IIt Pace

ANDHERI / BORIVALI / DADAR / CHEMBUR / THANE / MULUND/ NERUL / POWAI

IIT – JEE - 2013

FULL TEST – 5 PAPER – I (ADVANCED PATTERN)

MARKS: 218

SECTION - I PHYSICS

PART I: Single Correct Answer Type This section contains 6 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct. (+3, –1)

1.

The displacement of a particle starting from rest and moving under a constant acceleration is 1 calculated by the formula S  at 2 . If there occurs an error of 30% in the measurement of time 2 interval t, what error will be introduced in the calculation of S? (a) 15% (b) 60% (c) 69% (d) 30%

2.

A ball is projected from origin with speed 20 m/s at an angle 30o with x-axis. The x-coordinate of the ball at the instant when the velocity of ball becomes  r to the velocity of projection will be (a) 40 3 m (b) 40 m (c) 20 3 m (d) 20 m

3.

A particle is moving in a straight path with an acceleration a  bt n , where b is a positive constant ( n  1 ). The relation between the velocity and the position vector of the particle at time t = 1 s [Assuming particle is in rest at origin at t = 0]  n  3 r  n  1 r (a) v = r (b)v = (n + 2)r (c) v  (d) v  2 2

4.

Two identical spheres of radii 10 cm each are placed between two rigid vertical walls as shown. The spacing between the walls in 36 cm. Then the force of contact between the two spheres if the weight of each is W is (a) 1.67 W (b) 1.25 W (c) 1.33 W (d) 0.75 W

5.

If energy stored in the capacitors C1 and C 2 are same, then what is the value of

C1 ? C2

C2 2R

R

E

C1

E

(a)

36 25

(b)

1 36

(c)

4 9

(d)

9 4

CENTERS: MUMBAI / DELHI / AKOLA / KOLKATA / LUCKNOW / NASHIK / GOA

6.

Which of the following supports energy conservation? {where terms have usual meaning} C (a) C P  C V  R (b) P   (c) PV  nRT (d) U  nC V T CV PART II: Multiple Correct Answer(s) Type

This section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) or (D) out of which ONE or MORE are correct. (+4, –1) 7.

An ideal monoatomic gas goes under cyclic process shown in following curve U 3 (a) For AB is W 2 (b) For BC Q = W (c) For complete cycles W > 0 (d) For complete cycle Q > 0

8.

Rate of cooling of a body by radiation depends on (a) Area if the body (b) Mass of the body (c) Specific heat (d) Temperature of the body and surrounding

9.

Two thin conducting shells of radii R and 2R are shown in figure. The outer shell carries a charge +Q and inner shell is neutral

S

(a) With switch open potential of inner sphere is same as that of point at distance

3R from centre 2

(b) When switch S is closed, potential of inner sphere becomes zero Q (c) With switch S closed charge on inner sphere is  2 (d) By closing switch capacitance of system decreases 10.

A frame is rotating about hinge at O in a uniform transverse magnetic field as shown in the figure. Dimensions of various sections of the rod are shown. Some points are marked on the rod C Choose the correct alternative x x x x x

x x

x

x

A

x

b

xa

2C x x

x x

x O x

x

x

x

x

x



C

x

x

x b x

x

x

x

x

xd x C x x

x x

x

x

x

x B x

x

x

x

x

x

x

x

(a) Potential difference between O and A can never be zero (b) Potential difference between A and C may be zero (c) Potential difference between O and C does not depend on b (d) Potential difference between A and B does not depend on a

11.

Consider the figure shown. A fish is moving up towards the surface of the lake with speed v. A bird is diving towards the lake surface to catch the upcoming fish with speed u. Refractive index of water =  . Choose the correct alternatives

(a) Speed of the bird as observed by the fish is .u  v v (b) Speed of the fish as observed by the bird is  u  (c) Speed of the bird as observed by the fish may be equal to the actual speed (w.r.t. ground) of the bird (d) Speed of the fish as observed by the bird may be equal to the actual speed (w.r.t. ground) of the fish PART III: PARAGRAPH TYPE This section contains 2 multiple choice questions relating to ONE paragraph. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct. (+3,–1)

PASSAGE – I The scattering of photon by an electron is called compton effect. Energy and momentum are conserved in such an event and as a result the scattered photon has lesser energy (longer wavelength) than incident photon.

