# Maths Part 1

September 11, 2017 | Author: Sanjay Verma | Category: Area, Circle, Triangle, Geometric Objects, Euclidean Geometry

#### Description

WORKSHOP FOR IJSO IIT-JEE | AIPMT | AIEEE | OLYMPIADS | KVPY | NTSE Subject : Mathematics

1.

DAILY PRACTICE PROBLEMS SESSION-2011-12

Topic : NUMBER SYSTEM

DPP No. 01

The number of zeros at the end of the product of the expression 10 × 100 × 1000 × 10000 × ....10000000000 is : (A) 10

2.

(C) 50

(D) 55

Find the unit digit of the product of all the odd prime numbers. (A) 2

3.

(B) 100

(B) 3

(C) 5

(D) 7

A leading chocolate producing company produces ‘abc’ chocolates per hour (abc is a three digit positive number). In how many hours it will produce ‘abcabc’ chocolates ? (A) abc

4.

(C)1001

(D) can’t be determined

Total number of factors of the expression 623 – 543 – 83 is : (A) 60

5.

(B) 101

(B) 62

(C) 46

(D) can’t be determined

A number ‘p’ is such that it is divisible by 7 but not by 2. Another number ‘q’ is divisible by 6 but not by 5, then the following expression which necessarily be an integer is : (A)

6.

7p  6q 42

(C)

6p  7q 42

(D) none of these

(B) 1

(C) 0

(D) 44

If (x – 5)(y + 6)(z – 8) = 1331, then the minimum value of x + y + z is : (A) 40

8.

5p  6q 71

If 223 + 233 + 243 + .. + 873 + 883 is divided by 110 then the remainder will be : (A) 55

7.

(B)

(B) 3

(C) 19

(D) not unique

The quotient when L.C.M. is divided by the H.C.F. of a G.P. with first term ‘a’ and common ratio ‘r’ is : (A) rn – 1

(B) rn

(C) a–1rn–2

(D) (rn – 1)

1 b Number of pairs of positive integers which satisfy the equation = 11 where a + b  100 1 b a (A) 6 (B) 7 (C) 8 (D) 9 a

9.

10.

Convert (231)8 into decimal system : (A) 163 (B) 153

(C) 123

(D) 113

WORKSHOP FOR IJSO IIT-JEE | AIPMT | AIEEE | OLYMPIADS | KVPY | NTSE Subject : Mathematics

1.

If sin (A – B) = (A) 45º, 15º

2.

Topic : TRIGONOMETRY

1 – 2p 1 p

1 1 and cos (A + B) = , 0º < A + B 90º, then A and B are 2 2 (B) 60º, 30º (C) 30º, 15º (D) 45º, 30º

2

(B)

5.

6. 7.

8.

p2 – 1 p2  1

(C)

1 p2 2 1 – p2

(D)

p2  1 p2 – 1

1 BD, then the value of sin is 2

x

(A) 4.

DPP No. 02

If sec A + tan A = p , then the value of sin A is (A)

3.

DAILY PRACTICE PROBLEMS SESSION-2011-12

9y 2  5x 2

2x

(B)

9y 2 – 5x 2

x

(C)

3y 2 – 5x 2

2x

(D)

3y2 – 4x 2

If sin 3 = cos (– 6º) , where 3and – 6º are acute angles, find the value of  (A) 42º (B) 21º (C) 24º (D) None of these

1  sin  1  sin  + is equal to : 1  sin  1  sin  (A) – 2 sec  (B) 2 sec 

(C) 2 cosec 

(D) 2 tan 

sin6A + cos6 A is equal to : (A) 1 – 3 sin2 A cos2A (B) 1 – 3sin A cos A

(C) 1 + 3 sin2 A cos2A

(D) 1

If sec x = P, cosec x = Q, then : (A) P2 + Q2 = PQ (B) P2 + Q2 = P2Q2

(C) P2 – Q3 = P2Q2

(D) P2 + Q2 = – P2Q2

ABCD is a parallelogram, where AB = 6 3 cm, BC = 6 cm and ABC = 120º. The bisectors of the angles A, B, C and D form a quadrilateral PQRS. Find the area of PQRS (in cm2) (A) 18 3

(B) (2  3 )

(C)

36 3

(D) 18 3 (2  3 )

9.

