Tarea 1 - Analisis Estadistico

October 9, 2022 | Author: Anonymous | Category: N/A
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  _LHWOZ _L HWOZUHB UHBC C B LCEHFLC LCEHFLC A BO RZ_KHA RZ_KHAA AF GCE_ARCB BO HLIOLHOZÍC

Oseuoac Cecbèmhef Prfgoshflca bo Hliolhoríc Suímhec 

RZCJCKF; RCZOC 3  ―  OKOZEHEHF PZCERHEF E_ZUF; CLÃAHUHU OURCBÍURHEF X BHUOÓF BO OTPOZHMOLRFU BFEOLRO; BZ. A_HU CAJOZRF OURZCBC CAWC OUR_BHCLROU; - PCAFMHLF MOBHLC ECMHAF OZLOURF (EFFZBHLCBFZ) - POBOMFLRO CJCLRF K_CL BCLHOA - MOURCL[C CJCB KFU_È OUROJCL - KCZC IFL[CAOU GZCLN OURCAGOZ - AO[ECLF AOEEC K_CL CLRDFLX

RZ_KHAAF ―  POZÛ  POZÛ :0:3

 

RCZOC 3 RCJ_ACEHÕL X MOBHBCU BO ZOU_MOL OKOZEHEHF PZÃERHEF;

C pcrthr pcrthr bo ulc pfjacehõl bo L= ??00 00

scefs bboo mctorhca mctorhca curígorf bo ulc omprosc

mhlorc so bosoc osthmcr oa posf mobhf boa frf pfr scef, ol ircmfs. c)  C pcrthr bo ostc pfjacehõl fjtolic afs pcrãmotrfs; mobhc pfjacehflca, mobhclc, bosvhcehõl ostãlbcr, efogheholto bo vcrhcehõl. Ovcaûo ac shmotríc.  j)  C pcrthr bo ostc pfjacehõl eflstruyc ulc tcjac bo bhstrhjuehõl bo groeuolehcs e)  Fjtolic ulc muostrc caoctfrhc bo tcmcóf 9?, usclbf ul mètfbf caoctfrhf. b)  Botormhlcr ac mobhc muostrca ( T  ) y ac vcrhclzc muostrca (s:) o)  Osthmcr oa hltorvcaf eflghbolehca pcrc ac mobhc pfjacehflca (α) ol ul hltorvcaf ca 8?% bo eflghclzc efl ac shiuholto gõrmuac;

 

α ;

 

³ t(l-3)*(s:/l)3/: 

 

Prfj( - t(l-3) *(s:/l)3/: 1 α 1 + t(l-3) *(s:/l)3/:) = 3-c  s :  L √ l α ; T  ³ t(92,0.89?)* (  )  l  L √ 3

t(92,0.89?) = 3.88:

α ; T  ³ b

s :  L √ l b =3.88:* (  )  l  L √ 3

Prfj( T  - b 1 α 1

T  +

b)= 0.8?

b; orrfr bo osthmcehõl s :  L √ l b = 3.88: (  )  l  L √ 3

g). Ovcaucr sh oa hltorvcaf bo eflghclzc efltholo ca vcafr boa pcrãmotrf.

 

RCJAC BO BCRFU Rcjac 3; Bctfs boa posf boa frf ol ircmfs pfr scef bo ulc pfjacehõl. 3 

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UFA_EHÕL;  Hlehsf c

Mobhc pfjacehflca Uo fjtholo ca bhvhbhr ac sumc bo bctfs lumèrhefs oltro ac eclthbcb bo oaafs.

α = :58.88

Mobhclc Os cquoa vcafr quo so oleuoltrc ujhecbf ol oa pultf eoltrca boa eflkultf bo bctfs frbolcbfs bo ulc vcrhcjao euclthtcthvc, ol oa ecsf bo dcjor : lûmorfs eoltrcaos, so dceo ul prfmobhf oltro cmjfs. Mo = T(l+3)/:

f

Mo = (T(l)/: + T(l+:)/:)/: Mo = :20

Bosvhcehõl ostãlbcr pfjacehflca Uo boghlo efmf ulc mobhbc quo mhbo ac rcíz eucbrcbc bo ac vcrhcjhahbcb v crhcjhahbcb f bhsporshõl mobhc eucbrãthec bo afs bctfs rospoetf c su prfmobhf. Mhbo ac rcíz eucbrcbc bo ac vcrhcjhahbcb f bhsporshõl mobhc eucbrãthec bo afs bctfs rospoetf c su prfmobhf.

 ∓ (√)  = = ∛     = .  

 

Efogheholto bo vcrhcehõl Os ul efogheholto cbhmolshflca quo pormhto ovcaucr ac mcilhtub bo ac vcrhcjhahbcb bo afs bctfs rospoetf c su mobhc crhtmèthec

 

  Ûtha pcrc efmpcrcr ac vcrhcjhahbcb v crhcjhahbcb bo bfs f mãs bhstrhjuehflos bo groeuolehc.

..  % = ̏

 

 

Cshmotríc

.. % = 4.0099

Uo bheo quo ulc bhstrhjuehõl os shmètrhec f shl sosif sh afs vcafros bo ac mobhc, ac mobhclc y ac mfbc sfl hiucaos.

√  )   = 5 ∙ ( ̏ √

 

 

  = √0.00:98

Haustrcehõl 3; Irãghec ol ac quo so muostrc ulc cshmotríc loicthvc.

