Guia 1 Ejercicios para Resolver

 

. 8. Ro baestr  yo ueh phr  d do das bhphs do th chrabh (k > .8: Ftu/m ¼ it ¼ ºI) do .< ge do osposar, ch buhc os ue t fcora mobma bae das bhphs do phpoc lruosa sophrhdhs par ueh bhph do yosa, bacabhdhs bae < ge do sophrhbgòe oetro occhs. Oc osphbga o tro cas thfc ras do thfc rabh ostè ccoea bae hgschngoeta do igfrh do vgdrga (k > :.:6: Ftu/m ¼ it ¼ ºI). Hroh> 8 it6  Dotornge    Ch

rosgstoebgh tçrngbh do ch phro

Vosp0 V> :,22 ºI*m/ tu; V>?86 puclhdhs   Ro puodo rhesiarnhr h R.G sg _ds . Ca proigor  e K>8 \/ *ºB>:,??: \/n*K y do osposar b eabgda, Ch :,2 n y Cb>:,8? n. Oc torbor nht rghc, F, Ro getorbhch oe ro cas nhtorg cos H y B , os do osposar baeabgda Cf>:,8?  , pora do baedubtgvgd hd dosbaeabgdh Kf>1. Oc hroh do ch hrod 8 n6  Oe baedgbgaeos do

porhbgòe do osthda osthfco, chs nodgbgaeo   rovoche ueh

oxto eh go porhturhºB do. Ro tonporhtu to Tgei>=:: ch suporig rh do chºBsup eh tonpor  getoreh Ts,,g>9::  doc ueh marea turhTs,a>6: doc hgr  ºB, shfo quo y origbgo oc baoigbgo to do baev bbgòe getorgar m > 6? \ /n6*K. ±Buèc os oc vhcar do Kf1  

 

 Vospuosth 0 k F 8.?2  /n  K. 

 

2.  _eh bhsh tgoeo ueh phrod banpuosth do nhdorh, hgscheto do igfrh do vgdrga y thfcora do yosa, bana so gedgbh oe oc osquonh. Oe ue dgh irga do Gevgorea cas baoigbgoetos do trhesioroebgh do bhcar par baevobbgòe sae ma>9: \/n 6*K y mg>2: \/n6*K. Oc hroh tathc do ch suporigbgo do ch phrod os 2?: n6. k   f > :.:2= \/n∜K;

k s > :.86 \/n∜K; k   p >:.8< \/n∜K. h) Dotorngeo ueh oxprosgòe sgnfòcgbh phrh ch rosgstoebgh tçrngbh tathc d do o ch phrod, gebcuyoeda osthfcobgdhscas oiobtas do ch baevobbgòe getoreh y oxtoreh phrh chs baedgbgaeos f) Dotorngeo chs pordgdhs do bhcar tathc h trhvçs do ch phrod  4,68 K\   b) Rg oc vgoeta sapchrh do nheorh vgacoeth, ocovheda h ma>2:: \/n6*K. Dotorngeo oc parboeth`o do hunoeta oe ch pordgdh do bhcar :,? :,? % gebronoeta

4. _e tufa do hbora geaxgdhfco (HGRG 2:4) (k>66,6 \/n*K) os ushda phrh oc trhesparto do ue pradubta ihrnhbçutgba roirglorhda. Tgoeo ue dgènotra getorgar do 29 nn y ue osposar do phrod do 6 nn. oc pradubta ihrnhbçutgba y oc hgro hnfgoeto sae h tonporhturhs do 9 ºB y 62 ºB, rospobtgvhnoeto, ngoetrhs quo oc baoigbgoeto baevobtgva getorgar sae 4:: \ / n6* K y baoigbgoetos do baevobbgòe oxtorgar 9 \ / n6* K, (h) ±Buèc os ch lhehebgh do bhcar par uegdhd do caelgtud doc tufa1 (C>8 n) X>86,9 \ (f) ±Buèc os ch lhehebgh do bhcar par uegdhd do caelgtud, sg so bacabh ueh bhph do hgscheto do 8: nn do do sgcgbhta do bhcbga (ksb>:,:?: \ / n* K) X> :,:9 \ / n ¼ B. Tada oc bae`ueta so oxpaeo h ueh baevobbgòe quo radoh su baedgbgòe os do m > 9: \ / n6 ¼ B y T   > 8? B. Ch tonporhturh do ch suporigbgo oxtorgar doc tufa do hbora getorgar os 4:: B. Bhcbuco ch thsh do trhesioroebgh do bhcar pordgda par oc bae`ueta doc tufa do hgschngoeta phrh ueh caelgtud do tufa do 6: n. oe \htts ◩

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