The angle of elevation of the top of a tower as observed from a point on the horizontal ground is ‘x’. If we move a distance ‘d’ towards the foot of the tower, the angle of elevation increases to ’y’, then the height of the tower is : d tan x tan y d tan x tan y (A) (B) d(tan y + tan x) (C) d(tan y – tan x) (D) tan y  tan x tan y – tan x

10.

Let  be an acute angle such that sec2 +tan2 = 2. The value of (cosec2 + cot2), is (A) 9 (B) 5 (C) 4 (D) 2

11.

If x = r sin  cos  , y = r sin  sin  , z = r cos  then the value of x2 + y2 + z2 is (A) 0 (B) 1 (C) r2 (D) None

12.

Given 3 sin + 5 cos  = 5, then the value of (3 cos – 5 sin )2 is equal to 9 1 1 (A) 9 (B) (C) (D) 5 3 9

13.

If tan4 + tan2 = 1, then cos 4  + cos 2 has the value equal to : (A)

14.

1 2

(B) 1

(D)

3 2

(B) 15 m

(C) 10 3 m

(D) 20 m

The shadow of a pole standing on a horizontal plane is a metre longer when the sun’s elevation is  than when it is . The height of the pole of will be : (A) a

16.

1 4

On the level ground, the angle of elevation of the top of a tower is 30º. On moving 20 m nearer, the angle of elevation is 60º. The height of the tower is(A) 10 m

15.

(C)

cos  cos  m cos  

sin  sin  (B) a sin     m

sin  cos  (C) a sin     m

sin  cos  (D) a cos    m

An aeroplane flying horizontally 1 km above the ground is observed by person on his right side at an elevation of 60º. If after 10 seconds the elevation is observed to be 30º, from the same point and in the same direction, then uniform speed per hour (in km) of the aeroplane is (neglect the height of the person for computations).

720 (A) 360 3

(B)

3

(C) 720

(D) 720 3

1 1 1 1 + + + ...+ for any natural number n, is : n(n  1) 2.3 3 .4 1.2 (A) always greater than 1 (B) always less than 1 (C) always equal to 1 (D) not definite

11.

The expression

12.

The digit at the 100th place in the decimal representation of (A) 1

(B) 2

6 , is : 7

(C) 4

(D) 5

13.

In how many ways can 576 be expressed as the product of two distinct factors ? (A) 10 (B) 11 (C) 12 (D) 13

14.

Find the highest power of 63 whcih can exactly divide 6336!. (A) 2050 (B) 1054 (C) 1020

(D) 2120

Find the unit digit of the product of all the odd prime numbers. (A) 1 (B) 5 (C) 0

(D) None of these

15.

WORKSHOP FOR IJSO DAILY PRACTICE PROBLEMS SESSION-2011-12

IIT-JEE | AIPMT | AIEEE | OLYMPIADS | KVPY | NTSE Subject : Mathematics 1.

(B) 40º

(D) 60º

(C) 45º

(D) 60º

(B) 60º

(C) 105º

(D) 90º

ABCD is a cyclic quadrilateral such that ADB = 30º and DCA = 80º. Find the value of DAB.

(A) 70º 5.

(C) 80º

What is the value of ‘d’ in the given figure ?

(A) 150º 4.

(B) 140º

In the given figure, the value of x is :

(A) 30º 3.

DPP No. 03

In the given figure, calculate the measure of POR ; where O is the center of the circle.

(A) 120º 2.

Topic : GEOMETRY

(B) 100º

(C) 120º

(D) 150º

It is given that AB and AC are the equal sides of an isosceles ABC, in which an equilateral DEF is inscribed. As shown in the figure, BFD = a and ADE = b, and FEC = c. Then : A

D

b

E c

B

(A) a =

bc 2

(B) b =

ac 2

a F

C

(C) c = 2a + 2b

(D) a =

bc 3

6.

In a right-angled triangle, the product of two sides is equal to the half of the square of the third side, i.e. hypotenuse. One of the acute angles may be (A) 60º

7.

(B) 30º

(C) 45º

(D) 15º

In the given parallelogram ABCD, if 3(BE) = 2(DC) and the area of DQC is 36 square unit, then find the area of BQE (sq. unit) : E

A

B Q

D

(A) 16 8.

C

(B) 20

(C) 24

(D) 18

In the following figure, if MN || BC, MN divides the triangle into two equal parts, then the value of the ratio of MA and AB will be : A

M

N

B

C

1 (A) 9.

