HINTS & SOLUTIONS (YEAR-2008-09)_NSEJS (STAGE-I) ANSWER KEY Que s.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Ans.
C 17
D 18
D 19
D 20
C 21
B 22
C 23
B 24
D 25
A
D
A
B
AD
Que s.
C 16
26
27
28
29
30
Ans.
C
B
C
D
B
B
D
A
C
B
A
C
B
B
Que s.
31
32
33
34
35
36
37
38
39
40
AD
ABCD
BC
AD
ABC
CD
AC
B
AD
Ans. ABD
A
(PART A-1) 1.
Least count = value of 1 division of main scale/Total division of vernier scale 0.1 =
2.
LN =
x 20
⇒ x = 2mm
1 BC 2
∆ABC ~ ∆MNL
[By AA similarity]
Area ∆ABC BC 2 Area ∆MNL = LN = (2) = 4 2
area ∆LMN = 3.
A
[by mid-point theorem]
L B
N M
C
area ∆ABC 48 = = 12 sq. unit . 4 4
(1 – tan A + sec A) (1 – cot A + cosec A)
sin A
1
cos A
1
= 1 − cos A + cos A 1 − sin A + sin A cos A − sin A + 1 sin A − cos A + 1 cos A sin A
=
1 − (sin A − cos A ) 1 + (sin A − cos A ) cos A sin A
=
5.
=
12 − (sin A − cos A )2 cos A sin A
=
1 − (sin2 A + cos 2 A − 2 sin A cos A ) cos A sin A
=
2 sin A cos A = 2. sin A cos A
Neopentane contain only one type of H i.e. only (1º H) 1º
CH3 1º
1º
H3C – C – CH3 1º
CH3 136
CAREER POINT, 128, Shakti Nagar, Kota-324009 (Raj.), Ph. 0744-2503892
10.
Work done = Change in kinetic energy
1 1 × 2 × 25 – × 2 × 36 = 189 J 2 2
= 11.
Let the speed of the scooter = v m/min. ∴ Distance BC = 18 v and Distance CD = t v. In ∆ACD tan 60º =
h=
=
3
h =
B
3tv
tan 30º = 1
h
AD CD
h = tv
3
A
30º 18 min
C
60º t min
D
..... (i) AD BC + CD
h 18 v + vt
v(18 + t ) 3
..... (ii)
From (i) & (ii) 3tv=
∴ 13.
v(18 + t ) 3
3t = 18 + t t = 9 min.
2AgNO3(aq.)+H2S(g) → Ag2S(s) + 2HNO3 (aq.) CuSO4 (aq.)+ H2S (g) → CuS (s) + H2SO4(aq.) According to the equations, ratio of the amounts of H2S needed for precipitation is 1:2.
14.
M=
=
no. of moles of solute × 1000 V(ml)
6.02 × 10 20 × 1000 6.02 × 10 23 × 100
= 0.01M
15.
P, Q → prime number PR is divisible by Q. R is a multiple of Q. Option A → Q divides R is correct. Option B → P is not a multiple of R.∴ wrong Option C → P is prime & R is not multiple of P ∴ wrong Option D → P divides PQ is correct.
18.
Volume of icecream in cylinder = volume of icecream in 12 cones 1
2
2 3 π(6)2 × h = 10 3 π(3) × 12 + 3 π(3)
36 h = 10 [36 + 18] h = 15 cm.
137
CAREER POINT, 128, Shakti Nagar, Kota-324009 (Raj.), Ph. 0744-2503892
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