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Lecture 1 Introduction The rules of the game Print version Lecture on Theory of Elasticity and Plasticity of Dr. D. Dinev, Department of Structural Mechanics, UACEG 1.1
Contents 1
Introduction 1.1 Elasticity and plasticity . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2 Overview of the course . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.3 Course organization . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
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Mathematical preliminaries 2.1 Scalars, vectors and tensors . . . . . . . 2.2 Index notation . . . . . . . . . . . . . . 2.3 Kronecker delta and alternating symbol 2.4 Coordinate transformations . . . . . . . 2.5 Cartesian tensors . . . . . . . . . . . . 2.6 Principal values and directions . . . . . 2.7 Vector and tensor algebra . . . . . . . . 2.8 Tensor calculus . . . . . . . . . . . . .
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1.2
Introduction
1.1
Elasticity and plasticity
Introduction Elasticity and plasticity • What is the Theory of elasticity (TE)? – Branch of physics which deals with calculation of the deformation of solid bodies in equilibrium of applied forces – Theory of elasticity treats explicitly a linear or nonlinear response of structure to loading • What do we mean by a solid body? – A solid body can sustain shear – Body is and remains continuous during the deformation- neglecting its atomic structure, the body consists of continuous material points (we can infinitely ”zoom-in” and still see numerous material points) • What does the modern TE deal with? – Lab experiments- strain measurements, photoelasticity, fatigue, material description – Theory- continuum mechanics, micromechanics, constitutive modeling – Computation- finite elements, boundary elements, molecular mechanics 1.3
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Introduction
Elasticity and plasticity • Which problems does the TE study? – All problems considering 2- or 3-dimensional formulation 1.4
Introduction
Elasticity and plasticity • Shell structures 1.5
Introduction
Elasticity and plasticity • Plate structures 1.6
Introduction
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Elasticity and plasticity • Disc structures (walls) 1.7
Introduction Mechanics of Materials (MoM) • • • •
Makes plausible but unsubstantial assumptions Most of the assumptions have a physical nature Deals mostly with ordinary differential equations Solve the complicated problems by coefficients from tables (i.e. stress concentration factors)
Elasticity and plasticity • • • • •
More precise treatment Makes mathematical assumptions to help solve the equations Deals mostly with partial differential equations Allows us to assess the quality of the MoM-assumptions Uses more advanced mathematical tools- tensors, PDE, numerical solutions 1.8
1.2
Overview of the course
Introduction Overview of the course • Topics in this class – Stress and relation with the internal forces – Deformation and strain – Equilibrium and compatibility – Material behavior – Elasticity problem formulation – Energy principles – 2-D formulation – Finite element method – Plate analysis – Shell theory – Plasticity Note • A lot of mathematics • Few videos and pictures 1.9
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Introduction Overview of the course • Textbooks – Elasticity theory, applications, and numerics, Martin H. Sadd, 2nd edition, Elsevier 2009 – Energy principles and variational methods in applied mechanics, J. N. Reddy, John Wiley & Sons 2002 – Fundamental finite element analysis and applications, M. Asghar Bhatti, John Wiley & Sons 2005 – Theories and applications of plate analysis, Rudolph Szilard, John Wiley & Sons 2004 – Thin plates and shells, E. Ventsel and T. Krauthammer, Marcel Dekker 2001 1.10
Introduction Overview of the course • Other references – Elasticity in engineering mechanics, A. Boresi, K. Chong and J. Lee, John Wiley & Sons, 2011 – Elasticity, J. R. Barber, 2nd edition, Kluwer academic publishers, 2004 – Engineering elasticity, R. T. Fenner, Ellis Horwood Ltd, 1986 – Advanced strength and applied elasticity, A. Ugural and S. Fenster, Prentice hall, 2003 – Introduction to finite element method, C.A. Felippa, lecture notes, University of Colorado at Boulder – Lecture handouts from different universities around the world 1.11
1.3
Course organization
Introduction Course organization • Lecture notes- posted on a web-site: http://uacg.bg/?p=178&l=2&id=151&f=2&dp=23 • Instructor – Dr. D. Dinev- Room 514, E-mail:
[email protected] • Teaching assistant – Dr. A. Taushanov- Room 437 • Office hours – Instructor: Tues: 13-14; Thurs: 16-17 – TA: . . . . . . . . . . . . Note • For other time → by appointment 1.12
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Introduction 7
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Course organization • Grading 1.13
Introduction Course organization • Grading is based on – Homework- 15% – Two mid-term exams- 50% – Final exam- 35% • Participation – Class will be taught with a mixture of lecture and student participation – Class participation and attendance are expected of all students – In-class discussions will be more valuable to you if you read the relevant sections of the textbook before the class time 1.14
Introduction Course organization • Homeworks – Homework is due at the beginning of the Thursday lectures – The assigned problems for the HW’s will be announced via web-site • Late homework policy – Late homework will not be accepted and graded • Team work – You are encouraged to discuss HW and class material with the instructor, the TA’s and your classmates – However, the submitted individual HW solutions and exams must involve only your effort – Otherwise you’ll have terrible performance on the exam since you did not learn to think for yourself 1.15
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Mathematical preliminaries
2.1
Scalars, vectors and tensors
Mathematical preliminaries Scalars, vectors and tensor definitions • Scalar quantities- represent a single magnitude at each point in space – Mass density- ρ – Temperature- T • Vector quantities- represent variables which are expressible in terms of components in a 2-D or 3-D coordinate system – Displacement- u = ue1 + ve2 + we3 where e1 , e2 and e3 are unit basis vectors in the coordinate system • Matrix quantities- represent variables which require more than three components to quantify – Stress matrix
σxx σ = σyx σzx
σxz σyz σzz
σxy σyy σzy
1.16
2.2
Index notation
Mathematical preliminaries Index notation • Index notation is a shorthand scheme where a set of numbers is represented by a single symbol with subscripts a1 a11 a12 a13 ai = a2 , ai j = a21 a22 a23 a3 a31 a32 a33 – a1 j – ai1
→ →
first row first column
• Addition and subtraction
a1 ± b1 ai ± bi = a2 ± b2 a3 ± b3 a11 ± b11 ai j ± bi j = a21 ± b21 a31 ± b31
a12 ± b12 a22 ± b22 a32 ± b32
a13 ± b13 a23 ± b23 a33 ± b33 1.17
Mathematical preliminaries Index notation • Scalar multiplication
λ a1 λ ai = λ a2 , λ a3
λ a11 λ ai j = λ a21 λ a31
λ a12 λ a22 λ a32
λ a13 λ a23 λ a33
• Outer multiplication (product)
a1 b1 ai b j = a2 b1 a3 b1
a1 b2 a2 b2 a3 b2
a1 b3 a2 b3 a3 b3 1.18
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Mathematical preliminaries Index notation • Commutative, associative and distributive laws ai + bi = bi + ai ai j bk = bk ai j ai + (bi + ci ) = (ai + bi ) + ci ai (b jk c` ) = (ai b jk )c` ai j (bk + ck ) = ai j bk + ai j ck 1.19
Mathematical preliminaries Index notation • Summation convention (Einstein’s convention)- if a subscript appears twice in the same term, then summation over that subscript from one to three is implied 3
aii = ∑ aii = a11 + a22 + a33 i=1
3
ai j b j =
∑ ai j b j = ai1 b1 + ai2 b2 + ai3 b3
j=1
– j- dummy index– subscript which is repeated into the notation (one side of the equation) – i- free index– subscript which is not repeated into the notation 1.20
Mathematical preliminaries Index notation- example • The matrix ai j and vector bi are
1 ai j = 0 2
0 3 , 2
2 4 1
2 bi = 4 0
• Determine the following quantities – aii = a11 + a22 + . . . = . . . (scalar)- no free index – ai j ai j = a11 a11 + a12 a12 + a13 a13 + . . . = 1 × 1 + 2 × 2 + . . . = . . . (scalar)- no free index – ai j b j = ai1 b1 + ai2 b2 + ai3 b3 a11 b1 + a12 b1 + a13 b3 ... = ... ... = ... ... (vector)- one free index 1.21
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Mathematical preliminaries Index notation- example • Determine the following quantities ai j a jk = ai1 a1k + ai2 a2k + ai3 a3k i = 1 a11 a1k + a12 a2k + a13 a3k = i = 2 a21 a1k + . . . i = 3 a31 a1k + . . . The first expression gives the components of the 1-st row a11 a1k + a12 a2k + a13 a3k = k = 1 a11 a11 + a12 a21 + a13 a31 = . . . k = 2 a11 a12 + a12 a22 + a13 a32 = . . . k = 3 a11 a13 + a12 a23 + a13 a33 = . . . Finally
1 ai j a jk = 6 6
10 19 10
6 18 7
(matrix)- two free indexes
• ai j bi b j = a11 b1 b1 + a12 b1 b2 + a13 b1 b3 + . . . = . . . (scalar)- no free index 1.22
Mathematical preliminaries Index notation- example • Determine the following quantities – bi bi = b1 b1 + b2 b2 + . . . = . . . (scalar)- no free index b1 b1 b1 b j bi b j = b2 b j = . . . ... b3 b j
b1 b2
b1 b3
= ...
