Formula Booklet Physics XII

Formula Booklet – Physics XII

Dear students It is the dream of every one of you to make a mark in this arena called life. The IITJEE is one of the most rigorous test that you have to clear to take firm steps towards achieving this. All of you want to do well in this examination or some other engineering entrance competition in order to realize your dreams and also to see those tears of satisfaction in the eyes of your parents who are proud of your success. To succeed in any endeavour what a person needs is velocity. Yes, the same velocity that you study in physics. Velocity is a combination of speed and direction. Speed is the ability to do our work with utmost efficiency and negligible wastage of resources such as time. At this stage of our career speed is very important for all of us. I would like to take the help of an example to explain the term ‘direction’. A young guy was lost on a road and he asked an elderly fellow, “Sir, could you tell me where this road will take me?” Without a moment’s hesitation the elderly chap said, “ Son, this road will take you anywhere in the world you want to go, if you are moving in the right direction.” So direction is the right path towards our aim. You can tread on that path only when you have your goal clearly in front of your eyes and you are working for that goal intensely with a strong desire and an unshakable determination level, always believing that you’ll do it. Your attitude and motivation are of utmost importance. Remember, this test that you are taking is not just a test of your knowledge but also of how strong are you, mentally. In this booklet we have made a sincere attempt to keep your velocity of preparations to the maximum. The formulae will help you revise your chapters in a very quick time and the motivational quotes will help you move in the right direction. Hope you’ll benefit from this book and all the best for your examinations. Praveen Tyagi Gaurav Mittal Prasoon Kumar

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Formula Booklet – Physics XII

CONTENTS Description

Page Number

1.

Elecrotstatics and Capacitance

03

2.

Current Electricity

12

3.

Magnetic Effects of Current

15

4.

Magnetic Properties of Current

18

5.

Electromagnetic Induction

20

6.

Alternating Current

22

7.

Light

26

8.

Modern Physics

35

9.

Some Study Tips

43

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Formula Booklet – Physics XII

ELECTROSTATICS & CAPACITANCE ELECTROSTATICS 1. (a)

Coulomb’s Law 1 q 1q 2 , K = Dielectric constant or relative permittivity of the medium Fm = 4πε 0 K r 2

(b)

Fm =

(c) (d)

F0 [F0 – Force between point charges placed in vacuum] K –1 –3 4 2 [ε0] = [M L T A ] Fe =2.4 x 1039 [For electron–proton pair) Fg

=1.2 x 1036 (For proton–proton pair) 2. (a) (b)

Electric field →

→

E=

F q0 →

Electric field due to a point charge: (i) E = (ii)

1 q ^ . r (if charge q is placed at the origin) 4πε 0 r 2

→ →

→ 1 q( r − r 0) (if charge q is placed at some point having position vector E= r0) 4 πε0 → → 3 | r− r0|

→

(c)

[E] = [M1L1T–3A–1]

3. (a)

Electric field on the axis of a uniformly charged ring 1 qx Eaxial = (R = radius of the ring) 4πε 0 R 2 + x 2 3 / 2

(b)

Ecentre = 0

4. (a)

Electric dipole dipole moment p = q(2l) (where 2l = length of the dipole) 1 2pr Eaxial = (r = distance of axial point w.r.t. centre of dipole) 4πε 0 r 2 − l 2 2

(b)

≅

1 2p 4πε 0 r 3

(

)

[

]

(if r >>l)

p 1 2 4πε 0 r + l 2

≈

1 p 4πε 0 r 3

(c)

Eequat. =

(d) (e)

(Eaxial/Eequat.) = 2/1 Dipole field at an arbitrary point (r, θ) 1 2p cos θ 1 p sin θ (i) Er = ; (ii) Eθ = 3 4πε 0 4 πε r r3 0 1 p 1 + 3 cos 2 θ (iii) E = E 2r + E θ2 = 4πε 0 r 3

(f)

Dipole field component at (x, y, z) point 1 3xz p 1 3yz p ; (ii) Ey = ; (i) Ex = s 4πε0 r 5 4πε 0 r

[

]

3/ 2

(if r >>l)

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Formula Booklet – Physics XII

(iii)

(g)

Ez =

(

1 p 3z 2 − r 2 4πε 0 r5 →

) →

→

(ii) τ = pE sin θ

Torque on a dipole : (i) τ = p x E ; → →

(h)

Potential energy of a dipole: (i) U = − p . E = − pE cos θ (ii) Work done in rotating a dipole from angle θ1 to angle θ2 W = U2 – U1 = pE (cos θ1 – cos θ2)

5.

