Nucleophilic Substitution Reactions.pdf

February 11, 2018 | Author: Bhushan Dravyakar | Category: Chemical Reactions, Solvent, Unit Processes, Applied And Interdisciplinary Physics, Chemical Substances
Share Embed Donate


Short Description

Download Nucleophilic Substitution Reactions.pdf...

Description

Notes Nucleophilic Substitution Reactions Alkyl halides undergo many reactions in which a nucleophile displaces the halogen atom bonded to the central carbon of the molecule. The displaced halogen atom becomes a halide ion.

Some typical nucleophiles are the hydroxy group (−OH), the alkoxy group (RO−), and the cyanide ion (−C

N). Reaction of these nucleophiles with an alkyl halide

(R&bond;X) gives the following reactions and products:

The halogen ion that is displaced from the carbon atom is called the leaving group, and the overall reaction is called a nucleophilic substitution reaction. Leaving Group For a molecule to act as a nucleus or substrate in a nucleophilic substitution reaction, it must have both a polar bond and a good leaving group. For an atom or a group to be a good leaving group, it must be able to exist independently as

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

1

Organic Chemistry-I

a relatively stable, weakly basic ion or molecule. Groups that act as leaving groups are always capable of accommodating the negative charge through a high electronegativity or by delocalization. Because halogen atoms have high electronegativities and form relatively stable ions, they act as good leaving groups. Nucleophilic Substitution Reactions: Mechanisms Experimental data from nucleophilic substitution reactions on substrates that have optical activity (the ability to rotate plane‐polarized light) shows that two general mechanisms exist for these types of reactions. The first type is called an SN2 mechanism. This mechanism follows second‐order kinetics (the reaction

rate depends on the concentrations of two reactants), and its intermediate contains both the substrate and the nucleophile and is therefore bimolecular. The terminology SN2 stands for “substitution nucleophilic bimolecular.” The second type of mechanism is an S N1 mechanism. This mechanism follows first‐order kinetics (the reaction rate depends on the concentration of one

reactant), and its intermediate contains only the substrate molecule and is therefore

unimolecular.

The

terminology

SN1

stands

for

“substitution

nucleophilic unimolecular.” SN2 mechanism The alkyl halide substrate contains a polarized carbon halogen bond. The SN2 mechanism begins when an electron pair of the nucleophile attacks the back lobe of the leaving group. Carbon in the resulting complex is in pentavalent (trigonal bipyramidal) shape. With the loss of the leaving group, the carbon atom again regains a tetrahedral (pyramidal) shape; however, its configuration is inverted.

Figure 1 Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

2

The SN2 mechanism can also be illustrated as shown below.

Organic Chemistry-I

Figure 2 Notice that in either picture, the intermediate shows both the nucleophile and the substrate. Also notice that the nucleophile must always attack from the side opposite the side that contains the leaving group. This occurs because the nucleophilic attack is always on the back lobe (antibonding orbital) of the carbon atom acting as the nucleus. SN2 mechanisms always proceed via backward attack of the nucleophile on the substrate. This process results in the inversion of the relative configuration, going from starting material to product. This inversion is often called the Walden inversion,

Figure 3 Steric hindrance SN2 reactions require a rearward attack on the carbon bonded to the leaving group. If a large number of groups are bonded to the same carbon that bears the leaving group, the nucleophile's attack should be hindered and the rate of the reaction slowed. This phenomenon is called steric hindrance. The larger or bulkier the group(s)-greater the steric hindrance and slower the rate of reaction. Table-1 shows the effect of steric hindrance on the rate of reaction for a specific, unspecified nucleophile and leaving group. Different nucleophiles Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

3

Organic Chemistry-I

and leaving groups would result in different numbers but similar patterns of results. SN2 reactions give good yields on 1° (primary) alkyl halides, moderate yields on 2°(secondary) alkyl halides, and poor to no yields on 3° (tertiary) alkyl halides.