(matrix)- two free indexes 1.23
Mathematical preliminaries Index notation- example • Determine the following quantities – Unsymmetric matrix decomposition 1 1 ai j = (ai j + a ji ) + (ai j − a ji ) |2 {z } |2 {z } symmetric
antisymmetric
– Symmetric part 1 (ai j + a ji ) = . . . 2 – Antisymmetric part 1 (ai j − a ji ) = . . . 2 1.24
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2.3
Kronecker delta and alternating symbol
Mathematical preliminaries Kronecker delta and alternating symbol • Kronecker delta is defined as 1 1 if i = j = 0 δi j = 0 if i = 6 j 0
0 1 0
0 0 1
• Properties of δi j δi j = δ ji δii = 3
δ11 a1 + δ12 a2 + δ13 a3 = a1 δi j a j = . . . = ai ... δi j a jk = aik δi j ai j = aii δi j δi j = 3 1.25
Mathematical preliminaries Kronecker delta and alternating symbol • Alternating (permutation) symbol is defined as +1 if i jk is an even permutation of 1,2,3 −1 if i jk is an odd permutation of 1,2,3 εi jk = 0 otherwise • Therefore ε123 = ε231 = ε312 = 1 ε321 = ε132 = ε213 = −1 ε112 = ε131 = ε222 = . . . = 0 • Matrix determinant a11 det(ai j ) = |ai j | = a21 a31
a12 a22 a32
a13 a23 a33
= εi jk a1i a2 j a3k = εi jk ai1 a j2 ak3 1.26
2.4
Coordinate transformations
Mathematical preliminaries
Coordinate transformations 9
• Consider two Cartesian coordinate systems with different orientation and basis vectors 1.27
Mathematical preliminaries Coordinate transformations • The basis vectors for the old (unprimed) and the new (primed) coordinate systems are 0 e1 e1 ei = e2 , e0i = e02 e3 e03 • Let Ni j denotes the cosine of the angle between xi0 -axis and x j -axis Ni j = e0i · e j = cos(xi0 , x j ) • The primed base vectors can be expressed in terms of those in the unprimed by relations e01 = N11 e1 + N12 e2 + N13 e3 e02 = N21 e1 + N22 e2 + N23 e3 e03 = N31 e1 + N32 e2 + N33 e3 1.28
Mathematical preliminaries Coordinate transformations • In matrix form e0i = Ni j e j ei = N ji e0j • An arbitrary vector can be written as v = v1 e1 + v2 e2 + v3 e3 = vi ei = v01 e01 + v02 e02 + v03 e03 = v0i e0i 1.29
Mathematical preliminaries Coordinate transformations • Or v = vi N ji e0j • Because v = v0j e0j thus v0j = N ji vi • Similarly vi = Ni j v0j • These relations constitute the transformation law for the Cartesian components of a vector under a change of orthogonal Cartesian coordinate system 1.30
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2.5
Cartesian tensors
Mathematical preliminaries Cartesian tensors • General index notation scheme a0 = a,
zero order (scalar)
a0i = Nip a p ,
first order (vector)
a0i j = Nip N jq a pq , second order (matrix) a0i jk = Nip N jq Nkr a pqr , third order ... • A tensor is a generalization of the above mentioned quantities Example • The notation v0i = Ni j v j is a relationship between two vectors which are transformed to each other by a tensor (coordinate transformation). The multiplication of a vector by a tensor results another vector (linear mapping). 1.31
Mathematical preliminaries Cartesian tensors • All second order tensors can be presented in matrix form N11 N12 N13 Ni j = N21 N22 N23 N31 N32 N33 • Since Ni j can be presented as a matrix, all matrix operation for 3 × 3-matrix are valid • The difference between a matrix and a tensor – We can multiply the three components of a vector vi by any 3 × 3-matrix – The resulting three numbers (v01 , v02 v03 ) may or may not represent the vector components – If they are the vector components, then the matrix represents the components of a tensor Ni j – If not, then the matrix is just an ordinary old matrix 1.32