Electric flux

(a)

dφ = E . dS

(b)

φ ∫ E . dS = EA cos θ

→ →

→ →

(If electric field is constant over the whole surface)

2

(c) (d)

Unit of φ = (Nm /Coulomb) = J.m/Couplomb 1 3 –3 –1 [φ]= [M L T A ]

6.

Gauss’s Law:

→ →

7.

q ε0 Electric field due to various systems of charges

(a)

Isolated Charge:

∫

E . dS =

r q

E⊥ (b)

Electric dipole: • –q

1 q 4 π ε0 r 2

E=

Fig. 1 P

y• •

• +q

2a

E||

P •

→

→

1 2p (i) E || = 4π ε 0 x 3

→

→

(ii) E ⊥ = −

x

1 p 4 π ε0 y 3

Fig. 2 • r • –q

θ

• +q

→

(iii)E =

p

1 p 1 + 3 cos 2 θ 4π ε 0 r 3

Fig. 3

(c)

+++ + + q + R + + + A ring of charge:+ • + x + + + + + + + ++ Fig. 4 +

•P

E=

1 qx 4π ε 0 R 2 + x 2

(

)

3/ 2

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Formula Booklet – Physics XII

(d)

(e)

+ ++ + +q + R + + + A disc of charge: • + + x + + + + + + Fig. 5 ++ + +

•P

+ + + + σ + +

Infinite sheet of charge:

σ  x 1 − 2 2ε 0  x + R2 

E=

E=

  

σ 2ε 0

Fig. 6

(f)

+ + + + λ

Infinitely long line of charge:

E=

•P

x

λ 2π ε 0 x

Fig. 7

(g)

+ + + Finite line of charge: + + +

α β

E⊥=

P E||=

λ 4 π ε0

λ (sin α + sin β) 4 π ε0 x

(cos α+cos β)

x Fig. 8

(h)

(i)

+ + Charged spherical shell: + + +

Solid sphere of charge:

+ + + R

+ q + +

+ + + Fig. 9

+ + + R + ++ + + + + + ++ Fig. 10

+

(i) Inside: 0 ≤ r ≤ R E=0 (ii) Outside: r ≥ R E=

q 4π ε 0 r 2

(i) Inside: 0 ≤ r ≤ r E = ρr/3ε0 (ii) Outside : r ≥ R E=

ρR 3ε 0

R   r 

2

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Formula Booklet – Physics XII

8.

Force on a charged conductor: The force per unit area or electric pressure Pelec. =

9.

10. (a) (b) (c) (d)

Charged soap bubble: (a) Pin – Pout =

4T σ 2 − r 2ε 0

(b)

If air pressure inside and outside are assumed equal then: Pin = Pout and

or

r=

or

r = [Q /128π ε0T]

8ε 0 T

or T =

σ2 2

2

σ2r 8ε 0

or σ = √(8ε0T/r)

→

→

E = −VV 1 q 4π ε0 r

(f)

Potential due to a group of charges, V =

(g)

Potential due to a dipole:

(k)

Q = 8πr√(2ε0rT)

Electric potential: V = (W/q) Unit of V = Volt 2 –3 –1 [V] = [ML T A ]

Potential due to a point charge, V =

(i) (j)

or

4T σ 2 = r 2ε 0

1/3

(e)

(h)

dF σ 2 = dA 2ε 0

1 p ; (ii) equatorial point, V = 0; 4π ε 0 r 2 p cos θ

(i)

Axial point, V =

(iii)

V (r, θ) =

1 4π ε 0

1  q1 q 2 q 3  +   + 4π ε 0  r1 r2 r3 

ρ2

Potential due to a charged spherical shell 1 q 1 q (ii) surface: V = ; 4π ε0 r 4π ε 0 R

(i)

outside: V =

(iii)

inside : V = Vsurface =

1 q 4π ε 0 R

Potential due to a charged spherical conductor is the same as that due to a charged spherical shell. Potential due to a uniformly charged nonconducting sphere (i)

outside: V=

(iii)

inside: V=

1 q ; 4π ε 0 r

(ii) surface: V =

(

)