2

(B)

2 1

(C)

2

2

(D)

2 1 2

In the given triangle ABC, points P, Q and R divide the sides BC, CA and AB in the ratios 1 : 2, 3 : 2 and 3 : 2 respectively. Find the ratio of the area of quadrilateral ARPQ to the area of the triangle ABC. A Q R B

(A) 10.

7 15

(B)

C

P

2 3

(C)

2 5

(D)

38 75

As shown in the figure, OD = 36 cm, OA = 20 cm and AB = 25 cm. Find the length of chord BC. D 36

B

O 25

C

20

A

(A) 48 cm 11.

(B) 68 cm

(C) 56 cm

(D) 63 cm

Two circles of radius r and centres O1 and O2 are moved towards one another and AB is the common chord. The line joining O1 O2 when extended meets the circumference of one of circles at P. What is the maximum possible area of APB ? A O1

O2

P

B

(A) r2

(B)

4 2 r 3

(C)

3 3 2 r 4

(D) 2r2

12.

P and Q are the points on the side BC, R and S are on the side CA, and T is on the side AB of a ABC such that P and Q trisect BC, and CR : RS : SA = 1 : 1 : 2. T bisects AB. If area of the triangle ABC = M sq. units, the area of pentagon PQRST is : (A)

13.

M 3

(B)

M 4

(C)

2M 3

(D)

M 2

RM is the direct common tangent to the circles with centres C1 and C2. Points C1, P, Q, C2 K and N are six distinct points on the same straight line. The radii of both the circles are integral multiples of a cm and radius of the circle with C1 as the center is greater than that of the circle with C2 as the center. If PQ = 2cm and RM = 8 cm, then find the length of KN.

P

Q

C1

K

N

C2 M R

(A) 14.

9 5

(B) 3 cm

(C)

11 4

(D) 2 cm

The inscribed circle of right angled triangle ABC touches the sides AB, BC and CA at D, E and F respectively. If AD = 6 cm and BE = 5 cm, then find the length of AC. A

6 F D

B 5

(A) 59 cm 15.

C

E

(B) 57 cm

(C) 55 cm

(D) 61 cm

In PQR, PQ = PR, S and T are points on PR and PQ respectively such that RQ = QS = ST = TP. PTS equals : P

T

S

Q

(A) 16.

 7

(B)

R

2 7

(C)

3 7

(D)

5 7

In the figure, AB and CD are diameters of the circle. AB is perpendicular to CD and chord DF intersects AB at E. If DE = 6 units and EF = 2 units, then the area of the circle is : C F

A

O E

B

D

(A) 32

(B) 22

(C) 36

(D) 24

17.

In the adjoining figure, ABCD is a parallelogram. AD is parallel to FE and

AF 2 BG is then find . FB 3 GD

C

D E G A

(A)

18.

3 5

(B)

F

B

3 8

(C)

1 2

(D)

2 5

Consider the rectangle ABCD as shown, E is a point on CD su ch that AE = 3 unit, BE = 4 unit and AE  BE. The area of rectangle ABCD is : A

B 3

D

(A) 8 sq. unit

(B) 10 sq. unit

E

4 C

(C) 12 sq. unit

(D) 14 sq. unit

WO RKS HO P F OR IJ SO IIT-JEE | AIPMT | AIEEE | OLYMPIADS | KVPY | NTSE Subject : Mathematics

1.

2.

The equation 2x +

DAILY PRACTICE PROBLEMS SESSION-2011-12

Topic : ALGEBRA AND SETS

DPP No. 04

x  3 = 9 has :

(A) Two real roots and one imaginary roots

(B) One real & one imaginary

(C) Two imaginary roots

(D) Two real roots

Rahul and Sameer solved a quadratic equation while solving it, Rahul made a mistake in the constant term and obtained the roots as 5, – 3. Where as sameer made a mistake in the coefficient of x and obtained the roots as 1, – 3. The correct roots of quadratic equation are : (A) 1, 3

3.

4.

(D) 1, – 1

(A) at least three real roots

(B) no real roots

(C) at least two real roots

(D) two real roots and two imaginary roots

If a3 = b3 and a  b, then the sum of the roots of equation x2 – (a2 + ab + b2) x + k = 0 is equal to : (C) a2

(B) k

The number of roots satisfying the equation (A) 1

6.

(C) – 1, – 3

If f(x) = ax2 + bx + c, g(x) = – ax2 + bx + c, where ac  0, then f(x).g(x) = 0, has :

(A) 0 5.