Mathematical preliminaries Cartesian tensors • The second order tensor can be created by a dyadic (tensor or outer) product of the two vectors v0 and v 0 v1 v1 v01 v2 v01 v3 N = v0 ⊗ v = v02 v1 v02 v2 v02 v3 v03 v1 v03 v2 v03 v3 1.33
Mathematical preliminaries Transformation example • The components of a first and a second order tensor given by 1 1 bi = 4 , ai j = 0 3 2
in a particular coordinate frame are 0 2 2
3 2 4
• Determine the components of each tensor in a new coordinates found through a rotation of 60◦ about the x3 -axis 1.34
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Mathematical preliminaries
Transformation example • The rotation matrix is cos 300◦ 0 Ni j = cos(xi , x j ) = cos 210◦ cos 90◦
cos 30◦ cos 300◦ cos 90◦
1 cos 90◦ 2√ cos 90◦ = − 3 2 cos 0◦ 0
√ 3 2 1 2
0
0 0 1 1.35
Mathematical preliminaries Transformation example • The transformation of the vector bi is b0i = Ni j b j =
1 2√ − 23
√ 3 2 1 2
0
0
• The second order tensor transformation is √ 3 1 0 1 2 2√ 1 0 a0i j = Nip N j p a pq = − 3 0 2 2 3 0 0 1
1 0 4 = ... 0 2 1
0 2 2
1 3 2√ 2 − 3 2 4 0
√ 3 2 1 2
0
T 0 0 = ... 1 1.36
2.6
Principal values and directions
Mathematical preliminaries
Principal values and directions for symmetric tensor 12
• The tensor transformation shows that there is a coordinate system in which the components of the tensor take on maximum or minimum values • If we choose a particular coordinate system that has been rotated so that the x30 -axis lies along the vector, then vector will have components 0 v= 0 |v| 1.37
Mathematical preliminaries Principal values and directions for symmetric tensor • It is of interest to inquire whether there are certain vectors n that have only their lengths and not their orientation changed when operated upon by a given tensor A • That is, to seek vectors that are transformed into multiples of themselves • If such vectors exist they must satisfy the equation A · n = λ n,
Ai j n j = λ ni
• Such vectors n are called eigenvectors of A • The parameter λ is called eigenvalue and characterizes the change in length of the eigenvector n • The above equation can be written as (A − λ I) · n = 0,
(Ai j − λ δi j )n j = 0 1.38
Mathematical preliminaries Principal values and directions for symmetric tensor • Because this is a homogeneous set of equations for n, a nontrivial solution will not exist unless the determinant of the matrix (. . .) vanishes det(A − λ I) = 0,
det(Ai j − λ δi j ) = 0
• Expanding the determinant produces a characteristic equation in terms of λ −λ 3 + IA λ 2 − IIA λ + IIIA = 0 1.39
Mathematical preliminaries Principal values and directions for symmetric tensor • The IA , IIA and IIIA are called the fundamental invariants of the tensor IA = tr(A) = Aii = A11 + A22 + A33 1 1 IIA = tr(A)2 − tr(A2 ) = (Aii A j j − Ai j Ai j ) 2 2 A11 A12 A22 A23 A11 A13 + = + A21 A22 A32 A33 A31 A33
IIIA = det(A) = det(Ai j ) • The roots of the characteristic equation determine the values for λ and each of these may be back-substituted into (A − λ I) · n = 0 to solve for the associated principle directions n. 1.40
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Mathematical preliminaries Example • Determine the invariants and principal values and directions of the following tensor: 3 1 1 A= 1 0 2 1 2 0 • The invariants are IA = . . . ,
IIA = . . .
IIIA = . . .
