Solutions Manual Introductory Circuit Analysis 12th Edition Boylestad

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Chapter 1 1.



2.



3.



4.

=

5.

6.

d 20,000 ft  1 mi   60 s   60 min  = = 1363.64 mph t 10 s  5,280 ft  1 min   1 h 

 1h  4 min   = 0.067 h  60 min  d 31 mi =  = 29.05 mph t 1.067 h

 3 ft  100 yds   1 yd 

 1 mi   5,280 ft  = 0.0568 mi  

60 mi  1 h  1 min  = 0.0167 mi/s h  60 min   60 s 

t=

7.

a. b. c.

d





0.0568 mi = 3.40 s 0.0167 mi/s

95 mi  5,280 ft   1 h  1 min  = 139.33 ft/s h  mi   60 min   60 s  d 60 ft t=  = 0.431 s  139.33 ft/s d 60 ft  60 s   60 min   1 mi  =  = 40.91 mph t 1 s 1 min   1 h   5,280 ft 

8.



9.



10.



11.

MKS, CGS, C =

12.

 0.7378 ft - lb  1000 J   = 737.8 ft-lbs 1J  

5 5 5 (F  32)  (68  32)  (36) = 20 9 9 9 SI: K = 273.15 + C = 273.15 + 20 = 293.15

Chapter 1

1

13.

 3 ft  12 in.   2.54 cm  0.5 yd     = 45.72 cm 1 yd   1 ft   1 in. 

14.

a.

°F = 2(°C) + 30° = 40° + 30° = 70°

b.

°F =

c.

very close

d.

30°C  90°F vs. 86° 5°C  40°F vs 41°

a.

14.6

b.

c.

1,046.1

d.

e.

3.14159 = 3.1

a.

14.60

b.

c.

1,046.06

d.

e.

3.14159 = 3.14

a.

14.603

b.

c.

1,046.060

d.

e.

3.14159 = 3.142

a.

104

15.

16.

17.

18.

9 9 (C)  32  (20)  32 = 68° 5 5

e. 100

b. 106

56.0 1 = 0.0625 = 0.1 16

56.04 1 = 0.0625 = 0.06 16

56.042 1 = 0.0625 = 0.063 16 c. 103

d. 103

c. 2.4  106

d. 60  103

f. 101 5  103

a.

15  103

e.

4.02  104 f. 2  1010

20.

a. b. c. d.

4.2  103 + 48.0  103 = 52.2  103 = 5.22  104 90  103 + 360  103 = 450  103 = 4.50  105 50  105  6  105 = 44  105 = 4.4  104 1.2  103 + 0.05  103  0.4  103 = 0.85  103 = 850

21.

a. b. c. d. e. f.

(102)(103) = 105 = 100  103 (102)(103) = 101 = 10 (103)(106) = 1  109 (102)(105) = 1  103 (106)(10  106) = 10 (104)(108)(1028) = 1  1024

19.

2

b.

Chapter 1

22.

a. b. c. d.

(50  103)(2  103) = 100  100 = 100 (2.2  103)(2  103) = 4.4  100 = 4.4 (82  106)(1.2  106) = 98.4 (30  104)(4  103)(7  108) = 840  101 = 8.40  103

23.

a. b. c. d. e. f.

102/104 = 102 = 10  103 102/103 = 105 = 10  106 104/103 = 107 = 10  106 107/102 = 1.0  109 1038/104 = 1.0  1042 100 / 10 2 = 101/102 = 1  103

24.

a. b. c. d.

(2  103)/(8  105) = 0.25  108 = 2.50  107 (4  103)/(4  106) = 4/4  109 = 1  109 (22  105)/(5  105) = 22/5  100 = 4.4 (78  1018)/(4  106) = 1.95  1025

25.

a. c.

(102)3 = 1.0  106 (104)8 = 100.0  1030

26.

a. b. c. d.

27.

a.

