Solución de Ejercicios de Las Guías de Electromagnetismo
September 18, 2022 | Author: Anonymous | Category: N/A
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\KFRLW^FCOC CL LI ^OIROC@W BON\ISOC M\ISFCF^NFQIFKOWFO CL @NNFCLKSL CLQOWSOMLKS@ CL BF^FNO MOSLWFO8 BF^FNO FFF FKJLKFLWÍO @WFLKSOC@W8 FKJ. FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
J\FO #? ’ ILV CL N@\ N@\I@ I@MG MG V NOM NOMQ@ Q@ LI NSWF NSWFN@ N@” ”
’Li molstr` mlcf`nrl cfnl, li gulk molstr` lxpifno, li molstr` suplrf`r clmulstro, li jrok molstr` fkspfro” Zfiifom O. Zorc FKJ FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
?
QW@GILMO^
?. °Nuïi clgl slr io cfstoknfo lktrl io norjo puktuoi q ? = 72.> ι N y io norjo puktuoi q 7 = - 3:.? ι N n`k `ghlt` cl qul io bulrzo liæntrfno cl otronnfþk lktrl liios tlkjo uko mojkftuc cl x?1-2 N
r=0
Nïinui` cl ios mojkftucls8
^ljøk li cfojromo cl bulrzos sl tflkl8
o) g)
FKJ FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
>
>. C`s norjos p`sftfvos cl 3.?5 ι N noco uko, y uko norjo kljotfvo cl „ 2.>2 ι N, lstïk bfhos lk i`s værtfnls cl uk trfokjui` lqufiïtlr` cl ?>.1 nm cl ioc`. Noinuil io bulrzo liæntrfno s`grl io norjo kljotfvo. q >=-2,>2¼N
?>nm
?>nm
21± ?>nm q ?=3,?5¼N Jl`mltrío cli pr`gilmo8
q 7=3,?5¼N
Srfïkjui` k`togil cl 21±
∘ ∘ sfk21±=
CNI8 Okïifsfs vlnt`rfoi8
q > 21± 21± Bl?> Bl7> Rlnt`rfoimlktl ios n`mp`klktls lk x, sl noknliok 21± Bl?>
Bl?>(sfk21±) 21±
Br Bl7>(sfk21±)
Bl7> Nïinui` cl ios mojkftucls8
6 77 3,3,?5√?122,2,>2√?12 6√?1 B = B = B = ?>√?1∘ ∘ >77 =?3,?2K =7sfk21±=7?3,?2 2 7 =73,? |?,21 √ ?1?6 N|=?,>7 √ ?1?> ?l-------------------6,?16
=5,7>3
k=
k------------------:3
2. Lk io bfjuro m`stroco sl i`noifzok trls norjos puktuoils ugfnocos lk ios lsqufkos cl uk trfokjui` lqufiïtlr`. Noinuil io bulrzo liæntrfno klto s`grl io norjo cl :.1 ι N. y
:.1 ι N
1.< m
x
7.1 ι N
- 3.1 ι N
`s21±± slk21± n`s21 n`s21± B?
B?
B7
21± 21± B7
B?
B?
B7
BW B7
21±
21±
slk21±
7√?1 ∗ ∗ 7 √?1 :√?1 :√?1 6√?1 ?=? = 1,2n`s ⃚ slk ↗ ? = 7. > 2. 7. > 2. ∘ ∘ ∘ ∘ ̇ ̇ ⃚ ↗ 7 = ̇ ̇ ⃚> = ↗ ⃚> = Nïinui` cl ios mojkftucls8
7,>2
31 31 7,< 7,<
31 31
7,< 7,<
⃚ = 3,:6̇ ̇ == 3,:6 3131,,2 =31,6
31,2
tok∗ ∗∗,, =5>,7± ↗?51±=72>±
ο=
FKJ FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
6
5. Lk io bfjuro sl mulstrok trls norjos puktuoils fcæktfnos, noco uko cl moso m = 1.?11 Dj. y cl norjo q, n`ijocos cl trls nulrcos. ^f ios i`kjftucls cl ios nulrcos fzquflrco y clrlneo s`k I = >1.1 nm y li ïkjui` ε = 311¼N, G (>, 1,7) m N (-?, 7,>) q >
q 7 G (>, 1,7)
q >=+?11¼N, N (-?, 7,>) m
⃚= ̇ ̇ ⃚ T7717] || = 7 1 7 =7.575 ̇ = |⃚| T ++̇. ̇∗∗] =1.:1:̇1̇1.:1: O (?, 7,?) - N (-?, 7,>)= (7, 1,-7)
q ? O (?, 7,?)
