PROBLEM 9.142 Determine the mass moments of inertia and the radii of gyration of the steel machine element shown with respect to the x and y axes. (The density of steel is 7850 kg/m3.)
SOLUTION
First compute the mass of each component. We have m = ρSTV
Using Figure 9.28 for components 1, 4, and 5 and the equations derived above (before the solution to Problem 9.144) for a semicylinder, we have I x = ( I x )1 + ( I x )2 + ( I x )3 + ( I x ) 4 − ( I x )5
where ( I x ) 2 = ( I x )3
1 1 = (10.5504 kg)(0.042 + 0.142 ) m 2 + 2 (2.41683 kg)[3(0.07 m) 2 + (0.04 m) 2 ] 12 12 1 + (1.90979 kg)[3(0.044 m) 2 + (0.04 m) 2 ] + (1.90979 kg)(0.04 m) 2 12 1 − (1.90979 kg)[3(0.044 m)2 + (0.04 m)2 ] 12 = [(0.0186390) + 2(0.0032829) + (0.0011790 + 0.0030557) − (0.0011790)] kg ⋅ m 2 = 0.0282605 kg ⋅ m 2
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