P Block Question Bank 458

July 29, 2017 | Author: dev1996 | Category: Silicate, Nitric Acid, Boron, Chlorine, Hydrogen
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Reconstruct Your Chemistry With Prince Sir



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Question Bank

Reconstruct Your Chemistry With Prince Sir P-BLOCK ELEMENTS ONLY ONE OPTION IS CORRECT Q.1


Which is incorrectly matched? (A) CsBr3 l Cs+ + Br3

(B) I4O9 l I3+ + (IO3 )3

(C) AgBrO3 l Ag+ + BrO3

(D) I2O4 l IO2 + IO2


220°C 32 0° C

(X) 320°C (Y)

(A) (X) = Phosphorous acid , (Y) = Metaphosphoric acid (B) (X) = Pyrophosphoric acid , (Y) = Metaphosphoric acid (C) (X) = Metaphosphoric acid , (Y) = Pyrophosphoric acid (D) (X) = Metaphosphoric acid , (Y) = Phosphene gas Q.3



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 H3PO3  (X) + PH3 ; is (A) Dehydration reaction (C) Disproportionation reaction

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(B) Oxidation reaction (D) Dephosphorelation reaction

Which of the following species is not a pseudohalide? (A) CNO–


(C) OCN–

(D) N 3


An orange solid (X) on heating, gives a colourless gas (Y) and a only green residue (Z). Gas (Y) on treatement with Mg, produces a white solid substance ................. (A) Mg3N2 (B) MgO (C) Mg2O3 (D) MgCl2


Conc. HNO3 is yellow coloured liquid due to (A) dissolution of NO in conc. HNO3 (B) dissolution of NO2 in conc. HNO3 (C) dissolution of N2O in conc. HNO3 (D) dissolution of N2O3 in conc. HNO3


A gas at low temperature does not react with the most of compounds. It is almost inert and is used to create inert atmosphere in bulbs. The combustion of this gas is exceptionally an endothermic reaction. Based on the given information, we can conclude that the gas is (A) oxygen (B) nitrogen (C) carbon mono-oxide (D) hydrogen


When chlorine gas is passed through an aqueous solution of a potassium halide in the presence of chloroform, a voilet colouration is obtained. On passing more of chlorine water, the voilet colour is disappeared and solution becomes colourless. This test confirms the presence of ........... in aqueous solution. (A) chlorine (B) fluorine (C) bromine (D) iodine


When PH3 absorbed in HgCl2 solution the corresponding phosphide is obtained

Reconstruct Your Chemistry With Prince Sir (A) Hg2P3

(B) Hg3P2

(C) Hg3(PO4)2

(D) None of these


An explosive compound (A) reacts with water to produce NH4OH and HOCl. Then, the compound (A), is (A) TNG (B) NCl3 (C) PCl3 (D) HNO3


An inorganic salt (A) is decomposed at about 523 K to give products (B) and (C). Compound (C) is a liquid at room temperature and is neutral to litmus paper while oxide (B) on burning with white phosphorous, given a dehydrating agent (D). Compounds (A), (B), (C) and (D) will be identified as (A) NH4NO3, N2O, H2O, P2O5 (B) NH4NO2, K2O, H2O, P2O5 (C) CaCO3 , CaO, H2O, CaCl2 (D) CaCO3 , CaO, H2O, Ca(OH)2


An inorganic compound (A) made of two most occuring elements into the earth crust, having a polymeric tetra-headral network structure. With carbon, compound (A) produces a poisonous gas (B) which is the most stable diatomic molecule. Compounds (A) and (B) will be (A) SiO2’ CO2 (B) SiO2’ CO (C) SiC,CO (D) SiO2’ N2


