A mixt ure of ammonia and air is scrubbed in a plat e column wit h f resh wat er. If t he ammonia concent rat ion is reduced f rom 5% t o 0.01% and t he wat er and air rat es are respect ively 0.65 t o 0.45 kg /m2s, how many t heoret ical plat es are required? The equilibrium relat ionship can be writ t te n Y Y =X , where X is t he mole rat io in t he liquid phase.
GIVEN: Y1
Fresh water 0.65 kg/m2s
0.65 kg/m2s 0.01% ammonia N=?
1
YN+1 XN
0.45 kg/m2s 5% ammonia
SOLUTION: Top Coordinates: Coo rdinates: Xo = 0 Y1 = ammonia / air = 0.0001/ 0.999 = 1.001 x 10-4 Coordinates:: Bottom Coordinates YN+1 = YN+1 / 1-YN+1 = 0.05/1-0.05 = 0.053 NH3 in H2O = amt. in YN+1 ± am amt. t. \in \in Y 1 =0.45 =0.4 5 (0.05 (0.05)) ± {0.95 (0.45 (0.45)) / 0.999 0.999}} x0.0 x0.0001 001 = 0.022 kg/m2s XN = 0.022 / 0.65 = 0.035
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