Pham Thuy Dung - EBBA 10.2 - 11181050. Problem 1 Given The Following Activities and Precedences, Draw An AOA or AON Diagram

 

CHAPTER 8 - PROJECT SCHEDULING  ASSIG  ASSIGNMENT NMENT Pham Thuy Dung - EBBA 10.2 – 11181050.

Problem 1 Given the following activities and precedences, draw an AOA or AON diagram:

Answer 

 AON diagram: diagram:

Problem 2 Given the following network,

 

a. What What is th the e criti critica call path path? ? b. How long long will will it take take to comple complete te this this project project? ? c. Can activity activity B be delayed without delaying the completion completion of the project? project? If so, so, how many days? Answer  a. Po Poss ssiible ble pa path ths s  A-D-G = 8 + 7 + 5 = 20  A-C-E-G = 8 + 3 + 6 + 5 = 22  A-C-F-H = 8 + 3 + 7 + 3 = 21 B-E-G = 10 + 6 + 5 = 21 B-F-H = 10 + 7 + 3 = 20

Critical path is path with longest duration, here longest duration is of path A-C-E-G with duration 22 days. Therefore the critical path is A-C-E-G.

b. Proj Project ect dura duration tion iis s the len length gth of tthe he crit critical ical pat path h whic which h is 22 day days. s.

c. Acti Activity vity B iis s not on th the e criti critical cal and c can an be dela delayed yed wit without hout del delaying aying tthe he project. Longest path containing activity B is B-E-G with duration 21. Hence activity B can be delayed 22 - 21 days = 1 day Do give a positive rating if you think this answer helped. Problem Given the3estimated activity times below and the network in Problem 2 above  Activity a

m

b

7.5 10.5 3.5 7.5 5.5

14.5 12.5 4.5 8.5 9.5

 A B C D E

6.5 8.5 2.5 6.5 5.5

F G

5.5 7.5 4.5 6.5

9.5 8.5

H

2.5 3.5

3.5

 

What is the critical path probability that the project will be completed within: (a) 21 days? (b) 22 days? (c) 25 days? Answer  Activity

a

m

b

te=(a+4m+b)/6

SD= (b-a)/6

Var= SD^2

 A

6.5

7.5

14.5

8.500

1.333

1.778

B

8.5

10.5

12.5

10.500

0.667

0.444

C

2.5

3.5

4.5

3.500

0.333

0.111

D

6.5

7.5

8.5

7.500

0.333

0.111

E

5.5

5.5

9.5

6167

0.667

0.444

F

5.5

7.5

9.5

7.500

0.667

0.444

G

4.5

6.5

8.5

6.500

0.667

0.444

H

2.5

3.5

3.5

3.333

0.167

0.028

Activit te=(a+4m+b) Predecesso y  /6 rs

 A

8.500

B

10.500

 

 

Successo rs

ES

EF

LS

LF

Slac k



C,D

0.00

8.50

0.00

8.50

0.00



E,F

0.00

10.5

1.50

12.0

1.50

0

0

C

3.500

A

E,F

8.50

12 12.0 0

8.50

12.0 0

0.00

D

7.500

A

G

8.50

16.0 0

10.6 7

18.1 7

2.17

E

6167

B,C

G

12.0 0

18.1 7

12.0 0

18.1 7

0.00

F

7.500

B,C

H

12.0 0

19.5 0

13.8 3

21.3 3

1.83

 

G

6.500

D,E

H

3.333

F

 

 





18.1 7

24.6 7

18.1 7

24.6 7

0.00

19.5 0

22.8 3

21.3 3

24.6 7

1.83

Base on zero slack, the critical path is A-C-E-G a. p( p(x x