H=1.0O=16.0

b) Moles of NaOH that reacted with 25.0 cm3 FA 1 solution

c) Moles of HCl that is in 25.0 cm3 FA 1 solution

d) Concentration of HCl in FA 1, in moldm-3

e) Concentration of HCl in FA 1, in gdm-3 H= 1.0 Cl=35.5 f) Mass of HCl in 25.0 cm3 of FA 1 Question 7 FA 1 : HCl solution FA 2: NaOH solution 4.40 gdm-3 Equation for reaction:

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HCl + NaCl  NaCl + H2O 25.0 cm3 of solution FA 1 required exactly 18.60 cm3 of FA 2 solution for complete reaction. Determine a) Concentration of NaOH in moldm-3 Na=23.0 H=1.0 O=16.0

b) Moles of NaOH that reacted with 25.0 cm3 FA 1 solution

c) Moles of HCl that is in 25.0 cm3 FA 1 solution

d) Concentration of HCl in FA 1, in moldm-3

e) Concentration of HCl in FA 1, in gdm-3 H= 1.0 Cl=35.5

f) Mass of HCl in 25.0 cm3 of FA 1 Question 8 FA 1 : HCl solution 3.65 gm-3 FA 2: NaOH solution Equation for reaction: HCl + NaCl  NaCl + H2O

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25.0 cm3 of solution FA 1 required exactly 27.50 cm3 of FA 2 solution for complete reaction. Determine a) Concentration of HCl in moldm-3 H= 1.00 Cl=35.5

b) Moles of HCl in 25.0 cm3 FA 1 solution

c) Moles of NaOH that reacted with 25.0 cm3 FA 1 solution

d) Concentration of NaOH in FA 2, in moldm-3

e) Concentration of NaOH in FA 2, in gdm-3 Na=23.0 H=1.0 O=16.0

f) Mass of NaOH in 27.50 cm3 of FA 2 Question 9 CH3COOH(aq) + NaOH(aq)  CH3COONa(aq) + H2O(l) 25.0 cm3 portions of vinegar (ethanoic acid, CH3COOH, 'acetic acid') from a local supermarket were pipetted into a conical flask and titrated with a solution of sodium hydroxide that has a concentration 0.2000 moldm-3 using phenolphthalein indicator.

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The average titration value was 14.70 cm3 of the sodium hydroxide solution.

Determine: a) Moles of NaOH that reacted with 25.0cm3 of the vinegar solution

[2] 3

b) Moles of Ethanoic acid in the 25.0cm vinegar solution

[2] c) Concentration of ethanoic acid in the vinegar solution, in moldm -3

[2] d) Concentration of ethanoic acid in the vinegar solution, in gdm -3 H= 1.0 C=12.0 O=16.0

[2] Question 10 Ammonia , NH3 react with Hydrochloric acid, HCl in a neutralization reaction 5.00 cm3 portions of household ammonia solution found in window cleaner was titrated with a hydrochloric acid solution of 1.00 mol/dm3. The average titre volume using methyl orange indicator was 22.50 cm3 of hydrochloric acid.

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a) Write a balanced equation between ammonia and hydrochloric acid. ……………………………………………………………………[2] b) Determine the moles of hydrochloric acid that reacted with 5.00 cm3 of the ammonia solution. [2] c) Determine the moles of ammonia in 5.00 cm3 of the ammonia solution. [2] d) Determine the concentration ammonia in the solution, in moldm -3

[2] e) Determine the concentration of ammonia in the solution in gdm -3 N=14.0 H=1.0

[2]