Solvent effects For protic solvents (solvents capable of forming hydrogen bonds in solution) an increase in the solvent's polarity results in a decrease in the rate of SN2 reactions. This decrease occurs because protic solvents solvate the nucleophile, thus lowering its ground state energy. Because the energy of the activated complex is a fixed value, the energy of activation becomes greater and, therefore, the rate of reaction decreases.

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

4

Organic Chemistry-I

Polar aprotic solvents (solvents that cannot form hydrogen bonds in solution) do not solvate the nucleophile but rather surround the accompanying cation, thereby raising the ground state energy of the nucleophile. Because the energy of the activated complex is a fixed value, the energy of activation becomes less and, therefore, the rate of reaction increases.

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

5

Organic Chemistry-I

Figure 4 illustrates the effect of solvent polarity on the energy of activation and, thus, the rate of reaction.

Figure 4 The smaller activation energy leads to the more rapid reaction. SN1 mechanism SN1 indicates a substitution, nucleophilic, unimolecular reaction, described by the expression rate = k [R-LG]. This implies that the rate determining step of the mechanism depends on the decomposition of a single molecular species. This pathway is a multi-step process with the following characteristics: Step-1: slow loss of the leaving group, LG, to generate a carbocation intermediate, then Step-2 : rapid attack of a nucleophile on the electrophilic carbocation to form a new σ-bond

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

6

Organic Chemistry-I

Multi-step reactions have intermediates and a several transition states (TS). In an SN1 there is loss of the leaving group generates an intermediate carbocation which is then undergoes a rapid reaction with the nucleophile.. General case

SN1 reaction

Let's look at how the various components of the reaction influence the reaction pathway: Alkyl group (R-) Reactivity order: (CH3)3C- > (CH3)2CH- > CH3CH2- > CH3In an SN1 reaction, the rate determining step is the loss of the leaving group to form the intermediate carbocation. The more stable the carbocation is, the easier it is to form, and the faster the SN1 reaction will be. Some students fall into the trap of thinking that the system with the less stable carbocation will react fastest, but they are forgetting that it is the generation of the carbocation that is rate determining. Since a carbocation intermediate is formed, there is the possibility of rearrangements (e.g. 1,2-hydride or 1,2-alkyl shifts) to generate a more stable carbocation. This is usually indicated by a change in the position of the substituent or a change in the carbon skeleton of the product when compared to the starting material. Leaving Group (LG) The only event in the rate determining step of the SN1 is breaking the C-LG

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

7

Organic Chemistry-I

bond. Therefore, there is a very strong dependence on the nature of the leaving group, the better the leaving, the faster the SN1 reaction will be. Nucleophile (Nu)

Since the nucleophile is not involved in the rate determining step, the nature of the nucleophile is unimportant in an SN1 reaction. However, the more reactive the nucleophile, the more likely an SN2 reaction becomes. Stereochemistry In an SN1, the nucleophile attacks the planar carbocation. Since there is an equally probability of attack on each face there will be a loss of stereochemistry at the reactive center as both products will be observed.

Solvent Since the hydrogen atom in a polar protic solvent is highly positively charged, it can interact with the anionic nucleophile which would negatively affect an SN2, but it does not affect an SN1 reaction because the nucleophile is not a part of the rate-determining step (See SN2 Nucleophile). Polar protic solvents actually speed up the rate of the unimolecular substitution reaction because the large dipole moment of the solvent helps to stabilize the transition state. The highly positive and highly negative parts interact with the substrate to lower the energy of the transition state. Since the carbocation is unstable, anything that can stabilize this even a little will speed up the reaction.

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

8

Organic Chemistry-I

Sometimes in an SN1 reaction the solvent acts as the nucleophile. This is called a solvolysis reaction (see example below). The polarity and the ability of the solvent to stabilize the intermediate carbocation is very important as shown by the relative rate data for the solvolysis (see table below). The dielectric constant of a solvent roughly provides a measure of the solvent's polarity. A dielectric constant below 15 is usually considered non-polar. Basically, the dielectric constant can be thought of as the solvent's ability to reduce the internal charge of the solvent. So for our purposes, the higher the dielectric constant the more polar the substance and in the case of SN1 reactions, the faster the rate.