• The characteristic equation is −λ 3 + 3λ 2 + 6λ − 8 = 0 • The roots are λ1 = −2, λ2 = 1 and λ3 = 4 1.41
Mathematical preliminaries Example • For λ1 = −2 we have (A − λ1 I) · n1 = 0 0 5 1 1 n11 1 2 2 n21 = 0 0 1 2 2 n31 • The homogeneous set of equations have linear dependent equations and the solution represents only the ratio between the solution set • Applying n31 = 1 and solving the first end second equations we get n1 = . . . • Similarly for λ2 = 1 and λ3 = 4 1.42
2.7
Vector and tensor algebra
Mathematical preliminaries Vector and tensor algebra • Scalar product (dot product, inner product) a · b = |a||b| cos θ • Magnitude of a vector |a| = (a · a)1/2 • Vector product (cross-product)
e1 a × b = det a1 b1
e2 a2 b2
e1 3 a3 b3
• Vector-matrix products Aa = Ai j a j = a j Ai j aT A = ai Ai j = Ai j ai 1.43
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Mathematical preliminaries Vector and tensor algebra • Matrix-matrix products AB = Ai j B jk ABT = Ai j Bk j AT B = A ji B jk tr(AB) = Ai j B ji tr(ABT ) = tr(AT B) = Ai j Bi j where ATij = A ji and tr(A) = Aii = A11 + A22 + A33
2.8
1.44
Tensor calculus
Mathematical preliminaries Tensor calculus • Common tensors used in field equations a = a(x, y, z) = a(xi ) = a(x) − scalar ai = ai (x, y, z) = ai (xi ) = ai (x) − vector ai j = ai j (x, y, z) = ai j (xi ) = ai j (x) − tensor • Comma notations for partial differentiation ∂ a ∂ xi ∂ ai ai, j = ∂xj ∂ ai j,k = ai j ∂ xk
a,i =
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Mathematical preliminaries Tensor calculus- example • Vector differentiation ai, j =
∂ ai = ∂xj
∂ a1 ∂x ∂ a2 ∂x ∂ a3 ∂x
∂ a1 ∂y ∂ a2 ∂y ∂ a3 ∂y
∂ a1 ∂z ∂ a2 ∂z ∂ a3 ∂z
1.46
Mathematical preliminaries Tensor calculus • Directional derivative – Consider a scalar function φ . Find the derivative of the φ with respect of direction s ∂ φ dx ∂ φ dy ∂ φ dz dφ = + + ds ∂ x ds ∂ y ds ∂ z ds – The unit vector in the direction of s is dx dy dz n = e1 + e2 + e3 ds ds ds – The directional derivative can be expressed as a scalar product dφ = n · ∇φ ds 1.47
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Mathematical preliminaries Tensor calculus • Directional derivative – ∇φ is called the gradient of the scalar function φ and is defined by ∇φ = e1
∂φ ∂φ ∂φ + e2 + e3 ∂x ∂y ∂z
– The symbolic operator ∇ is called del operator (nabla operator) and is defined as ∇ = e1
∂ ∂ ∂ + e2 + e3 ∂x ∂y ∂z
– The operator ∇2 is called Laplacian operator and is defined as ∇2 =
∂2 ∂2 ∂2 + + ∂ x2 ∂ y2 ∂ z2 1.48
Mathematical preliminaries Tensor calculus • Common differential operations and similarities with multiplications Name Gradient of a scalar Gradient of a vector Divergence of a vector Curl of a vector Laplacian of a vector
Operation ∇φ ∇u = ui, j ei e j ∇ · u = ui, j ∇ × u = εi jk uk, j ei ∇2 u = ∇ · ∇u = ui,kk ei
Similarities ≈ λu ≈ u⊗v ≈ u·v ≈ u×v
Order vector ↑ tensor ↑ dot ↓ cross →
Note The ∇-operator is a vector quantity 1.49
Mathematical preliminaries Tensor calculus- example • Scalar and vector functions are φ = x2 − y2 and u = 2xe1 + 3yze2 + xye3 . Calculate the following expressions • Gradient of a scalar ∇φ = . . . • Laplacian of a scalar ∇2 φ = ∇ · ∇φ = . . . • Divergence of a vector ∇·u = ... • Gradient of a vector ∇u = . . . 1.50
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Mathematical preliminaries Tensor calculus- example • Curl of a vector
e1
e2
e3
∇ × u = det
∂ ∂x
∂ ∂y
∂ ∂z
= ...
2x
3yz
xy 1.51
Mathematical preliminaries Tensor calculus • Divergence (Gauss) theorem Z
u · ndS =
S
Z
∇ · udV
V
where n is the outward normal vector to the surface S 1.52
Mathematical preliminaries
The End • Welcome and good luck • Any questions, opinions, discussions? 1.53
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