Applying conservation of energy and momentum we get h  '   1  cos   where  is wavelength of incident photon,  ' is wavelength of scattered m 0c photon, m 0 is rest mass of electron. Now, consider scattering of X rays of photon 10 pm. 12.

13.

The wavelength of X rays scattered thorough 45o is (a) 10.7 pm (b) 10.4 pm (c) 11.3 pm

(d) None of these

The maximum wavelength present in scattered X rays is (a) 11.3 pm (b) 12.4 pm (c) 114.9 pm

(d) 14.86 pm

PASSAGE – II A charge q is moving towards the centre of an earthed conducting sphere of radius b with uniform velocity v. Distance of two points A and B from centre of sphere are 3a & 2a. Conducting sphere is earthed with an ammeter and resistance in series (as shown) x Aq

b

R

B A

Let at any instant point charge is at x distance from center. Ignore induction effects. 14.

Net charge on surface of conductor at this instant (a) + q

15.

(b) – q

Reading of ammeter at this instant xV V (a) q 2 (b) q b b

(c) q

(c)

x b

qbv x2

(d) q

b x

(d) Zero

PART IV: Integer Answer Type This section contains 4 questions. The answer to each question is a single/two digit integer, ranging from 0 to 99 (both inclusive) (+4,0) 16.

The block shown in figure is released from rest with the spring initially unstretched. The spring constant is 500 N/m and mass of the block is 1 kg. Find the maximum extension in spring (in cm)

17.

Water is filled in a large tank containing two small openings shown in figure. If the resultant x horizontal force experienced by the vessel is N the find the value of x. 5

18.

A monoatomic gas initially in state A( P0 , V0 ) is taken through a cyclic process ABCA as shown in figure. The pressure of point B is twice of that of A. The curve BC is a rectangular hyperbola. If the net work done by the gas is xP0 V0 , then find the value of x.

19.

When a metallic surface is illuminated with monochromatic light of wavelength  , stopping potential for photoelectric current is 3 V0 . When same metallic surface is illuminated with a light of wavelength 2 , the stopping potential is V0 . If the threshold wavelength for the surface is n , find the value of n. PART V: Matrix Match Type

This section contains 1 question. Each question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in Column - II are labelled p, q, r, s and t. Any given statement in Column-I can have correct matching with ONE OR MORE statement(s) in Column- II. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example: If the correct matches are A - p , s and t ; B - q and r ; C - p and q ; and D - s and t. (+8, 0)

20.

A current carrying rod is on a rough inclined plane as shown in figure. Angle of inclination (  ) is greater than angle of repose. Column I describes various directions of applied magnetic field and column II enlists their effects on the rod. Match column I with column II suitably

(A) (B) (C) (D)

Column – I  B  B0 ˆj  B   B0 ˆj  B  B 0 kˆ  B   B kˆ 0

Column – II (p) Rod may remain in equilibrium (q) Rod cannot remain in equilibrium (r) Frictional force on the rod is up along the incline (s) Frictional force on the rod is down along the incline (t) Rod may remain in rotational equilibrium

ANSWER KEY 1.

c

2.

a

3.

b

4.

a

5.

a

6.

a

7.

abcd

8.

abcd

9.

abc

10.

abc

11.

abd

12.

a

13.

d

14.

d

15.

c

16.

2

17.

8

18.

1

19.

4

20.

A(q, r), B(p, r, s, t), C (q, r), D (p, r, s, t)

CENTERS: MUMBAI / DELHI / AKOLA / KOLKATA / LUCKNOW / NASHIK / GOA

SECTION - II CHEMISTRY PART I: Single Correct Answer Type This section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct. (+3, –1) 1.

In the quantitative determination of nitrogen, N2 gas liberated from 0.42 gm of a sample of organic compound was collected over water. If the volume of N2 gas collected was 100 11 ml at total pressure 860 mm Hg at 250 K, % by mass of nitrogen in the organic compound is [Aq. tension at 250 K is 24 mm Hg and R = 0.08 L atm mol–1 K–1] (A) 10 3 % (B) 5 3 % (C) 20 3 % (D) 100 3 %

2.