1 q 4πε0 R

1 q 3 R 2 − r2 ; (iv) centre: V = 3 x 1 q = 1.5 Vsurface 3 4πε0 2 4π ε0 R 2R

Common potential (Two spheres joined by thin wire) (i)

common potential V=

(ii)

q1 =

1 4π ε 0

r1 (Q1 + Q 2 ) rQ = 1 ; (r1 + r2 ) r1 + r2

 Q1 + Q2     r +r   1 2 

q2 =

r2 Q r1 + r2

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Formula Booklet – Physics XII

(iii) 11.

q1 r1 = q 2 r2

or

σ1 r2 = σ 2 r1

(a)

Potential energy 1 q1 q 2 = q1V1 U= 4πε 0 r

(b)

U=

(c)

U = − p .E

12. (a)

If n drops coalesce to form one drop, then 1/3 2/3 (c) V = n Vsmall ; Q = nq; (b) R=n r ; 1/3 1/3 (e) E=n Esmall (d) σ = n σsmall

13.

Energy density of electrostatic field: u =

(For a system of two charges)

1 q1q 2 1 q1q 3 1 q 2 q3 + + 4π ε 0 r12 4 π ε 0 r13 4π ε0 r23

(For a system of three charges)

→ →

(For an electric dipole)

1 ε0E 2 2

CAPACITANCE 14. (a) (b) (c)

Capacitance: C = (q/V) Unit of C = farad (F) –1 –2 4 2 Dimensions of C = [M L T A ]

15.

Energy stored in a charged capacitor U=

1 CV2 ; 2

17.

1 1 Q2 U= QV; (c) U = 2 2 C 1 1 σ2 2 Energy density: (a) u = ε0E ; (b) u = 2 ε0 2 Force of attraction between plates of a charged capacitor

(a)

F=

1 σ2A ε0E2A; (b) F = ; 2ε 0 2

18. (a)

Capacitance formulae Sphere: (i) Cair = 4π ε0R;

(b)

Spherical capacitor: (i) Cair =

(c)

Parallel plate capacitor: (i) Cair =

(d)

Cylindrical capacitor: (i) Cair =

(e)

Two long parallel wires: C=

(a) 16.

(b)

(c)

F=

Q2 2ε 0 A

(ii) Cmed = K (4π ε0R) 4π ε 0ra rb ; rb − ra

ε0A ; d

(ii) Cmed = (ii) Cmed =

4π ε 0 K ra rb (rb − ra )

Kε 0 A d

2πKε 0 l 2 π ε 0l ; (ii) Cmed = loge (rb / ra ) log e (rb / ra )

ε0 l where d is the separation between wires and a radius of log e (d/a )

each wire (d>>a) 19. (a) (b)

Series Combination of Capacitors (Charge remains same) q1 = q2 = q3 = q q q q V1 = (Potential difference is different) , V2 = , V3 = C1 C2 C3

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Formula Booklet – Physics XII

(d) (e)

1 1 1 1 = + + C C1 C 2 C 3 For two capacitors in series: C = C1C2/(C1 + C2) Energy stored: U = U1 + U2 + U3

20. (a) (b) (c) (d)

Parallel Combination of Capacitors (Potential difference remains same) V1 = V2 = V3 = V (Charges are different) q1 = C1V, q2 = C2V, q3 = C3V C = C1 + C2 + C3 U = U1 + U2 + U3

21. (a) (b)

Effect of dielectric Field inside dielectric, Ed = E0/K Polarization charges on surface of dielectric: Qp 1 1   (ii) σp = =σ 1 −  (i) Qp = Q  1 −  ; A  K  K

(c)

Polarization vector: (i) | P | =Qp/A ;

22.

Capacitance formulae with dielectric

(a)

C−

(b)

C=

ε0 A d−t

(c)

C=

ε 0 A  K1 + K 2    d  2 

(c)

→

K ε0 A ε0 A = 1  K d − t (K − 1)  d − t 1 −   K

→

(ii) | P | =ε0χEd

(For a dielectric slab of thickness t)

(For a metallic slab of thickness t)

K1

K2

A/1

A/2

d

Fig. 11

(d)

2ε A  K K C = 0  1 2 d  K1 + K 2

d/2

K1

  

K2 A/2

d/2

A/2

Fig. 12

(e)

C=

2K 2 K 3  ε0 A   K1 +   4d  K 2 + K 3 

K1

K2

d

K3

d

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Formula Booklet – Physics XII

(f)

For n plates with alternate plates connected: C = (n–1) ε0A/d

(g)

C=

ε0A

K1 K2 K3

 t1 t2 t3    K + K + K  2 3   1

t1

t2

t3

Fig. 14 23.

