Peterson Coil

PETERSON COIL

Name

: R.A.S.C. Ranathunga

Course

: IESL

Group

:G4

Field

: Electrical

Instructed by

: Mr. Pathirawasa

Date of performance: 12/02/2012

CALCULATIONS: For Resistive Inductance, VL = IL. (r+JwL) | |=√

i.e. L =

√| |

Specimen Calculation: VL = 20.5 v √|

L=

IL = 0.35A |

L = 0.18632 H L = 186.32 mH

Theoretical Calculations:

L= C = 40.8µF

ω =2πf =2 * π *50

L = 0.082778 H L = 82.778 mH

r = 2.8Ω

TABULATIONS:

Fault Current (If) mA 460 440 420 400 380 360 340 320 300 280 260 260 280 300 320 340 360 380 400 420 440 460 480 500 520

Inductance of Coil (L) mH 186.3199 167.3791 158.9858 141.2616 132.3964 127.076 122.164 109.4551 104.0354 93.24262 84.45624 71.82845 65.0559 63.06697 60.59184 57.90411 55.7476 54.7264 53.26033 52.32415 50.97755 50.11606 48.87472 47.69061 46.93105

Fault Current Vs Inductance of Coil

Fault Current (mA)

550 540 530 520 510 500 490 480 470 460 450 440 430 420 410 400 390 380 370 360 350 340 330 320 310 300 290 280 270 260 255mA250 240 230 220 210 200 190 180 170 160 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 0

77mH

0

10

20

30

40

50

60

70

80

90 100 110 120 130 140 150 160 170 180 190 200

Inductance of Coil (mH)

RESULTS :

Value of Inductance for minimum fault current

From the graph = 77 mH

Theoretical Value = 82.778 mH

DISCUSSION: