Insulation Thickness
Short Description
Design Calculation of Insulation Thickness for HFO Pipeline...
Description
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
DESIGN CALCULATION INSULATION THCKNESS FOR HFO
FOR 150 NB HFO PIPE For unloading header A)
B)
C)
DESIGN DATA : A = S = V = T = O = D1
=
D2 D
= =
= = = = =
Outside Diameter of Un-Insulated Pipe
=
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness) Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
30 50 0.5 55 T+S 2 168.3
= =
= = = =
0
C C m/s 0 C 0
=
= = = =
mm
=
0.1683 m
= =
0.0426 m 0.3109 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C As per Clause 0.2 No. 7.1.1.2 ( C)
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.190806548 0.001109154
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 6.760824662 Kcal/m hr.
Therefore, Expected exterior surface temperature of insulation, Se
=
0 0 30.99983976 C < 55 C
Therefore, Actual Insulation Thickness Provided on Cylinder pipe
0 52.5 C
42.6 mm 310.9 mm
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
=
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 150 NB HFO PIPE A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
30 50 0.5 55 T+S 2 168.3
0
C C m/s 0 C 0
=
= = = =
mm
=
0.1683 m
= =
0.0426 m 0.3109 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.190806548 0.001109154
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 6.760824662 Kcal/m hr.
Therefore, Expected exterior surface temperature of insulation, Se
=
0 0 30.99983976 C < 55 C
Therefore, Actual Insulation Thickness Provided on Cylindrical pipe
0 52.5 C
42.6 mm 310.9 mm
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
=
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 250 NB HFO PIPE Common Header suction line ( after HFO tank ) A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
30 50 0.5 60 T+S 2 273
0
C C m/s 0 C 0
=
0 55 C
mm
=
0.273 m
63.9 mm 436.9 mm
= =
0.0639 m 0.4369 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
= = = =
Film coefficient due to radiation + Film coefficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
0
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.205444597 0.002218309
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.998950978 Kcal/m hr. C
Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 31.03505561 C < 60 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe
=
50 mm
(Rev-C)
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 150 NB HFO PIPE For Discharge line from HFO unloading pump to the common Header ( before HFO tank) A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
30 50 0.5 50 T+S 2 168.3
0
C C m/s 0 C 0
=
= = = =
mm
=
0.1683 m
= =
0.0426 m 0.3109 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
0
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.190806548 0
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.009621922 Kcal/m hr. C
Therefore, Expected exterior surface temperature of insulation, Se
=
0 0 30.88874646 C < 50 C
Therefore, Actual Insulation Thickness Provided on Cylinder pipe
0 50 C
42.6 mm 310.9 mm
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
=
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 200 NB HFO PIPE Short recirculation line from forwarding pump to HFO tank
A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
30 50 0.5 60 T+S 2 219.1
0
C C m/s 0 C 0
=
= = = =
mm
=
0.2191 m
42.6 mm 361.7 mm
= =
0.0426 m 0.3617 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.862596554 W/m k 2 0 6.761908169 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
(Rev-B)
0 Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.181315469 0.002218309
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
0 55 C
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 7.886903738 Kcal/m hr. C
Therefore, Expected exterior surface temperature of insulation, Se
=
0 0 31.1663725 C < 60 C
Therefore, Actual Insulation Thickness Provided on Cylinder pipe
=
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 150 NB HFO PIPE For discharge line from forwarding pump to boiler A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
35 55 0.5 140 T+S 2 168.3
0
C C m/s 0 C 0
=
= = = =
mm
=
0.1683 m
= =
0.0426 m 0.3109 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.035 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.931363509 W/m k 2 0 6.821048407 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.190806548 0.021807498
