Lifting Lugs

February 3, 2018 | Author: Adi Cahyoko | Category: Solid Mechanics, Nature, Mathematics, Engineering, Science
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LIFTING LUGS ON TOP HEAD FR(x.z)

FR(x,z) FR(x,z,y)

 d

Fz

Fy

Fx



x

x

y

y Mx

My

h

Mt P

P H B VIEW Y-Z

VIEW X-Z

Lug Dimension: Lug width Lug thickness Lug radius Shackle/bolt pin diameter Pin hole diameter Center of lug from A-A Swing angle Side swing angle Lenght of weld Fillet weld size used Allowable load on weld

B H R dp d h   Lw fw f

Lifting Weight & Design Load: Load ( Empty Weight = 4721.50 kg ) Dinamic Factor Total load Number of lifting lug Load per lug

W = = Wt = n = P =

Lug material: Lug material selected Yield stress of material

Sy =

:

Allowable stress for lug (AISC Code): g stress Allowable bending Allowable shear stress Allowable tension stress Allowable bearing stress Force Acting on the Lug: At View X-Z Resultan force Vertical force Horizontal force At View Y-Z Transverse force Resultan force Required thickness

= = = = = = = = = = =

140 20 40 21 30 75 60 90 320 9.00 66.19

mm mm mm mm mm mm Deg. Deg. mm mm MPa

46317.92 N 2.00 92635.83 N 3.00 30878.61 N

SA 240 304L

Fb Fs Ft Fp

= = = =

172.40 MPa

y 0.66 * Sy 0.25 * Sy 0.66 * Sy 0.9 * Sy

FR(x,z) = P / Sin () Fz = FR(x,z) * Sin () Fx = FR(x,z) * Cos () Fy = P / Tan () 2

2

FR(x,z,y) = (Fy + FR(x,z) )^

0.5

t = FR(x,z,y)/(2*Fs*(R - d/2)) Thickness is acceptable, since

= = = =

113.78 43.10 113.78 155.16

= = =

35655.55 N 30878.61 N 17827.77 N

=

0.00 N

=

35655.55 N

= <

MPa MPa MPa MPa

16.55 mm 20.00 mm

Moment Acting on the Lug: Moment in z-direction Moment in y-direction Moment in x-direction

Mz = Fy * h My = Fz * h Mx = Torsion

= = =

0.00 N-mm 1337083.03 N-mm 0.00 N-mm

Stress Analysis on lug: Section modulus at x-axis

2 Zz-z = B * H / 6

=

3 9333.33 mm

Section modulus at y-axis

2 Zy-y = B * H / 6

=

3 65333.33 mm

= = =

0.00 MPa 20.47 MPa 6.37 MPa

Bending stress

fbz = Mz / Zz-z fby = My / Zy-y ft = Fx / ((B * H))

Tensile / compressive stress p Unity Check: ft/Ft + fbz/Fb + Fby/Fb < 1

= 0.2358 Stress is acceptable, since < 1

Stress Analysis on weld: Compression load on fillet weld per linier mm

=

2

Section modulus of fillet weld Bending force at fillet weld Shear force at fillet weld Resultan force at fillet weld Fillet weld size

L = Fx / Lw

WR

<

1.0000

55.71 N/mm

Swz = B / 3

=

2 6533.33 mm

Swy Wbz Wby Wsz Wsy

= = = = =

2800.00 2800 00 204.66 0.00 96.50 0.00

= = = = =

B*H My / Swz Mz / Swy Fz / Lw Fy / Lw

mm2 N/mm N/mm N/mm N/mm

2 2 2 2 2 0.5 = (L +Wbz +Wby +Wsz +Wsy )^ tw = WR / f Fillet weld size is acceptable, since

= = <

A = 2 * (R - d/2) * H fs = FR(x,z,y) / A Shear stress is acceptable, since

= = <

2 1000.00 mm 35.66 MPa 43.10 MPa

= = <

2 420.00 mm 84.89 MPa 155.16 MPa

233.02 N/mm 3.52 mm 9.00 mm

Shear Stress at Pin Hole: Shear area Shear stress Bearing Stress at Pin Hole: Additional check plate thickness to lug Bearing area Bearing g stress

T =

0

Ap = dp * H fpp = FR(x,z,y) ( y) / Ap p Bearing stress is acceptable

mm

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