A sulphate of a metal (A) on heating evolves two gases (B) and (C) and an oxide (D). Gas (B) turns K2Cr2O7 paper green while gas (C) forms a trimer in which there is no S–S bond. Compound (D) with HCI, forms a Lewis base (E) which exists as a dimer. Compounds (A), (B), (C), (D) and (E) are respectively (A) FeSO4, SO2, SO3, Fe2O3, FeCl3 (B) Al2(SO4)3, SO2, SO3, Al2O3, FeCl3 (C) FeS, SO2, SO3, FeSO4, FeCl3 (D) FeS, SO2, SO3 , Fe2(PO4)3, FeCl2


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A tetra-atomic molecule (A) on reaction with nitrogen(I)oxide, produces two substances (B) and (C). (B) is a dehydrating agent in its monomeric form while substance (C) is a diatomic gas which shows almost inert behaviour. The substances (A) and (B) and (C) respectively will be (A) P4, P4O10, N2 (B) P4, N2O5’ N2 (C) P4, P2O3, Ar (D) P4, P2O3, H2


First compound of inert gases was prepared by scientist Neil Barthlete in 1962. This compound is (A) XePtF6 (B) XeO3 (C) XeF6 (D) XeOF4


Carbongene has X% of CO2 and is used as an antidote for poisoning of Y . Then, X and Y are (A) X = 95% and Y = lead poisoning (B) X = 5% and Y = CO poisoning (C) X = 30% and Y = CO2 poisoning (D) X = 45% and Y = CO poisoning


The correct order of acidic strength of oxides of nitrogen is (A) NO < NO2 < N2O < N2O3 < N2O5 (B) N2O < NO < N2O3 < N2O4 < N2O5 (C) NO < N2O < N2O3 < N2O5 < N2O4 (D) NO < N2O < N2O5 < N2O3 < N2O4


Nitrogen dioxide is dissolved in water to produce (A) HNO3 and HNO2 (B) only HNO3 and N2


(C) only HNO2

Consider two reactions I. Zn + conc. HNO3 (hot)  Zn(NO3)2 + X + H2O

(D) HNO 2

Reconstruct Your Chemistry With Prince Sir

II. Zn + dil. HNO3 (cold)  Zn(NO3)2 + Y + H2O Compounds X and Y are respectively (A) N2O, NO (B) NO2, N2O (C) N2, N2O Q.20



T1 hot 2 H3BO3  X T Y red   B2O3 if T1 < T2 then X and Y respectively are (A) X = Metaboric acid and Y = Tetraboric acid acid (C) X = Borax and Y = Metaboric acid

(D) NO2, NO

(B) X = Tetraboric acid and Y = Metaboric (D) X = Tetraboric acid and Y = Borax

Boron forms BX3 type of halides. The correct increasing order of Lewis-acid strength of these halides is (A) BF3 > BCl3 > BBr3 > BI3 (B) BI3 > BBr3 > BCl3 > BF3 (C) BF3 > BI3 > BCl3 > BBr3 (D) BF3 > BCl3 > BI3 > BBr3 Which one of the following compounds on strong heating evolves ammonia gas? (A) (NH4)2SO4 (B) HNO3 (C) (NH4)2Cr2O7 (D) NH3NO3

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The compound (SiH3)3N is (A) pyramidal and more basic than (CH3)3N (B) planar and less basic than (CH3)3N (C) pyramidal and less basic than (CH3)3N (D) planar and more basic than (CH3)3N


The correct order of acidic strength of oxy-acids of chlorine is (A) HCIO < HCIO2 < HCIO3 < HCIO4 (B) HCIO4 < HCIO3 < HCIO2 < HCIO (C) HCIO > HCIO4 > HCIO3 > HCIO2 (D) HCIO4 < HCIO2 > HCIO3 > HCIO


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In a molecule of phosphorus (V)oxide, there are (A) 4P–P, 10P–O and 4P=O bonds (B) 12P–O and 4P=O bonds (C) 2P–O and 4P=P bonds (D) 6P–P, 12P–O and 4P=P bonds


