Span Deflection Report Uthm

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Span Deflection Report...

Description

LIGHT STRUCTURE LABORATORY FULL REPORT BFC21201 BFC

Course Code

BFC21201

Course Name

Makmal Hidraulik Dan Mekanik Bahan

Date Group Group Leader

 Norhafidzah Bt Abdul Rahman

Members of Group

1.Muhammad Amin Bin Rosli 2.Mohd Ashraf Bin Mohd Azhan 3.Muhammad Arif Bin Mohd Nazir 4.Mohamad Radzif Bin Mohd Raes

Lecturer/Instructor/Tutor Encik Ahmad Fahmy Bin Kamarudin Received Date Criteria

1

2

3

4

5

SCR 

VT

Student in laboratory more than 1 hour late

Student in laboratory within 30 minutes to 1 hour late

Student in laboratory within 10 to 30 minutes late

Student in laboratory just  before laboratory start start

Student in laboratory 10 minutes earlier 

1

Purpose is not identified

Purpose is somewhat vague

Purpose is identified

Purpose is identified

Purpose is clearly identified Relevant variables are described

1

Purpose

Relevant variables are not described

Relevant variables are not described

Relevant variables are described in somewhat unclear 

Relevant variables are described

Materials (optional)

There is not a list of the necessary lab materials

Most lab materials included

All necessary lab materials included but not listed in any

All necessary lab materials included and listed

All necessary lab materials included and listed in an organized

Procedures are not listed

Procedures are listed but not in clear steps

Procedures are listed in clear steps  but not numbered and/or and/or in complete sentences

Procedures are listed in clear steps

Procedures are listed in clear 

Attendance & Discipline Aim &

1

steps Each step is numbered and in a complete sentence

Procedure

1 Each step is numbered and in a complete sentence Diagrams are included to describe

Data is not represented or is not accurate Data

Data lacks precision Greater than 20%; difference with accepted values

Good representation of the data using tables and tor graphs Less than 15% difference with accepted values Precision is acceptable

Accurate representation of the data using tables and/or graphs Data is fairly precise Less than 10?% difference with accepted value

Accurate representation of the a using tables and/or graphs Graphs and tables are labeled and data is  precise with less than 5% 5% difference with accepted values

4

TSCR(X)

Trends / patterns are not analyzed

Trends / patterns are not analyzed

Trends /patterns are logically analyzed for the most part

Trends / patterns are logically analyzed

Questions are not answered

Answers to questions are incomplete

Questions are answered in complete sentences

Questions are answered in complete sentences

Analysis is inconsistent

Analysis is general

Analysis is thoughtful

A statement of the results i s incomplete with little reflection on the lab

A statement of the r esults of the lab indicates whether results support the hypothesis

Accurate statement of the results of the lab indicates whether results support the hypothesis

Tends / patterns are logically analyzed

Analysis / Result

Questions are answered

4

Analysis is not r elevant thoroughly and in complete sentences  No discussion was included or shows little effort and reflection on the lab Discussion

Accurate statement of the results of lab indicates whether results support hypothesis Possible sources of error and it was learned from the lab discussed

4

Possible sources of error identified Participation (during experiment

Interview

Student was hostile about  participating

Participation was minimal

Did the job but did not appear to be very interested. Focus lost on several occasion

Used time pretty well. Stayed focused on the experiment most of the time

Showed interest, used time very well, guide other students and very focused on experiment

The student cannot answer questions about the experiment

The student can answer some questions about the experiment

The student can answer questions about the experiment and begins to make connections between the experiment and its applications

The student can explain the results of the experiment in detail and the ways in which they relate to the research focus

The student can explain the results of the experiment in detail and the ways in which they relate to the research focus. The student can also evaluate the significance of the experiment to the real situation

 NAME OF LECTURER:

Comment by examiner

SIGNATURE:

DATE:

TOTAL SCORE:

Received

1

3

1.0

OBJECTIVE

To determine the relationship between span and deflection

2.0

INTRODUCTION

A beam must possess sufficient stiffness so that excessive deflections do not have an adverse effect on adjacent structural members. In many cases, maximum allowable deflections are specified by Codes of Practice in terms of the dimensions of the beam, particularly the span. The actual deflections of a beam must be limited to the elastic range of the beam, otherwise permanent distortion results. Thus in determining the deflections of beam under load, elastic theory is used.

3.0

THEORY

The double integration method is a powerful tool in solving deflection and slope of a beam at any  point because we will be able to get the equation of the elastic curve.