(B) – 1, 3

(B) 3

(D) b2

5  x = x 5  x is/are : (C) 2

(D) 4

The possible values of the coefficient ‘a’ for which x2 + ax + 1 = 0 and x2 + x + a = 0 have at least one common root are : (A) a = 1 & 2

7.

(C) a = – 1 & 2

(B) 3

(C) 4

(D) 5

(2x2 + 3x + 5)1/2 + (2x2 + 3x + 20)1/2 = 15, therefore x is : 8  (A)   3 

9.

10.

(D) a = – 1 & – 2

If 4a – 5 + b = 2a + b × 2b × 2a – 4 – 63, then find the sum of a and b. (A) 2

8.

(B) a = 1 & – 2

 14    11   (B)   (C) 4 &   5   2  1 1 1 Find the sum of the series + + + ..... (3  7 ) (7  11) (11 15) 1 1 1 (A) (B) (C) 3 6 12

(D) 4

(D)

1 24

The roots of the equation 12x2 + mx + 5 = 0 will be in the ratio 3 : 2, if m equals :

(A)

1 12

(B)

5 12 10

(C)

5 10 12

(D) ± 5 10

11.

What is the maximum possible value of (A)

12.

13.

1 2

(B)

5 8

x for which (x – 2)2 = 9 and (y – 3)2 = 25 ? y 1 5 (C) (D) 8 2

The set {x : (x – 3)(x – 5) > 0} is equal to : (A) {x : 3 < x < 5}

(B) {x : x < 3}  {x : x < 5}

(C) {x : x < 3}  (x : x > 5}

(D) none of these

If A is the set of all integral multiples of 3 and B is the set of all integral multiples of 5, then A  B is the set of all integral multiples of : (A) 3 + 5

14.

(B) 6

(D) LCM (3, 5)

(C) 9

(D) 18

If the sets A and B are defined as 1   A = x , y  ; y  , 0  x  R  , B = x  

(A) A  B  A 16.

(C) GCD (3, 5)

If A has 3 elements and B has 6 elements, then the minimum number of elements in A  B is : (A) 3

15.

(B) 5 – 3

x , y  ; y   x, x  R, then

(B) A  B  B

(C) A  B  

(D) None of these

Out of 800 boys in a school, 224 played cricket, 240 played hockey and 336 played basketball. Of the total, 64 played both basketball and hockey ; 80 played cricket and basketball and 40 played cricket and hockey 24 player all the three games. The number of boys who did not play any game is (A) 128

17.

(B) 216

20.

1 2

(C)

1 4

(D) – 1

(B) y – x

(C)

1 1 – x y

(D)

(B)

x 3  y  3 x 3 y 1  ( xy ) 2  y 3 x 1 (A) x + y

19.

(D) 160

If a2 + b2 + c 2 = 1, then which of the following cannot be a value of (ab + bc + ca) ? (A) 0

18.

(C) 240

If a1/3 + b1/3 + c1/3 = 0, then : (A) a + b + c = 0 (B) a + b + c = 3abc

(C) a3 + b3 + c3 = 0

1 1 + x y

(D) (a + b + c)3 = 27abc

In a group of 500 people, 200 can speak Hindi alonewhile only 125 can speak English alone. The number of people who can speak both Hindi and English is : (A) 175 (B) 325 (C) 300 (D) 375

WORKSHOP FOR IJSO IIT-JEE | AIPMT | AIEEE | OLYMPIADS | KVPY | NTSE Subject : Mathematics 1.

DAILY PRACTICE PROBLEMS SESSION-2011-12

Topic : MENSURATION

DPP No. 05

A cow is tied by a rope to one of the vertices of a square of side 14cm. The length of the rope is 7 cm. What percentage of the field is grazed by the cow ? (A) 15%

2.

(B) 25%

(C) 18%

(D) 19.6%

A solid sphere is cut into 16 identical with 5 cuts. What is the percentage increase in the combined total surface area of all the pieces over that of the original sphere ? (A) 350%

3.

(B) 150%

(C) 200%

(D) 250%

There is a cage in hemisphere-shape in which a canary sleeps at the centre of the base. It wakes up, flies to the top-most point in the cage, then in a straight line to the cage door at the intersection of the curved surface and the base. It covers a total distance of 241 yards. Find out the approximate radius of the hemispheric cage. (A)120.5 yards

4.

(B) 140 yards

(C) 50 yards

(D) 100 yards

If the perimeter of a rectangle is p and its diagonal is d, then the difference between the length and width of the rectagle is

(A)

5.

