Resolucao Eear 2 2011

September 16, 2022 | Author: Anonymous | Category: N/A
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RESOL󰁕󰃇󰃃O SARGENTO AERON󰃁󰁕TICA 2/2011  Profo.: Waldomário Melo

P󰁲󰁥󰁺󰁡󰁤󰁯󰁳 󰁣󰁯󰁮󰁣󰁵󰁲󰁳󰁡󰁮󰁤󰁯󰁳! M󰁥󰁵 󰁮󰁯󰁭󰁥 󰃩 󰁐󰁲󰁯󰁦󰂺 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 󰁍󰁥󰁬󰁯󰀬 󰀱󰀳 󰁡󰁮󰁯󰁳 󰁤󰁥 󰁥󰁸󰁰󰁥󰁲󰁩󰃪󰁮󰁣󰁩󰁡 󰁥󰁭 󰁣󰁯󰁮󰁣󰁵󰁲󰁳󰁯󰁳󰀬  󰁧󰁯󰁳󰁴󰁡󰁲󰁩󰁡 󰁤󰁥 󰁥󰁸󰁴󰁥󰁲󰁮󰁡󰁲 󰁡 󰁴󰁯󰁤󰁯󰁳 󰁡 󰁧󰁲󰁡󰁮󰁤󰁥 󰁳󰁡󰁴󰁩󰁳󰁦󰁡󰃧󰃣󰁯 󰁤󰁥 󰁰󰁯󰁤󰁥󰁲 󰁥󰁳󰁴󰁡󰁲 󰁴󰁥󰁮󰁤󰁯 󰁥󰁳󰁴󰁡 󰁯󰁰󰁯󰁲󰁴󰁵󰁮󰁩󰁤󰁡󰁤󰁥, 󰁭󰁵󰁩󰁴󰁯 󰁧󰁥󰁮󰁴󰁩󰁬󰁭󰁥󰁮󰁴󰁥 󰁰󰁲󰁯󰁰󰁯󰁲󰁣󰁩󰁯󰁮󰁡󰁤󰁡 󰁰󰁥󰁬󰁡 D󰁩󰁲󰁥󰃧󰃣󰁯 󰁤󰁯 󰁃󰁵󰁲󰁳󰁯 󰁈󰁥󰁲󰁴󰁺, 󰁡 󰁱󰁵󰁡󰁬 󰁦󰁡󰃧󰁯 󰁰󰁡󰁲󰁴󰁥 󰁡󰁰󰁲󰁥󰁳󰁥󰁮󰁴󰁡󰁲󰀭󰁬󰁨󰁥󰁳 󰁡 󰁲󰁥󰁳󰁯󰁬󰁵󰃧󰃣󰁯, 󰁣󰁯󰁭󰁥󰁮󰁴󰃡󰁲󰁩󰁯󰁳 󰁥 󰁤󰁩󰁣󰁡󰁳 󰁳󰁯󰁢󰁲󰁥 󰁡 󰁲󰁥󰁳󰁯󰁬󰁵󰃧󰃣󰁯 󰁤󰁡 󰁐󰁒󰁏󰁖󰁁 󰁅󰁅󰁁󰁒 󰀲󰀯󰀲󰀰󰀱󰀱, 󰁤󰁥 󰁦󰁯󰁲󰁭󰁡 󰁩󰁮󰃩󰁤󰁩󰁴󰁡 󰁥󰁭 B󰁥󰁬󰃩󰁭, 󰁣󰁯󰁭󰁯 󰁳󰁥󰁭󰁰󰁲󰁥. A󰁧󰁲󰁡󰁤󰁥󰃧󰁯 󰁰󰁲󰁩󰁭󰁥󰁩󰁲󰁡󰁭󰁥󰁮󰁴󰁥 󰁡 D󰁥󰁵󰁳, 󰁡 󰁭󰁩󰁮󰁨󰁡 󰁦󰁡󰁭󰃭󰁬󰁩󰁡 󰁥 󰁡 󰁤󰁩󰁶󰁥󰁲󰁳󰁯󰁳 󰁰󰁡󰁲󰁣󰁥󰁩󰁲󰁯󰁳. M󰁥󰁵󰁳 󰁱󰁵󰁥󰁲󰁩󰁤󰁯󰁳, 󰁳󰁥󰁭 󰁭󰁡󰁩󰁳 󰁤󰁥󰁬󰁯󰁮󰁧󰁡󰁳, 󰁰󰁡󰁳󰁳󰁥󰁭󰁯󰁳 󰁡󰁯󰁳 󰁣󰁯󰁭󰁥󰁮󰁴󰃡󰁲󰁩󰁯󰁳. A󰁨! C󰁯󰁮󰁴󰁩󰁮󰁵󰁡󰁭󰁯󰁳 󰁭󰁡󰁴󰁲󰁩󰁣󰁵󰁬󰁡󰁮󰁤󰁯 󰁰󰁡󰁲󰁡 󰁮󰁯󰁳󰁳󰁡󰁳 󰁴󰁵󰁲󰁭󰁡󰁳 󰁰󰁲󰁥󰁰󰁡󰁲󰁡󰁴󰃳󰁲󰁩󰁡󰁳 󰁤󰁥 󰁓󰁯󰁬󰁤󰁡󰁤󰁯 󰁂󰁯󰁭󰁢󰁥󰁩󰁲󰁯  󰁥 󰁏󰁦󰁩󰁣󰁩󰁡󰁬 󰁂󰁯󰁭󰁢󰁥󰁩󰁲󰁯󰀮 

CONC󰁕RSO DE SARGENTO AERON󰃁󰁕TICA 2/2011

PRO󰁖A TIPO 04 REALI󰁚ADO EM 05 DE DE󰁚EMBRO DE 2010   GABARITO: D 51. S󰁥 󰁳󰁥󰁮 󰁹 = 󰁭 󰁥 󰁣󰁯󰁳 󰁹 = 󰁮, 󰁯 󰁶󰁡󰁬󰁯󰁲 󰁤󰁥 2

󰁡) 󰁭.

