Mini-Assignment 1 PDF

 

MINI-ASSIGNMENT 1 From the textbook, 1.  Chapter 2, Question 19, Given data

a.  What are the mean and median patient wait times for offices with a wait wait-tracking -tracking system? What are the mean and median patient wait times for offices without a wait-tracking system?

Ans:- The mean and median patient wait times for offices offices with a wait-tracking system Mean = 17.2 Median = 13.5

Formula = average(b2:b11) Formula =median(b2:b11)

B12 Cell B13 Cell

The mean and median patient wait times for offices without a wait-tracking system Mean = 29.1 Median = 23.5

Formula = average(a2:a11) Formula =median(a2:a11)

A12 Cell A13 Cell

b.  What are the variance and standard deviation of patient wait times for offices with a waittracking system? What are the variance and standard deviation of patient wait times for visits to offices without a wait-tracking system? Ans:- The variance and and standard deviation of patient wait times for offices with a wait-tracking system Variance = 86.17 Standard Deviation = 9.28

Formula = var.s(b2:b11) Formula =stdev.s(b2:b11)

B14 Cell B15 Cell

The variance and standard deviation of patient wait times for offices without a wait-tracking system Variance = 275.65 Standard Deviation = 16.6

Formula = var.s(a2:a11) Formula =stdev.s(a2:a11)

A14 Cell A15 Cell

 

  e. Do offices offices with a wait-tracking system have have shorter patient wai waitt times than off offices ices without a waittracking system? Explain. Ans:- Yes, the offices with wait tracking system have shorter patient wait time than offices without a wait tracking system. This above conclusion was drawn from the box plot for the given data. From boxplot, it is evident that total wait time t ime and the mean for the given set of sample is less for offices with a wait-tracking system compared to without wait tracking tr acking system.

2.  Chapter 2, Question 21 a.  Considering only offices without a wait-tracking system, what is the z-score for the 10th patient in the sample (wait time = 37 minutes)? Ans:- The z-score for the 10th patient in the sample sample is 0.47 (formula (formula = STANDARDIZE( STANDARDIZE(A11,A12,A15)) A11,A12,A15))

 

b.  Considering only offices with a wait-tracking system, what is the z-score for the 6th patient in the sample (wait time = 37 minutes)? How does this t his z-score compare with the z-score z -score you calculated for part a? Ans:- The z-score for the the 6th patient in the sample is 2.13 (formula = STANDARDIZE(B7,B12,B15)). The z-scores are used to measure the distance from the mean when compared to part a, the distance of 37 min from the mean is further away. c.  Based on z-scores, do the data for offices without a wait-tracking system contain any outliers? Based on z-scores, do the data for offices with a wait-tracking system contain any outliers? Ans:- As per the z-score any value less than −3 or greater than +3 is considered as an outlier.   The below table shows the z-score for all the values, and it's clear that for no given data, the z-score value is less than -3 and greater greate r than +3, we can conclude that there are no outliners. However, the data points of 67 min for without wait tracking track ing system and 37 min for with wait tracking system can be considered as outliners as they are falling in 4th quartile.

Without WaitTracking

z score

System

With Wait-

z score

Tracking System

24

-0.30718

31

1.486557

67

2.282737

11

-0.66787

17

-0.72879

14

-0.34471

20

-0.5481

18

0.086177

31

0.114438

12

-0.56015

44

0.897435

37

2.132886

12

-1.02994

9

-0.88332

23

-0.36741

13

-0.45243

16

-0.78902

12

-0.56015

37

0.475821

15

-0.23699