ISMC 2016 Primary 3 Solutions

September 5, 2022 | Author: Anonymous | Category: N/A
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V84

7. 766

37 =: (766 ‘ (766  ‘ =:)  =:) ü 3 1 37

37 =: 1 grm 37 goe . Ujm+ouacmrs

3.

Ujm ouacmrs no Hbkuao C grm auktnpkms b` 0. Jmohm, tjm ouacmr 5: wbuke wbuke jgvm cmmo no Hbkuao C. Ujmrm`brm, tjm ouacmr 5< wgs no Hbkuao G.  G

C

= 77

0 73 7:

H 7 < 78 7>

E 3 : 75 36 30

M 8 > 7= 37 3<

@ 5 76 70 33 3:

oe

re

8.

Mkkmo ns cmtwmmo Enogj goe Hycnk, sb Mkkmo ns 3  goe Hycnk ns 8 . Hycnk ns cmtwmmo Cnkky goe Mkkmo, sb Cnkky aust cm 5tj.

5.

Ujmrm grm < cnres butsnem tjm squgrm goe > cnres butsnem tjm hnrhkm. Mstjmr ommes tb ergw 3 abrm cnres no tjm spghms tjgt grm nosnem tjm hnrhkm cut obt nosnem tjm squgrm.

C

C

=.

386 ‘ 386  ‘ 76<  76< 1 738 Ujmrm grm 738 Ü 3 1 350 ebts gktblmtjmr.  7 br 8 Ü 78 Ujm rmhtgolkm hbuke cm 8> ha cy 7 ha, br 78 ha cy 8 ha. Kmoltj b` squgrm 1 76 ha Kmoltj b` rmhtgolkm jgs tb cm abrm tjgo 76 ha cut kmss tjgo t jgo 36 ha. Jmohm kmoltj b` rmhtgolkm 1 78 ha, obt 8> ha. Ujmo crmgetj b` rmhtgolkm 1 78 ‘ 78  ‘ 76  76 1 8 ha Vmrnamtmr b` rmhtgolkm 1 (78 + 8) Ü 3 1 83 ha

77. 3675 3675 ‘  ‘ 7>>>  7>>> 1 7= ymgrs  Gamkng ns 7= ymgrs ymgrs bkemr tjgo Cbccy. Cbccy.  Gamkng wnkk wnkk cm twnhm gs bke gs Cbccy Cbccy wjmo jm jm ns 7= ymgrs bke. 3675 + 7= 1 363>  Gamkng wnkk wnkk cm twnhm gs bke gs Cbccy Cbccy wjmo Cbccy Cbccy ns 7= ymgrs bke bke no 363>. 73.

78 N` Sus ns snttnol snttnol bo tjm km`t b` Pgk, tjmo tjmo Pgk ns bppbsntm Una, wntj wntj Sus cmtwmmo cmtwmmo tjma. Xga ns bppbsntm Sus goe Una ns bo Xga„s rnljt.  rnljt.  75. Dgams wgs gjmge b` Agrnga. Xntn wgs : ‘ 0  ‘ 0 1 3 a cmjnoe Agrnga.  Xnohm Gkn wgs < a gjmge b` Agrnga wjnkm Dgams wgs : a gjmge b` Agrnga, Gkn ns 7 a cmjnoe Dgams. Ujmrm`brm, tjm bremr wgs Dgams, Gkn, Agrnga goe Xntn. Xmhboe no tjm rghm wgs Gkn.

 

7=.

70. 78

78

73

73

77

77

  m 76    k   p   b >   m   p :    `   b <   r   m    c   a   u    O

76 > : < 0 = 5 8 3 7

   j   s    n    `    `   b   r   m    c   a   u    O

0 = 5 8 3 7 7

3

8

5

=

Cus Xtbps

Uboy Auruk

 Gceuk

Cbys

Auruk jgs 78 ‘ 78 ‘ :  : 1 = `nsj Uboy jge 78 ‘ 78 ‘ 5  5 1 > `nsj 7. Xnohm M ns wjntm goe wjntm ebms obt obt tbuhj mntjmr pnoi br lrmmo, tjmo G goe C grm mntjmr pnoi br lrmmo. Sme goe ymkkbw jgs tb cm mntjmr E br @ snohm tjmy eb obt tbuhj mghj btjmr.

M  G

Ujmrm`brm, H jgs tb cm ckghi.

H @ C

36. Ubtgk ouacmr tjgt Dbjo, Imo goe Knbomk jgvm 1 (3= + 36 + 87) ü 3 1 8: Ouacmr b` cbbis Knbomk jgs 1 8: ‘ 8: ‘ 3=  3= 1 78 Ouacmr b` cbbis Imo jgs 1 8: ‘ 8:  ‘ 36  36 1 7: Ouacmr b` cbbis Dbjo jgs 1 8: ‘ 8: ‘ 87  87 1 < Imo jgs tjm abst ouacmr b` cbbis. Jm jgs 7: cbbis.

 

37.

33. Grrgolm Gr rgolm tjm lumssms no gshmoenol bremr4

35 3= ¤ 3< ¤ 3> ¤ 87

Ujm ns 3 lumssme grm wrbolhbrrmhtky. cy 39 goe 35 ns wrbol cy 89 goe 87 ns wrbol cy 5.goswmr Ujmrm`brm, wgs Egvne wjb

38.

Sme Cgkks 756 ^mkkbw Cgkks

<

< uonts 1 756 ‘ 756 ‘ <  < 1 788 7 uont 1 788  < 1 7> 8 uonts 1 8 Ü 7> 1 =< Ouacmr b` ymkkbw cgkks 1 =< + < 1 05

35.  G`tmr4

>

 Ggrbo

3

Jgruo 7

3 3

7>

76

7> 7> ‘  ‘ 7  7 1 7: 7: ü 3 1 >  G`tmr lnvnol tjm hbnos, hbnos, Ggrbo jgs > h hbnos bnos goe Jg Jgruo ruo jgs > + 7 1 76 hbnos hbnos Cm`brm lnvnol tjm hbnos, Ggrbo jgs > ‘ >  ‘ 3  3 1 < hbnos goe Jgruo jgs 76 + 3 1 73 hbnos

3=. Ujm tbp shbrmr `br Agtjmagtnhs ns g lnrk, lnrk, jmohm nt jgs tb cm mntjmr Mvmkyo br Agry. Jbw Jbwmvmr, mvmr, snohm Agry ene obt eb wmkk `br Agtjmagtnhs, tjmo tjm tbp shbrmr `br Agtjmagtnhs ns Mvmkyo. Umrmohm, wjb ns obt lbbe gt Molknsj, ebms obt jgvm g twno, sb jm ns obt tjm Jnstbry tbp shbrmr. Jmohm, Umrmohm ns tjm tbp shbrmr `br Xhnmohm. Agry, wjb ene obt eb wmkk `br Jnstbry, ns tjm tbp shbrmr `br Molknsj. @nogkky, tjm tbp shbrmr `br Jnstbry ns Cbccy.

Agtjmagtnhs Molknsj Jnstbry Xhnmohm

Cbccy x x   x

Umrmohm x x x  

Mvmkyo   x x x

Agry x   x x

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