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 21.75871059 Kcal/m hr. C
Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 38.1899364 C = 2k(O-S) where, D1
f ( S-A)
LHS RHS
= =
0.190806548 0.021807498
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 21.75871059 Kcal/m hr. C
Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 38.1899364 C < 140 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe
0 97.5 C
42.6 mm 310.9 mm
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
=
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 50 NB HFO PIPE From HFO tank to Drain oil Tank A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
35 55 0.5 60 T+S 2 60.3
0
C C m/s 0 C 0
=
= = = =
mm
=
0.0603 m
= =
0.0213 m 0.1816 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, 0.2 Group 3 As per IS , : 9842 clause 3.6
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] 2 7.931363509 W/m k 2 0 6.821048407 Kcal/m hr. C
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
0
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.200209344 0.001099538
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
=
50 mm
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 2 0 6.459155655 Kcal/m hr. C
Therefore, Expected exterior surface temperature of insulation, Se
=
0 0 35.9469447 C < 60 C
Therefore, Actual Insulation Thickness Provided on Cylinder pipe
0 57.5 C
21.3 mm 181.6 mm
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
=
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 150 NB HFO PIPE For Inter Tank Transfer line A)
B)
C)
DESIGN DATA : A = S = V = T = O =
= = = = =
D1
=
Outside Diameter of Un-Insulated Pipe
=
D2 D
= =
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness)
= =
Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
35 55 0.5 60 T+S 2 168.3
0
C C m/s 0 C 0
=
= = = =
mm
=
0.1683 m
= =
0.0426 m 0.3109 m
Mineral fiber block insulation conforming to ASTM C612 # 3 3 144 Kg/m 0 0.03 Kcal/hr. m C at 76.25 deg.C, Group 3 0.2 As per IS : 9842 , clause 3.6
Film coefficient due to radiation + Film co-efficient due to convection [5.755 x 10-8 x e x {(S+273)4 - (A+273)4}] / [(S-A)]+[1.957 x (S-A)1/4 x (2.857xV+1)1/2] W/m2k 7.931363509 Kcal/m2 hr. 0C 6.821048407
For Cylindrical Surface of Pipe : Insulation Thickness on Cylindrical Surface Considered
=
50 mm
=
50 mm
Check : D In D > = 2k(O-S) where, D1 LHS RHS
f ( S-A) = =
0.190806548 0.001099538
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe (II)
Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 6.763430497
Kcal/m2 hr.
Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 35.99155292 C < 60 C Therefore, Actual Insulation Thickness Provided on Cylinder pipe 0
=
0 57.5 C
42.6 mm 310.9 mm
Calculation for film co-efficient, f : f
(I)
Ambient Temperature Exterior Surface Temp. of Insulation Wind Velocity Temp. of oil pipe Temp. of Annulus area
50 mm
D-3490-CAL-13 LITL-003-MEV-213-R 0013 REV_B
FOR 100 NB HFO PIPE discharge line from Drain oil Pump to HFO tank (40 NB) A)
B)
C)
DESIGN DATA : A = S = V = T = O = D1
=
D2 D
= =
= = = = =
Outside Diameter of Un-Insulated Pipe
=
Increase in Diameter due to Tracer lines Outside Diameter of Insulated Pipe D = D1 + D2 + (2 * Insulation Thickness) In = Natural Algorithm Mean temperature Data of Insulation Material : Material Density Thermal Conductivity, k Emissivity of Finished surface, e
= = = =
0
C C m/s 0 C 0
= mm
=
0.1143 m
42.6 mm 256.9 mm
= =
0.0426 m 0.2569 m
=
0 87.5 C
= = = =
Mineral fiber block insulation conforming to ASTM C612 # 3 3 150 Kg/m 0 0.035 Kcal/hr. m C at 76.25 deg.C, Group 3 0.2 As per IS : 9842 , clause 3.6
For Cylindrical Surface of Pipe :
Check : D In D > = 2k(O-S) where, D1 LHS RHS
=
50 mm
=
50 mm
0
f ( S-A) = =
0.20805312 0.021807498
Since, LHS > RHS Therefore, Actual Insulation Thickness Provided on Cylindrical pipe Checking of insulated surface Temperature Expected Insulation surface temperature, Se
=
A + ф f
where
ф
= =
=
Rate of heat loss per unit area of insulation surface O-A D ln D + 1 2k D1 f 20.03980738
Kcal/m2 hr.
Therefore, Expected exterior surface temperature of insulation, 0 0 Se = 37.93793654 C
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