The structures of O3 and N3– are (A) linear and bent, respectively (C) both bent



(B) both linear (D) bent and linear, respectively

When conc. H2SO4 was treated with K4[Fe(CN )6], CO gas was evolved. By mistake, somebody used dilute H2SO4 instead of conc. H2SO4 then the gas evolved was (A) CO (B) HCN (C) N2 (D) CO2 A ( organic Compound )

 O 2  X  Y  Z

Compound (A) in pure form does not give ppt. with AgNO3 solution. A mixture cootaining 70% of (A) and 30% of ether is used as an anaesthetic. Compound (X) and (Y) are oxides while (Z) is a pungent smelling gas. (X) is a neutral oxide which turns cobalt chloride paper pink. Compound (Y) turns lime water milky and produces an acidic solution with water. Compounds (A), (X), (y) and (Z) respectively will be (A) CH4, H2O, CO2’ Cl2 (B) CHCl3 , H2O, CO2, Cl2

Reconstruct Your Chemistry With Prince Sir (C) CH3OH, H2O, CO2, N2 Q.29




(D) NH2CONH2, H2O, N2O, CO2

An inorganic white crystalline compound (A) has a rock salt structure. (A) on reaction with conc. H2SO4 and MnO2, evolves a pungent smelling, greenish-yellow gas (B). Compound (A) gives white ppt. of (C) with AgNO3 solution. Compounds (A), (B) and (C) will be respectively (A) NaCl, Cl2, AgCl (B) NaBr, Br2, NaBr (C) NaCl, Cl2, Ag2SO4 (D) NazCO3 , CO2, Ag2CO3 cu  powder

condensation  R SiCl H 2O RCl      R2Si(OH)2    A 2 2 Si Compound (A) is (A) a linear silicone (B) a chlorosilane (C) a linear silane (D) a network silane

When oxalic acid reacts with conc. H2SO4 , two gases produced are of neutral and acidic in nature respectively. Potassium hydroxide absorbs one of the two gases. The product formed during this absorption and the gas which gets absorbed are respectively (A) K2CO3 and CO2 (B) KHCO3 and CO2 (C) K2CO3 and CO (D) KHCO3 and CO Concentrated HNO3 reacts with iodine to give (A) HI (B) HOI (C) HOIO2 (D) HOIO3


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Conc. H2SO4 cannot be used to prepare HBr from NaBr because it (A) reacts slowly with NaBr (B) oxidises HBr (C) reduces HBr (D) disproportionates HBr




COOH Compound (X) is (A) malonic acid

P4O10 , 150C    X

(B) carbon suboxide (C) tartaric acid


Molecular shapes of SF4, CF4 and XeF4 are (A) the same, with 2, 0 and 1 lone pairs of electrons respectively (B) the same, with 2, 0 and 1 lone pairs of electrons respectively (C) the different, with 0, 1 and 2 lone pairs of electrons respectively (D) the different, with 1, 0 and 2 lone pairs of electrons respectively


Match List-I with List-II List-I Chemical reaction

(D) acetic acid

List-II Name of process

800C / Pt


4NH3 + 5O2   4NO + 6H2O



Contact process

 2  2Cl + 2H O 4HCl + O2 450 2 2 500 / V O


Ostwald's process

2SO2 + O2  2SO3

Deacon's process

3230C / CuCl

2 5



IV. 2N2 + 3H2    2NH3 (A) I-a, II-b, III-d, IV-c


(d) Haber's proces (B) I-b, II-c, III-a, IV-d

Reconstruct Your Chemistry With Prince Sir Q.37

(C) I-a, II-d, III-c, IV-b

(D) I-a, II-c, III-b, IV-d

Ammonia can be dried by (A) conc. H2SO4 (B) P4O10

(C) CaO

(D) anhydrous CaCl2


When chlorine reacts with a gas X, an explosive inorganic compound Y is formed. Then X and Y will be (A) X = O2 and Y = NCl3 (B) X = NH3 and Y=NCl3 (C) X = O2 and Y = NH4Cl (D) X = NH3 and Y = NH4Cl


The solubility of anhydrous AlCl3 and hydrous AlCl3 in diethyl ether are S1 and S2 respectively. Then (A) S1 = S2 (B) S1 > S2 (C) S1 < S2 (D) S1 < S1 but not S1 = S2


Which one of the following statements is not true regarding diborane? (A) It has two bridging hydrogens and four perpendicular to the rest. (B) When methylated, the product is Me4B2H2. (C) The bridging hydrogens are in a plane perpendicular to the rest. (D) All the B–H bond distances are equal.