Spherical capacitor with inner sphere grounded

(a)

C=

(b)

Charge on inner sphere = –q1, while charge on outer sphere = +q2

(c) 24. (a)

4π ε 0 r1 r2

(r2 − r1 )

+ 4 π ε0 r2

r  Magnitude of charge on inner sphere: q1 =  1  q2  r2  Insertion of dielectric slab Battery remains connected when slab is introduced (i) V’ = V; (ii) C’ = KC ; (iii) Q’ = KQ ; (iv) E’ = E; (v) U’ = KU

(b)

Battery is disconnected after charging the capacitor and slab is introduced (i) Q’ = Q; (ii) C’ = KC ; (iii) E’ = E/K; (iv) V’ = V/K; (v) U’ = U/K

25. (a)

Charge transfer, Common potential and energy loss when two capacitors are connected C V + C 2 V2 q1 + q 2 = Common potential: V = 1 1 C1 + C 2 C1 + C 2

(b)

Charge transfer: ∆q =

(c) 26. (a) (b)

C1C 2 (V1 − V2 ) C1 + C 2

1 C1C 2 (V1 − V2 )2 2 C1 + C 2 Charging and discharging of a capacitor –t/RC ) ; (ii) V = V0 (1–e–t/RC); (iii) I = I0e–t/RC; Charging: (i) q = q0 (1–e (iv) I0 = V0/R –t/RC –t/RC –t/RC ; (ii) V = V0e ; (iii) I = – I0e Discharge: (i) q = q0e (b) Time constant: τ = RC

Energy loss: ∆U =

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Formula Booklet – Physics XII

CURRENT ELECTRICITY 1. (a)

Electric Current I = (q/t); (b) I = (dq/dt); (c) I = (ne/t); (d) q = ∫ IdT

2. (a)

Ohm’s law, Resistivity and Conductivity V = IR ; (b) R= ρ(l/A) ; (c) σ = (1/ρ) (d) vd = (eEτ/m); (e) I = neAvd; ne 2 τ m  m  l  R =  2    ; (g) ρ = ; (h) σ = m ne 2 τ  ne τ   A 

(f) 3. (a)

Current density J = (I/A); (b) J = nevd; (c) J = σE; (d) µ = (vd/E); (e) σ =neµ

4.

Temperature Coefficient of Resistance

(a)

R = R0[1 + α(T–T0)] ; (b) α =

(d)

α=

5.

Cell: (a) E =

6. (a) (c)

Series Combination of Resistances (b) V = V1 + V2 + V3; R = R1 + R2 + R3; V1 = IR1, V2 = IR2, V3 = IR3 I = constant = I1 = I2 = I3; (d)

7.

Parallel Combination of resistances 1 1 1 1 = + + ; R R1 R 2 R 3 I= I1 + I2 + I3; V = constant = V1 = V2 = V3; V V V I1 = , I2 = , I3 = R1 R2 R3 For a parallel combination of two resistances: R 1R 2 R2 R= ; (ii) I1 = I; (iii) (i) R1 + R 2 R1 + R 2 Heating effect of current W = VI t; P = VI ; 2 2 P = I R = V /R; I 2 Rt H = I2 Rt Joule = Calorie J

(a) (b) (c) (d) (e)

8. (a) (b) (c) (d)

R − R0 ; (c) ρ = ρ0 [1+α(T–T0)] ; R 0 (T − T0 )

ρ − ρ0 ρ0 (T − T0 )

W ; Q

(b) I =

E ; (c) V = E – Ir r+R

(where V = IR)

I2 =

R1 I R1 + R 2

9.

Electric bulb: (a) Resistance of filament R = V2/P; (b) Maximum current that can be allowed to pass through bulb, Imax = (P/V)

10. (a)

Total Power Consumed Parallel combination: P = P1 + P2 + P3 1 1 1 1 Series combination: = + + P P1 P2 P3

(b)

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Formula Booklet – Physics XII

11.