An ideal gaseous sample at initial state i (P0, V0, T0 ) is allowed to expand to volume 2V0 using two different process, in the first process the equation of process is 2PV2 = K1 and in second process the equation of the process is PV = K2. Then (A) Work done in first process will be greater than work in second process (magnitude wise) (B) The order of values of work done cannot be compared unless we know the value of K1 and K2 (C) Value of work done (magnitude) in second process is greater in above expansion irrespective of the value of K1 and K2. (D) 1st process is not possible.

3.

In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356 pm, then radius of carbon atom is (A) 77.07 pm (B) 154.14 pm (C) 251.7 pm (D) 89 pm

O

O CHO

4.



H   B ;  A  &  B are isomers ; Isomer (B) is :

(A)

(a)

CH 2

O

(b)

O

O O

O

(c)

O

CHH 2

O

OH

(d) O

O O

H OH

OH

OH

5.





O3 H HO    A     B     C  ; Pr oduct  C  is :  Zn 

 72% 

O

(a)

O

(b)

(c)

O

CHO (d)

C  CH3

CENTERS: MUMBAI / DELHI / AKOLA / KOLKATA / LUCKNOW / NASHIK / GOA

PART II: Multiple Correct Answer(s) Type This section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) or (D) out of which ONE or MORE are correct. (+4, –1) 6.

7.

Which of the following reactions give alkylation product: (a)

(b)

(c)

(d)

An ideal gas undergoes through following cyclic process. 1–2 : Reversible adiabatic compression from P1V1T1 to P2V2T2 2–3 : Reversible isochoric heating from P2V2T2 to P3V3T3 3–4 : Reversible adiabatic expansion from P3V3T3 to P4V4T4 4–1 : Reversible isochoric cooling from P4V4T4 to P1V1T1 Efficiency of the cycle is:

 T T  (A) 1 –  4 1   T3  T2 

T (B) 1 – 1 T2

V  (C) 1 –  2   V1 

r 1

(D) 1 –

| Q41 | | Q2 3 |

8.

Which of the following statement (s) are wrong. (A) Photons having energy 400 kJ can break 4 mole bonds of a molecule A2 where A – A bond dissociation energy is 100kJ/mol. (B) Two bulbs are emitting light having wavelength 2000Å & 3000Å respectively if the bulbs A & B are 40watt and 30watt respectively then the ratio of no. of photons emitted by A & B per day is 1/2. (C) When an electron makes transition from lower to higher orbit photon is emitted. (D) None of the above

9.

Stepwise hydrolysis of P4O10 takes place via formation of (A) Tetrametaphosphoric acid (B) Tetrapolyphosphoric acid (C) Pyrophosphoric acid (D) Orthophosphoric acid

10.

Select the correct statement about the compound NO[BF4] (A) It has 5 σ and 2 π bond (B) Nitrogen-oxygen bond length is higher than nitric oxide (NO) (C) It is a diamagnetic specie (D) B–F bond length in this compound is lower than in BF3.

PART III: PARAGRAPH TYPE This section contains 2 multiple choice questions relating to one paragraph. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct. (+4, –1) PARAGRAPH FOR QUESTION NOS. 11 TO 12 (A) is white coloured and on treatment with dil. H2SO4 evolves a gas which turns lime water milky but does not reduce K2Cr2O7 solution. A solution of (A) on treatment with H2S/OH– produces a white ppt. (B). The ppt. is then dissolved in HCl to form a solution (C). To the solution on addition of NaOH/NH4OH a white ppt. is first obtained which on adding excess of the reagent dissolves.

11.

Which of the following statement is correct about (B) (a) B is soluble in dil.H2 SO4 (b) (B) is soluble in dil. NaOH (c) (B) is soluble in dil NH4OH (d) (B) is soluble in dil. CH3COOH

12.

