Practica 8 Preparacion-Y-Estandarizacion-De-Soluciones-Acuosas

July 12, 2022 | Author: Anonymous | Category: N/A
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Z\DE^CHD H²:6 Z\AZD\DECKH S AU^DHND\CRDECKH NA UKGQECKHAU DEQKUDU 4.-@AHA\DGCNDNAU2

Gds tctugdeckhas vkgumãtrceds as uh mãtknk dhdgítcek qua ekhscsta ah d`ra`dr uh vkgumah na uhd skguecõh astdhndrczdnd (ekheahtrdecõh ekhkecnd) d uhd skguecõh nasekhkecnd pdrd natarmchdr su ekheahtrdecõh. Gdss tctu Gd tctugd gdec eck khas has vkgu gumã mãtr trce ceds ds sa`ò sa`òh h gd ra rad dee eecõ cõh h químc uímced ed puan puanah ah sar na hautrdgczdecõh, praecpctdecõh kxcnk ranueecõh y ekmpgaxkmãtrced. Gds tctugdeckhas vkgumãtrceds na hautrdgczdecõh tcahah gu`dr eudhnk sa radgczd uhd radeecõh químced na hautrdgczdecõh ahtra äecnk y uhd ldsa. Ag tctugdhta as uhd skguecõh vdgkrdnd y ag tctugdnk as gd skguecõh prklgamd, sc ag tctugdhta as uh äecnk ag klbatk as natarmchdr gd edhtcndn na ldsa na uhd muastrd. Zdrd pkna Zdrd pknarr ra radg dgcz czdr dr uhd uhd na nata tarm rmch chde decõ cõh h eudh eudhtctctd tdtctcvd vd ma manc ncdh dhta ta uh uhd d tctug tctugde decõ cõh h vkgumãtrced prcmardmahta sa tcaha qua prapdrdr gd skguecõh vdgkrdnd (tctugdhta), pdrd gk eudg sa tkmd ekmk ldsa gks ndtks aspaeíiceks nag radetcvk purk, gua`k sa prkeana d tkmd ekmk ldsa gks ndtks aspaeíiceks nag radetcvk purk, y gua`k sa prkeana d astd as tdhn hndr drcz czdr dr ampg ampgad adhn hnk k uh pd pdtr trõh õh pr prcm cmdr drck ck k sa saeeuh uhnd ndrc rck k pd pdrd rd va varc rciciced edrr su ekheahtrdecõh varndnard. Gd prasahta präetced tcaha pkr ichdgcndn na ahsaôdr y dncastrdr dg astuncdhta d prap prapdr drdr dr y as astd tdhn hndr drcz czdr dr,, pd pdrd rd dsí dsí ta taha harr gd ldsa ldsa su suice iceca caht hta a pd pdrd rd gd gdss sc sc`u `uca caht htas as präetceds na vkgumatríd. Zdrd aiaetk na gks g ks eägeugks vkgumãtrceks gds ekheahtrdeckhas na gks skgutks sa ldsdh ah nks pdras na aeudeckhas scmpgas narcvdnds na gds naichceckhas na mcgcmkg, mkg y ekheahtrdecõh mkgdr, as dsí qua pdrd uhd aspaeca químced D, sa asercla2  

Edhtcndn Edht cndn na D ( mkg )=

Mdsd Mdsd na D ( ` )

 Mksdmkgdr  Mksd mkgdr na D

Edhtcndn Edht cndn na D ( mmkg ) =

 

( )  ` mkg

Mdsd Mdsd na D ( m`)

  m`  Mksd mcgcmkgdr na D mmkg

(

)

 

Na gd naichcecõh na ekheahtrdecõh mkgdr sa narcvd gds sc`ucahtas nks aeudeckhas, qua skh2 Edhtcndn na D (mkg)=vkgumah (G)*ekheahtrdecõh na D (mkg/G) Edhtcndn na D (mmkg)=vkgumah (mG)*ekheahtrdecõh na D (mmkg/mg). 3.:> ` F purk / gt x 4 mg / 4.6> ` = 1, purazd
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