󰁢) 󰁮 .

sec  y cos sec  y

󰁤) 󰁭/󰁮

T󰃓PICO: TRIGONOMETRIA (R󰁥󰁬󰁡󰃧󰃵󰁥󰁳 T󰁲󰁩󰁧󰁯󰁮󰁯󰁭󰃩󰁴󰁲󰁩󰁣󰁡󰁳) T󰁲󰁩󰁧󰁯󰁮󰁯󰁭󰃩󰁴󰁲󰁩󰁣󰁡󰁳) P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 1 sec  y cos sec  y

=

cos  y 1 seny seny m . = = = 1 cos  y 1 cos  y n seny

cos 60 o =

cateto  adjacente

cos 60 o =

4

1

hipotenusa

󰁡

 

a

󰁯

60  (

4

2=a a = 8cm

4󰁣󰁭

GABARITO: D 55. A 󰁦󰁵󰁮󰃧󰃣󰁯 󰁧: 󰁛󰀭5,5󰁝

→ B 󰁴󰁥󰁭 󰁣󰁯󰁭󰁯 󰁩󰁭󰁡󰁧󰁥󰁭 󰁯 󰁣󰁯󰁮󰁪󰁵󰁮󰁴󰁯 I = 󰁛20,30󰁝. P󰁡󰁲󰁡 󰁱󰁵󰁥 󰁥󰁬󰁡 󰁳󰁥󰁪󰁡 󰁳󰁯󰁢󰁲󰁥󰁪󰁥󰁴󰁯󰁲󰁡 󰃩 󰁮󰁥󰁣󰁥󰁳󰁳󰃡󰁲󰁩󰁯 󰁱󰁵󰁥 B 󰁳󰁥󰁪󰁡 󰁩󰁧󰁵󰁡󰁬 󰁡󰁯 󰁩󰁮󰁴󰁥󰁲󰁶󰁡󰁬󰁯: 󰁡) 󰁛5,20󰁝 󰁢) 󰁛󲀓5,20󰁝 󰁣) 󰁛󲀓5,30󰁝 󰁤) 󰁛20,30󰁝

T󰃓PICO: F󰁕N󰃇󰃃O P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: U󰁭󰁡 󰁦󰁵󰁮󰃧󰃣󰁯 󰃩 󰁤󰁩󰁴󰁡 󰁳󰁯󰁢󰁲󰁥󰁪󰁥󰁴󰁯󰁲󰁡 󰁳󰁥 CD󰁦   = I󰁦 , 󰁯󰁵 󰁳󰁥󰁪󰁡, 󰁣󰁯󰁮󰁴󰁲󰁡󰁤󰁯󰁭󰃭󰁮󰁩󰁯 󰁥 󰁩󰁭󰁡󰁧󰁥󰁭 󰁳󰃣󰁯 󰁯 󰁭󰁥󰁳󰁭󰁯 󰁣󰁯󰁮󰁪󰁵󰁮󰁴󰁯. L󰁯󰁧󰁯, 󰁰󰁡󰁲󰁡 󰁱󰁵󰁥 󰁧 󰁳󰁥󰁪󰁡 󰁳󰁯󰁢󰁲󰁥󰁪󰁥󰁴󰁯󰁲󰁡, 󰁯 󰁣󰁯󰁮󰁪󰁵󰁮󰁴󰁯 B 󰁤󰁥󰁶󰁥 󰁳󰁥󰁲 󰁯 󰁩󰁮󰁴󰁥󰁲󰁶󰁡󰁬󰁯 󰁛20,30󰁝. 

󰃩:

󰁣) 󰁭󰁮.

T󰃓PICO: GEOMETRIA PLANA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚:

 

GABARITO: C  52. U󰁭 󰁰󰁯󰁬󰃭󰁧󰁯󰁮󰁯 󰁣󰁯󰁮󰁶󰁥󰁸󰁯 ABCD 󰃩 󰁴󰁡󰁬 󰁱󰁵󰁥 󰁡󰁰󰁥󰁮󰁡󰁳 󰁤󰁯󰁩󰁳 󰁤󰁥 󰁳󰁥󰁵󰁳 󰁬󰁡󰁤󰁯󰁳 󰁳󰃣󰁯 󰁰󰁡󰁲󰁡󰁬󰁥󰁬󰁯󰁳 󰁥󰁮󰁴󰁲󰁥 󰁳󰁩 󰁥 󰁯󰁳 󰁯󰁵󰁴󰁲󰁯󰁳 󰁤󰁯󰁩󰁳 󰁬󰁡󰁤󰁯󰁳 󰁳󰃣󰁯 󰁣󰁯󰁮󰁧󰁲󰁵󰁥󰁮󰁴󰁥󰁳. D󰁥󰁳󰁳󰁡 󰁦󰁯󰁲󰁭󰁡, 󰁰󰁯󰁤󰁥󰀭󰁳󰁥 󰁤󰁩󰁺󰁥󰁲 󰁱󰁵󰁥 ABCD 󰃩 󰁵󰁭: 󰁡) 󰁬󰁯󰁳󰁡󰁮󰁧󰁯. 󰁢) 󰁰󰁡󰁲󰁡󰁬󰁥󰁬󰁯󰁧󰁲󰁡󰁭󰁯. 󰁣) 󰁴󰁲󰁡󰁰󰃩󰁺󰁩󰁯 󰁩󰁳󰃳󰁳󰁣󰁥󰁬󰁥󰁳. 󰁤) 󰁴󰁲󰁡󰁰󰃩󰁺󰁩󰁯 󰁲󰁥󰁴󰃢󰁮󰁧󰁵󰁬󰁯.

T󰃓PICO: GEOMETRIA PLANA  P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: T󰁯󰁤󰁯 󰁱󰁵󰁡󰁤󰁲󰁩󰁬󰃡󰁴󰁥󰁲󰁯 󰁣󰁵󰁪󰁯 󰁤󰁯󰁩󰁳 󰁬󰁡󰁤󰁯󰁳 󰁡󰁰󰁥󰁮󰁡󰁳 󰁳󰃣󰁯 󰁰󰁡󰁲󰁡󰁬󰁥󰁬󰁯󰁳, 󰁥󰁬󰁥 󰃩 󰁵󰁭 󰁴󰁲󰁡󰁰󰃩󰁺󰁩󰁯. C󰁯󰁭󰁯 󰁯󰁳 󰁯󰁵󰁴󰁲󰁯󰁳 󰁤󰁯󰁩󰁳 󰁬󰁡󰁤󰁯󰁳 󰁳󰃣󰁯 󰁩󰁧󰁵󰁡󰁩󰁳, 󰁯󰁵 󰁳󰁥󰁪󰁡, 󰁯󰁳 󰁬󰁡󰁤󰁯󰁳 󰁯󰁢󰁬󰃭󰁱󰁵󰁯󰁳 󰁳󰃣󰁯 󰁣󰁯󰁮󰁧󰁲󰁵󰁥󰁮󰁴󰁥󰁳, 󰁴󰁡󰁬 󰁴󰁲󰁡󰁰󰃩󰁺󰁩󰁯 󰃩 󰁩󰁳󰃳󰁳󰁣󰁥󰁬󰁥󰁳. 