To the solution (C) when K4[Fe(CN)6] is added a ppt appears . Which of the following is true regarding the ppt. formed. (a) Colour is yellow (b) The ppt dissolves in dil. HCl (c) Colour is white (d) The ppt do not dissolve in dil. NaOH PARAGRAPH FOR QUESTION NOS. 13 TO 14

If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic form, known as Latimer diagram. The Latimer diagram for chlorine in acid solution is 1.20V 1.18V 1.60V 1.67V 1.36V ClO4–  ClO3–  HClO2  HClO   Cl2   Cl– in basic solution. 0.37V 0.30V 0.68V 0.42V 1.36V ClO4–   ClO3–   ClO2–   ClO–   Cl2   Cl– The standard potentials for two nonadjacent species can also be calculated by using the concept that G° as an additive property but potential is not an additive property and G° = – nFE0. If a given oxidation state is a stronger oxidising agent than in the next higher oxidation state, disproportionation can occur. The reverse of disproportionation is called comproportionation. 13.

What is the potential of couple (A) 1.78 V

14.

ClO  at pH = 14? Cl 

(B) – 0.94 V

(C) 0.89 V

(D) – 0.89 V

Which of the following statement is correct ? (A) Cl2 undergoes disproportionation into Cl– and ClO– both at pH = 0 and pH = 14. (B) Cl2 undergoes disproportionation into Cl– and ClO– at pH = 14 but not at pH = 0. (C) Cl2 undergoes disproportionation into Cl– and ClO– at pH = 0 but not at pH = 14. (D) None of these

PART IV: Integer Answer Type This section contains 5 questions. The answer to each question is a single digit integer, ranging from 0 to 9 (both inclusive) (+4, 0)

CH 3 15

CH 3  CH  CH  CH3

EtOH   x 

Br

S

E



(including stereoisomer)

1 N1 consider all products

Total number of products are:

16.

For some crystals, the radius ratio for cation and anion is 0.525, its coordination number will be

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17.

A complex is represented as CoCl3 .NH 3 . Its 0.1 molal solution is aqueous solution shows depression in freezing point of 0.5580. K f for H 2 O is 1.86 K/ molality. Assuming 100% ionization of complex and coordination number of Co as six, find the value of x.

18.

At 27°C and at 1 bar pressure the e.m.f. of the cell Pb/PbCl2/HCl/ AgCl/Ag is 0.42 volts and its temperature coefficient

dE  4.2  10 4 V/deg. Heat of formation of lead chloride H PbCl2  86 kcal (4.2 J = 1 cal). Heat dT

of formation of AgCl = - x kcal/mole. Find x/15 19.

0.7 g of Na 2 CO3 .xH 2O is dissolved in 100 mL H2O , ml of which required 19.8 mL of 0.1 N HCl. The value of x is

PART V: Matrix Match Type This section contains 1 question. Each question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in Column - II are labelled p, q, r, s and t. Any given statement in Column-I can have correct matching with ONE OR MORE statement(s) in Column- II. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example: If the correct matches are A - p , s and t ; B - q and r ; C - p and q ; and D - s and t. (+8, 0)

(A) (B) (C) (D)

Column I (Co-ordination compound) Na2[Pt(SCN)2(Ox)2] [CrCl2(NH3)4]NO3 [Pt(NO2)(Gly)(NH3)] K3[Fe(OH)2(C2O4)2]

(P) (Q) (R) (S)

Column II (Type of isomerism shown) Ionization isomerism Linkage isomerism Geometrical isomerism Optical isomerism

CENTERS: MUMBAI / DELHI / AKOLA / KOLKATA / LUCKNOW / NASHIK / GOA

Answer key

1.

(A)

2.

(C)

3

(A)

4.(B)

5.

10.(AC)

6.(ABD)

7.(ABCD)

8.

(ABC)

9.(ABCD)

11.

(A)

12.

13.

(C)

14.(B)

15. 20.

(6) 16. (6) (A) Q,R,S (B) P,R (C) Q,R (D) R,S

17.

(5)

18.

(C)

(2)

19.

(C)

(2)

CENTERS: MUMBAI / DELHI / AKOLA / KOLKATA / LUCKNOW / NASHIK / GOA

SECTION III : MATHEMATICS PART I : Single Correct Answer Type This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct. (+3, –1) n 1

1

If

r 2

r 0

r 10

(A) 4

2

3

99

 log 2  r  1  =  log r (r  1) , then 'n' is equal to (B) 3

(C) 5

(D) 6

4     then f (x) is Let f : R   0,  be defined as f (x) = sin–1  2 4 x  12 x  17    6 (A) injective as well as surjective. (B) surjective but not injective. (C) injective but not surjective. (D) neither injective nor surjective.

