Mechanical Engineering Reviewer.pdf
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ALCORCON ENGINEERING REVIEW CENTER· Manila: 4th FIr,
Anadeta Bidg. 891 Galicia St. cor:Espana AVe.
Sampaloc Mli!nila (leI. 742-5fS..OO)
'Cebu: 4TH FIr. Vlllacam~a-Capuras Bldg., Sanciangco St. Cabu City (Tel # 254-33-84)
MACHiNE ELEMENTS RqlUng Cylinders 1. Cylinders Rolling in opposite direction:
~
. Tangential speed
Vi "" Va :::: 11: 01 Nt :::: '";&
1t
Dz N2
"Relatioflof diameter and speed 01 N1 :: D:.! N2
,
$peedRatlo:::' SpeedofDIi?l~r . eM) SpeedoftbeDnven
"
CenierDistance '" R1 + Rz = o!+ °2 2
;&
Tangential speed
V1 ::: V:;: := 11: 01 Nl
.. := 11:
D:iNz
(;; Relation of diameter and speed
D1 N1 :::: DzN2 ". Spee d R81.0= t' ..,.,
Speed .of Driver Speed .of the Driven
G Center Distance :::: R; _ R2 "" 0 1 - D2 2
STRESSES DEFINITIONS:
.Force 1'-1':;: ? :;: 1. Stress (S):::: - - . .., In , kgfcm-, KN/m . Area Stress::: a total resistance that a material .offers to an applied load.
2. Ultimate stress (Su) -
is the s~ess tMt
would cause failure
,
,
3. Yieldstress(Sy) - maximum stress without causing deformation 4. Allowable stress(Sall) ::: Ultimate stress/Factor of SafetY
Types 'of. Stresses A. Tensile Stress
CSt)
S, Compressive Stress(Sc)
Fe , A
D .
.
,
:;,>-"
'.
, F -
\..
JI'
.
t~'", t
o A ::: n D ~ (fof'punching a hole)
flo
D. Bearing Stress(Sb)
L
where: A::: DL E. Factor of ~fety(FS)
A Based on yield strength:
D
S
FS:::: - Y San
B. Based on ultimate strength:
where:
Sail ::: allowable stress
S...::: ultimate stress
Sy ::: yield stress
F. Torsional Shear stress(Ss)
s.. : :
Tc J
where:
=:
16T'
7tD3
T :: torque J.:: polar moment of inertia 1I:D4
32 (for sofid shaft)
J :::
c :: r (for circular cross section) d :: diameter:
G. Bending Stress(St)
F
t
St:: Me ~
.'
For rectangular beam:
l..
aM
St::
bh 2
"lhere: M :::: moment c :: distance of farthest fiber from neutral axis :: moment of inertia aboutthe neutral axis f ;;;; bh3112 (for rectangular cross section)
4 ==
sectio~ modulus
of rectangular shaft : :.:
,.
T
M
c
nd 3
=-16S
Z :: section modulus of circular shaft ::: -
*.
.
~Of~~ @ ~fAvK} Strain and Elongation A. Strain :::: y
l
S. Stress::::
c.
F
A
Stress Modulus of elasticity, E :: - - Strain
FL AY
F
D. Y:: FL
AE
where:
Y:: elongation due to applied load L :::: original length F :: force For steel: E = 30 X 106 psi
A= area
S
= stress
DtN,"'-
nNz.
!it :. 0-N"Iv
OJ
D~-c.. (£0.[
k ::: coefficient of thermal expansion, wJm-"C 1/ /'
h ::: final temperature, °C ,
\ _I",
'-' ~ lIISX C ~I
Relation between shearing and tensile stress based on theory of failure: Stmax ::
~
Variable Stress
8m-:::
~1tth~::. ~~td~~~
~
~ .rk~ ~ ~ lei ot 61rCSS/~
_1_ '" 8 m + Sa FS Sy. Sn
where:
Sy. ::.: yield point
FS :: factor of safety
Sm ::: mean stress :::
So ::: endurance limit
Smax +SmltL
2 Smax -Smin
vo ::: variable component stress:::
t:;,
--"-"~-
Smax ::: maximum stress
Smin ::: minimum stress
2
/
" Poisson's Ratio(u) ::: is the ratio of lateral unit deformation to axial unit deformation.
where:
u•
2~ -1
fll. Psteel ill> :!~!ii~~
G::;
shear modulus of elasticity
- I "
0:;;J4(;
r ~l~eJ ~
~ o.;/G !t>~
E ::: modulus of elasticity
~ pa)~:C l{~oY r~~eJ ~ D.'~r
h>
o.e_
ALCORCON ENGINEERING REVIEW CENTER Manila: 41i> Fir. Anacleta Bldg. 891 Galicia St. cor. Espana Ave. Sampaloc Manila (Tel. 742-56-00) Cebu: 4TH Fir. Villacampa-Capuras Bldg., Sanciangco Sf. Cebu City (Tel # 254-33-84)
Machine Design Problems - DAY 1 MACHINE ELEMENTS 1. PROBLEM (ME Bd. Apr. 91) Two parallel shafts connected by pure rolling tum in the same direction having a speed ratio of 2.75. What is the distance of the shafts if the smaller cylinder is 22 em in diameter? 2. Two cylinders rolling in opposite direction has a speed ratio of 3 .. If center distance is 40 in, find the diameter of smaller cylinder.
, ','
l~
J:;
, ,
-= ',G, s X )6~ ~I. .•. , ( &t>';f) ( ::zq-~'t ",'jOr xld
(cln (J.
CXkf;
~ ~Slf1b
~
J
\w
Pr ~ O. 'db 'VI ~ ~_
¥lOY)- tL
O=j;f
l.
Q l.\ I (g t ~ 38 ~ . ~ Q
t}.
&\ ~ -l= :: -
8·
[-;:-
A
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