GABARITO: A 56. S󰁥󰁪󰁡 󰁺󲀙 󰁯 󰁣󰁯󰁮󰁪󰁵󰁧󰁡󰁤󰁯 󰁤󰁯 󰁮󰃺󰁭󰁥󰁲󰁯 󰁣󰁯󰁭󰁰󰁬󰁥󰁸󰁯 󰁺 = 1 󲀓 3󰁩. O 󰁶󰁡󰁬󰁯󰁲 󰁤󰁥 2󰁺 + 󰁺󲀙 󰃩: 󰁡) 3 󲀓 3󰁩

󰁢) 1 󲀓 3󰁩

󰁣) 3 + 󰁩

󰁤) 1 + 󰁩

T󰃓PICO: N󰃚MEROS COMPLE󰁘OS P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 󰁺 = 1 󲀓 3󰁩 󰁺󲀙= 1 + 3󰁩 2󰁺 + 󰁺󲀙 = 2.(1 󲀓 3󰁩) + (1 + 3󰁩) = 3󰀭 3󰁩 

GABARITO: C  57. S󰁥 󰁡 󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟 󰁤󰁥 󰁵󰁭 󰁣󰁩󰁬󰁩󰁮󰁤󰁲󰁯 󰁦󰁯󰁲 󰁩󰁧󰁵󰁡󰁬 󰃠(󰁡󰁯)  󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟󰁟, 󰁥󰁬󰁥 󰃩 󰁤󰁥󰁮󰁯󰁭󰁩󰁮󰁡󰁤󰁯 󰁣󰁩󰁬󰁩󰁮󰁤󰁲󰁯 󰁣󰁩󰁬󰁩󰁮󰁤󰁲󰁯 󰁥󰁱󰃼󰁩󰁬󰃡󰁴󰁥󰁲󰁯. 󰁡) 󰃡󰁲󰁥󰁡 󰁤󰁡 󰁳󰁥󰁣󰃧󰃣󰁯 󰁭󰁥󰁲󰁩󰁤󰁩󰁡󰁮󰁡; 󰃡󰁲󰁥󰁡 󰁤󰁡 󰁢󰁡󰁳󰁥. 󰁢) 󰃡󰁲󰁥󰁡 󰁬󰁡󰁴󰁥󰁲󰁡󰁬; 󰃡󰁲󰁥󰁡 󰁤󰁡 󰁢󰁡󰁳󰁥. 󰁣) 󰁡󰁬󰁴󰁵󰁲󰁡; 󰁤󰁩󰃢󰁭󰁥󰁴󰁲󰁯 󰁤󰁡 󰁢󰁡󰁳󰁥. 󰁤) 󰁡󰁬󰁴󰁵󰁲󰁡; 󰁲󰁡󰁩󰁯 󰁤󰁡 󰁢󰁡󰁳󰁥. 

T󰃓PICO: GEOMETRIA ESPACIAL P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: C󰁩󰁬󰁩󰁮󰁤󰁲󰁯 E󰁱󰃼󰁩󰁬󰃡󰁴󰁥󰁲󰁯: H = 2.R = D (D: 󰁤󰁩󰃢󰁭󰁥󰁴󰁲󰁯)  

GABARITO: B  53. S󰁥󰁪󰁡󰁭 󰁡󰁳 󰁦󰁵󰁮󰃧󰃵󰁥󰁳 󰁬󰁯󰁧󰁡󰁲󰁩󰁴󰁭󰁩󰁣󰁡󰁳 󰁦(󰁸) = 󰁬󰁯󰁧󰁡󰁸 󰁥 󰁧(󰁸) = 󰁬󰁯󰁧 󰁢󰁸. S󰁥 󰁦(󰁸) 󰃩

GABARITO: B 58. 󰁵󰁭󰁡 󰁥󰁱󰁵󰁡󰃧󰃣󰁯 󰁰󰁯󰁬󰁩󰁮󰁯󰁭󰁩󰁡󰁬 󰁤󰁥 󰁣󰁯󰁥󰁦󰁩󰁣󰁩󰁥󰁮󰁴󰁥󰁳 󰁲󰁥󰁡󰁩󰁳 󰁡󰁤󰁭󰁩󰁴󰁥 󰁣󰁯󰁭󰁯 󰁲󰁡󰃭󰁺󰁥󰁳

󰁣󰁲󰁥󰁳󰁣󰁥󰁮󰁴󰁥 󰁥 󰁧(󰁸) 󰃩 󰁤󰁥󰁣󰁲󰁥󰁳󰁣󰁥󰁮󰁴󰁥, 󰁥󰁮󰁴󰃣󰁯: 󰁡) 󰁡 > 1 󰁥 󰁢 < 1. 󰁢) 󰁡 > 1 󰁥 0 < 󰁢 < 1. 󰁣) 0 < 󰁡 < 1 󰁥 󰁢 > 1. 󰁤) 0 < 󰁡 < 1 󰁥 0 < 󰁢 < 1.

󰁯󰁳 󰁮󰃺󰁭󰁥󰁲󰁯󰁳 󲀓2, 0, 2 󰁥 1 + 󰁩. O 󰁭󰁥󰁮󰁯󰁲 󰁧󰁲󰁡󰁵 󰁱󰁵󰁥 󰁥󰁳󰁳󰁡 󰁥󰁱󰁵󰁡󰃧󰃣󰁯 󰁰󰁯󰁤󰁥 󰁴󰁥󰁲 󰃩: 󰁡) 6 󰁢) 5 󰁣) 4 󰁤) 3

T󰃓PICO: LOGARITMOS P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚:

T󰃓PICO: EQ󰁕A󰃇󰃕ES POLINOMIAIS P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚:

P󰁡󰁲󰁡 󰁱󰁵󰁥 󰁵󰁭󰁡 󰁦󰁵󰁮󰃧󰃣󰁯 󰁬󰁯󰁧󰁡󰁲󰃭󰁴󰁭󰁩󰁣󰁡 󰁤󰁯 󰁴󰁩󰁰󰁯 󰁦(󰁸) = 󰁬󰁯󰁧󰁡󰁸 󰁳󰁥󰁪󰁡 󰁣󰁲󰁥󰁳󰁣󰁥󰁮󰁴󰁥, 󰃩 󰁮󰁥󰁣󰁥󰁳󰁳󰃡󰁲󰁩󰁯 󰁥 󰁳󰁵󰁦󰁩󰁣󰁩󰁥󰁮󰁴󰁥 󰁱󰁵󰁥 󰁡 > 1. N󰁯 󰁣󰁡󰁳󰁯 󰁥󰁭 󰁱󰁵󰁥 0 < 󰁢 < 1, 󰁡 󰁦󰁵󰁮󰃧󰃣󰁯

RA󰃍󰁚ES COMPLE󰁘AS

󰁧(󰁸) = 󰁬󰁯󰁧󰁢󰁸 󰃩 󰁤󰁥󰁣󰁲󰁥󰁳󰁣󰁥󰁮󰁴󰁥. 