Two cards are drawn one by one without replacement from a deck of 52 cards. The probability that the second card is higher in rank than the first card, is (Ranks in increasing order can be taken from Ace to King.) (A)

1 17

(B)

8 17

(C)

16 17

(D)

9 17

4

Let A = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19} & x1 + x2 + x3 + x4 = 20 where x i  A ; 1  i  4 ; i  N then number of solutions of the given equation (A) 165 (B) 455 (C) 310 (D) 255

5

In ABC , If A – B = 120° and R = 8r, then the value of

1  cos C equals 1  cos C

(All symbols used have their usual meaning in a triangle) (A) 12 (B) 15 (C) 21 6

Consider two functions f (x) = 1 ecot

2

x

and g (x) =

(D) 31

2 sinx  1 +

1  cos 2x 1  sin 4 x

Statement-1 : The solutions of the equation f (x) = g (x) is given by x = ( 2n  1)

 n I. 2

Statement-2 : If f  x   k and g  x   k ( where k  R ) then solutions of the equation f (x) = g (x) is the solution corresponding to the equation f (x) = k. (A) Statement-1 is true, Statement-2 is true and Statement-2 is correct explanation for Statement-1. (B) Statement-1 is true, Statement-2 is true and Statement-2 is NOT the correct explanation for Statement-1. (C) Statement-1 is true, Statement-2 is false. (D) Statement-1 is false, Statement-2 is true. x

7

Let f (x) =



(A) 2g'' =

0 g2

dt 1  t3

and g (x) be the inverse of f (x), then which one of the following holds good? (B) 2g'' = 3g2

(C) 3g'' = 2g2

(D) 3g'' = g2

5

8

Number of roots of the equation

  k5 (1)k (x 5k )(3k )  32 is

k 0

(A) 1

(B) 2

(C) 3

(D) 5

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PART II : Multiple Correct Answer(s) Type This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONE or MORE are correct. (+4, –1) 9

Possible ordered pair(s) (x, y) on the complex plane satisfying the relation (4 – 3i)x2 + (3 + 2i)xy = 4y2 – (A) (4, – 3)

10

(B) (– 2, 2)

x2 + (3xy – 2y2)i is/are 2 (C) (6, 9)

(D) (10, 15)

Consider two circles S1  x 2  y2  8x  0 and S2  x 2  y 2  2x  0 . Let PQR be formed by the common tangents to circles S1 and S2. Then which of the following hold(s) good? (A) Incentre of PQR is (1, 0). (B) The equation of radical axis of circles S1 and S2 is y = 0. 16 . 9 (D) If transverse common tangent intersects direct common tangents at points A and B, then AB equals 4.

(C) Product of slope of direct common tangents is

2x 2n sin 11

12

Let f  x   lim

1 x

n 

1 x x then which of the following alternatives are correct 2n

xf  x   2 (A) lim x 

f  x  dose not exist (B) lim x 1

f  x  dose not exist. (C) lim x 0

f  x  is equal to zero. (D) lim x 

A student made the mistake in writing quotient rule of differentiation and writes f (n ) d  f ( x )  f ( x ).g ' ( x )  g ( x )f ' ( x )   = and still gets correct answer. Let F(n) = , , then 2 g (n ) n  N dx  g ( x )  (g( x )) (A) F(n) = F(n +1) 20

20

(C)

(B) F(n) = F(n + 2)

 F( n )

=

n 1

 F(2n  1)

(D) F(1) , F(2) , F(3) ....form a G.P.

n 1

PART III : Paragraph Type This section contains 3 multiple choice questions relating to ONE paragraph.Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct.(+3, –1) Let f (x) be a real valued continuous function on R defined as f (x) = x2 e– | x | 13

The value of k for which the curve y = kx2 (k > 0) intersect the curve y = e| x | at exactly two points, is (A) e2

14

e2 2

(C)

e2 4

(D)

e2 8

The area bounded by ordinates at points of local maximum, the curve y = f (x) and x-axis is equal to (A)

15

(B)



4 e2  5 e

2



(B)

e2  5 e

(C)





2 e2  5 e

2

(D) 4

Range of the function f (x) is  2 (A) 0, 2   e 

 4 (B) 0, 2   e 

 4 (C) 0,   e

(D) (0, e2)

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PART IV : Integer Answer Type This section contains 5 questions. The answer to each question is a single digit integer, ranging from 0 to 9 (both inclusive). (+4, 0)



2



16

If a x 2  y2  2y  1   x  2y  3 is an ellipse and a   b,   , the the value of b is

17

Number of points, where f  x   x 2   x  , x   2, 2 is discontinuous is ________.

