Problem 003-Mm _ Method of Members _ Engineering Mechanics Review

6/5/2015

Problem 003­mm | Method of Members | Engineering Mechanics Review

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Problem 003­mm | Method of Members SPONSORED LINKS

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Log in or Register to Discuss This! Problem 003­mm For the structure shown in Fig. (MM)­P003 below, determine the reactions at A and D and the internal force in member CF.  

  Solution 003­mm Click here to show or hide the solution From the FBD of the whole system ΣMD = 0 2Ax = 3(60) + 6(30)

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Problem 003­mm | Method of Members | Engineering Mechanics Review

Ax = 180  kN

 

  ΣMA = 0 2D x = 3(60) + 6(30) D x = 180  kN

  From the FBD of member ABC ΣFx = 0 3 5 3 5

FC F = Ax FC F = 180

FC F = 300  kN

 

  ΣMB = 0 3Ay = 1.5(

4 5

FC F )

3Ay = 1.2(300) Ay = 120  kN

  From FBD of the whole system ΣFV = 0 D y = Ay + 60 + 30

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=

y

+ 60 + 30

Problem 003­mm | Method of Members | Engineering Mechanics Review

D y = 120 + 60 + 30 D y = 210  kN

  Summary Ax = 180  kN leftward Ay = 120  kN downward D x = 180  kN rightward D y = 210  kN upward FC F = 300  kN tension

  Tags: reaction at the support support reaction three­force member non­axial member axial member cantilever frame ‹ Problem 002­mm | Method of Members

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