(2  102)2 = 4  104 (5  103)3 = 125  109 (4  103)(3  103)2 = (4  103)(9  104) = 36  101 = 360 ((2  103)(0.8  104)(0.003  105))3 = (4.8  103)3 = (4.8)3  (103)3 = 110.6  109 = 1.11  1011 (103)2 = 1.0  106 (10 2 )(10 4 ) = 102/103 = 1.0  105 3 10 3 2 (10 ) (10 2 ) (10 6 )(10 2 ) 10 4   4 = 1.0  108 4 4 10 10 10 3 4 (10 )(10 ) = 107/104 = 1.0  1011 4 10

b. c. d. e.

(10 )(10 ) (10 ) 10  2 2

28.

a. b. c.

Chapter 1

(104)1/2 = 10.0  103 (107)9 = 1.0  1063

(1  104)3(102)/106 = (1012)(102)/106 = 1010/106 = 1.0  1016 2

f.

b. d.

2

3

3



1 1  = 1.0  101 3 (10 )(10 ) 10 4

(3  10 2 ) 2 (10 2 ) = (9  104)(102)/(3  104) = (9  106)/(3  104) = 3  102 = 300 4 3  10 (4  10 4 ) 2 16  10 8 = 2  105  3 3 (20) 8  10 (6  104 ) 2 36  108 = 9.0  1012  2 2 4 (2  10 ) 4  10

3

d.

(27  10 6 )1 / 3 3  10 2 = 1.5  107 = 150.0  109  5 5 2  10 2  10

e.

(4  10 3 ) 2 (3  10 2 ) (16  10 6 )(3  10 2 ) 48  10 8 = 24.0  1012   2  10  4 2  10  4 2  10  4

f.

(16  106)1/2(105)5(2  102) = (4  103)(1025)(2  102) = 8  1020 = 800.0  1018

g.

 (3  103 )3  1.60  102   (2  102 )(8  104 )       5 2 (7  10 )

2

1/ 2

(27  109 )(2.56  104 )(16  102 )1/ 2 49  1010 (69.12  105 )(4  101 ) 276.48  106   49  1010 49  1010 4 3 = 5.64  10 = 56.4  10



29.

Scientific:

Engineering:

30.

Scientific

Engineering:

4

a. b.

2.05 × 101 5.04 × 104

c.

6.74 × 104

d.

4.60 × 102

a. b.

20.46 × 100 50.42 × 103

c.

674.00 × 106

d.

46.00 × 103

a. b.

5.0 × 102 4.5 × 101

c. d.

1/32 = 0.03125 = 3.125 × 102 3.14159 = 3.142 × 100

a. b.

50.0 × 103 0.045 × 103

c. d.

31.25 × 103 3.142 × 100

Chapter 1

+2 31.

a.

6  104 = 0.06  10+6 = 0.06 × 10+6 3 3

b.

0.4  103 = 400  106 = 400 × 106 +3 2

c.

+3

50  105 = 5000  103 = 5  106 = 0.005  109 = 0.005 × 109 3

+2

3 3

+4 d.

+3

3

12  107 = 0.0012  103 = 1.2  106 = 1200  109 = 1200 × 109 4

+3

+3

3 32.

a.

0.05  100 s = 50  103 s = 50 ms +3 +3

b.

2000  106 s = 2  103 s = 2 ms 3 3

c.

0.04  103 s = 40  106 s = 40 s +3 +6

d.

8400  1012 s  0.0084  106 s = 0.0084 s 6

Chapter 1

5

+3 increase by 3 100

e.

100  103  103 m = 0.1  103 m = 0.1 km 3

33.

34.

35.

6

a.

 60 s  1.5 min   = 90 s 1 min 

b.

 60 min   60 s  2 × 102 h   = 72 s   1 h  1 min 

c.

 1 s  0.05 s   6  = 0.05  106 s = 50  103 s 10 s 

d.

 1 mm  0.16 m  3  = 0.16  103 mm = 160 mm 10 m 

e.

