Solución-Ejercicio, Medición de Una Base de Triangulación AB

Bhbrififj, obefifùk eb ukm cmsb eb Urfmkaudmifùk MC

 

Yb nm rbmdfzmej dm obefifùk eb ukm cmsb eb trfmkaudmifùk MC. Yf dms imrmitbrïsims eb dm wfkinm usmem sjk L ? 7.7777=3/·I, Uj ? 37¸I, Q ? =2.0 ar/o, Wj ? 2la, Y ? 7.73 io3, B ? 3.= x =7 0 la/io3, y sf md sbr ijktrmstmem ijk ukm wfkinm pmtrùk fkvmr. Yb jcsbrvm qub 56.66>o eb dm wfkinm ijrrbspjkebk m 27 o eb dmwfkinm pmtrùk fkvmr.< imdiudmr dm djkaftue obefem, ijrrbafem y imdfcrmem pmrm djs vmdjrbs eb dm sfaufbktb dfcrbtm8 Ijrrbiifùk pjr tbopbrmturm8

It? LD(U L D(U-U -UJ) ? 7.7777=3/·I

L8 ijb`ifbktb eb efdmtmifùk eb dm wfkinm. D8 djkaftue djkaftue ebd trmoj obefej. ?56.601

o.

U8 tbopbrmtur tbopbrmturm m ebd mocfbktb bk bd fkstmktb eb dm obefifùk. Uj8 tbopbrmturm eb imdfcrmofbktj

ItM-3 ?  

? =1.2·I

? 37·I

(7.7777=3)(56.01 o.)(=1.2-37)·I ? -=.566 ≎ -=.2o.o ·I

 

Ijrrbiifùk pjr tbksfùk.  

Ip? Ip8 ijrrbiifùk pjr tbkifùk. D8 djkaf djkaftue tue ebd trmoj trmoj obefej. obefej. ? 56.601 o. W8 tbkifùk eb obefifùk.

?>.9 La.

Wj8 tbkifùk eb imdfcrmofbktj. ?2 La. Y8 sbiifùk rbitm eb dm wfkinm. B8 ojeudj eb bdmsifeme ebd mibrj

Ip

?

Ip

? ? 9.6 o.o

M-3

M-3

?7.73 io3

? 3.= ^ =7 0 La/io3

Ijrrbiifùk pjr njrfzjktmdfeme.

 

In?In8 ijrrbiifùk pjr njrfzjktmdfeme. N8 ebskfvbd bktrb bstmims eb mpjyj. D8 djkaftue bktrb mpjyjs.

? (7.99+7.32) o.

?56.601 o.

Abkbrmdobktb sb tjom bd prfobr tbrofkj eb dm `jroudm mktbrfjrobktb bsirftm, ym qub pmrm Abkbrmdobktb ebskfvbdbs pbqubýjs, m pmrr ebd sbaukej tærofkj, dms sbrfb vm tjomkej vmdjrbs oís pbqubýjs.

Bd sfakj eb dm ijrrbiifùk pjr mdtm eb njrfzjktmdfeme m mpdfimrsb m tjem obefifùk, sfboprb bs kbamvj, sbm bd ebskfvbd pjsfvj j kj

In

?-

In

?-

M-3

M-3