l5prob1
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Description
X
X
X
X Y Y p 0 < p < 1 p = 1/2 Y (1/ (1/2) , y = 0, 1, 2, 3, 4 p(1/(12)−(1/ p) p) , y = 0, 1, 2, . . . , n 4
y n y
y
y
4−y
n−y
4
y
4−y
p (1 − p) P ( P (Y = y) = p ) y
, y = 0, 1, 2, 3, 4
P ( P (Y = y ) = P ( P (Y = y ) =
Y Y P ( P (Y = Y = 0) = 252/ 252/300 P ( P (Y = 50 50..000) = 46/ 46/300 P ( P (Y Y = 100. 100.000) = 2/ 2/300 E (Y ) Y ) = 8333, 8333, 33 T
p( p(t)
E (T ) T ) = 4, 6 E (G) = 2, 75
G = P ( P (G = 2) = 0, 0, 3 P ( P (G = 2, 5) = 0, 0, 2 P ( P (G = 3) = 0, 0, 3 P ( P (G = 3, 5) = 0, 0, 1 P ( P (G = 4) = 0, 0, 1 V ar( ar(G) = 0, 4125
9 · 10−6
1, 21 · 10−19
λ = 2
0, x
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