Linear Inequality DLP

 

 

Department of education Region 02 Division of Quirino Maddela District II CABARUAN INTEGRATED SCHOOL Detailed Lesson Plan in MATH VIII

Name of Teacher: MAYLEEN V. YANTO Grade and Section: VIII- PURITY

Date: September 17, 2019 Time: 1:00-2:00

Quarter 2 Week 6 Day 2 I. Objectives:

a. Identify the solution of a linear equation or inequality in two variables. b. Determine whether a point is a solution of a linear inequality or not. c. Appreciate Appreciate the concept of linear inequality in two variables. A. Content Standard:

The learner demonstrates key concepts of linear inequalities in two variables, systems of linear inequalities in two t wo variables and linear functions.   B. Performance Standard:

The learner is able to formulate and solve accurately real-life problems involving linear inequalities in two variables, systems of linear inequalities in two variables, and linear functions.  C. Learning Competencies:

Differentiate linear inequalities in two variables from linear equations in two variables. (MBAL-IIa-2) II. Content : The learner demonstrates understanding on the solution solutio n of linear inequality. III. Learning Resources A. References: 1. Curriculum Guide 2. Teaching Guide pages 200-203  3. Learners’ Materials pages 220-222 4. Textbook: Next Century Mathematics: Intermediate Algebra, pages 83 - 84 5. LRDMS http://lrmds.deped.gov.ph/.  6.Other References: Materials : Powerpoint printed materials , show me board and marker IV. Procedures Teacher’s Activity  Pupil’s Activity  A.  Preliminary Activity A. Review of Previous/Presen Checking of attendance and opening prayer. ting New One student will lead The students will stay in their Lessons the prayer. group. The students will go their groups quietly. 1.  Prepation –  Identify what symbol is being shown. Each question

Less than or Equal to

KRA/OBJECTIVE 

 

 

is equivalent to one trash. They need to put it trash to the right garbage bin.

≤(Biodegradable) ≠(Residual) >(Hard Palstic) ≥(Special Waste)

Not equal to Greater than Greater than or equal to Less than Equal

10. 2x + 5y ≥ 10;(5,0)  10;(5,0)  x = 5 and y = 0 2(5) + 5(0) ≥ 10  10  10 + 0 ≥ 10  10  10 ≥ 10 False  False  Thus, (0, 0) is a solution to 2x + 5y > 10 ----------------------------2x + 5y ≥ 10;(0,0)  10;(0,0)  x = 0 and y = 0 2(0) + 5(0) ≥ 10  10 

 

 

0 + 0 ≥ 10  10  0 ≥ 10 False  False  Thus, (0, 0) is not a solution to 2x + 5y > 10 -------------------------------2x + 5y ≥ 10;(-2,3) 10;(-2,3) x = -2 and y = 3 2(-2) + 5(3) ≥ 10  2(-2) 10  ((-4) 4) + 15 ≥ 10  10  11 ≥ 10 True  True  Thus, (5, 0) is a solution to 2x + 5y > 10 Did you understand? D. Discussing New Concepts and Presenting New Skills S #1

E. Discussing New Concepts and Presenting New Skills S #2

1. What can you say about the solution of a linear equation? 2. When can you say that a point is a solution to a linear inequality in two variables? 3. How can you solve if a point is a solution to a linear equation or inequality in two variables?  The first one will serve as an example, the other four will be performed by each group. Fill in the blanks then state whether each given ordered pair is the inequality. 1. ax solution + 2y ≤ 8;of(6,1) x = ___ and y = ___  ___ + 2 (___) ≤ 8 6 + ___ ≤ 8  ___ ≤ 8  8   ________ Thus, __________  _______________  _____________ __   identify x and y   substitute the values of x and y   simplify   True or False   Write your conclusion 



OBJECTIVE 3

They will present their output through their interest.

1. x + 2y ≤ 8; (6,1) x = 6 and y = 1 6 + 2 (1) (1) ≤ 8 6+2≤8 8≤ 8  8  TRUE Thus, (6,1) is a solution of the inequality x + 2y ≤ 8  8  2. x - y ≥ -2: (-6, -8) x = -6 and y = -8

 



-6 - ( -8)≥ -8)≥-2 -6 + 8 ≥-2 -2 _≥  _≥-2 -2

OBJECTIVE 2,3,6

 

 

2. x - y ≥ -2: (-6, -8) x + ___ and y = ___  ___ - ( ___)≥-2 ___)≥-2 -6 + ___≥-2 ___≥-2  ___≥-2  ___≥ -2  ___________ Thus, _______  ____________ 3. 2x – 2x –  y 7: (3, -1) x = ___ and y = ____ 2(___)- ___< 7  ___ + ___< 7  ___< 7  ____________ Thus, _______  ____________ 4. 3x – 3x – y  y > 6;(0,0) x = ___ and y = ____ 3(___) + ___>6  ____ + ___>6  ___  __________ Thus, ______  ___________ 5. x + y ≤ 8; (5,4)  (5,4)  x = ___ and y = ___  ___ +___ ≤ 8  8   ___ ≤ 8  8   __________

TRUE Thus, (-6,-8) is a solution of the inequality x - y ≥ -2 3. 2x – 2x – y  y < 7: (3, -1) x = 3 and y = -1 2(3)- -1< 7 6 + 1< 77< 7 FALSE Thus, (3,-1) is not a solution of the inequality 2x – 2x – y  y < 7 4. 3x + y > 6;(0,0) x = 0 and y = 0 3(0) + 0>6 0+ 0>6 0>6 FALSE Thus, (0,0) is NOT a solution of the inequality 3x + y > 6 5. x + y ≤ 8; (5,4)  (5,4)  x = 5 and y = 4 5 +4 ≤ 8  8   _9 ≤ 8  8  FALSE Thus, (5,4) is a solution of the inequality x + y ≤ 8  8 

Thus, _____  __________ *Ribbons will be given to the most outstanding group.  F. Developing Mastery (Formative Assessment) G. Making Generalizations (Abstraction of the Lesson)

What have you learned from the activity? How did you come up with your answer?

Answers may vary

  The solution of a linear equation is the set of points which lies on



What can you conclude from our lesson?

the line.

OBJECTIVE 4

 

 

  A solution of a linear inequality in two variables is an ordered pair (x, y) which makes the equation or



inequality true. H. Finding Practical Application of Concepts

In a ¼ sheet of paper work with your seatmate and write one linear inequality and give one solution.

I. Evaluatin Evaluating g Learning

Which of the following points is a solution to the following equations/ inequalities? Encircle your answer/s.

J. Assignments (Optional)

Students will be working cooperatively.

−2 ; (-4,5) 1.  5 −  > −2

1. NS

2.   − 2 > −2; −2; (3,4 3,4)) 

2. NS

−8; (3, −1 −10 0)  3.  4 +  < −8;

3. NS

5,1))  4.   +  ≥ −2 ; (5,1

4. S

5.  −3 +  ≤ 0; (1, (1,1) 1) 

5. S

.Which ordered pair satisfies the inequality 3/2 x - 1/4y ≤ 1 ?  ?  a. (0, -5) b. (3, -5) c. (0, 1) d. (6, 0)

V. Remarks(Mga tala)

Prepared By: MAYLEEN V. YANTO Teacher III Checked: FERDIE B. MAXIMO HT-I Noted:

DANTE P. TAIPAN Principal II