TAREA 7

UNIVERSIDAD DE GUAYAQUIL FACULTAD: INGENIERIA QUIMICA ASIGNATURA: CALCULO DE INGENIERIA QUIMICA II (IQ-402)

TAREA # 7 SEMESTRE IIII PARALELO: A 

PARCIAL: II

ESTUDIANTE: MÉLANIE MARTINEZ VERA DOCENTE: ING !OSE VALDEZ DIAZ 20"-20"$

E!ERCICIOS FELDER 

CAPITULO % & 'ALANCES DE PROCESOS DE SOLUCION Y MEZCLA &-"-PRODUCCION DE ACIDO CLORIDRICO E *+,. +./1/,+. 3 /.5+3 6./,38. C 963.. (+./5/. 3 ,/.938.) 38 6956 C6+53 3 +6./ 53 33 ;/68 , 3 6,?38;68 6 36 C(9) 6 "00@C  2O() 6 2@C 6/6 /.5+,/ "000B9 3 C (6+) 6 20 ./ 3. 38 40@C E 6+.8363 3;3/?,86/ 6 +68;,63 ?.6/3 . 3.+,63 3 6 6 3.+,63 3  6 3.+,6 6 6 +56 3 33 ;/68

ṁ(

=

( 200− 84 ) "bm h

=

136 "bm

h

  de producto en (apor

"alance e energa L& MH& ṁ 3 +.8+38;/6 *+,. ,5,. ($0 2SO4) 6;6 3 % 3 /,536 E *+,. ,5,. 38;/6 38 3 ,;3?6 6 70@F ?,38;/6 53 3 6./ 3 6956  *+,. +.8+38;/6. 638 3 ,;3?6 6 6 ;3?3/6;5/6 3 35,+,=8 3 ;,?. KC5*8;. 'TU .8 83+36/,. 6/6 +.8+38;/6/ "000  3 *+,. ,5,.

-

Solución

=alance de materia "ara gases  & = " + #  1000 lb = "+ # 

"ara parcial sólido 1000 lb ( 0.6 ) = " ( 0.95 )

 "=631.58 lb

Lectura del grDfco >85 E atson  T!  ∗( 1000 lb )=−115000 T!  ∆ H  & =−115 lb

^ ^

∆ H  "= 970.3

^

T!  ∗( 631.58 lb )=612822 T!  lb

^

Q = ∆ H  " −∆ H  & Q =612822 T! −(−115000 T! )

Q =727822 T! 

E!ERCICIO # "4

+,. +./1/,+.> G ($0@$0@F) "2> 3 /36/= 6./,38. C 96 6 &0@F ./ 6956 53 3;* 38;/68. 6 ,;3?6 3 6./+,=8 6 0@F S, 3 *+,. K+5* 3 6 ?*,?6 ;3?3/6;5/6 53 533 6+686/3

 '  & 1 =

( 1 ) (1 ) 2

 '  & 1 =0,5  '  & 1 =50

F& 2+5°

E!ERCICIO "$ S3 ?3+68 38 +.8,+,.83 6,6*;,+6 . ,.5+,.83 3 *+,. 5 K+5* 3 6 ?*,?6 ;3?3/6;5/6 53 3 533 6+686/ P./ ?3,. 3 58 353?6> ,8,53 +.?. 3 5;,,6 6 8/  3: 4 F'

E!ERCICIO # "%

C6+33 3 +6./ 83+36/,. 6/6 +.8+38;/6/ 40  3 C 3  6 "20F 6;6 & 3 C 6 20 6 "20F> , . 6./3 3 3/3838 6 "20F (F,9#&0)

!  3: 5+/GH  3: 48.8 G' (4/ Lb E %) "  3: 5+/GH  3: 48.8G' (8 Lb E +/%) 0

(

∆ H  +  = −99

0

(

∆ H  +  = 44

0

 )

T!  ( 8 "b )=−792 tu  "b

 )

 T!  ( 40 "b ) =1760 tu  "b

0

0

∆ H  = ∆ H  + − ∆ H  s ∆ H  = (1760 tu)− (−792 tu )=2552 T!  0

 H g =1113,6

 T!  (32 "b ) =35635,2 T!   "b

0

∆ H  T = H g− ∆ H  ∆ H  T = ( 35635,2 −2552 ) T! =33089.2 T!  0

E!ERCICIO # 20