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D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

DESIGN CALCULATION INSULATION THCKNESS FOR HFO

FOR 150 NB HFO PIPE For unloading header A)

B)

C)

DESIGN DATA : A = S = V = T = O = D1

=

D2 D

= =

= = = = =

Outside Diameter of Un-Insulated Pipe

=

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness) Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

30 50 0.5 55 T+S 2 168.3

= =

= = = =

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C As per Clause 0.2 No. 7.1.1.2 ( C)

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.001109154

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 6.760824662 Kcal/m hr.

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 30.99983976 C < 55 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 52.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 55 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.001109154

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 6.760824662 Kcal/m hr.

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 30.99983976 C < 55 C

Therefore, Actual Insulation Thickness Provided on Cylindrical pipe

0 52.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 250 NB HFO PIPE Common Header suction line ( after HFO tank ) A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 60 T+S 2 273

0

C C m/s 0 C 0

=

0 55 C

mm

=

0.273 m

63.9 mm 436.9 mm

= =

0.0639 m 0.4369 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

= = = =

Film coefficient due to radiation + Film coefficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

0

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.205444597 0.002218309

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.998950978 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 31.03505561 C < 60 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe

=

50 mm

(Rev-C)

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE For Discharge line from HFO unloading pump to the common Header ( before HFO tank) A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 50 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

0

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.009621922 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 30.88874646 C < 50 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 50 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 200 NB HFO PIPE Short recirculation line from forwarding pump to HFO tank

A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 60 T+S 2 219.1

0

C C m/s 0 C 0

=

= = = =

mm

=

0.2191 m

42.6 mm 361.7 mm

= =

0.0426 m 0.3617 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

(Rev-B)

0 Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.181315469 0.002218309

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

0 55 C

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 7.886903738 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 31.1663725 C < 60 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE For discharge line from forwarding pump to boiler A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

35 55 0.5 140 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.035 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.931363509 W/m k 2 0 6.821048407 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.021807498

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 21.75871059 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 38.1899364 C = 2k(O-S) where, D1

f ( S-A)

LHS RHS

= =

0.190806548 0.021807498

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 21.75871059 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 38.1899364 C < 140 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 97.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 50 NB HFO PIPE From HFO tank to Drain oil Tank A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

35 55 0.5 60 T+S 2 60.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.0603 m

= =

0.0213 m 0.1816 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.931363509 W/m k 2 0 6.821048407 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

0

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.200209344 0.001099538

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.459155655 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 35.9469447 C < 60 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 57.5 C

21.3 mm 181.6 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE For Inter Tank Transfer line A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

35 55 0.5 60 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 144 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, Group 3 0.2 As per IS : 9842 , clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] W/m2k 7.931363509 Kcal/m2 hr. 0C 6.821048407

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.001099538

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 6.763430497

Kcal/m2 hr.

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 35.99155292 C < 60 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe 0

=

0 57.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 100 NB HFO PIPE discharge line from Drain oil Pump to HFO tank (40 NB) A)

B)

C)

DESIGN DATA : A = S = V = T = O = D1

=

D2 D

= =

= = = = =

Outside Diameter of Un-Insulated Pipe

=

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness) In = Natural Algorithm Mean temperature Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

0

C C m/s 0 C 0

= mm

=

0.1143 m

42.6 mm 256.9 mm

= =

0.0426 m 0.2569 m

=

0 87.5 C

= = = =

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.035 Kcal/hr. m C at 76.25 deg.C, Group 3 0.2 As per IS : 9842 , clause 3.6

For Cylindrical Surface of Pipe :

Check : D In D > = 2k(O-S) where, D1 LHS RHS

=

50 mm

=

50 mm

0

f ( S-A) = =

0.20805312 0.021807498

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 20.03980738

Kcal/m2 hr.

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 37.93793654 C

View more...
DESIGN CALCULATION INSULATION THCKNESS FOR HFO

FOR 150 NB HFO PIPE For unloading header A)

B)

C)

DESIGN DATA : A = S = V = T = O = D1

=

D2 D

= =

= = = = =

Outside Diameter of Un-Insulated Pipe

=

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness) Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

30 50 0.5 55 T+S 2 168.3

= =

= = = =

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C As per Clause 0.2 No. 7.1.1.2 ( C)

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.001109154

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 6.760824662 Kcal/m hr.