When AgNO3 is heated strongly, the products formed are (A) NO and NO2 (B) NO2 and O2 (C) NO2 and N2O

(D) NO and O2

HNO3 + P4O10  HPO3 + A ; the product A is (A) N2O (B) N2O3 (C) NO2

(D) N2O5






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Which of the following is the correct order of acidic strength? (A) Cl2O7 > SO2 > P4O10 (B) CO2 > N2O5 > SO3 (C) Na2O > MgO > Al2O3 (D) K2O > CaO > MgO 2 Ca + C2 CaC2 N A Compound (A) is used as a/an (A) fertilizer (B) dehydrating agent (C) oxidising agent

(D) reducing agent

A gas which exists in three allotropic forms ,  and  is (A) SO2 (B) SO3 (C) CO2

(D) NH3


A red coloured mixed oxide (X) on treatment with conc. HNO3 gives a compound (Y). (Y) with HCl , produces a chloride compound (Z) which can also be produced by treating (X) with conc. HCl. Compounds (X) , (Y), and (Z) will be (A) Mn3O4, MnO2, MnCl2 (B) Pb3O4, PbO2, PbCl2 (C) Fe3O4, Fe2O3, FeCl2 (D) Fe3O4, Fe2O3, FeCl3


There is no S–S bond in (A) S2O42– (B) S2O52–


(C) S2O32–

(D) S2O72–

One mole of calcium phosphide on reaction with excess of water gives

Reconstruct Your Chemistry With Prince Sir (A) one mole of phosphine (C) two moles of phosphine Q.49


(B) two moles of phosphoric acid (D) one mole of phosphorus penta-oxide

C C NaH2PO4 230   Na3(P3O9) 638   (D) Compound (D) contains 200 (PO4) units (A) Bunsen’s salt (B) Graham’s salt (C) Reimann’s salt

(D) Werner’s salt

Three allotropes (A), (B) and (C) of phoiphorous in the following change are respectively A

513 K 1200 atm


823 K In an inert atm. and then rapid cooling to room temp.


(A) white, black, red (B) black, white, red (C) red, black, white (D) red, violet, black Q.51

When an inorganic compound reacts with SO2 in aqueous medium, produces (A). (A) on reaction with Na2CO3, gives compound (B) which with sulphur, gives a substance (C) used in photography. Compound (C) is (A) Na2S (B) Na2S2O7 (C) Na2SO4 (D) Na2S2O3


Borax is actually made of two tetrahedra and two triangular units joined together and should be written as: Na2[B4O5(OH)4]·8H2O Consider the following statements about borax: (a) Each boron atom has four B–O bonds (b) Each boron atom has three B–O bonds (c) Two boron atoms have four B–O bonds while other two have three B–O bonds (d) Each boron atom has one –OH groups Select correct statement(s): (A) a, b (B) b, c (C) c, d (D) a, c


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GO COMPREHENSIVE Question No. 53 to 55 (3 questions) Read the following short write-up and answer the questions at the end of it The name 'silica' covers an entire group of minerals, which have the general formula SiO2, the most common of which is quartz. Quartz is a framework silicate with SiO4 tetrahedra arranged in spirals. The spirals can turn in a clockwise or anticlockwise direction – a feature that results in there being two mirror images, optically active, varieties of quartz. The following pictures represent various silicate anions. Their formulae are respectively:

(A) SiO 32

Si 3O 72

(C) SiO 24

Si 3O92

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8 Si 3O10

Si 3O87

Si 3O96 (having three tetrahedral) is represented as:

By (A)

(C) both


(B) SiO 44

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(D) none

The silicate anion in the mineral kinoite is a chain of three SiO4 tetrahedra that share corners with adjacent tetrahedra. The mineral also contains Ca2+ ions, Cu2+ ions, and water molecules in a 1:1:1 ratio mineral is represented as: (A) CaCuSi3O10·H2O (B) CaCuSi3O10·2H2O (C) Ca2Cu2Si3O10·2H2O (D) none of these Question No. 56 to 57 (2 questions) Questions given below are based on electronic configurations of the elements. The three elements X, Y and Z with the electronic configurations shown below all form hydrides: Element Electronic configuration X 1s2, 2s2, 2p2 2 Y 1s , 2s2, 2p6, 3s1 Z 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s2, 4p5


Which line of properties (A, B, C, or D) correctly lists properties of the hydrides of these elements?

Reconstruct Your Chemistry With Prince Sir (A)

(B) (C)



Hydride of X Colourless gas insoluble in H2O Colourless liquid, no reaction with H2O Colourless gas found naturally Non-polar compound reacts with Cl2 in light

Hydride of Y Silver/grey solid, reacts with H2O to form an alkaline solution Silver/grey solid, forms H2 O Does not conduct electricity in the molten state Silver/grey ionic solid with formula YH2

Which of the following exists as gas? (A) X2 (B) Y2

Hydride of Z Colourless gas form a strong acid in H2O Ionic solid with formula ZH Colourless gas, reacts with Cl2 Forms when water is added to phosphorus and element Z

(C) Z2

(D) all of the above

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Question No. 58 to 59 (2 questions) Read the following write-ups and answer the questions at the end of it. Silicons are synthetic polymers containing repreated R2SiO units. Since, the empirical formula is that of a ketone (R2CO), the name silicone has been given to these materials. Silicones can be made into oils, rubbery elastomers and resins. They find a variety of applications because of their chemical inertness, water repelling nature, heat-resistance and good electrical insulating property. Commercial silicon polymers are usually methyl derivatives and to a lesser extent phenyl derivatives and are synthesised by the hydrolysis of R2SiCl2[R=methyl (Me) or phenyl ()]

B Q.58


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Me Me Me | | | H 2O Me2SiCl 2   O  Si  O  Si  O  Si  O  | | | Me Me Me

If we mix Me3SiCl with Me2SiCl2, we get silicones of the type:

Me Me Me Me | | | | (A) Me  Si  O  Si  O  Si  O  Si  Me | | | | Me Me Me Me

Me Me | |  O  Si  O  Si  O  | | (B) O O | |  O  Si  O  Si  O  | | Me Me

(C) both of the above

(D) none of the above

If we start with MeSiCl3 as the starting material, silicones formed is:

Reconstruct Your Chemistry With Prince Sir Me Me Me Me | | | | (A) Me  Si  O  Si  O  Si  O  Si  Me | | | | Me Me Me Me

(C) Both of the above Q.60

The molecular shapes of diborane is shown: Consider the following statements for diborane: 1. Boron is approximately sp3 hybridised 2. B–H–B angle is 180° 3. There are two terminal B–H bonds for each boron atom 4. There are only 12 bonding electrons available Of these statements: (A) 1, 3 and 4 are correct (B) 1, 2 and 3 are correct (C) 2, 3 and 4 are correct (D) 1, 2 and 4 are correct Question No. 61 to 62 (2 questions) The following flow diagram represents the industrial preparation of nitric acid from ammonia:



Me Me | |  O  Si  O  Si  O  | | (B) O O | |  O  Si  O  Si  O  | | Me Me (D) None of the above

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(A) B)  HNO + NO  NO (  (C) water NH3 + O2  3 900C (excess air)


Answer the questions given below: Which line of entry describes the undefined reagents, products and reaction conditions? A B C (A) catalyst R.T. (25°C) NO2 (B) catalyst R.T. (25°C) N2O (C) catalyst high pressure NO2 (D) high pressure catalyst N2O3