 1 ns  1.2  107 s  9  = 1.2  102 ns = 120 ns 10 s 

f.

1 min   1 h  1 day  4  108 s    = 4629.63 days   60 s   60 min   24 h 

a.

100 cm  = 8000  103 cm = 8 cm 80  103 m    1m 

b.

 1 m   1 km  = 60  105 km 60 cm     100 cm  1000 m 

c.

 1 m  12 × 103 m  6  = 12  103 × 10+6 m = 12 × 103 m 10 m 

d.

 1m  1m  4 2 60 cm2    = 60  10 m 100 cm   100 cm 

a.

 1m  100 in.   = 2.54 m  39.37 in. 

b.

12 in.  4 ft    1 ft 

 1m   39.37 in.  = 1.22 m  

Chapter 1

c. d.

36.

37.

38.

39.

40.

41.

 4.45 N  6 lb   = 26.7 N  1 lb   1 N   1 lb  60  103 dynes  5   = 0.13 lb 10 dynes   4.45 N 

e.

 1 in.   1 ft  150,000 cm    = 4921.26 ft  2.54 cm  12 in. 

f.

 5280 ft  12 in.   1 m  0.002 mi     = 3.22 m  1 mi   1 ft   39.37 in. 

1 yd  5280 ft   = 1760 yds  3 ft   12 in.   1 m  5280 ft    = 1609.35 m, 1.61 km  1 ft   39.37 in. 

5280 ft,

60 mi 5280 ft h 1 mi

12 in. 1 ft

1m 39.37 in.

1h 60 min

1000 m   39.37 in.   1 ft   1 mi  10 km       1 km   1 m  12 in.   5280 ft  d 6.214 mi 1 mi = ,t=  = 40.39 min 1 mi  6.5 min 6.5 min

1 min 60 s

= 26.82 m/s

= 6.214 mi

 3 ft  12 in.  100 yds    = 3600 in  3600 quarters 1 yd   1 ft 

500 mi = 8.33 h = 8 h:19.8 min  60 mi/h d 500 mi = 6.67 h = 6h:40.2 min 75 mph: t =   75 mi/h difference = 1h:28.6 minutes

60 mph:

t=

d



cm   0.016 h   60 min   60 s   1 m  = 345.6 m d = t = 600  s    1 h  1 min  100 cm 

Chapter 1

7

42.

 14 ft  d = 86 stories    story 

d d 1605 steps  1 minute  t    802.5 seconds  = 13.38 minutes 2 steps t   60 seconds  second

=

43.

44.

 14 ft   1 mile  d = (86 stories)    1204 ft   = 0.228 miles  5,280 ft   story  min 10.22 min  = 44.82 min/mile mile 0.228 miles 5 min 1 mile  5,280 ft  1056 ft  ,  mile 5 min  1mile  minute

a.

 1 Btu  = 4.74  103 Btu 5 J  1054.35 J 

b.

 1 m3  1 gallon   4 3 24 ounces    = 7.1  10 m  128 ounces   264.172 gallons 

c.

 86,400 s  5 1.4 days   = 1.21  10 s 1 day  

d.

 264.172 gallons  1 m3   1 m3  

46.

6(4 × 2 + 8) = 96

47.

(42 + 6/5)/3 = 14.4

48.

2 5  3

 8 pints    = 2113.38 pints 1 gallon 

2

2

= 5.044

49.

MODE = DEGREES: cos 21.87 = 0.928

50.

MODE = DEGREES: tan1(3/4) = 36.87

51.

8

 14 ft  distance = 86 stories   = 1204 ft  story 

d d 1204 ft t  = 1.14 minutes  1056 ft t min

=

45.

  1 step   9  = 1605 steps  ft   12 

400 /(6

2



 10 / 5) = 7.071

Chapter 1

52.

205  106

53.

1.20  1012

54.

6.667  106 + 0.5  106 = 7.17  106

Chapter 1

9