Download Latihan SPM Permutations and Combinations...
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SEKOLAH MENENGAH KEBANGSAAN AGAMA MAAHAD MUAR ADDITIONAL MATHEMATICS FORM 5 PERMUTATIONS AND COMBINATIONS
SPM 2009
(PERMUTATION)
22. There are 4 different Science books and 3 different Mathematics books on a shelf. Calculate the number of different ways to arrange all the books in a row if (a) no condition is imposed, (b) all the Mathematics books are next to each other. [4 marks] {Ans: (a) 5040, (b) 720} SPM 2008
(PERMUTATION)
23. Diagram 23 shows six numbered cards.
3
5
6
7
8
9
Diagram 23 A four digit number is to be formed by using four of these cards. How many (a) different numbers can be formed? (b) different odd numbers can be formed?
[4 marks] {Ans: (a) 360, (b) 240}
SPM 2007
(COMBINATION)
23. A coach wants to choose 5 players consisting of 2 boys and 3 girls to form a badminton team. These five players are chosen from a group of 4 boys and 5 girls. g irls. Find (a) the number of ways the team can be formed, (b) the number of ways the team members can be arranged in a row for a group photograph, if the three girls sit next to each other. [4 marks] {Ans: (a) 60, (b) 36} SPM 2006
(PERMUTATION)
22. Diagram 9 shows seven letter cards.
U
N
I
F
O
R
Diagram 9 A four letters code is to be formed using four of these the se cards. Find (a) the number of different four-letter codes that can be formed, (b) the number of different four letter codes which end with a constant.
M
[4 marks] {Ans: (a) 840, (b) 480}
SPM 2005
(COMBINATION)
22. A debating team consists of 5 students. These students are chosen from 4 monitors, 2 assistant monitors and 6 prefects. Calculate the number of different ways the team can be formed if (a) there is no restriction, (b) the team contains only 1 monitor and exactly 3 prefects. [4 marks] {Ans: (a) 792, (b) 160} SPM 2004
(PERMUTATION)
23. Diagram 6 shows five cards of different letters.
H
E
B
A
T
Diagram 6 (a) Find the number of possible arrangements, in row, of all the cards, (b) Find the number of these arrangements in which the letters E and A are side by side.
[4 marks] {Ans: (a) 120, (b) 48}
SPM 2003
(PERMUTATION)
22. Diagram 6 shows 5 letters and 3 digits.
A B C D E 6 7 8 Diagram 6 A code is to be formed using those letters and digits. The code must consist of three letters followed by 2 digits. digi ts. How many codes can be formed if no letter or digit is repeated in each code? [3 marks] {Ans: 360}
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