Formation of HNO3 when (C) is dissolved in H2O takes place through various reactions. Select the reaction not observed in this step. (A) NO2 + H2O  HNO3 + HNO2 (B) HNO2  H2O + NO + NO2 (C) NO2 + H2O  HNO3 + NO (D) none of these


B(OH)3 + NaOH l NaBO2 + Na[B(OH)4] + H2O How can this reaction is made to proceed in forward direction? (A) addition of cis 1,2 diol (B) addititon of borax (C) addition of trans 1,2 diol (D) addition of Na2HPO4 Question No. 64 to 71 (8 questions) Questions given below consist of two statements each printed as Assertion (A) and Reason (R);

Reconstruct Your Chemistry With Prince Sir


while answering these questions you are required to choose any one of the following four responses: (A) if both (A) and (R) are true and (R) is the correct explanation of (A) (B) if both (A) and (R) are true but (R) is not correct explanation of (A) (C) if (A) is true but (R) is false (D) if (A) is false and (R) is true Assertion : Borax bead test is applicable only to coloured salt. Reason : In borax bead test, coloured salts are decomposed to give coloured metal meta borates.


Assertion : Reason :

Aluminium and zinc metal evolve H2 gas from NaOH solution Several non-metals such as P, S, Cl, etc. yield a hydride instead of H2 gas from NaOH


Assertion : Reason :

Conc. H2SO4 can not be used to prepare pure HBr from NaBr It reacts slowly with NaBr.


Assertion : neutral. Reason :

Oxygen is more electronegative than sulphur, yet H2S is acidic, while H2O is


Assertion : Reason :

Al(OH)3 is amphoteric in nature. It can not be used as an antacid.


Assertion : Reason :

Chlorine gas disproportionates in hot & conc. NaOH solution. NaCl and NaOCl are formed in the above reaction.


Assertion : Reason :

Silicones are very inert polymers. Both Si–O and Si–C bond energies are very high.


Assertion :

Liquid IF5 conducts electricity.

Reason :

Liquid IF5 self ionizes as, 2IF5 l IF4  IF6


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H–S bond is weaker than O–H bond.

Paragraph for Question No. 72 to 74 There are some deposits of nitrates and phosphates in earth’s crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under the laboratory conditions but microbes do it easily. Ammonia forms large number of complexes with transition metal ions. Hybridization easily explains the ease of sigma donation capability of NH3 and PH3. Phosphine is a flammable gas and is prepared from white phosphorous. Q.72

Among the following, the correct statement is (A) Phosphates have no biological significance in humans (B) Between nitrates and phosphates, phosphates are less abundant in earth’s crust (C) Between nitrates and phosphates, nitrates are less abundant in earth’s crust (D) Oxidation of nitrates is possible in soil

Reconstruct Your Chemistry With Prince Sir Q.73

Among the following, the correct statement is : (A) Between NH3 and PH3, NH3 is a better electron donor because the lone pair of electrons occupies spherical ‘s’ orbital and is less directional (B) Between NH3 and PH3, PH3 is a better electron donor because the lone pair of electrons occupies sp3 orbital and is more directional (C) Between NH3 and PH3, NH3 is a better electron donor because the lone pair of electrons occupies sp3 orbital and is more directional (D) Between NH3 and PH3, PH3 is a better electron donor because the lone pair of electrons occupies spherical ‘s’ orbital and is less directional


White phosphorus on reaction with NaOH gives PH3 as one of the products. This is a (A) dimerization reaction (B) disproportionation reaction (C) condensation reaction (D) precipitation reaction


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When a compound X reacts with ozone in aqueous medium, a compound Y is produced. Ozone also reacts with Y and produces compound Z. Z acts as an oxidising agent, then X, Y and Z will be (A) X = HI, Y = I2 and Z = HIO3 (B) X = KI, Y = I2 and Z = HIO3 (C) X = KI, Y = I2 and Z = HIO4 (D) X = HI, Y = I2 and Z = HIO4


