ISMC 2016 Primary 4 Solutions

September 5, 2022 | Author: Anonymous | Category: N/A
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_9

5.

Hfr e judcbr tf cb ilvlslc`b cy 2 eji 9, tmb `est `est ilalt mes tf cb ?. Hfr e judcbr tf cb ilvlslc`b cy > tmb sud fh e`` tmb ilalts mes tf cb e du`tlp`b fh >. Hfr e judcbr tf cb ilvlslc`b cy 9 tmb `est twf ilalts mevb tf hfrd e du`tlp`b fh 9. ^f her, hfur fut fh tmb slx ilalts eii up tf 3 + = + < + ? 4 5< ^ljnb tmb judcbr ls tf cb es sde`` es pfsslc`b, tmb jbxt du`tlp`b fh > ls 35, eji sljnb 35 „ 5< 4 3, tmb ilalt 3 mes tf fnnupy tmb Ybjs p`enb, eji ? mes tf fnnupy tmb Mujirbis p`enb. Ymb `est twf ilalts (3?) ls e du`tlp`b fh 9. Mbjnb tmb 8-ilalt judcbr ls 3=< ?3?.

3.

^ljnb tmb `erabst nfddfj hentfr ls 53, tmbj E eji C erb du`tlp`bs fh 53. ^ljnb 5=? 4 53 Ñ 52, eji 52 4 5 Ñ 52 fr > Ñ 2, tmbj tmb twf judcbrs nfu`i cb bltmbr E 4 53 Ñ 5 eji C 4 53 Ñ 52 fr E 4 53 Ñ > eji C 4 53 Ñ 2 Mfwbvbr, sljnb tmb `erabr judcbr ls jft e du`tlp`b fh tmb sde``br, tmbj tmb twf judcbrs dust cb 53 Ñ > 4 >8 eji 53 Ñ 2 4 8?.

>.

Ymb frlalje` hlaurb mes tmb sedb pbrldbtbr es tmb rbnteja`b wltm tmb ifttbi `ljbs. @bjatm fh rbnteja`b 4 53 nd       d Crbeitm fh rbnteja`b 4 3 + = 4 5? nd   n    3 _brldbtbr 4 3 Ñ (5? + 53) 4 99 nd     d   n    =

53 nd

9.

Ymb smfrtbr prfareddb ls Jbws. Ymb `fjabr prfareddb ls Ilsnfvbry ^nlbjnb.

2.

Nfdcljlja tmb twf smeibi perts wl`` dekb e queirejt.  Mbjnb  fh tmb nlrn`b ls smeibi. 

I F

NC

 E

8.







2









8



Nmejab  4   eji  4   tf Ymbrbhfrb,

1.

 

 4

2

2



=

 4

2



?

?





  eji  4

 , tmbj c 4 3?, e 4 52 eji n  4  4 39,

 4  

Hrfd Hla. E eji C, C, ce``s ce``s 5, 3, 1 eji = erb jft tmb `lamtbr fjbs. Ennfrilja Ennfrilja tf Hla N tmbj, fjb fh tmb `lamtbr ce``s dust cb 9 eji tmb ftmbr dust cb bltmbr > fr 2. Mfwbvbr, lh tmb `lamtbr ce``s erb > eji 9, es lj Hla E, tmbj ce``s 1, = eji 2, 8 (lj Hla C) smfu`i cb cbbj ce`ejnbi eji jft tl`tbi. Mbjnb, ce`` > ls jft tmb `lamtbr ce``. Ymbrbhfrb, ce`` 2 dust cb tmb ftmbr `lamtbr ce``. Ymb twf `lamtbr ce``s erb ce``s 9 eji 2.

 

=.

C

 E N

ri eji 9tm c`ejks smfu`i e`sf cb tmb jbxt `erabst pfsslc`b. Ymb 5st c`ejk smfu`i cb tmb `erabst eji tmb 3 ji c`ejk smfu`i cb tmb sde``bst Ymb >ri eji 9tm c`ejks smfu`i cb tmb jbxt `erabst judcbrs sf = eji 1.

 sf



< eji 5.



Ymb `est hfur judcbrs dust hfrd tmb sde``bst judcbr7 ( tm

tm

Ñ

+

 „ 

tm

Ymb 2 , 8c`ejk  ejismfu`i 1  c`ejks smfu`i cb tmb jbxt Ymb `est tmb jbxt `erabst sf 8.sde``bst pfsslc`b





sf 3, > eji 9.

Ymbrbhfrb, tmb c`ejks smfu`i cb hl``bi tmus7 [ 

53.

<

ñ  5

Ñ (  (  =

+

1

)T  „ 

(

3

Ñ

>

+

9

-

8

)

3

2 ujlts 4 52 53 ujlts 4 (52 ñ 2) Ñ 53 4 >8 Ymb judcbr ls >8.

>

5 9

 

 

=+1

)

 

5>.

5st `eybr mes 5 frejab 3ji `eybr mes 9 frejabs >ri `eybr mes < frejabs 9tm `eybr mes 58 frejabs 2tm `eybr mes 32 frejabs 8tm `eybr mes >8 frejabs Ymus tfte` ls 5 + 9 + < + 58 + 32 + >8 4 `ljb fh syddbtry

(>) Nfet

(9) Met

Judcbr fh plbnbs > 8 =

58.

Yrub Jfjb fh tmb eja`bs irewj erb dfrb tmej
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