GABARITO: C 54. E󰁭 󰁵󰁭 󰁴󰁲󰁩󰃢󰁮󰁧󰁵󰁬󰁯 󰁲󰁥󰁴󰃢󰁮󰁧󰁵󰁬󰁯, 󰁵󰁭 󰁤󰁯󰁳 󰁣󰁡󰁴󰁥󰁴󰁯󰁳 󰁭󰁥󰁤󰁥 4 󰁣󰁭, 󰁥 󰁯 󰃢󰁮󰁧󰁵󰁬󰁯 󰁱󰁵󰁥 󰁬󰁨󰁥 󰃩 󰁡󰁤󰁪󰁡󰁣󰁥󰁮󰁴󰁥 󰁭󰁥󰁤󰁥 60󰂰. A 󰁨󰁩󰁰󰁯󰁴󰁥󰁮󰁵󰁳󰁡 󰁤󰁥󰁳󰁳󰁥 󰁴󰁲󰁩󰃢󰁮󰁧󰁵󰁬󰁯, 󰁥󰁭 󰁣󰁭, 󰁭󰁥󰁤󰁥: 󰁡) 6 󰁢) 7 󰁣) 8 󰁤) 9

S󰁥 󰁯 󰁮󰃺󰁭󰁥󰁲󰁯 󰁣󰁯󰁭󰁰󰁬󰁥󰁸󰁯 󰁚 = 󰁡 + 󰁢󰁩  󰃩 󰁡 󰁲󰁡󰁩󰁺 󰁤󰁡 󰁥󰁱󰁵󰁡󰃧󰃣󰁯 n   1 n n 2 2 a n x + a n − 1 x −   + a n − 2 x −    + ... + a 2 x + a1 x + a0 = 0 󰁤󰁥 󰁣󰁯󰁥󰁦󰁩󰁣󰁩󰁥󰁮󰁴󰁥󰁳 󰁲󰁥󰁡󰁩󰁳, 󰁥󰁮󰁴󰃣󰁯 󰁳󰁥󰁵 󰁣󰁯󰁮󰁪󰁵󰁧󰁡󰁤󰁯 󰁣󰁯 󰁮󰁪󰁵󰁧󰁡󰁤󰁯  Z  =  a −  bi 󰁴󰁡󰁭󰁢󰃩󰁭 󰃩 󰁲󰁡󰁩󰁺 󰁤󰁥󰁳󰁳󰁡 󰁥󰁱󰁵󰁡󰃧󰃣󰁯. L󰁯󰁧󰁯:

󰁸1 = 󰀭2

󰁸2 = 0

󰁸3 = 󰀭2

󰁸4 = 1 + 󰁩

 x5 =  x 4  = 1 − i

O󰁳 󰁮󰃺󰁭󰁥󰁲󰁯󰁳 󰁤󰁥 󰁲󰁡󰃭󰁺󰁥󰁳 󰁤󰁥󰁦󰁩󰁮󰁥󰁭 󰁯 󰁧󰁲󰁡󰁵 󰁤󰁡 󰁥󰁱󰁵󰁡󰃧󰃣󰁯. P󰁯󰁲󰁴󰁡󰁮󰁴󰁯, 5 󰁲󰁡󰃭󰁺󰁥󰁳 󰁴󰁥󰁲󰁥󰁭󰁯󰁳 󰁮󰁯 󰁭󰃭󰁮󰁩󰁭󰁯 󰁧󰁲󰁡󰁵 5.

 

  󰁷󰁷󰁷.󰁣󰁵󰁲󰁳󰁯󰁨󰁥󰁲󰁴󰁺.󰁣󰁯󰁭 GABARITO: B  59. U󰁭 󰁴󰁥󰁳󰁴󰁥 󰁤󰁥 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 󰁦󰁯󰁩 󰁡󰁰󰁬󰁩󰁣󰁡󰁤󰁯 󰁥󰁭 󰁤󰁵󰁡󰁳 󰁴󰁵󰁲󰁭󰁡󰁳 󰁤󰁩󰁳󰁴󰁩󰁮󰁴󰁡󰁳 󰁤󰁥

GABARITO: C  63. C󰁯󰁮󰁳󰁩󰁤󰁥󰁲󰁥 󰁡 󰁦󰁩󰁧󰁵󰁲󰁡 󰁣󰁯󰁭󰁰󰁯󰁳󰁴󰁡 󰁤󰁥 󰁴󰁲󰃪󰁳 󰁣󰃭󰁲󰁣󰁵󰁬󰁯󰁳 󰁣󰁯󰁮󰁣󰃪󰁮󰁴󰁲󰁩󰁣󰁯󰁳 󰁤󰁥 󰁲󰁡󰁩󰁯󰁳

󰁵󰁭󰁡 󰁥󰁳󰁣󰁯󰁬󰁡, 󰁡 󰁰󰁲󰁩󰁭󰁥󰁩󰁲󰁡 󰁣󰁯󰁭 40 󰁡󰁬󰁵󰁮󰁯󰁳 󰁥 󰁡 󰁳󰁥󰁧󰁵󰁮󰁤󰁡 󰁣󰁯󰁭 20. A󰁳 󰁭󰃩󰁤󰁩󰁡󰁳 󰁡󰁲󰁩󰁴󰁭󰃩󰁴󰁩󰁣󰁡󰁳 󰁤󰁡󰁳 󰁮󰁯󰁴󰁡󰁳 󰁤󰁡 󰁰󰁲󰁩󰁭󰁥󰁩󰁲󰁡 󰁥 󰁤󰁡 󰁳󰁥󰁧󰁵󰁮󰁤󰁡 󰁴󰁵󰁲󰁭󰁡 󰁦󰁯󰁲󰁡󰁭, 󰁲󰁥󰁳󰁰󰁥󰁣󰁴󰁩󰁶󰁡󰁭󰁥󰁮󰁴󰁥, 6,0 󰁥 7,0. A󰁳󰁳󰁩󰁭, 󰁡 󰁭󰃩󰁤󰁩󰁡 󰁡󰁲󰁩󰁴󰁭󰃩󰁴󰁩󰁣󰁡 󰁤󰁡󰁳 󰁮󰁯󰁴󰁡󰁳 󰁤󰁯󰁳 60 󰁡󰁬󰁵󰁮󰁯󰁳 󰁦󰁯󰁩 󰁡󰁰󰁲󰁯󰁸󰁩󰁭󰁡󰁤󰁡󰁭󰁥󰁮󰁴󰁥: 󰁡) 6,14 󰁢) 6,3 󰁣) 7,2 󰁤) 7,5

󰁭󰁥󰁤󰁩󰁮󰁤󰁯, 󰁲󰁥󰁳󰁰󰁥󰁣󰁴󰁩󰁶󰁡󰁭󰁥󰁮󰁴󰁥, 5 󰁣󰁭, 4 󰁣󰁭 󰁥 3 󰁣󰁭. A 󰃡󰁲󰁥󰁡, 󰁥󰁭 󰁣󰁭2, 󰁤󰁡 󰁰󰁡󰁲󰁴󰁥 󰁨󰁡󰁣󰁨󰁵󰁲󰁡󰁤󰁡 󰃩: 󰁡) 9π  󰁢) 16π  󰁣) 18π  󰁤) 24π 