=
?> ?>
Noinui` cli vlnt`r p`sfnfþk Mæt`c` cl noglzo mlk`s n` n`io io
=
⃚⃚= T33̇7̇] || = 3 7 ? =3. ̇ = |⃚| T∗∗. +++̇ +] =1.5:>̇1.3>23̇1.7?5 N (-?, 7,>) - G (>, 1,7)= (-3, 7,?)
=
7> 7>
=
Noinui` cl ios mojkftucls8
∗ ∗ 7711√?1 ?11√?1 ?>=6√?1 ?>= 6√?1 7 7. 11√?1 . 5 75 75 ? 11√?1 =77. < 1:K ∗ ∗ 6√?1 > >11√?1 11√?1 ?11√?1 ?11√?1 =?7.5= 3.
⃚ =77. ? >1± = = > >↗ ↗ = >>1±4 >>1± = 4 =7/> >1 >1± ± = 7 ø ï > >/7=7/> /7 ∳
(?) (7)
=3K [ r=7/>E
=Bl
Bl=3K
*Io mojkftuc cl ios norjos ls io mfsmo *Io cfstoknfo cl io norjo cl io lsqufko fkblrf`r o io cli nlktr` ls io mfsmo qul io cl io cfstoknfo cl io norjo cli nlktr` o io cl orrfgo
*Q`r i` tokt` io bulrzo liæntrfno ls io mfsmo FKJ FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
?5
3K +_
3K 3Kn`s>1±
3Kslk>1± >1±
Br 3K
Bl Cl io jrïbfno tlklm`s8
3
⃚⃚ == 733∘ ∘ >>∘ ∘ ̇̇3 3⃚ =3n`s>1± ̇ ̇ ̇3 slk>1±̇ ⃚ = 7∘ ∘ >>̇7̇ == 7∘ ∘ >> 77 = 3
3
7
?5. ^l tflklk trls norjos n`m` sl mulstro lk io bfjuro
,
V
, Noinuior io bulrzo rlsuitoktl lk _?.
B>? Br Noinui` cl ios mojkftucls8
B7?
>?= 6√?1 ??2√?1 >?=6√?1 2√?1 >>∗∗?√?1 ? √?1∗∗ =311K 6√?1 > >√?1 √?1 ?√?1 ?√?1 7>= =>11K > ⃚ = ̇>11̇ == 311 >11>11 = = 777
q ??== q 77== q >>== q
= 7 = 7 =?/7
71. Lk io bfjuro sl mulstrok c`s lsblrfiios cl fjuoi tomoÿ` norjocos n`k mojkftuc q y >q
rlsplntfvomlktl. Clsprlnfokc` ios bulrzos cl brfnnfþk, eoiior li pls` cli gi`qul Z, toi qul li sfstlmo sl lknulktrl lk lqufifgrf`. q = ?1 N
Bl
-q
Bl
1.>m
+>q
∗ 6√?1 > ? ?1√?1 1√?1 > d > >q q q =>1K = = =
1.>
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71
S
>1K
Sslk±Sslk S
S ±
Sn`s±
↗ = 1 4 >1 = 14 = = >1 ↟ = 1 4 ± ± = 14 = 7±
Sn`s±
1 >1 3=35 <
± >d
7?. Noinuior li nomp` liæntrfn` lk uko lsqufko cl uk nuocroc` cl 51 nm cl ioc`, sf ios `tros trls lsqufkos sl lknulktrok `nupocos p`r norjos cl ?5.7 x?1 -3 N. +q
+ q
??>.?nm 51nm Q L7 L?
3
3N √ ?1 6√?1 ?5. 7 ?=L>= = 51√ ?17 =7.2√ ?1:K/N 3N ?5. 7 6√?1 √ ?1 L7=L7 = = ??>.?√ ?17 =?.75√ ?1:K/N
FKJ FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
7?
L?slk3>..?33 7
FKJ FKC. V MLc. ^OM\LI OC@IB@ C\LßO^ OQOWFNF@
7>
73. Cltlrmfkl li pukt` c`kcl li nomp` liæntrfn` klt` slo nlr`. Rlr bfjuro
?=L7 = ? ? = 7.2< ? = =↗?7 =7.3 ?7 7?=1 ?. 3 ¿∘ 3 7¿ 7¿ 7 = 7 = 7?.3 3?.?.3? = 7>.7.156….. = ?.57m4 = 7>.7.156….. =1.>6m
?.57 m o io fzquflrco cl io norjo cl -7.
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