Generalized Method for Solving Clippers Problems

January 12, 2017 | Author: Anshuman Vyas | Category: N/A
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Generalized Method for Solving Clippers Problems As we know that clipper is an AC application of diode. There are different types of clippers e.g. series clipper, parallel clipper etc. but the method for solving all the type of circuits are same. Now let us discuss the procedure with the help of a problem. Suppose we have given a clipper circuit shown below:

Because clipper is an AC application of diode. So we apply an AC signal at the input Vi. Our aim is to find out the waveform of Vo. The solution steps are: Step 1 : First of all analyze the circuit by bifurcating the input waveform in positive half cycle and negative half cycle.

Step 1.1 : Positive half cycle : Positive half cycle is equivalent to a battery of positive polarity and variable potential. Step 1.2 : Negative half cycle : Negative half cycle is equivalent to a battery of negative polarity and variable potential.

Step 2 : Now analyze the circuit with positive half cycle.

The next step is to check the condition of diode i.e., whether the diode is forward bias or reverse bias. In the circuit shown above it is clear that the diode is forward bias and hence equivalent to short circuit (because it is ideal diode).

Now analyze the variation of Vo.

It is clear that

And because Vi varies sinusoidally, so Vo also varies sinusoidally. Step 3 : Now analyze the circuit with negative half cycle

The next step is to check the condition of diode i.e., whether the diode is forward bias or reverse bias. In the circuit shown above it is clear that the diode is reverse bias and hence equivalent to open circuit (because it is ideal diode). Now analyze the variation of Vo.

It is clear that

Step 4: Now combine these two waveform.

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