Taller de Mecanización de Evaluación Del Módulo

August 26, 2022 | Author: Anonymous | Category: N/A
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Xmjjir hi Ai`mlkzm`kðl hi Ivmjum`kðl hij aðhujd =. Risuijvm jvm7 m. V(0+ V(0+=2 =2−9 −9)7 )72− 2−8+ 8+2Q 2Q⋉⋉(8+2−=) 10(8+2-=)

`. 8⋉V0+3 V0+3⋉⋉(9+0−3)Q−0 (9+0−3)Q−0⋉⋉(9−(=+2)) 18 18⋉⋉V0+3 V0+3⋉⋉(?−3)Q−0 (?−3)Q−0⋉⋉(9−(0)) 18⋉V0+3⋉(2)Q−0⋉(2) 18 18⋉⋉V0+=2Q−3 18 18⋉⋉V=9Q−3 13>−3 198

10⋉9 1=9 b. (=+5−0)⋉(0+2)−0>7(9−2+0) 19(0+2)-0>7(9-2+0) 19 19⋉⋉9-0>7(9+2+0) 19 19⋉⋉9-0>73 129-0>73 129-9 12>

h. =5 − 0 ⋉ (? − 8) + 98 7 2 1=5−0 ⋉ (8)+25 1=5−=2+25 19+25 102

2. ris risuij uijvm vm jds igi igir`k r`k`kd `kdss hi Crm``kdlis

´−

( − )−( + )( + )

8 =

9

0 2

8

= 0

2

=

0

=

´− ´−

8 == 0



22 0

2





=0 9 0

=0 9 0





´− + ?

= 0  = 7 2 8 2 ⋉

0

´ ( −0 )

0

( )

2 =  5 + 7 0 2 2

=

´−

22 0



39 ;

´

2

−5 2

´−

=0= ;

´ −=8.99

=

´

2

−5 2

7



= 5

 

=

´−

 

5

´ −=8.2?

0. Ris Risuij uijvm vm jm jmss dpi dpirm` rm`kdl kdlis is hi p pdt dtil` il`km km

´

´

 9

=0 −== =3

9  9

9





=5

9

=5

2 ⋉

9

=3

9



9

´ (− 8 ) − ´ ´ 3

´

´

 9

2−=

=5



9

=3

9  9

=5

= ⋉

9

8

9

=3

2

´ (− 8 ) ´ ´ 2

´ (− 8 ) ´ ´ 2

´  9

9



9

=5

´ (− 8 ) ´ ´

=3

2

´9 ´9

=



9



9

2

´9 ´ 29

´ (− 8 ) ´ ´ ´´´ ´´´ ´´ ´´ ´ −38

 

´´´ ´

 2

=2>

=?> ⋉

0



 2

=?>

=2>



0

´



0 2

´

 2

´

 2



9;>8;

=0> =3>

=3>

=2>

=?>

0



9;>8; 2 ⋉

=0>

0

=3>

=?> ⋉

2



9;>8;

=>

0

´  2  2



08> ⋉

0

=>

=3>

=?>

´

9;>8;

´´

2=> 0 0



0

=>

=>

08>

´2

8. ri risu suij ijvm vm jd skeu skeuki kilt ltii

 

     

^iráaitrd7 +J+ + J + =2 `a + ? `a  ^iráaitrd7 J=2`a + J?`a ^iráaitrd7 8> `a  mrimp 7 ώ r

2

1 0,=8=3 . (0 `a )2 1 0,=8=3 . ; `a 1 2?,25 `a

mrime 7 ώ r

2

Írim e - írim p 

2

2

1 298,83 `a  - 2?,25 `a

2

1 223,=; `a

2

1 0,=8=3 . (; `a ) 1 0,=8=3 . ?= `a 1 298,83 `a

2

2

2

2

 

9. Risu Risuijvm ijvm jd jdss skeuk skeukiltis iltis iigir`k`k gir`k`kds ds hi `í `íj`ujd j`ujd hi vvdjua djuail il hi sd sdjkhds jkhds m. @mj @mj`uj `ujmm ij vvdju djuail ail hi iistd stdss `u `uirp irpds7 ds7

S 1 mµbµ` S 1 2>µ;µ5 S 1 =23>

S1 S1

= 0

= 0

µeµo

µ 5?.98 µ =5

S 1 889.>9;

S 1 ώµrµo S 1 ώµr 2 µ o S 1 ώµ 3 2 µ =9 S 1 ώµ 3 2 µ =9 S 198> ώ 

 

S 1=3;3.83 3. Ris Risdjv djvir ir jm jmss ske skeuki ukilti ltiss i`u i`um`k m`kdl dlis is

1 8  xµ 0 1(00 + x ) µ =

´ =2 x 100 + x ´ =2 x − x 100 + x − x ´ == x 100 ´

 == x ==

1

00 ==

 x 10

´

 8  x =9

µ =9−

3 x + 2? 9

µ =91> µ =9

´ 8 x −0 ( 3 x + 2? )1> ´ −0 x ( 3 x + 2? ) 7 −=? x −?8 ´ 8 x −=? x −?8 1> ´ −=8 x −?8 1> ´ =8 x −?8 + ?8 1> + ?8 ´ −=8 x 1?8  −=8 x   ?8 1 ´ −=8 −=8

 

 x 1−3

´

 2 x

µ =21

9 x

0

µ =2−2 µ =2

=2

´ ? x 19 x −28 ´ ? x −9 x 19 x −28 −9 x ´ 0 x 1−28 ´

 0 x 0

1

−28 0

 x 1−?