T󰃓PICO: ESTAT󰃍STICA (M󰃩󰁤󰁩󰁡 A󰁲󰁩󰁴󰁭󰃩󰁴󰁩󰁣󰁡) P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: P󰁡󰁲󰁡 1󰂪 󰁴󰁵󰁲󰁭󰁡 󰁴󰁥󰁭󰁯󰁳:  M 1 =  x1 (notas) n1 ( alunos )  x1

40

= 6 →  x1 = 240

 M 2 =  x 2

20

 

GABARITO: A 64. U󰁭 󰁱󰁵󰁡󰁤󰁲󰁡󰁤󰁯 󰁥 󰁵󰁭 󰁴󰁲󰁩󰃢󰁮󰁧󰁵󰁬󰁯 󰁥󰁱󰁵󰁩󰁬󰃡󰁴󰁥󰁲󰁯 󰁥󰁳󰁴󰃣󰁯 󰁩󰁮󰁳󰁣󰁲󰁩󰁴󰁯󰁳 󰁥󰁭 󰁵󰁭󰁡

 x 2 (notas) n 2 ( alunos )

󰁣󰁩󰁲󰁣󰁵󰁮󰁦󰁥󰁲󰃪󰁮󰁣󰁩󰁡 󰁤󰁥 󰁲󰁡󰁩󰁯 R. A 󰁲󰁡󰁺󰃣󰁯 󰁥󰁮󰁴󰁲󰁥 󰁡󰁳 󰁭󰁥󰁤󰁩󰁤󰁡󰁳 󰁤󰁯󰁳 󰁡󰁰󰃳󰁴󰁥󰁭󰁡󰁳 󰁤󰁯 󰁱󰁵󰁡󰁤󰁲󰁡󰁤󰁯 󰁥 󰁤󰁯 󰁴󰁲󰁩󰃢󰁮󰁧󰁵󰁬󰁯 󰃩:

 

󰁡) 2  

= 7 →  x 2 = 140

 M Turma

T󰃓PICO: GEOMETRIA PLANA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: A󰁨󰁡󰁣. = A󰁭󰁥󰁮󰁯󰁲 + A󰁣󰁯󰁲󰁯󰁡  2 2 2 2 A󰁨󰁡󰁣. = π3  + (π5  󰀭 π4 )= 18π󰁣󰁭  

T󰃓PICO: L󰁥󰁩 󰁤󰁯󰁳 S󰁥󰁮󰁯󰁳 P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: = 2 R =  D

Q󰁵󰁡󰁤󰁲󰁡󰁤󰁯

2

3 3cm   󰁤󰁥 󰁡󰁰󰃳󰁴󰁥󰁭󰁡. A 󰃡󰁲󰁥󰁡 󰁬󰁡󰁴󰁥󰁲󰁡󰁬 󰁤󰁥󰁳󰁳󰁡 󰁰󰁩󰁲󰃢󰁭󰁩󰁤󰁥, 󰁥󰁭 󰁣󰁭 , 󰃩: 󰁣) 24

󰁤) 27

T󰃓PICO: GEOMETRIA ESPACIAL P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 a×m

2 2

= 9cm

2

 

=

2  R

2

 R  3

 R 2 2  R

 

 

=

2

 

λ  󰁤󰁥

2

󰁥󰁱󰁵󰁡󰃧󰃣󰁯 󰁸  + 󰁹  󲀓 3󰁸 󲀓 4 = 0, 󰃩 󰁣󰁯󰁲󰁲󰁥󰁴󰁯 󰁡󰁦󰁩󰁲󰁭󰁡󰁲 󰁱󰁵󰁥: 󰁡) B 󰃩 󰁩󰁮󰁴󰁥󰁲󰁩󰁯󰁲 󰁡 λ 󰁥 C 󰃩 󰁥󰁸󰁴󰁥󰁲󰁩󰁯󰁲 󰁡 λ. 󰁢) B 󰃩 󰁥󰁸󰁴󰁥󰁲󰁩󰁯󰁲 󰁡 λ 󰁥 C 󰁩󰁮󰁴󰁥󰁲󰁩󰁯󰁲 󰁡 λ. 󰁣) B 󰁥 C 󰁳󰃣󰁯 󰁥󰁸󰁴󰁥󰁲󰁩󰁯󰁲󰁥󰁳 󰁡 λ. 󰁤) B 󰁥 C 󰁳󰃣󰁯 󰁩󰁮󰁴󰁥󰁲󰁩󰁯󰁲󰁥󰁳 󰁡 λ.

T󰃓PICO: GEOMETRIA ANAL󰃍TICA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 2

2

B(1, 2) → 󰁸  + 󰁹  󲀓 3󰁸 󲀓 4 = 0 2

2

(1)  + (2)  󲀓 3.(1) 󲀓 4 1+4󲀓3󲀓4 0 󰀭2 < 0 B 󰃩 󰁩󰁮󰁴󰁥󰁲󰁩󰁯󰁲 󰁡 λ. 2

 Alateral = 3 A face = 3.(9) = 27cm

 

GABARITO: D  65. D󰁡󰁤󰁯󰁳 󰁯󰁳 󰁰󰁯󰁮󰁴󰁯󰁳 B(1,2) 󰁥 C(0,1) 󰁥 󰁵󰁭󰁡 󰁣󰁩󰁲󰁣󰁵󰁮󰁦󰁥󰁲󰃪󰁮󰁣󰁩󰁡

61. U󰁭 󰁰󰁩󰁲󰃢󰁭󰁩󰁤󰁥 󰁴󰁲󰁩󰁡󰁮󰁧󰁵󰁬󰁡󰁲 󰁲󰁥󰁧󰁵󰁬󰁡󰁲 󰁴󰁥󰁭 2 3 cm 󰁤󰁥 󰁡󰁲󰁥󰁳󰁴󰁡 󰁤󰁡 󰁢󰁡󰁳󰁥 󰁥

2 3 ×3 3

 

2

) 30󰁯 

GABARITO: D

 A face =

 R 3

2

2

 A face =

 R

T󰁲󰁩󰃢󰁮󰁧󰁵󰁬󰁯 E󰁱󰁵󰁩󰁬󰃡󰁴󰁥󰁲󰁯 

ap3

󰁢) 21

A󰁰󰃳󰁴󰁥󰁭󰁡 2

ap 4

 