Below is the same reaction conducted in two different solvents and the relative rate that corresponds with it.

The figure below shows the mechanism of an SN1 reaction of an alkyl halide with water. Since water is also the solvent, this is an example of a solvolysis reaction.

Summary

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

9

Organic Chemistry-I

This pathway is most common for systems with good leaving groups, stable carbocations and weaker nucleophiles. A typical example is the reaction of HBr with a tertiary alcohol. SN1 Mechanism for Reaction of Alcohols with HBr

Step 1: An acid/base reaction. Protonation of the alcoholic oxygen to make a better leaving group. This step is very fast and reversible. The lone pairs on the oxygen make it a Lewis base. Step 2: Cleavage of the C-O bond allows the loss of the good leaving group, a neutral water molecule, to give a carbocation intermediate. This is the rate determining step (bond breaking is endothermic) Step 3: Attack of the nucleophilic bromide ion on the electrophilic carbocation creates the alkyl bromide.

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

1

Organic Chemistry-I

SN1 MECHANISM FOR REACTION OF ALKYL HALIDES WITH H2O

Step 1: Cleavage of the already polar C-Br bond allows the loss of the good leaving group, a halide ion, to give a carbocation intermediate. This is the rate determining step (bond breaking is endothermic) Step 2: Attack of the nucleophile, the lone pairs on the O atom of the water molecule, on the electrophilic carbocation creates an oxonium species. Step 3: Deprotonation by a base yields the alcohol as the product. Note that this is the reverse of the reaction of an alcohol with HBr. In principle, the nucleophile here, H2O, could be replaced with any nucleophile, in which case the final deprotonation may not always be necessary.

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

1

SN1 vs SN2 Reactions

Organic Chemistry-I

Whether an alkyl halide will undergo an SN1 or an SN2 reaction depends upon a number of factors. Some of the more common factors include the natures of the carbon skeleton, the solvent, the leaving group, and the nature of the nucleophile. Nature of the carbon skeleton Only those molecules that form extremely stable cations undergo S

N1

mechanisms. Normally, only compounds that yield 3° (tertiary) carbonications (or resonance‐stabilized carbocations) undergo S N1 mechanisms rather than S N2

mechanisms. Carbocations of tertiary alkyl halides not only exhibit stability

due to the inductive effect, but the original molecules exhibit steric hindrance of the rear lobe of the bonding orbital, which inhibits S N2 mechanisms from occurring. Primary alkyl halides, which have little inductive stability of their cations and exhibit no steric hindrance of the rear lobe of the bonding orbital, generally undergo S N2 mechanisms. Figure 1 illustrates the tendencies of alkyl halides toward the two types of substitution mechanisms.

Polar protic solvents such as water favor S N1 reactions, which produce both a cation and an anion during reaction. These solvents are capable of stabilizing the charges on the ions formed during solvation. Because S N2 reactions occur via a concerted mechanism (a mechanism which takes place in one step, with bonds breaking and forming at the same time) and no ions form, polar protic solvents would have little effect upon them. Solvents with low dielectric constants tend not to stabilize ions and thus favor S N2 reactions. Conversely, solvents of high dielectric constants stabilize ions, favoring S N1 reactions. In general, good leaving groups are those capable of forming stable ions or molecules upon displacement from the original molecule. Conversely, poor leaving groups form ions of poor to moderate stability. Strong bases, such as

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

1

OH −, NH

2 −,

Organic Chemistry-I

and RO −, make poor leaving groups. Water, which is less basic

than a hydroxide ion, is a better leaving group. Poor bases usually make good leaving groups. A poor base is an ion or group in which the electrons are tightly bound to the molecule due to high electronegativity or resonance. Some good leaving groups are the sulfate ion and the p‐toluenesulfonate (tosylate ion).

The following list ranks atoms and molecules in order of their stability as leaving groups, from most to least stable.

Dr. Bhanuben Nanavati College of Pharmacy, Mumbai

1

View more...

Comments

Copyright ©2017 KUPDF Inc.
SUPPORT KUPDF