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Which of the following statements is/are correct regarding B2H6? (A) banana bonds are longer but stronger than normal B–H bonds (B) B2H6 is also known as 3c–2e compound (C) the hybrid state of B in B2H6 is sp3 while that of sp2 in BH3 (D) it cannot be prepared by reacting BF3 with LiBH3 in the presence of dry ether


Which of the following pairs of nitrates gives the same gaseous products on thermal decomposition? (A) KNO3 and Pb(NO3)2 (B) KNO3 and NaNO3 (C) Pb(NO3)2 and Cu(NO3)2 (D) NaNO3 and Ca(NO3)2 2NO2 l N2O4The dimerisation of NO2 is accompanied with (A) decrease in paramagnetism (B) change in colour (C) increase in temperature’ (D) increase in paramagnetism



C(OH)4 is unstable because a carbon atom cannot hold more than one –OH groups but Si(OH) 4 is a stable compound because (A) C–O bond energy is low (B) C–O bond energy is high (C) Si-O bond energy is low (D) Si-O bond energy is high


Which of the following statements is/are correct regarding inter-halogen compounds of ABx types? (A) x may be 1,3,5 and 7 (B) A is a more electronegative halogen than B (C) FBr3 cannot exit

Reconstruct Your Chemistry With Prince Sir (D) the structures of ClF3 and IF7 show deviation from normal structures and could be explained on the basis of VSEPR theory Q.7

When an inorganic compound (X) having 3c-2e as well as 2c-2e bonds reacts with ammonia gas at a certain temperature, gives a compound (Y) iso-structural with benzene. Compound (X) with ammonia at a high temperature, produces a hard substance (Z). Then (A) (X) is B2H6 (B) (Z) is known as inorganic graphite (C) (Z) having structure similar to graphite (D) (Z) having structure similar to (X)


Boric acid (A) exists in polymeric form due to inter-molecular hydrogen bonding. (B) is used in manufacturing of optical glasses. (C) is a tri-basic acid (D) with borax, it is used in the preparation of a buffer solution.


The correct statement(s) related to allotropes of carbon is/are (A) graphite is the most stable allotropes of carbon and having a two dimensional sheet like structure of hexagonal rings of carbon (sp2) (B) diamond is the hardest allotrope of carbon and having a three dimensional network structure of C(sp3) (C) fullerene (C60) is recently discovered non-crystalline allotrope of carbon having a footballlike structure. (D) Vander Waal's force of attraction acts between the layers of graphite 6.14 Å away from each other





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Al2(SO4)3 + NH4OH  X, then (A) X is a white coloured compound (C) X is soluble in NaOH

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(B) X is insoluble in excess of NH4OH (D) X cannot be used as an antacid

The hybrid states of phosphorous atoms in each PCl5 and PBr3 in gaseous phase are sp3d. But, in solid PCl5, phosphorous shows sp3d2 and sp3 hybrid states. While, P in PBr5 is in Sp3 hybrid state. This is because (A) PCl5 in solid form exists as [ PCl4]+[PCI6]– (B) PBr5 in solid form exists as [PCI4]+[ PBr6]– (C) PCl5 in solid form exists as [PCI4]+Cl– (D) PBr5 in solid form exists as [PBr4]+Br– The species that undergo(es) disproportionation in an alkaline medium is/are (A) Cl2 (B) MnO42– (C) NO2 (D) CIO4–


Select correct statement(s): (A) Borax is used as a buffer (B) 1 M borax solution reacts with equal volumes of 2 M HCl solution (C) Titration of borax can be made using methyl orange as the indicator (D) Coloured bead obtained in borax-bead test contains metaborate


Select correct statement about B2H6 (A) Bridging groups are electron-deficient with 12 valence electrons

Reconstruct Your Chemistry With Prince Sir (B) It has 2c - 2e B–H bonds (C) It has 3c - 2e B–H–B bonds (D) All of above are correct statements Q.15

Which of the following is / are correct for group 14 elements? (A) The stability of dihalides are in the order CX2 < SiX2 < GeX2 < SnX2 < PbX2 (B) The ability to form p–p multiple bonds among themselves increases down the group (C) The tendency for catenation decreases down the group (D) They all form oxides with the formula MO2.