󰁡) 18

󰁤) 3  2

 R 2

10󰁣󰁭

2  D = 20cm

L󰁡󰁤󰁯  R 

H󰁥󰁸󰃡󰁧󰁯󰁮󰁯

30󰂰 󰁯󰁰󰁯󰁳󰁴󰁯 󰁡 󰁵󰁭 󰁬󰁡󰁤󰁯 󰁤󰁥 10 󰁣󰁭. O 󰁤󰁩󰃢󰁭󰁥󰁴󰁲󰁯 󰁤󰁡 󰁣󰁩󰁲󰁣󰁵󰁮󰁦󰁥󰁲󰃪󰁮󰁣󰁩󰁡, 󰁥󰁭 󰁣󰁭, 󰃩: 󰁡) 10 󰁢) 15 󰁣) 20 󰁤) 25

  o sen30 10 =  D 1

󰁣) 2  3

T󰃓PICO: GEOMETRIA PLANA (P󰁯󰁬󰃭󰁧󰁯󰁮󰁯󰁳 R󰁥󰁧󰁵󰁬󰁡󰁲󰁥󰁳 󰁩󰁮󰁳󰁣󰁲󰁩󰁴󰁯󰁳) P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚:

 x1 +  x 2 240 + 140 = =   ≅ 6,3. n1 + n 2 40 + 20

GABARITO: C  60. U󰁭 󰁴󰁲󰁩󰃢󰁮󰁧󰁵󰁬󰁯, 󰁩󰁮󰁳󰁣󰁲󰁩󰁴󰁯 󰁥󰁭 󰁵󰁭󰁡 󰁣󰁩󰁲󰁣󰁵󰁮󰁦󰁥󰁲󰃪󰁮󰁣󰁩󰁡, 󰁴󰁥󰁭 󰁵󰁭 󰃢󰁮󰁧󰁵󰁬󰁯 󰁤󰁥

10

󰁢) 3  

0

2

C(0, 1) → 󰁸  + 󰁹  󲀓 3󰁸 󲀓 4 = 0

2

2

GABARITO: C 62. U󰁭󰁡 󰁣󰁵󰁢󰁯 󰁴󰁥󰁭 3 󰁣󰁭 󰁤󰁥 󰁡󰁬󰁴󰁵󰁲󰁡, 󰁥 󰁵󰁭 󰁰󰁡󰁲󰁡󰁬󰁥󰁬󰁥󰁰󰃭󰁰󰁥󰁤󰁯 󰁲󰁥󰁴󰃢󰁮󰁧󰁵󰁬󰁯 󰁴󰁥󰁭 󰁤󰁩󰁭󰁥󰁮󰁳󰃵󰁥󰁳 1 󰁣󰁭, 2 󰁣󰁭 󰁥 3 󰁣󰁭. A 󰁲󰁡󰁺󰃣󰁯 󰁥󰁮󰁴󰁲󰁥 󰁯󰁳 󰁶󰁯󰁬󰁵󰁭󰁥󰁳 󰁤󰁯 󰁣󰁵󰁢󰁯 󰁥 󰁤󰁯 󰁰󰁡󰁲󰁡󰁬󰁥󰁬󰁥󰁰󰃭󰁰󰁥󰁤󰁯 󰃩: 󰁡) 3/2 󰁢) 4/3 󰁣) 9/2 󰁤) 8/3

2

(0)  + (1)  󲀓 3.(0) 󲀓 4 0+1󲀓0󲀓4 0 󰀭3 < 0 C 󰃩 󰁩󰁮󰁴󰁥󰁲󰁩󰁯󰁲 󰁡 λ.

0

T󰃓PICO: GEOMETRIA ESPACIAL P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: Vcubo Vparal

=

a

3

 L × c ×  H 

=

3

3

1× 2 × 3

=

27 6

=

9 2

 

2

 

  󰁷󰁷󰁷.󰁣󰁵󰁲󰁳󰁯󰁨󰁥󰁲󰁴󰁺.󰁣󰁯󰁭 GABARITO: D 66. O 󰁨󰁩󰁳󰁴󰁯󰁧󰁲󰁡󰁭󰁡 󰁡󰁰󰁲󰁥󰁳󰁥󰁮󰁴󰁡 󰁡󰁳 󰁡󰁬󰁴󰁵󰁲󰁡󰁳 󰁤󰁥 30 󰁭󰁥󰁮󰁩󰁮󰁡󰁳 󰁱󰁵󰁥 󰁦󰁲󰁥󰁱󰁵󰁥󰁮󰁴󰁡󰁭

GABARITO: D 70. A 󰁦󰁵󰁮󰃧󰃣󰁯 󰁭󰁯󰁤󰁵󰁬󰁡󰁲 󰁦(󰁸)= 󰁼󰁸 󲀓 2󰁼 󰃩 󰁤󰁥󰁣󰁲󰁥󰁳󰁣󰁥󰁮󰁴󰁥 󰁰󰁡󰁲󰁡 󰁴󰁯󰁤󰁯 󰁸 󰁲󰁥󰁡󰁬 󰁴󰁡󰁬

󰁯 3󰂰 󰁡󰁮󰁯 󰁤󰁯 E󰁮󰁳󰁩󰁮󰁯 M󰃩󰁤󰁩󰁯 󰁤󰁥 󰁵󰁭󰁡 󰁥󰁳󰁣󰁯󰁬󰁡. C󰁯󰁮󰁳󰁩󰁤󰁥󰁲󰁡󰁮󰁤󰁯 󰁱󰁵󰁥 󰁡󰁳 󰁣󰁬󰁡󰁳󰁳󰁥󰁳 󰁡󰁰󰁲󰁥󰁳󰁥󰁮󰁴󰁡󰁤󰁡󰁳 󰁮󰁯 󰁧󰁲󰃡󰁦󰁩󰁣󰁯 󰁩󰁮󰁣󰁬󰁵󰁥󰁭 󰁳󰁥󰁵󰁳 󰁬󰁩󰁭󰁩󰁴󰁥󰁳 󰁩󰁮󰁦󰁥󰁲󰁩󰁯󰁲󰁥󰁳 󰁥 󰁮󰃣󰁯 󰁯󰁳 󰁬󰁩󰁭󰁩󰁴󰁥󰁳 󰁳󰁵󰁰󰁥󰁲󰁩󰁯󰁲󰁥󰁳, 󰃩 󰁣󰁯󰁲󰁲󰁥󰁴󰁯 󰁡󰁦󰁩󰁲󰁭󰁡󰁲 󰁱󰁵󰁥 󰁯 󰁮󰃺󰁭󰁥󰁲󰁯 󰁤󰁥 󰁭󰁥󰁮󰁩󰁮󰁡󰁳 󰁣󰁯󰁭 󰁡󰁬󰁴󰁵󰁲󰁡 󰁮󰃣󰁯 󰁩󰁮󰁦󰁥󰁲󰁩󰁯󰁲 󰁡 170 󰁣󰁭 󰃩: 󰁡) 13 󰁢) 18 󰁣) 22 󰁤) 25

󰁱󰁵󰁥: 󰁡) 0 < 󰁸 < 4

󰁢) 󰁸 > 0

T󰃓PICO: F󰁕N󰃇󰃃O MOD󰁕LAR P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 󰁹

2

T󰃓PICO: ESTAT󰃍STICA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: C󰁯󰁭󰁯 󰁡󰁳 󰁣󰁬󰁡󰁳󰁳󰁥󰁳 󰁩󰁮󰁣󰁬󰁵󰁥󰁭 󰁯󰁳 󰁬󰁩󰁭󰁩󰁴󰁥󰁳 󰁩󰁮󰁦󰁥󰁲󰁩󰁯󰁲󰁥󰁳 󰁡󰁰󰁥󰁮󰁡󰁳, 󰁩󰁳󰁴󰁯 󰃩, 󰁳󰃣󰁯 󰁩󰁮󰁴󰁥󰁲󰁶󰁡󰁬󰁯󰁳 󰁤󰁯 󰁴󰁩󰁰󰁯 󰁛󰁡,󰁢), 󰁯 󰁮󰃺󰁭󰁥󰁲󰁯 󰁤󰁥 󰁡󰁬󰁵󰁮󰁡󰁳 󰁣󰁯󰁭 󰁡󰁬󰁴󰁵󰁲󰁡 󰁮󰃣󰁯 󰁩󰁮󰁦󰁥󰁲󰁩󰁯󰁲 󰁡 170 󰁣󰁭 󰃩 󰁡 󰁳󰁯󰁭󰁡 󰁤󰁯 󰁮󰃺󰁭󰁥󰁲󰁯 󰁤󰁥 󰁡󰁬󰁵󰁮󰁡󰁳 󰁮󰁡󰁳 󰁣󰁬󰁡󰁳󰁳󰁥󰁳 󰁛170,180), 󰁛180,190) 󰁥 󰁛190,200), 󰁯󰁵 󰁳󰁥󰁪󰁡, 15 + 8 + 2 = 25 󰁡󰁬󰁵󰁮󰁡󰁳 󰁮󰁯 󰁴󰁯󰁴󰁡󰁬.

GABARITO: B 67. S󰁥 A = 󰁴󰁧 120󰂰 󰁥 B = 󰁴󰁧 240󰂰, 󰁥󰁮󰁴󰃣󰁯: 󰁡) B = A.

󰁢) B = 󲀓A.

󰁣) B = 2A.

󰁤) B = 󲀓2A.  

T󰃓PICO: TRIGONOMETRIA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 󰀭 R󰁥󰁤󰁵󰃧󰃣󰁯 II Q 󰁰󰁡󰁲󰁡 I Q: 180 󰁯 󰀭 120󰁯 = 60󰁯  󰁯

󰁯

A 󰁲󰁡󰁺󰃣󰁯 󰁥󰁮󰁴󰁲󰁥 󰁯 6󰂰 󰁴󰁥󰁲󰁭󰁯 S 1 󰁥 󰁯 8󰂰 󰁤󰁥 S2 󰃩: 󰁡) 150 󰁢) 125 󰁣) 100

󰁤) 75

T󰃓PICO: PROGESS󰃃O ARITM󰃉TICA 󰁥 PROGRESS󰃃O GEOM󰃉TRICA     P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: S1 = (1, 5, 25, 125, ...) 󰁡1 = 1 󰁱 = 5/1 = 5 󰁡6 = 󰁡1.󰁱

󰁯

󰁡6 = 1.5 5 󰁡6 = 5

󰁴󰁧240  = +󰁴󰁧60  = L󰁯󰁧󰁯: B = 󰀭A 

󰁸

GABARITO: B 71. S󰁥󰁪󰁡󰁭 󰁡󰁳 󰁳󰁥󰁱󰁵󰃪󰁮󰁣󰁩󰁡󰁳 S1 = (1, 5, 25, 125, ...) 󰁥 S 2 = (4, 7, 10, 13, ...).

󰁯

󰁴󰁧120  = 󰀭󰁴󰁧60  = − 3 (  A) 󰀭 R󰁥󰁤󰁵󰃧󰃣󰁯 III Q 󰁰󰁡󰁲󰁡 I Q: 240 󰁯 󰀭 180󰁯 = 60󰁯 

󰁤) 󰁸 ≤ 2

󰁣) 󰁸 > 4

󰁮󲀓1

6󲀓1

3 (  B) 

󰁡6 = 3125

GABARITO: A 68. D󰁡󰁤󰁯󰁳 󰁯󰁳 󰁰󰁯󰁮󰁴󰁯󰁳 A(󰁫,2), B(3,1) 󰁥 C(1,󲀓2), 󰁰󰁡󰁲󰁡 󰁱󰁵󰁥 󰁡 󰁤󰁩󰁳󰁴󰃢󰁮󰁣󰁩󰁡 󰁥󰁮󰁴󰁲󰁥 A 󰁥 B 󰁳󰁥󰁪󰁡 󰁩󰁧󰁵󰁡󰁬 󰃠 󰁤󰁩󰁳󰁴󰃢󰁮󰁣󰁩󰁡 󰁥󰁮󰁴󰁲󰁥 A 󰁥 C, 󰁯 󰁶󰁡󰁬󰁯󰁲 󰁤󰁥 󰁫 󰁤󰁥󰁶󰁥 󰁳󰁥󰁲: 󰁡) 󲀓7/4 󰁢) 󲀓3/4 󰁣) 1/5 󰁤) 3/5

T󰃓PICO: GEOMETRIA ANAL󰃍TICA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: d  A, B = d  A,C 

S2 = (4, 7, 10, 13, ...) 󰁡1 = 4 󰁲=7󰀭4=3  

󰁡8 = 󰁡1 + 7󰁲

󰁡8 = 4 + 7.(3)

 

 

󰁡8 = 25

󰁡6 /󰁡8 = 3125/25 󰁡6 /󰁡8 = 125

2

( x B −  x A ) + ( y B −  y A )

2

=

2

( xC  −  x A ) + ( yC  −  y A )

2

 

(3 − k ) 2 + (1 − 2) 2 = (1 − k ) 2 + ( −2 − 2) 2

GABARITO: B 72. C󰁯󰁮󰁳󰁩󰁤󰁥󰁲󰁡󰁮󰁤󰁯 D = 󰁛0,10󰁝 󰁯 󰁤󰁯󰁭󰃭󰁮󰁩󰁯 󰁤󰁥 󰁵󰁭󰁡 󰁦󰁵󰁮󰃧󰃣󰁯 󰁹 = 󰁦(󰁸), 󰁵󰁭 󰁧󰁲󰃡󰁦󰁩󰁣󰁯 󰁱󰁵󰁥 󰁰󰁯󰁤󰁥󰁲󰁩󰁡 󰁲󰁥󰁰󰁲󰁥󰁳󰁥󰁮󰁴󰃡󰀭󰁬󰁡 󰃩:

=−

7 / 4



GABARITO: A 69. S󰁥 󰁣󰁯󰁳󰁸 = 2/3 󰁥 󰁳󰁥󰁮 󰁸 > 0, 󰁥󰁮󰁴󰃣󰁯 󰁳󰁥󰁮 2󰁸 󰃩: 󰁡)

4 5 9

󰁢)

 

2 5 3

 

󰁣)

5 3 2  

󰁤)

3 6

 

T󰃓PICO: TRIGONOMETRIA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 2

2

sen  x + cos  x = 1 2

 2    3 

sen  x + 

senx =

2

=1

 

5 3

  5    2  4 5 .  = . 3 3 9         

sen2 x = 2 senx. cos  x = 2.

