Statics and Mechanics of materials- Chapter 10

January 21, 2017 | Author: Matthew Scott | Category: N/A
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F

-.f=Ee*

(1o*loo) = GqtN,nn-{ $t*t**= *(o,atnf Problam10,2

-= 97.3xros Pe 97.? MPa

fRO?[IfT.tnY IilTIRIAL. O ztll ThcMcCtt-lH Ccpir* lF. Afl dtb rxrd. No Ft dtb Menrnlmry bc diilph!64 nnoo*m, r fu|r:l b q Lr q V :l ru, *h p;* lb Fh rft of b l*5rr, r rrd bqila b H ffiitn b Fhors ard €fucr0or!pr*a It Mcf.fl*'-Hill for tr€fuiadividrdcou,tnpryantion. $tudarils rnrngthir melrul$'crurrl it witM pcrmirlbn.

probrem 10s

;iffi;; lfl*J"di$*ljl1JilffiiTfl::;}XffiHffiffi|i;ilH'#1il hown is the same as in part a.

=(*Yf'6)

= o'8in'

t = (t[a't) = i.e in, tJ-c,t)= E(-2, - o-8")= 2.c,sgi,,r oo lL'ft -€ zt 6 o o !1. ;n

(o) T^*=ts" W

= qetlr=; = q.1? ksr'

L*

(b)

Tc

/=

J

c3 = 3I ffi

PfOblem

.\rr = I2'* .+ "

= =

e,oo\ = -(R\(zr Tr (gg t? )

ffl#*%ffi"H.tottd

J

to)frfl

es"/,Jsl',a{l}

S = I.t T*,*=

F

zT IT3E:

1.39666 i,,,3

10.a (a) Determinethe torquethat can be appliedto a solid shaftof 3.6 in. outer diameterwithout exceedingan allowableshearingstressof l0 ksi. (D) Solve pafi a,

10.4

: l

.:.

-L d ==

c=+A=

shaftisreplaced byahollowshaftofthesam"*assanaorr.O- :

({X3.6)=

t.g in.

= { (r-e)t= 9-reoq ,.ng (fO)(t.tGoq)= gl.Go?*ip.i", or :f = H= |

( b)

Il"//"w s['of*: fi'r

cr = *d, = (tX 3-e) =

equo,l mcgses *4.

J : T ( a r t - c , u )=

W=

or

= 7.63 Hf .ft

t-B in-

6pqss sec,*r',,no.! a.re.Ls -u"l

A = Trez = Tr(c..- c,. ) ez=ffi=2..sq$ti.,

T=T'

{

b. .|uol.

cr = {c,rc

+q.+6q in+

t?'i.33kip.i,' T : t6.17k,F.ff-

PROPRIETAR'YMATERIAL' o 201I The.McGraw-Hill Companics,Irrc.All rightsreserved. No part of this Manualmay bc displayed,reproduced, or distributedin any.fo11 o1by any means,withou! tlrc prior p.trission of the publisher,or usedbeyondth€ limited distribution to teachprsand educators permittedby McGraw-Hillror theirindividualcou^"",ritlrn pi"p"lttn. studentsusingthis manualareusingit witlnut permission.

PfOblgm

ri

I0.5 (e) For thc 3-in.-diametersolid cylinder rnd loding *rown, detenninethc maximumshoring stress. (D) Determincthc inner dimreter of the hollow rylinder, of 4-in. outerdiurutor, for which the manimum$tr€ssis the sarne8s in part a.

10.5 T,

sh4+ti

T

(b) Hollow sLr*t;

,

c=*Jt= |(ao1 = l,5in.

= -4, = (L)(ryI -- 7,5+sksi (f.s)t Tcg (b)

!,

I

cz=+d = {(to) = z.o i,,.

{ce = $(c.{l- c,t) = T c" t** (2)(tlox3.o') q.2s + inl = = 1 = ?,,01 )or .- JIS. cr = LTrT^*>

ffi

Ct = l- 7+ 315 ir, PfOblem

i

4,= 2C, ?

g , 1 ? i n-

10.6 (a) Determinethe torquethat canbe appliodto a solid shaftof 0.75-in.diameter

10.6

trJiHffff tf;ffitH?$:"*T:i:ffi-"il:1H.:?*:'H*il#,ffiH and with an inncr diameter equal to half of its owll outer diamden.

SOLUTION

(d Sr.0;J sho{t: s = +"1= (*Xo.zs) -- o.3?.fin. |.*,.,= lo !ts,' J'= * c* i { (a-e7s)" = O-ogloig ir,r

T= +

=(o€?l?FX,*-. = o.sask,.p.i,ror sitElL.in <

(b) llo0!o, sh$tt E.

tlne sa-n-e. ur
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