Operaciones Combinadas Números Enteros Con Solución

September 3, 2022 | Author: Anonymous | Category: N/A
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MATEMÁTICAS NÚMEROS ENTEROS (Operaciones Combinadas)

2º ESO

SOLUCIÓN 1.-

6



3

2.-

3



[−5 ⋅ 6

3.-

2



3

2



4 ⋅1

+



[−

2

+



(−

2

+



⋅  

10

[−

 5.-

[ ( − 8) : ( − 2 )



 6.-

[ 14

+

(− 6 ) ]

 7.-

[3 ⋅ ( 5



10 : 2 ]

 8.-

( 6 − 2)

 9.-

5



10.-

4



11.-

[3 ⋅ ( 2 ⋅ 3 +

12.-

5

13.-

[ − 12 : ( 2

14.-

(7

15.-



4

16.-



{1 − [ 1

17.-

[3 ⋅ ( 7

18.

[  − 6 ⋅ ( 2 −  5 ) + 5 ⋅ (

19.-

[ ( 3 ⋅ 4 −  2 ⋅ 5 )

20.-

5



21.-



{3

22.-

4



23.-

(7

24.-

4

25.- 

10 :

26.- 

8 : (3

(− 6 )



3

2)



[−



5

2



3

[







5

:

  [ 17

 ⋅

[  5 ⋅ ( 1 − 4 )

7

(5

−  

14 : 7

4



3



⋅ 

3)

)

)

7



(2



5

3



+

(− 7 )

+

5)



3





4

5)⋅

[ ( 8  − 4 ) : (−

[ −3



4 :

(6

(− 1) ] }



  4)

2





4:

+

4

{  − 1



(3



3



+

7

)] 4

4



)

+

18 : 9 ) ]  

3





[

[−

5)



3 2



+

2

5



(8



2 ) :  ( 8

3



5)



2





5



2

)]

(2

5)



3:3)



3 7

)

:

(− 3 ) ]



10 : 2

2

) ]

6 : (1



1

55

  2 ]}



6



7



14



26



4 : 2 )]  



8



2− 8 : 4 )]  

2



2 ]



(  −

18

1

(6





1}

  (1

+

3

1









15

7

[ − 3  ⋅ ( 1 −  4 ) −

6 )]



(−

[ ( 3 − 5 ) ⋅ ( 2  −  4 ) + 10 : (− 3 −









1  ]

[ −  3 ⋅ ( 5  − 7 )

[−5



  [ ( 3 − 8 )  ⋅ ( 2 − 5 ) : ( 1 − 4 ) ]

4:2

−  





(5− 2 )

− 

3

2 ⋅  ( 10 : 5 ) ]





+

 3 ]



3 ) ]

  3 ) ]

4

25

5)



( − 3 ) ] } − {  4

(3

)]

+

[ − (− 1 )

7 ) ]  :

2 −

10 



44

  28

 

3





)]

12 :  4

+

[2 ⋅

7  ) ]



3 2

6 : 2 )]

(−2 −



( + 3 ) ] 



: 4



6

( 1 − 3 )  ] :   [ ( 2 −   7 ) ⋅   ( 4

( 1 − 5 )  ]



2

⋅ 

6  ]



[ −  8 : ( 5 − 7 )  − 16 : ( 2







(6 : 2

:

(8 : 2 )]





5⋅ ( 4



0

  : ( − 2 ) −  3 : ( 1 − 2 ) ] [ 10

:

 

 

8:4

− 

]

5)

  13  

8 ] −  2  



(7− 2 )









24 : 3 ]

3 : 3)

[ −  8

2:3



[ 2 ⋅ ( 4 − 1 ) − 3  ⋅ ( − 1 − 5 ) − 8

5) ⋅

2

+

+

9





)⋅ (2 ⋅

2

3

5

2











)

: 3 ) − 8⋅ ( − [ ( 1 − 6) ⋅ ( 12  



10



6 : (2

[ ( 1 − 4) ⋅ ( 2 − 



[ − 10



 −



8:4

5 ⋅2



5]

4)



4  ⋅ ( − 1



 4.-

6

13

( 12 : 4

4



5



 

5 −

28

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