T󰃓PICO: F󰁕N󰃇󰃃O P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: B󰁡󰁳󰁴󰁡 󰁰󰁲󰁯󰁬󰁯󰁮󰁧󰁡󰁲󰁭󰁯󰁳 󰁰󰁡󰁲󰁡 󰁯 󰁥󰁩󰁸󰁯 󰁤󰁡󰁳 󰁡󰁢󰁳󰁣󰁩󰁳󰁳󰁡󰁳 󰁰󰁡󰁲󰁡 󰁶󰁥󰁲󰁩󰁦󰁩󰁣󰁡󰁲󰁭󰁯󰁳 󰁯 D󰁯󰁭󰃭󰁮󰁩󰁯 󰁤󰁡 󰁦󰁵󰁮󰃧󰃣󰁯 󰁮󰁯 󰁩󰁮󰁴󰁥󰁲󰁶󰁡󰁬󰁯 󰁛0, 10󰁝.

3

 

  󰁷󰁷󰁷.󰁣󰁵󰁲󰁳󰁯󰁨󰁥󰁲󰁴󰁺.󰁣󰁯󰁭

C󰁯󰁮󰁣󰁵󰁲󰁳󰁯 󰁤󰁥 B󰁯󰁬󰁳󰁡󰁳 GABARITO: D 73. P󰁡󰁲󰁡 󰁰󰁡󰁲󰁴󰁩󰁣󰁩󰁰󰁡󰁲 󰁤󰁥 󰁵󰁭 󰁳󰁯󰁲󰁴󰁥󰁩󰁯, 󰁵󰁭 󰁧󰁲󰁵󰁰󰁯 󰁤󰁥 152 󰁰󰁥󰁳󰁳󰁯󰁡󰁳 󰁲󰁥󰁳󰁰󰁯󰁮󰁤󰁥󰁵 󰃠 󰁰󰁥󰁲󰁧󰁵󰁮󰁴󰁡: 󲀜V󰁯󰁣󰃪 󰃩 󰁦󰁵󰁭󰁡󰁮󰁴󰁥?󲀝. S󰁥 40 󰁰󰁥󰁳󰁳󰁯󰁡󰁳 󰁲󰁥󰁳󰁰󰁯󰁮󰁤󰁥󰁲󰁡󰁭 󲀜SIM󲀝, 󰁡 󰁰󰁲󰁯󰁢󰁡󰁢󰁩󰁬󰁩󰁤󰁡󰁤󰁥 󰁤󰁡 󰁰󰁥󰁳󰁳󰁯󰁡 󰁳󰁯󰁲󰁴󰁥󰁡󰁤󰁡 󰁮󰃣󰁯 󰁳󰁥󰁲 󰁦󰁵󰁭󰁡󰁮󰁴󰁥 󰃩: 󰁡) 11/16 󰁢) 17/18 󰁣) 15/17 󰁤) 14/19

T󰃓PICO: PROBABILIDADE P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 T󰁯󰁴󰁡󰁬 = 152 F󰁵󰁭󰁡󰁮󰁴󰁥󰁳 = 40 N󰃣󰁯 F󰁵󰁭󰁡󰁮󰁴󰁥󰁳 = 152 󲀓 40 = 112 P= P=

S󰁡󰁲󰁧󰁥󰁮󰁴󰁯 A󰁥󰁲󰁯󰁮󰃡󰁵󰁴󰁩󰁣󰁡 1󰀭2012 15 J󰁡󰁮󰁥󰁩󰁲󰁯 󰁤󰁥 2011

Favorável Total 112 14 =

150

 

M󰁡󰁩󰁯󰁲󰁥󰁳 I󰁮󰁦󰁯󰁲󰁭󰁡󰃧󰃵󰁥󰁳

19

GABARITO: A 74. N󰁡 󰁦󰁩󰁧󰁵󰁲󰁡, AB

⊂ 󰁲 . S󰁥 󰁲 󰁴󰁥󰁭 󰁥󰁱󰁵󰁡󰃧󰃣󰁯 󰁸 󲀓 󰁹 󲀓 1 = 0, 󰁥 ABCD 󰃩 󰁵󰁭 󰁱󰁵󰁡󰁤󰁲󰁡󰁤󰁯, 󰁥󰁮󰁴󰃣󰁯 󰁯 󰁬󰁡󰁤󰁯 󰁤󰁥 ABCD 󰁭󰁥󰁤󰁥:

(91) 3276󰀭6141

󰁡) 2   󰁢) 3   󰁣) 3 2   󰁤) 2  3

T󰃓PICO: GEOMETRIA ANAL󰃍TICA P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: O 󰁬󰁡󰁤󰁯 󰁱󰁵󰁡󰁤󰁲󰁡󰁤󰁯 󰁳󰁥󰁲󰃡 󰁡 󰁤󰁩󰁳󰁴󰃢󰁮󰁣󰁩󰁡 󰁤󰁯 󰁰󰁯󰁮󰁴󰁯 D 󰁡 󰁲󰁥󰁴󰁡 󰁲: l=

dD   , r  =

3.1 + 0.(−1) + (−1)

 

2

(1) + (−1)

=

󰁷󰁷󰁷.󰁣󰁵󰁲󰁳󰁯󰁨󰁥󰁲󰁴󰁺.󰁣󰁯󰁭

2

2

GABARITO: B 1 1 󰁴 󰁴 75. S󰁥󰁪󰁡 P =     󰁥 P  󰁡 󰁭󰁡󰁴󰁲󰁩󰁺 󰁴󰁲󰁡󰁮󰁳󰁰󰁯󰁳󰁴󰁡 󰁤󰁥 P. A 󰁭󰁡󰁴󰁲󰁩󰁺 Q = P.P  󰃩: 0 1 1 1  1 1 2 1 1 2 󰁤)   󰁣)   󰁢)   󰁡)           2 0  1 0 1 1 1 2

T󰃓PICO: MATRI󰁚 P󰁲󰁯󰁦󰁥󰁳󰁳󰁯󰁲: 󰁗󰁡󰁬󰁤󰁯󰁭󰃡󰁲󰁩󰁯 M󰁥󰁬󰁯 󲀓 M󰁡󰁲󰁣󰁡 󰁦󰁯󰁲󰁴󰁥 󰁤󰁡 M󰁡󰁴󰁥󰁭󰃡󰁴󰁩󰁣󰁡 RESOL󰁕󰃇󰃃O HERT󰁚: 1 1   0 1 1 0 P t  =    1 1 1 1 1 0 1.1 + 1.1 1.0 + 1.1 2 1 Q=   . = =  0 1 1 1  0.1 + 1.1 0.0 + 1.1 1 1 P=

4

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