Effect of stretching a resistance wire 2

2

r  R 2 l 1 A1  l 2   A1   =  1  = x =  = R 1 l 2 A 2  l 1   A 2   r2  E nE = nr + R R

12.

Cells in series: I =

13.

Cells in parallel: I =

E

(r / n ) + R

4

[ Q l1A1 = l2A2]

(if n r > a : B =

µ0 I 2 πr

)

µ0 N I a 2

2 x3 point of inflexion: It occurs at x = a/2  4µ N I   = 0.716 Bcentre Field at the point of inflexion: B =  0  5 5a 

25.

Magnetic moment of circular coil: (a) M = NIA ; (b) Field: B=

26. (a) (b) (c)

Field due to an arc of current: B = (µ0Il/4πR2) ; B = (µ0Iθ/4πR) At the centre of a semicircular coil: B = (µ0I/4R)

27.

Field due to finite length of wire: B =

28.

µ 0 2M 4π x 3

µ0I (sin φ1 + sin φ2) 4πa  2 2 µ0I   Field at the centre of a square loop: B =   πl    →

→

→

→

29.

Ampere’s law: (a∫)

30.

Field due to a current in cylindrical rod:

(a)

outside: B = (µ0 I/2πr) ; (b) surface: B = (µ0 I/2πR); (c) inside: B=

31. (a)

Field due to a current carrying solenoid: inside: B = µ0n I ; (b) at one end : B = (µ0n I/2) µ nI at an axial point: B = 0 (cos α2 – cos α1) 2

(c)

B . d l = µ0 I ; (b) ∫

H. d l =1

µ0I r 2π R 2

32.

Field due to a toroid: (a) inside: B=µ0nI – µ0NI/2πR ; (b) outside: B = 0

33.

Force on electric current: F = H x B

34.

Force between two parallel conductors:

35.

Comparison of magnetic and electric forces between two moving charges: (Fmagnetic/Felectric) = 2 2 (v /c )

→

→

→

F µ 0 I1 I 2 = l 2πd

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Formula Booklet – Physics XII

→

36.

Force on a current loop in a magnetic field: F = 0 (any shape)

37.

Torque on a current loop in a magnetic field: τ = M x B

38. (a) (b)

Moving coil galvanometer: τ–NIAB; τ =Kθ ;

(c)

I= 

(d)

Current sensitivity = (θ/I) = (NaB/K) ; (e) Voltage sensitivity = (θ/V) = (θ/IR) = (NAB/KR)

39. (a) (b) (c) (d)

Ammeter: Shunt resistance S = (IgG/ I– Ig); Length of shunt wire, l = S πr2/ρ; Effective resistance of ammeter, RA = GS/(G+S); For an ideal ammeter, RA = 0

40.

Voltmeter:

(a)

V High resistance in series, R =  − G  ;

(b) (c)

For converted Voltmeter, RV = R + G; For an ideal Voltmeter, RV = ∞

41.

Force on a moving charge: → → → F = q v x B  ; (b) F = q v B sin θ  

(a)

→

→

→

or τ M B sin θ

 K  θ ;  N AB 

  Ig 

  

42.

Path of a moving charge in a magnetic field

(a)

When v is ⊥ to B : (i) path = circular; (ii) r = (mv/qB) ; (iii) ν = (qB/2πm); (iv) T = (2πm/qB) ; (v) ω = qB/m)

(b)

When angle between v and B is θ: (i) path=helical ; (ii) r = (mv⊥/qB) = (mv sin θ/qB); 2πm (iii) ν = (qB/2πm); (iv) T = ; (v) ω = (qB/m); qB (vi) pitch p = 2πr/tan θ (where tan θ = (v⊥/v ||)

43. (i) (ii) (iii) (iv) (v) (vi)

Cyclotron: T = (2πm/qB) ; ν = (qB/2πm) ; ω = (θB/m) ; radius of particle acquiring energy E, r = [√(2mE)/qB]; velocity of particle at radius r, v = qBr/m; the maximum kinetic energy (with upper limit of radius = R)

→

→

→

K max =

→

1 q 2 B2 R 2 2 m

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Formula Booklet – Physics XII

44. (a)

(b)

Magnetic field produced by a moving charge: →

→

→

µ q (v x r ) B= 0 ; 4π r3

B=

µ 0 q v sin θ 4π r2

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Formula Booklet – Physics XII

MAGNETIC PROPERTIES OF CURRENT 45. (a) 46. (a) (c)

Magnetic field: F B = max ; qv

1  dF  B=   I  dl  max

(b)

Atomic magnetic moments: eL eS µL = – ; (b) µS = – ; 2m m eh eJ µJ = – g ; (d) µB = = 0.927 x 10–23 J/T 4πm 2m

47.