Ovcaucmfs ac shmotríc; Bcbf quo oa vcafr bo Cs os loicthvf (Cs 1 0), pfbomfs cghrmcr quo roprosoltc cshmètrhec efl sosif loicthvf c ac hzquhorbc

 

 Hlehsf j

3° ecaeuacmfs afs bctfs loeoscrhfs pcrc ac eflstruhr luostrc tcjac bo groeuolehcs;

Mãxhmf; Mãx = :8:

Mílhmf; Míl = 399

Zclif; Mãx √ Míl = 33?

Lûmorf bo hltorvcafs;



m = 3 + 5.5::  afi(l) = 30

Cmpahtub;

 =    = 33.? ≄ 3:  

 

Ol jcso c oaaf, fjtuvhmfs ac shiuholto tcjac bo bhstrh bhstrhjuehõl juehõl bo groeuolehcs;  Hlehsf j Rcjac :; Rcjac bo bhstrhjuehõl bo groeuolehcs.

m 3 : 5 2 ? 7 9 4 8

^ Ah 399 348 :00 :3: ::5 :5? :27 :?4 :78

As) 348 :00 :3: ::5 :5? :27 :?4 :78 :43

Th 34:.99 382.53 :0?.4? :39.58 ::4.85 :20.29 :?:.03 :75.?2 :9?.04

gh 5 8 :3 72 300 33: 303 73 :3

Gh 5 3: 55 89 389 508 230 293 28:

dh 0.70% 3.40% 2.:0% 3:.40% :0.00% ::.20% :0.:0% 3:.:0% 2.:0%

Dh 0.70% :.20% 7.70% 38.20% 58.20% 73.40% 4:.00% 82.:0% 84.20%

Th*gh ?24.53 3924.94 25::.43 3583:.98 ::48:.79 :785:.34 :?2?:.?: 37097.:3 ?997.97

30

:43

:8:

:47.7:

4

?00

3.70%

300.0%

---

 

 Hlehsf e √ 

- Pcrc ovhtcr quo so rophtcl afs vcafros y/f so mfbhghquol, af quo so dhzf guo boscrrfaacr ulc Mcerf uthahzclbf oa aoliucko WJC bo Oxeoa.

√ 

Auoif so efphõ afs vcafros ol acs tcjacs, acs eucaos cpcroeol c eflthlucehõl.

3 : 5 2 ? 7 9 4 8 30 33 3:

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35 32 3? 37 39 34 38 :0 :3 :: :5

588 573 529 577 89 549 5? 3:? 297 230 330

:2 :?

85 338

:54 :?? :?? :35 ::8 :00 :70 :?4 :?7 ::: :?2

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82 :24

:2? ::4

?3 ?: ?5 ?2 ?? ?7 ?9 ?4 ?8 70 73 7: 75 72 7? 77 79 74 78 90 93 9: 95 92 9?

249 54? 383 :25 :92 559 :0 5:2 2?0 393 ?8 547 340 :07 592 :38 :?2 49 320 22 280 32: 530 3?2 2:9

:75 :?7 :?9 :57 384 :35 :33 :20 :20 :74 :22 ::7 :55 ::9 :23 :58 :55 :25 :?8 :75 :25 :57 :49 :04 :79

Lftc; Ac tcjac cltorhfr muostrc oa lûmorf bo scef efl su rospoethvf efltolhbf f posf

bo frf. 

 

 

 

Haustrcehõl :; Mètfbf boscrrfaacbf ol WJC pcrc iolorcr lûmorfs caoctfrhfs y lf ropothbfs.

 Hlehsf b

Mobhc muostrca Uo fjtholo ca bhvhbhr ac sumc bo bctfs lumèrhefs oltro ac eclthbcb bo oaafs.

   ∓ ̏ =   

 

:20.4

Wcrhclzc Muostrca

̏ =

Ac vcrhclzc os ulc mobhbc bo què tcl bhsporsf os ul eflkultf bo bctfs. Os ûtha ca mfmoltf bo erocr mfboafs ostcbísthefs bojhbf c quo ac vcrhclzc jckc puobo sor ulc soóca bo quo ostãs sfjro ckustclbf tus bctfs.



"Ac vcrhclzc ( ) mhbo ac bhsporshõl bo afs bctfs bo ulc muostrc (T3, T:,…,TL) rospoetf c ac mobhc (x), ecaeuaclbf ac mobhc bo afs eucbrcbfs bo acs bhstclehcs bo tfbfs afs bctfs".

 :   = ∓3  ((√  √3)

 

   =

 575.0?

 Hlehsf o

Orrfr bo Osthmcehõl     = 3.88:∙∛  8:∙ ∛    ∙ ( √√√33)

 = ?.?09 ≄ ?.?

 

Hltorvcaf eflghbolehca ca 8? % pcrc ac mobhc pfjacehflca ( )

 =  ³   = :20.4 ³?.?  

 

 Hlehsf g

Pcrãmotrf Oa hltorvcaf bo eflghclzc ca 8?% sí eflthlo ca vcafr boa pcrãmotrf pfjacehflca () yc quo so oleuoltrc boltrf boa rclif

 

CLOTF Ol oa shiuholto olaceo bo brhvo olefltrcrã oa Oxeoa ol oa euca so rocahzõ ac tcroc; dttps;//brhvo.iffiao.efm/ghao/b/3zsTT83bwz 87x_YZI5nbdsWOJT3P5B5WOJT3P5B5dttps;//brhvo.iffiao.efm/ghao/b/3zsTT83bwz87x_YZI5nbds  L/vhow6usp=sdcrhli    L/vhow6usp=sdcrhli

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