´ 0 xµ => −

2 x 9

µ =>1

0 x =>

µ => + =8 µ =>

´ 23 x 10 x + =8>

´ 23 x −0 x 10 x + =8>−0 x ´ 20 x 1=8>

´

 20 x 20

 x 1

1

=8> 20

=8> 20

 

 x 13.>?3;9

´

 8  x

−0

µ =9 −

8 x

9

µ =91

2

( x −=0 )

0

=9

´ 0 ( 8 x − 0 )−2> x 12 ( x −=0 )

´ −? x −; 12 x − 23 ´ −? x −; + ; 12 x −23 + ; ´ −? x 12 x −=5 ´ −? x −2 x 12 x −=5 −2 x ´ −=> x 1−=5  −=> x −=5 1 ´ −=> −=>

 x 1

=5 =>

 x 1=.5

µ =9

 

5. Risu Risuijvm ijvm jd jdss skeu skeukilti kiltiss igir igir`k`kds `k`kds hi i`um i`um`kðl `kðl h hii 2hd ermh ermhd d

2

 x =,21 −= ½ ∗ = −8 µ 2 (− 0) 2 µ2

∗ = −8 µ 2 (−0 )1 9 2

 x =,21

 x =1

−= + 9 2µ 2

−=+ 9 2µ 2

, x 21

= 9

 x 1 −2 µ+2 7 =  x 1

−=−9 2 µ2

 x 1= , x 1

7−

−0 2

0 2

−=−9 2µ 2

 

 x =,21

−2 ½ ∗ 22− 8 µ ; (−= ) 2µ ;

=> ∗ 2 − 8 µ ; (−= ) 12 ∗ => 2

 x =,21

 x =1

−2 ½ 2 ∗ => => 2 µ;

−2 + 2 ∗ => =>

, x 21

2µ;

−2−2 ∗ => => 2µ ;

 x 1

−2 + 2 ∗ => => −= + ∗ => =>

 x 1

−2 + 2 ∗ => =>

 x 1

−= + ∗ =>

7

2µ;

;

2µ;

;



7

, x1

=

+ ∗ => => ;

−=+ ∗ => => ;

?. Rimjk Rimjk`i `i ij mlí mlíjksks jksks hi h hirkvm irkvmhm hm p pmrm mrm jm ccul`kð ul`kðl l

(

hirkvmhm c  ( ( x )1

hirkvmhm

=

´´

 =

(+ )  =

=  x

 )

= + x

 6 x

 

;. mlíj mlíjks ksks ks is istm tmhá hás s`d `d =. Pi ili ul ulmm klhus klhustrkm trkm il jm `u `umj mj si jjivm jm sskeuki keukilti lti klcd klcdram`k ram`kðl ðl m`ir m`ir`m `m hi háms hi kl`mpm`ktm`kðl m trmbmgmhdris pdr hkvirsms `musms hi ul tdtmj hi 8>> trmbmgmhdris hurmlti ul mýd. Pi ili ispujmhd pdr `mhm pd hi m``khilti 5 háms pdr kltdxk`m`kðl => háms pdr jiskðl 2= háms pdr `máhm hi mjturm _ XRMBMGMHDR = 2 0 8 9 3 5 ? ; => == =2 =0 =8

XK^D HI MCI@XM@KÐL HÁMP HI KL@M^M@KHMH Jiskðl, Kltdxk`m`kðl =5 Kltdxk`m`kðl, Jiskðl =5 @máhm hi mjturm 2= @máhm hi mjturm 2= @máhm hi mjturm 2= Jiskðl => Jiskðl => @máhm hi mjturm 2= Kltdxk`m`kðl, @máhm hi mjturm 2? @máhm hi mjturm 2= Jiskðl, `máhm hi mjturm 0= Jiskðl => Jiskðl => Jiskðl =>

 

HÁMP HI KL@M^M@KHMH 09    H    M    H    K    @    M    ^    M    @    L    K    I    H    P    M    K    H

0=

0>

2?

29

2=

2=

2=

2=

2=

2> =9 =>

=5

=5 =>

=>

9 >

XRMBMGMHDR [ M@@KHILXI

=>

=>

=>

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