Intensity of magnetization: I = (M/V)

48.

Magnetizing field: B −I; H= µ0 B ; For vacuum, H = µ0

(a) (b) (c) (d) (e)

For medium, h = B/µ; H =nI (solenoid); H = I/2 πr (straight wire);

(f)

H=

(g)

∫

49.

Magnetic susceptibility: χ = (I/H)

50.

Magnetic permeability:

(a)

µ = (B/H) ; (b) µr = (µ/µ0) ; (c) µr = (B/B0)

51. (a) (c)

Other relations: µ = µ0 (1+χ) ; (b) (d) B = B0 (1+ χ) :

52. 53.

Pole strength: m = F/B Magnetic moment of dipole : M = m x 2l

54.

Field due to a pole: B =

→

I dl sin θ r2

(Biot-Savart law) ;

→

H . d l = Ifree

µr = 1 + χ or χ = µr – 1; B = µ0 (H + I)

55.

µ0  m    4π  r 2  Field due to a bar magnet:

(a)

Axial point: B =

(b)

Equatorial point: B =

µ0 M 4π r 2 + l 2

(c)

At arbitrary point: B =

µ0 M 1 + 3 cos 2 θ 3 4π r

µ 0 2 Mr 4π r 2 − l 2

(

)

2

(

=

µ 0  2M    4π  r 3 

)

3/ 2

=

(if r > > l)

µ0  M    4π  r3 

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Formula Booklet – Physics XII

56.

Force and torque on a dipole in uniform magnetic field (a)

→

F = 0;

(b)

→

→

→

τ = M x B ; (c) τ MB sin θ → →

57.

Potential energy of a dipole in magnetic field: U = − M . B = – MB cos θ

58.

Tangent galvanometer:

(a)

B = BH tan θ;

(b)

I = K tan θ,

59.

Vibration magnetometer: T = 2π

where K =

2r B H µ0n I M BH

Nothing will happen until you generate the will to make it happen!

The most powerful weapon on earth is human soul on fire!

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Formula Booklet – Physics XII

ELECTROMAGNETIC INDUCTION 60.

Magnetic flux:

(a)

dφ = B. d A = BdA cos θ;

(b) φ= ∫ B . d A ;

(c)

φ = BA cos θ;

(d) ∫ B . d S = 0 ;

61. (a)

(c)

Faraday’s laws of e.m. induction: Induced e.m.f., e = – (dφ/dt); e 1 dφ Induced current, I = =− ; R R dt Induced charge, q = (φ1 – φ2)/R

62.

Motion of a conducting rod:

(b)

(a) (b) (c)

→

→

→

→

→

→

→

→

(e)

→

V. B = 0

→

F = − e ( v x B) ;

Induced e.m.f., e = B/v For a rod rotating with angular frequency ω or rotating disc, induced e.m.f., e=

1 2 Bl ω = Βπfl 2 = Baƒ 2

63. (a) (c) (e) (f)

Motion of conducting loop in a magnetic field: Induced e.m.f. e = Blv ; (b) Induced current, I = (e/R) = (Blv/R) F = IlB = B2l2v/R ; (d) P = Fv = IlBv = B2l2v 2R; H = I2R = (B2l2v2/R); In non uniform magnetic field, e = (B1–B2) lv and I = (B1–B2)lv/R

64. (a) (b)

Rotating loop: φ = NAB cos ωt = φ0 cos ωt, with φ0 = NAB; e = e0 sin ωt, where e0 = NaBω; (c) I = (e0 sin ωt/R) = I0 sin ωt, with I 0 = e0/R

65.