 =  () is given by )]⁄   [1 + (  =  | |

In calculus, the radius of curvature of a curve

In the derivation of flexure formula, the radius of curvature of a beam is given as

 =  Deflection of beam is so small, such that the slope of the elastic curve this expression the value become practically negligible, hence

 = 0   = 1 

 is very small, and squaring 

= 1" Thus,

 = 1  " " =   = 1  If EI is constant, the equation may be written as:

" =  Where, y

= deflection of the beam at any distance x

E

= modulus of elasticity of the beam

I

= moment of inertia about the neutral axis

M

= bending moment at a distance x from the end of the beam

EI

= flexural rigidity of the beam

      − =   = 2 = 2      − =   = 4  4 +       −  =  = 8  12 +  +  When x = 0; dy = 0 ⸫ A = 0 When x = L/2; y = 0; ⸫

0 =     +   = − 

When x = 0;

  =  − 

X= L/2;

  + 

(mid span; c)

(at support)

Where E can be obtained from backboard

 = 

d  b

4.0

APPARATUS

Brass Strip Beam

Steel Strip Beam

Hanger and Masses

4.1

Digital Dial Test

PROCEDURE

1) The moveable knife-edge supports was positioned so that they were 400mm apart from each other. 2) The chosen beam was placed on the support. 3) The hanger and the digital dial test indicator was placed at the mid span. The digital reading were zero at first. 4) An incremental load was applied and the deflection for each increment was recorded in the table below. 5) The above steps are repeated using span of 300mm, 400mm and 500mm for both brass and steel beam.

5.0

RESULT

Specimen beam: Brass

  =    = 105 × 10/ Second moment of area,   = 8.3 ,  = 3.3 Young’s Modulus,

 =  =  (.)(.) = 24.856 Mass of load,

 = 100 ×10− × 9.81 = 0.9810

Experiment 1: Span = 500 mm No.

1 2 3 4 5

Mass (N)

0.9810 1.9620 2.9430 3.9240 4.9050 

Deflection

Theoretical Def.(

(experimental) (mm)

(mm)

0.59 1.15 1.72 2.26 2.88

0.979 1.958 2.937 3.915 4.894

Use any mass between

100 to 500

)

% Difference

39.73 41.27 41.44 42.27 41.15

Experiment 2: Span = 400 mm No.

1 2 3 4 5

Mass (N)

0.9810 1.9620 2.9430 3.9240 4.9050 

Deflection

Theoretical Def.(

(experimental) (mm)

(mm)

0.34 0.66 0.96 1.24 1.55

0.501 1.002 1.504 2.005 2.506

Use any mass between

)

% Difference

32.14 34.13 36.17 38.15 38.15

10 to 500

Experiment 3: Span = 300 mm No.

1 2 3 4 5

Mass (N)

0.9810 1.9620 2.9430 3.9240 4.9050 

Deflection

Theoretical Def.(

(experimental) (mm)

(mm)

0.18 0.40 0.55 0.67 0.80

0.211 0.423 0.634 0.846 1.057

Use any mass between

10 to 500

)

% Difference

14.69 5.44 13.25 20.80 24.31

Specimen beam: Steel

  = 207/ = 207 ×10/ Second moment of area,   = 8.8  = 3.2     =  Young’s Modulus,

  ( ) . (.) = 

= 24.03 Mass of load,

 = 100 ×10− × 9.81 = 0.9810

Experiment 1: Span = 500 mm No.

1 2 3 4 5

Mass (N)

0.9810 1.9620 2.9430 3.9240 4.9050 

Deflection

Theoretical Def.(

(experimental) (mm)

(mm)

0.29 0.56 0.81 1.07 1.33

0.514 1.027 1.541 2.054 2.568

Use any mass between

100 to 500

)

% Difference

43.58 45.47 47.44 47.91 48.21

Experiment 2: Span = 400 mm No.

1 2 3 4 5

Mass (N)

0.9810 1.9620 2.9430 3.9240 4.9050 

Deflection

Theoretical Def.(

(experimental) (mm)

(mm)

0.18 0.31 0.44 0.57 0.71

0.263 0.526 0.789 1.052 1.315

Use any mass between

)

% Difference

31.56 41.06 44.23 45.82 46.01

10 to 500

Experiment 3: Span = 300 mm No.

1 2 3 4 5

Mass (N)

0.9810 1.9620 2.9430 3.9240 4.9050 

Deflection

Theoretical Def.(

(experimental) (mm)

(mm)

0.08 0.15 0.20 0.26 0.33

0.111 0.223 0.333 0.444 0.555

Use any mass between

10 to 500

)

% Difference

27.93 32.74 39.94 41.44 40.54

5.1

Data analysis

The negative sign in deflection indicates that the deflection is below the unreformed neutral axis. Brass beam in experiment 1

  =  − 

  −.× = × × ×.  ( )

= 0.979 % Difference = xpmtal−thotal thotal   ×100 =  −.−(−.) −.   ×100 = 43.50% Steel beam in experiment 1

  −  =   =  −.×  ××   × ( )

= 0.309 % Difference = xpmtal−thotal thotal   ×100 =  −.−(−.) −.   ×100 = 81.23%

6.0

DISCUSSION

Comment on the different between the theoretical and experimental results. Referring to the results from the calculation, we can conclude that, the different between the theoretical and experimental results are different for all Experiment 1, 2, and 3 using steel beam and brass beam. Thus, the percentage (%) of the difference between the theoretical and experimental results are different also. From the experiment, we can notice that, the span with the shorter length will give us the smaller value of deflection when the load is place at the mid span for both theoretical and experimental results. While when the span with the longer length, the higher the deflection occurs to the span than the shorter span.