Match the following: Column I 3+ (A) Bi  (BiO)+ (B) [AlO2]–  Al(OH)3

Column II (P) Heat (Q) Hydrolysis

(C) SiO 44  Si 2O 67

(R) Acidification

(D) (B4O 72 )  [B(OH)3]


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(S) Dilution by water

Reconstruct Your Chemistry With Prince Sir IIT JEE ASKED QUESTIONS Q.1

The reaction of P4 with X leads selectively to P4O6. The X is [JEE 2009] (A) Dry O2 (B) A mixture of O2 and N2 (C) Moist O2 (D) O2 in the presence of aqueous NaOH


The nitrogen oxide(s) that contain(s) N–N bond(s) is (are) (A) N2O (B) N2O3 (C) N2O4


In the reaction 2X + B2H6  [BH2(X)2]+ [BH4]¯ the amine(s) X is (are) (A) NH3 (B) CH3NH2



(C) (CH3)2NH

(D) (CH3)3N

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[JEE 2010]


All the compounds listed in Column I react with water. Match the result of the respective reactions with the appropriate options listed in Column II. [JEE 2010] Column I (A) (CH3)2SiCl2 (B) XeF4 (C) Cl2 (D) VCl5

Column II (p) Hydrogen halide formation (q) Redox reaction (r) Reacts with glass (s) Polymerization (t) O2 formation

Extra pure N2 can be obtained by heating (A) NH3with CuO


[JEE 2009]

The total number of dirpotic acids among the following is



[JEE 2009] (D) N2O5

(B) NH4NO3

[JEE 2011] (C) (NH4)2Cr2O7

(D) Ba(N3)2

Among the following, the number of compounds than can react with PCl5 to give POCl3 is O2, CO2, SO2, H2O, H2SO4, P4O10 [JEE 2011]

Reconstruct Your Chemistry With Prince Sir ONLY ONE OPTION IS CORRECT

Q.1 Q.8 Q.15 Q.22 Q.29 Q.36 Q.43 Q.50


Q.2 Q.9 Q.16 Q.23 Q.30 Q.37 Q.44 Q.51

Q.1 Q.7 Q.13 Q.19


Q.2 Q.8 Q.14 Q.20

B Q.3 C Q.4 B Q.10 B Q.11 B Q.17 B Q.18 B Q.24 A Q.25 A Q.31 A Q.32 C Q.38 B Q.39 A Q.45 B Q.46 D Q.52 C GO COMPREHENSIVE B Q.3 C Q.4 A Q.9 A Q.10 C Q.15 A Q.16 C Q.21 C Q.22

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Q.5 Q.12 Q.19 Q.26 Q.33 Q.40 Q.47


Q.6 Q.13 Q.20 Q.27 Q.34 Q.41 Q.48



Q.5 Q.11 Q.17


Q.6 Q.12 Q.18


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Q.1 Q.5 Q.9 Q.13 Q.16

A,B Q.2 A,B,C A,D Q.6 A,C A,B Q.10 A,B,C A,B,C,D Q.14 B,C (A) Q,S (B) R (C) P (D) Q,R

Q.3 Q.7 Q.11 Q.15

JEE QUESTIONS Q.1 B Q.2 A,B,C Q.3 B,C Q.5 (A – p, s); (B – p, q, r, t); (C – p, q, t); (D – p) Q.6. D Q.7 5


Q4. 6

Q.4 Q.8 Q.12


Q.7 B Q.14 A Q.21 B Q.28 B Q.35 D Q.42 D Q.49 B

Reconstruct Your Chemistry With Prince Sir


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Reconstruct Your Chemistry With Prince Sir


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