Induced electric field: Induced e.m.f. =

66. (a) (b) (c) (d) (e)

Self Inductance: L = φ/ I ; e = – (LdI/dt); 2 2 L = µ0N A/l = µ0n Al L = µrµ0N2A/l 2 L = µ0N πR/2

67. (a)

Mutual inductance: M = (φ2/ I1) ; (b) e2 = – M(dI 1/dt); (c) M = µ0NsNp A/lp

68. (a) (b)

Series and parallel combination L = L1 + L2 (if inductors are kept far apart and joined in series) L = L1 + L2 ±2M (if inductors are connected in series and they have mutual inductance M) LL 1 1 1 L= 1 2 or = + L1 + L 2 L L1 L 2 (if two inductors are connected in parallel and are kept for apart)

(c)

∫

→ →

E . dl

(For a solenoid with air core); (For a solenoid with a material core); (For a plane circular coil)

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Formula Booklet – Physics XII

(d) 69. (a) 70. (a) (b)

M = K√(L1L2)

(if two coils of self inductances, L1 and L2 are over each other)

Energy stored in an inductor: 1 2 U = LI 2 ; (b) uB = (B /2µ0) 2 Growth and decay of current in LR circuit –t/ (for growth), where τ = L/R I = I0 (1–e τ) –t/τ (for decay), where τ = L/R I = I0 e

The heights by great men reached and kept… …were not attained by sudden flight, but they, while their companions slept… …were toiling upwards in the night.

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Formula Booklet – Physics XII

ALTERNATING CURRENT 71. (a) (b)

A.C. Currrent and e.m.f. : I = I0 sin (ωt ± φ) ; e= e0 sin (ωt ± φ);

(c)

< I > = 0, < I >1/2 =

(d) (e) (f)

< I 2 > I 02 / 2 ;

2I 0 =0.637 I0 ; π

Irms = (I0/√2) = 0.707 I0 ; form factor = π/2√2

72. (a)

A.C. response of R, L, C and their series combinations Resistance only: (i) e = e0 sin ωt; (ii) I = I0 sin ωt ; (iii) phase difference φ = 0; (iv) e0 = I0R; (v) erms = Irms R

(b)

Inductance only: (i) e = e0 sin ωt; (ii) I = I0 sin (ωt–π/2) ; (iii) current lags the voltage or voltage leads the current by a phase π/2;

I0XL;

(iv) (c)

erms = Irms XL ;

(iv)

e0 =

(vi) XL = ωL

Capacitance only: (i) e = e0 sin ωt ; (ii) I = I0 sin (ωt + π/2); (iii) current leads the voltage or voltage lags the current by a phase π/2 ; (iv) (v) erms = Irms XC ; (vi) XC = (1/ωC)

e0 = I0XC;

(d)

Series LR circuit: (i) e = e0 sin ωt ; (ii) I = I0 sin (ωt + φ); –1 (iii) the current lags the voltage or voltage leads the current by a phase φ = tan (XL/R); (iv) cos φ = (R/Z) and sin θ = (XL/Z); 2 2 (v) Impedance, Z = √ [R +(ωL) )] ; (vi) e0 = I0Z; (vii) erms = Irms Z

(e)

Series RC circuit: (i) e = e0 sin ωt ; (ii) I = I0 sin (ωt + φ); –1 (iii) The current leads the voltage or voltage lags behind the current by a phase φ = tan (XC/R) (iv) cos φ = (R/Z); 2 2 (v) Impedance, Z = √[R + (1+ωC) )]; (vi) e0 = I0Z ; (vii) erms = Irms Z

(f)

Series LCR circuit:

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Formula Booklet – Physics XII

(i) (ii)

e = e0 sin ωt ; I = I0 sin (ωt – φ);

(iii)

φ=tan

(iv) (v) (vi)

current lags and circuit is inductive if XL < XC ; current leads and circuit is capacitive if XL < XC ; 2 2 Impedance, Z = √[R + (XL – XC) ];

(viii)

cos φ = (R/Z) and sin φ = 

–1

 XL − XC  R 

  , φ is positive for XL > XC, φ is negative for XL Ip Step up : es > ep, Ns > Np and Is < Ip e I  Efficiency, η =  s s   ep Ip    AC generator: e = e0 sin (2πƒt), (where e0 = NBAω)

DC motor: E−e I= (a)   R  (b) IE = Ie = I2R (c)

Back emf e efficiency, η   =  E  Applied emf

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Formula Booklet – Physics XII

LIGHT 1.