For Experiment 1 that used 500mm span using steel beam, when the load of 0.981 N/100g was  place at the mid span, test indicator give us the reading of deflection with -0.29. When the load is increased until the load reach 4.905 N/500g with difference 100g each reading respectively, the deflection recorded by test indicator are until the last one is -1.33 when the load placed at the mid span are 4.905 N/500g. The values of the deflection for both theoretical and experimental results increase proportionally to the load when the load of 100g, 200g, 300g, 400g and 500g are place on the mid span. For Experiment 2 that used 400mm span using steel beam, the first value of load are same with experiment 1 was place at the mid span, test indicator give us the reading of deflection with -0.18. When the load is increased with the same value in experiment 1, the test indicator also show the increasing reading and the v alue of deflection for this experiment is smaller than the experiment 1. Next, for Experiment 3 using 300mm span of steel beam, when the first load was place at the mid span, test indicator give us the reading of deflection with -0.08. When the load is increased with the same value with the load used in experiment 1 and 2, the values of the deflection for both results increase proportionally to the load as the load are increase. The value of deflection for this experiment is smaller than the experiment 1 and experiment 2 because the length of the span used, 300mm which is shorter than the span used for experiment 1 that is 500mm and experiment 2 that is 400mm. The values of the deflection for both theoretical and experimental results increase proportionally to the load when the load force to the span are increase.

To verify the experiment we done using steel beam, we done another experiment using the brass  beam with the same length. From the result we obtain by using brass beam, it show the same as the steel beam experiment. When the value of load using increased, the higher the reading of the deflection. The value of deflection calculated using theoretical also will increase if the value of load is increase.

From the results we get from this experiment, though the different between the theoretical and experimental results are very big, but the deflection in the span increase when the load is increase. Besides that, the value of deflection also increase when the length of span u sed is longer. Thus, we conclude that, the deflection of span is proportional to the load we place on it and the len gth of the span we used.

EXTRA QUESTIONS

1.

Calculate the deflection when x = L/3 (experiment 1, no. 3). Check the result by placing

the digital dial at this position.

a) Calculation: Steel beam When x = L/3, this mean that x = 166.67 (500/3), the value for Deflection (Experimental) we get is –  0.81 and the Theoretical Deflection we get from the calculation is –  1.541. The percentage (%) of the difference between the theoretical and experimental results for this extra experiment is 47.44%.

When, P = 2.9430 N 3

y mak 

 PL  

48 EI  (2.9430)(500) 3

 

48(207000)(24.03)

= –  1.541

When, P = 2.9430 N % Difference = {{-0.81 –  (-1.541)}/-1.541}x100 = 47.44%.

b) Calculation: Brass beam When x = L/3, this mean that x = 166.67 (500/3), the value for Deflection (Experimental) we get is –  1.72 and the Theoretical Deflection we get from the calculation is –  2.937. The percentage (%) of the difference between the theoretical and experimental results for this extra experiment is 41.44%.

When, P = 2.9430 N 3

y mak 

 PL  

48 EI  (2.9430)(500)3





48(105000)(24.856)

= –  2.937

When, P = 2.9430 N % Difference = {{-1.72 –  (-2.937)}/-2.937}x100 = 41.44%

2.

Calculate V mak in experiment 2, no.2.

a) Steel beam Given, Esteel= 207 x 109 Nm-2

Width, b = 8.8mm Thick, d = 3.2mm

I

bd  

From Equation,

12

(8.8)(3.32) 

3

3

12

= 26.84 mm4

2

From Equation,

v mak 

 PL 

16 EI 

(1.9620)(400) 3  

16(207000)(26.84)

= -1.413

 b)  Brass beam Given, E brass = 105 x 109 Nm-2

Width, b = 8.3mm Thick, d = 3.3mm

I

bd  

From Equation,

3

12

(8.3)(3.3) 3 

12 = 24.856 mm4

2

From Equation,

v mak 

 PL 

16 EI 

(1.9620)(400) 



3

16(105000)(24.856)

= -3.007

7.0

CONCLUSION

From this experiment, our group managed to determine the relationship between the deflection happened and the span. To determine the deflections happened when the beams under load, elasticity theory is used. From the results we get from this experiment, we knows that, the span with shorter length will give us the smaller value of deflection when the load is place at the mid span for both theoretical and experimental results. While for the span with the longer length, the deflection is higher than the shorter length of the span even though the load used is same for both of the span. Even the different in percentage between the theoretical and experimental results are very big, but the deflection in the span also increase when the load is increase. Thus, we conclude that, the deflection of span is proportional to the length of the span and the load we place on the span.

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