18

lim

19

  Let f  x   x  tan 3 x g (x) is inverse function of f (x). Then the value of 28 g    1  is ______. 4 

2

x 0

1  cos 2x 2

ex  e x  x

equals _______.

PART V: Matrix Match Type This section contains 1 question. Each question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in Column II are labelled p, q, r, s and t. Any given statement in Column-I can have correct matching with ONE OR MORE statement(s) in Column- II. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example: If the correct matches are A - p , s and t ; B - q and r ; C - p and q ; and D - s and t. (+8, 0) 20 (A)

Column-I Let y = f (x) be drawn with f (0) = 2 and for each real number 'a' the line

Column-II (P)

1

tangent to y = f (x) at a , f (a )  , has x-intercept (a – 2). If f (x) is of the form k of k epx, then   has the value equal to p (B) (C)

(Q)

2

The distance of the z-axis from the image of the point M (2, –3, 3) in the plane x – 2y – z + 1 = 0, is

(R)

2

If the curve C in the xy plane has the equation x2 + xy + y2 = 1, then the greatest distance of a point on C from the origin, is

(S)

4

CENTERS : MUMBAI / AKOLA / NASHIK / PUNE / DELHI / KOLKATA / LUCKNOW / GOA

ANDHERI / BORIVALI / DADAR / CHEMBUR / THANE / MULUND/ NERUL / POWAI

IIT – JEE - 2013

FULL TEST – 5 PAPER – I (ANSWER KEY)

DATE: 16/05/13

PHYSICS 1. 6. 11. 16. 20.

C 2. A 3. A 7. ABCD 8. ABD 12. A 13. 2 17. 8 18. A(Q, R), B(P, R, S, T), C (Q, R), D (P, R, S, T)

B ABCD D 1

4. 9. 14. 19.

A ABC D 4

5. 10. 15.

A ABC C

4. 9. 14. 19.

(B) (ABCD) (B) (2)

5. 10. 15.

(C) (AC) (6)

4. 9. 14. 19.

A CD A 4

5. 10. 15.

B AD B

4. 9. 14. 19.

D A, B, D 10. B 1

5. B A, C, D 15. A

4. 9. 14. 19.

(A) (ABC) (D) (8)

5. 10. 15.

(D) (CD) (4)

4. 9. 14. 19.

B BD B 7

5. 10. 15.

A ABC D

CHEMISTRY 1. 6. 11. 16. 20.

(A) 2. (C) (ABD) 7. (ABCD) (A) 12. (C) (6) 17. (5) (A) Q,R,S (B) P,R (C) Q,R (D) R,S

3 8. 13. 18.

(A) (ABC) (C) (2)

MATHS 1. 6. 11. 16. 20.

B C ABD 5

2. 7. 12. 17.

B B ABCD 4

3. 8. 13. 18.

B D C 4

A  S, B  P, C  Q PAPER – II PHYSICS

1. 6. 11. 16. 20.

B 2. C 3. A A 7. A, B, C, D 8. B, C B, C 12. D 13. D 3 17. 2 18. 2 A(P, Q, R, S, T), B(Q, R, T), C(P, Q, R, S, T), D(Q, S) CHEMISTRY

1. 6. 11. 16. 20.

(D) 2. (D) 3. (BCD) 7. (AD) 8. (D) 12. (B) 13. (3) 17. (5) 18. (A – R); (B – S, T) ; (C – P) ; (D – Q ,T)

(C) (AC) (D) (2)

MATHS 1. 6. 11. 16. 20.

C C ABCD 1

2. 7. 12. 17.

D ABD C 7

3. 8. 13. 18.

A AB C 7

A  Q, B  R, C  S

CENTERS: MUMBAI / DELHI / AKOLA / KOLKATA / LUCKNOW / NASHIK / GOA