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 30.99983976 C < 55 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 52.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 55 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.001109154

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 6.760824662 Kcal/m hr.

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 30.99983976 C < 55 C

Therefore, Actual Insulation Thickness Provided on Cylindrical pipe

0 52.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 250 NB HFO PIPE Common Header suction line ( after HFO tank ) A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 60 T+S 2 273

0

C C m/s 0 C 0

=

0 55 C

mm

=

0.273 m

63.9 mm 436.9 mm

= =

0.0639 m 0.4369 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

= = = =

Film coefficient due to radiation + Film coefficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

0

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.205444597 0.002218309

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.998950978 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 31.03505561 C < 60 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe

=

50 mm

(Rev-C)

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE For Discharge line from HFO unloading pump to the common Header ( before HFO tank) A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 50 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

0

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.009621922 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 30.88874646 C < 50 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 50 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 200 NB HFO PIPE Short recirculation line from forwarding pump to HFO tank

A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

30 50 0.5 60 T+S 2 219.1

0

C C m/s 0 C 0

=

= = = =

mm

=

0.2191 m

42.6 mm 361.7 mm

= =

0.0426 m 0.3617 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

(Rev-B)

0 Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.181315469 0.002218309

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

0 55 C

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 7.886903738 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 31.1663725 C < 60 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE For discharge line from forwarding pump to boiler A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

35 55 0.5 140 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.035 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.931363509 W/m k 2 0 6.821048407 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.021807498

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 21.75871059 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 38.1899364 C = 2k(O-S) where, D1

f ( S-A)

LHS RHS

= =

0.190806548 0.021807498

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 21.75871059 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 38.1899364 C < 140 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 97.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 50 NB HFO PIPE From HFO tank to Drain oil Tank A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

35 55 0.5 60 T+S 2 60.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.0603 m

= =

0.0213 m 0.1816 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.931363509 W/m k 2 0 6.821048407 Kcal/m hr. C

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

0

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.200209344 0.001099538

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

=

50 mm

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.459155655 Kcal/m hr. C

Therefore, Expected exterior surface temperature of insulation, Se

=

0 0 35.9469447 C < 60 C

Therefore, Actual Insulation Thickness Provided on Cylinder pipe

0 57.5 C

21.3 mm 181.6 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

=

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 150 NB HFO PIPE For Inter Tank Transfer line A)

B)

C)

DESIGN DATA : A = S = V = T = O =

= = = = =

D1

=

Outside Diameter of Un-Insulated Pipe

=

D2 D

= =

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)

= =

Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

35 55 0.5 60 T+S 2 168.3

0

C C m/s 0 C 0

=

= = = =

mm

=

0.1683 m

= =

0.0426 m 0.3109 m

Mineral fiber block insulation conforming to ASTM C612 # 3 3 144 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, Group 3 0.2 As per IS : 9842 , clause 3.6

Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] W/m2k 7.931363509 Kcal/m2 hr. 0C 6.821048407

For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered

=

50 mm

=

50 mm

Check : D In D > = 2k(O-S) where, D1 LHS RHS

f ( S-A) = =

0.190806548 0.001099538

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)

Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 6.763430497

Kcal/m2 hr.

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 35.99155292 C < 60 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe 0

=

0 57.5 C

42.6 mm 310.9 mm

Calculation for film co-efficient, f : f

(I)

Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area

50 mm

D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B

FOR 100 NB HFO PIPE discharge line from Drain oil Pump to HFO tank (40 NB) A)

B)

C)

DESIGN DATA : A = S = V = T = O = D1

=

D2 D

= =

= = = = =

Outside Diameter of Un-Insulated Pipe

=

Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness) In = Natural Algorithm Mean temperature Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e

= = = =

0

C C m/s 0 C 0

= mm

=

0.1143 m

42.6 mm 256.9 mm

= =

0.0426 m 0.2569 m

=

0 87.5 C

= = = =

Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.035 Kcal/hr. m C at 76.25 deg.C, Group 3 0.2 As per IS : 9842 , clause 3.6

For Cylindrical Surface of Pipe :

Check : D In D > = 2k(O-S) where, D1 LHS RHS

=

50 mm

=

50 mm

0

f ( S-A) = =

0.20805312 0.021807498

Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe Checking of insulated surface Temperature Expected Insulation surface temperature, Se

=

A + ф f

where

ф

= =

=

Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 20.03980738

Kcal/m2 hr.

Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 37.93793654 C

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