Preguntas y Respuestas Capitulo 2 Barry Brey

February 14, 2019 | Author: Gabriel Orosco | Category: Microprocessor, Operating System Technology, Computer Memory, Computer Architecture, X86 Architecture
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Preguntas y Respuestas Capitulo 2 Barry Brey...

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1. What are are programprogram-visi visible ble regis registers? ters? Program visible register are the registers that are directly used in an instruction. Que son los registradores visibles para el programa?  Los registros visibles del programa son los registros que se utilizan directamente en una instrucción. 2. The 80286 80286 addresses addresses regis registers ters that that are 8 and and 16 bits wide. El 80286 direiona registradores !ue son de 8 " de 16  16  bits de ancho. #. The e$tende e$tended d registers registers are address addressable able b" whih whih miroproessors?  The 8086 through the the !ore". !ore". %uales miroproesadores pueden direionar los registradores e$tendidos? #l 8086 a trav$s del !ore". &. The e$tend e$tended ed '( registe registerr is addresse addressed d as #%& . El registrador e$tendido '( se direiona omo #%& . ). Whih Whih register register holds holds a ount *or some some instrut instrutions? ions? !L' !&' !(' #!&' or )!&. %ual registrador guarda la uenta para algunas instruiones? !L' !&' !(' #!& o )!&. 6. What is is the purpose purpose o* the the +,E+, +,E+, register register? ? (olds the o*set address o+ the ne,t step in the program. %ul es el prop/sito del registrador +,E+,? -ostiene la dirección de desplazamiento del siguiente paso en el programa. . The arr" arr" ag bit is not not modied modied b" whih whih arithmet arithmeti i operations? /! and #!. %uales son las operaiones aritm3tias !ue no modian el bit de bandera de aarreo? /! y #!. 8. Will an overow overow our our i* a signed signed 445 is added added to a signed signed 015? /o' i+ you add 1 and 21 you have zero' 3hich is a valid number. urrir7a un desbordamiento si se suma un 445 on signo a un 015 on signo? /o' si se agrega 1 y 41 se tiene cero' que es un n5mero vlido. . 9 number number that ontain ontains s # one bits bits is said said to have have odd parit". :e die !ue un numero !ue ontiene # bits uno tiene peridad impar . 10. Whih a ag bi bit o ontrols th the +; +;T< pi pin on on th the miroproessor?  The 47ag. %ual bit de bandera ontrola la terminal +;T< en el miroproesador? La bandera . 11. Whi Whih mir mirop opro roe ess ssor ors s on onta tain in an 4: seg segm ment ent re regis gister? ter?  The 8086 8086 through through the !ore". !ore". %uales miroproesadores ontienen un registrador de segmento 4:? #l 8086 a trav$s del !ore". 12. What What is the the pu purp rpos ose e o* o* a segme egmen nt reg regis iste terr in in the the rea reall mode operation o* the miroproessor?  The segment register addresses the lo3est address in a 69 memory segment. %ual es el proposito de un registrador de segmento en la operai/n en modo real del miroproesador? #l registrador de segmento se direcciona a la dirección ms ba:a en un segmento de memoria de 69.

1#. +n the real mode= show the starting and ending addresses o* eah segment loated b" the *ollowing segment register values> a@ 10005 10000(;1 a@C: B 20005 and E9( B 0000#0005 "000( b@C: B 19005 and E%( B 000020005 1!000( @ C: B %0005 and E:+ B 000090005 !=000( d@:: B 80005 and E:, B 00000005 8@000( e@C: B 12#5 and EC( B 00009005 1!!@0( Cetermine la posii/n de memoria !ue se direiona mediante las siguientes ombinaiones de registradores del %ore2 en modo real> a@C: B 20005 and E9( B 0000#0005 "000( b@C: B 19005 and E%( B 000020005 1!000( @ C: B %0005 and E:+ B 000090005 !=000( d@:: B 80005 and E:, B 00000005 8@000( e@C: B 12#5 and EC( B 00009005 1!!@0( 22. ,roteted mode memor" addressing allows aess to whih area o* the memor" in the 80286 miroproessor? =ll 16A bytes. 9 ual rea de la memoria permite el aeso el direionamiento de memoria en modo protegido en el miroproesador 80286? = todos los 16A bytes. 2#. ,roteted mode memor" addressing allows aess to whih area o* the memor" in the ,entium & miroproessor? =ny location in the memory system. 9 ual rea de la memoria permite el aeso el direionamiento de memoria en modo protegido en el

miroproesador ,entium &? !ualquier rea en el sistema de memoria. 2&. What is the purpose o* the segment register in proteted mode memor" addressing?  The segment register is a selector that selects the descriptor +rom a descriptor table. t also sets privilege level o+ the request and chooses either the global or local table. %ual es el proposito del registrador de segmento en un direionamiento de memoria en modo protegido? #l registrador de segmentos es un selector que selecciona el descriptor de una tabla de descriptor. Tambi$n establece el nivel de privilegio de la solicitud y elige la tabla global o local. 2). 5ow man" desriptors are aessible in the global desriptor table in the proteted mode? 8'1@". %uantos desriptores son aesibles en la tabla de desriptores globales en modo protegido? 8'1@". 26. 4or an 80286 desriptor that ontains a base address o* 9000005 and a limit o* 10005= what starting and ending loations are addressed b" this desriptor? =00000(2 =01000(. %uales son las posiiones iniial " nal !ue se direionan sobre la base deun desriptor del 80286 !ue ontiene un direi/n base de 9000005 " un l7mite de 10005? =00000(2 =01000(. 2. 4or a %ore2 desriptor that ontains a base address o* 010000005= a limit o* 044445= and H B 0= what starting and ending loations are addressed b" this desriptor? 01000000( ;0100
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