8d2  p2 2

(B)

8d 2  p 2 2

(C)

6d2  p2 2

(D)

8d2  p2 4

On a square kilometre land, 2 cm of rain has fallen. Assuming that 50% fo the raindrops could have been collected and contained in a pool having a (100 × 10) m2 base, find to what level the water level in the pool has increased. (You have to assume that base of the pool is horizontal. (A) 9.86 m

6.

(B) 15 m

(C) 10 m

(D) 20 m

A large solid sphere is melted and moulded to form identical right circular cones wih base radius and height same as the radius of the sphere. One of these cones is melted and moulded to from a smaller solid sphere. What is the ratio of the surface area of the smaller sphere to the surface area of the larger sphere ? (A) 1 : 34/3

7.

(B) 1 : 23/2

(C) 1 : 33/2

(D) 1 : 24/3

A closed wooden box measures externally 9 cm long, 7 cm broad and 6 cm high. If the thickness of the wood is half a centimetre, find the capacity of the box. (A) 278 cm3

8.

(B) 215 cm3

(C) 224 cm3

(D) 240 cm3

An equilateral triangle of side 6 cm is cut into smaller equilateral triangle of side 2 cm. What is the greatest number of the smaller triangles that can be formed ? (A) 9

9.

(B) 6

(C) 12

(D) 15

A goat is tied at A, one of the vertices of a building which is in the shape of an equilateral triangular prism. The length of each side of the building is 6 cm. The length of the rope to which the goat is tied with is 12m. There is a huge lawn on the unshaded part of the compound. What is the area of the lawn that the goat can graze on ? (Figure shows the view from the top.)

A

(A) 144

(B) 128

(C) 84

(D) 60

10.

The diameter of a circle is 10 cm. The radius of this circle is taken as a diameter and another circle is drawn. A third circle is drawn with the radius of the second circle as its diameter. This process is repeated n times until the diameter of the nth circle is less than 0.01 cm. What is the value of n ? (A) 9 (B) 10 (C) 11 (D) 12

11.

Let A0 A1 A2 A3 A4 A5 be a regular hexagon inscribed in a circle of unit radius.Then the product of the lengths of the line segments A0 A1, A0 A2 & A0 A4 is: (A)

12.

3 4

(B) 3 3

(C) 3

(D)

3 3 2

Two cylinders of same volume have their heights in the ratio 1 : 3, find the ratio of their radii – (A)

3 :1

(B)

2 :1

(C)

5 :2

(D) 2 :

5

13.

If the radii of the ends of a bucket, 45 cm high are 28 cm, and 7 cm, determine it's surface area. (A) 555 cm2 (B) 545.50 cm2 (C) 561.49 cm2 (D) 567.49 cm2

14.

The height of a cone is 30 cm. A small cone is cut off at the top by a plane parallel to the base. If its

1 of the volume of the given cone, then the height above the base at which section has 27 been made is– (A) 10 cm (B) 15 cm (C) 20 cm (D) 25 cm volume be

15.

If h be the height and  the semi vertical angle of a right circular cone, then its volume is given by (A)

1 3 h tan2 3

(B)

1 2 h tan2 3

(C)

1 2 h tan3 3

(D)

1 3 h tan3 3

16.

The slant height of a cone is increased by P%. If radius remains same, the curved surface area is increased by – (A) P% (B) P2% (C) 2 P% (D) None

17.

A hollow spherical ball whose inner radius is 4 cm is full of water. Half of the water is transferred to a conical cup and it completely filled the cup. If the height of the cup is 2 cm, then the radius of the base of cone in cm is : (A) 4 (B) 8 (C) 8 (D) 16

18.

A square and an equilateral triangle are inscribed incircle of radius 2007 cm. The ratio of the squares of their sides is (A) 2 : 3 (B) 3 : 2 (C) 3 : 4 (D) 4 : 3

19.

In the diagram ABC is right angled at C. Also M, N and P are the mid points of sides BC, AC and AB, respectively. If the area of APN is 2 sq. cm, then the area of ABC, in sq. cm is :

(A) 8 20.

(B) 12

(C) 16

(D) 4

Two circles occupy the positions shown with respect to the two squares. The two circles are each inscribed in their square and the small square is inscribed in the large circle. What is the difference in the areas of the two shaded regions if the small square has sides which measure 8 cm ?

(A) 8 – 2

(B) 16 – 4

(C) 32 – 8

(D) 64 – 16