PPU 960 Physics Note [Sem 2 Chapter 14 - Electric Current]

February 16, 2017 | Author: Josh, LRT | Category: N/A
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Cha ter 1  – Electri c C rrent

Chapter 14 – Electric Current  14.1

Conduction of electricity

Consider a simple closed circuit consists of wires, a battery and a light bulb as shown in Figure A.

Figure A

From the Figure A, 

Direction of electric field,



Direction of electron,

 or current, : Positive to negative terminal

 flows: Negative to positive terminal The electron accelerates  becaus  bec ausee of the electric force acted on it. It is defined as the total nett charge,  flowing through the flowing through the area per unit time, .         SI unit for         

1 ampere of current is defined as one coulomb of charge passing through the surface area in one second.

14.2

Current density

It is defined as the current flowing through a conductor per unit cross-sectional area .

    It is a vector quantity  Unit = The direction of 

 

      is the same with the direction of the .

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Page 1 of 7

Cha ter 1  – Electri c C rrent

From,

        ( ) 

         

Electrical conductivity,

SI unit for  14.3

 is 

 is the measure of a material’s ability to conduct electric current.    

Drift velocity

The drift velocity is the average velocity that a particle, such as an electron, attains due to an electric field. When the electric field is applied to the metal , the freely moving electron experience an electric force and tend to drift with constant average velocity (called drift velocity) towards a direction opposite to the direction of the field as shown in  Figure  Figu re B .

Figure B **1 The magnitude of the drift velocity is smaller than the random velocities of the free electrons .

**2 The electric current is flowing in the opposite direction of the electron flows .

Drift velocity of charges,



L = length of metal rod

cross-sectional tional area A = cross-sec J = current density e = electron

lectri ric c file fil ed E = E lect I = current

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Page 2 of 7

Cha ter 1  – Electri c C rrent

ê

ê

ê

ê

 number of free electrons per volume in metal rod.  the number of free electron,  is given by:                The total charge  of the free electrons that pass pas s through the area   along the rod is  Q  Time,  required for electron move along the rod is              Then,       t               electron ] : number of free electron per unit volume [DENSITY of free electron] : charge of the electron Set,

14.4 ê

Resistivity and Ohm’s law

Resistance, R  di fferencee across an electrical component to the current passing Ratio of the potential differenc through it.

  

# It is a measure of the component’s opposition to the flow of the electric charge . # Scalar quantity with unit →

ê

 or  



Resistivity, The resistance of a unit cross-sectional area per unit length of the material .

  

# It is a measure of  material’s ability to oppose the flow of an electric current . # Scalar quantity with unit → # Known as specific resistance # high gh resi resist stiivity] # Good conductors [low resistivity] ; Good insulator [hi

 

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Page 3 of 7

Cha ter 1  – Electri c C rrent

ê



Conductivity, The reciprocal of the resistivity of a material .

  

# Scalar quantity with unit →

ê

 

Ohm’s Law States that the potential difference across a metallic conductor is proportional to the current flowing through it if its temperature is constant.

It can be stated in other form,

 

  

 is maintained across the conductor sets up by an electric field,  and this field produce a current,  that is proportiona proportionall to the potential difference . If the field is assumed to be uniform,    From ohm’s law,  … where  and        ( ) 

 

or 

   

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and



Page 4 of 7

Cha ter 1  – Electri c C rrent

Graphs of potential of  potential difference,

14.5

 against current,  for various materials.

METAL

SEMICONDUCTOR 

CARBON

ELECTROLYTE

Dependence of resistivity on temperature

Metal  T) = , Number of electrons per unit volume ( n) = UNCHANGED. o Temperature ( T o Metal atoms in the crystal lattice vibrate with greater amplitude and cause the number of  collisions between the free electrons and metal atoms increases. Hence the resistance in the metal increases .



Superconductor T) = o Temperature (  T

ê

    The resistance decreases to 0. 

Temperature coefficient of resistivity, Fractional increase in resistivity of a conductor per unit rise in temperat temperature ure

                    2013 © LRT Documents Copyrighted. All rights reserved.

Page 5 of 7

Cha ter 1  – Electri c C rrent

Since,



          

The resistivity of a conductor varies approximatel y linearly with temperature

 →  or  Thus,                       

# Unit for 

Graphs of resistance, of  resistance,

 against temperature,  for various materials.

METAL

SEMICONDUCTOR 

SUPERCONDUCTOR

CARBON

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Page 6 of 7

Cha ter 1  – Electri c C rrent Problems  1.

Resistivity of a wire depends on A. B. C. D.

2.

Length Material Cross-section area Electrons

 

A silver wire carries a current of  . Determine a) The numbers of electrons per second pass through the wire.  b) The amount of charge flows through a cross-sectional area of the wire in 55 s. 9 ) (Given charge of electron,

 

3.



4.

 

 

A high voltage transmission line with a diameter of  and a length of  carries a steady current of  . If the conductor is copper wire with a free charge density of  8 electrons , calculate the time taken by one electron to travel the full length of the line. 9 ) (



 



 

  long and has a

When a potential difference of 240 V is applied across a wire that is 9 . radius, the current density is Calculate Answers: a) The resistivity of the wire.  b) The conductivity of the wire. 1. B

 

 

2.

a)

9 

 b) 165 C 5.

   

A copper wire carries a current of  . The cross section of the wire is a square of side and its length is . 8 The density ofthe free electron in the wire is . Determine a) The current density  b) The drift velocity of the electrons c) The electric field intensity between both end of the wire d) The potential difference across the wire e) The resistance of the wire



(Given the resistivity of copper is

9 )

  

8 and

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3. 4.

8 s a)  8   b)  7   a) 6 A  b) 4   c)    d)   e)  Ω

Ω

5.

Ω

charge of electron,

 Page 7 of 7

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