Navat

August 3, 2022 | Author: Anonymous | Category: N/A
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6 AUFMAG TQT[H[Q[OSHO OLHDHFB (J3) (Yrocbamfs)  Gomcraa ka bf  Gomcr bf Fshjgftur Fshjgfturf> f> MH-1;9 MH-1;9 Khsaöo Khsaöo y dogstrud dogstruddhoga dhogass mhgarfs. mhgarfs. Ladef> 69-95-3936 Kodagta> Msd. Hgj. Hgkfbadho Vuhspa Sokríjuaz  Gomcraa kab Fbumgo.....  Gomcr Fbumgo........... ............ ............ ............ ............ ............ ............ ............ ............ ............ ............ ............ ............ ............ ............ ............ ........ 6.- (1 (1))  Ag bf axpbo axpbotf tfdh dhôg ôg por ab mèto mètoko ko Qgka Qgkarr Dut fg fgk k Lh Lhbb bb do dog g ra rabb bbag ago o eh ehkr kræu æubh bhdo do damagtfko, tfb domo sa muastrf ag bf lhjurf fknugtf. Bf propordhôg ag paso ka damagto rabfva as 6>1. Ab parfbta katarmhgfko pfrf bf bozf as ka 19 dm. Ab paso ughtfrho lrasdo ka bf bozf as 3499 @j/m4, ab paso ughtfrho eþmako kab rabfva as 6599 `j/m 4. Efbbfr bf dfgthkfk ka damagto y m4 ka rabfva ag bf bozf y socrabozf pfrf ab tfnao magdhogfko y otros kftos qua

sa bas phka.

SATYQAT[F> Yfrf bf bozf ka 6>1 y socrabozf dorraspogkhagta, efbbfr bos shjuhagtas> Yaso tfgkf ka mftarhfbas/sfdo ka damagto……311………….`j/sfd damagto……311………….`j/sfdo o Sagkhmhagto ka ugf cobsf c obsf por m4 ka bosf……9.6695 …………………

 

3 3.- (:)  Ab khsaöo kab seotdrata pfrf ugf koshlhdfdhôg ag paso y ag ocrf sa thaga ag bf shjuhagta  propordhôg>  propor dhôg> Damagto, fjrajfkos, fjuf, fdabarfgta, lhcrf fdaro. 6 > ;.1 / 9.34 > 9.9; > 9.9<

Yfrf astf propordhôg sa thaga> Yaso fjrajfko jruaso sado> 6919.9 `j/m4 y bf eumakfk 5.84% Yaso ughtfrho suabto sado kab fjrajfko ag dognugto as 6 ;49 `j/m4 ;3.1 `j/cbs Fjrajfkos> 6841 `j/m4 686.31 `j/cbs Fjuf aladthvf> 85bt/m4 8.::1 `j/cbs Fdabarfgta Thjught> 6:.3 `j/m4 6.: `j/cbs Lhcrf fdaro krfmax> 31.5 `j/m4

3.11 `j/cbs

\obumag mazdbf prapfrfkf (\mp)>……;3 m4……… \obumag ka racota………5.; m4…………. \obumag seotdrata dobodfko shg dompfdtfr………46.1 m4………… \obumag ka seotdrata dobodfko>……31 m4……………. Dfgthkfk ka mftarhfbas pfrf ab matrfko hgkhdfko>  Damagto ag cobsfs……………;31 cbs…… 

Fjrajfko (ag dognugto) ag m4>……;5.; m4…………



Fdabarfgta shjught………:33.; `j…………….…………



Lhcrfs ka fdaro krfmax>……6954.< `j………………………

4.(5))  Kata Katarm rmhg hgfr fr bf sa sadd ddhô hôg g ka ugf fcar fcartu turf rf su suct ctar arræ ræga gaff ovfb ovfbfk fkff qua qua sa saff as astf tfcb cbaa 4.- (5 jaom jaomad adæg æghd hdfm fmag agta ta y jufr jufrka ka ugf ra rabf bfdh dhôg ôg fgde fgdef/ f/fb fbtu turf rf ˄ 6. Astf Astf bfco bfcorr sa agdu agduag agtr trff mfyormagta ag ugf rodf dfbhzf f ;99 m ka prolugkhkfk dog raspadto f bf suparlhdha y thaga fkamæs bfs shjuhagtas prophakfkas> - Sashstagdhf domprashvf ka bf rodf hgtfdtf (τd) = 639 MYf - Ta fsuma ab JTH = 19 - Yaso aspadílhdo ka bf rodf φ = 3.:9 [og/m4 - Bf bfcor sa dogstruya pfrf ugf mhgaríf dogvagdhogfb, duyo fgdeo go kaca sar ≡ 4m. - Bf astfchbhkfk ka bf bfcor kaca astfr agtra LT = ;.6 f ;.30 agdhmf as fgthadogômhdo y kacfno as ug potagdhfb ka dobfpso. SATYQAT[F 3> >…………0 Tt/Tv = …………….0 λ dd=¿ ………………MYf

\

 

4 Zo/Eo =…………………… =……………………………0 ………0 LT = ……………….. Bf saddhôg ka bf bfcor mæs fkadufkf> Zo>…………… y Eo>……….……….. Bf saddhôg ka bf bfcor mæs fkadufkf> Zo>…………… y Eo>……….………..

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