Intensity of light

(a)

Spherical wave front: (i) I =

(b) (c) 2. 3. 4. (a)

P 2

, (ii) amplitude ∝

1 r 1

4 πr 1 Cylindrical wave front: (i) I ∝ , (ii) amplitude ∝ r r Plane wave front: (i) I ∝ r0, (i) A ∝ r0 (i.e. I and A are both constants)

Law of reflection: Angle of incidence (i) = Angle of reflection (r) sin i Law of reflection: Snell’s law: η = sin r Other relations v c 2η1 = 1 and η = v2 v

(c)

λ air or η η1 sin i = η2 sin r

5.

Electromagnetic nature of light

(a)

The magnitude of E and B are related in vacuum by: B=

(b)

(b) (c)

λmedium =

→

→

vmedium =

(Q νmedium = νair)

→

→

→

v air η

E C

→

E and B are such that E x B is always in the direction of propagation of wave 1 1 and v= c= µ0ε0 µε

(d)

Refractive index, η = √(µr εr) (µr = µ/µ0 and εr = ε/ε0) For non–magnetic material, µr ≈ 1 and η = √(εr)

(e)

The EM wave propagating in the positive x–direction may be represented by: Ey = E0 sin (kx – ωt) and Bz = B0 sin (kx – ωt)

6.

Energy transmitted by an electromagnetic wave

(a)

Energy density of electromagnetic wave is: u = ue + um =

(b)

As for EM wave, B = u=

1 1 B2 ε0 E2 + 2 2 µ0

E 1 and = √ (µ0 ε0), hence C c

1 1 E2 1 1 ε 0E 2 + = ε 0 E 2 + ε0 E 2 = ε 0E 2 2 2µ0 c 2 2 2

(c)

Time averaged value of energy density is: u =

7.

Intensity of an electromagnetic wave

(a)

In a medium: I =  ε0 E02  v

(b)

1  In free space: I =  ε 0 E02  c 2  

8.

Pointing vector

1 2

1 ε0 E 0 2 2

 

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Formula Booklet – Physics XII

(a)

→

→

→

S = ExH= 2

→ → 1 → → ( E x B ) = c 2ε 0 ( E x B ) µ0 2

(b) (c) (d)

S = cε0E = √(ε0/µ0)E I = S and S = cu Impedance of free space, Z = √ (µ0/ε0) ≅ 377 ohm

9. (a)

Pressure of EM Radiation Change in momentum (normal incidence)

(b)

(c)

∆p =

U S A∆t = c c

∆p =

2 U S A∆t (reflector) = c c

(absorber)

Pressure (normal incidence) P=

S =u c

(absorber)

P=

2S = 2u c

(reflector)

Pressure for diffused radiation P=

1S 1 = u 3 c 3

(absorber)

2 S 2 = u (reflector) 3 c 3 Quantum theory of light: Energy of photon, E = hν = hc/λ E h = Momentum, p = c λ Rest mass of photon = 0 2 Mass equivalent of energy, m = (E/c ) P=

10. (a) (b) (c) (d) 11. (a)

Inclined mirrors: number of images When 3600 is exactly divisible by θ0 and 3600/θ0 is an even integer then the number of images formed is n=

(b)

360 − 1 (whatever may be location of the object) θ

0 0 When 360 is exactly divisible by θ and 360/θ) is an odd integer, then the number of images formed is

360 − 1 (for symmetrical placement) θ 360 (for unsymmetrical placement) = θ

n=

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Formula Booklet – Physics XII

(c)

0 When 360 is not exactly divisible by θ, then the number of images formed is = integer value of n (where n = 360/θ)

12. (a)

Reflection amplitude and intensity When a ray of light is incident (with angle of incidence i ≈ 0) from a medium 1 of refractive index η1 to the plane surface of medium 2 of refractive index η2, then reflection amplitude is η − η2 R= 1 η1 + η 2

(b)

The ratio of the reflected intensity and the incident intensity is:

13.

Refraction of light sin i η= ; (b) sin r 1 1 η2 = ; (d) 2η1

(a) (c)

1

η2 =

I r  η1 − η 2 = I i  η1 + η 2

2

  . 

sin θ1 ; sin θ 2

Cauchy’s relation: η = A +

B λ2

14. (a) (b)

Parallel slab Angle of incidence, i = Angle of emergence, e Lateral shift = [t sin (i – r)/cos r]

15.

Composite block: η1 sin θ1 = η2 sin θ2 = η3 sin θ3 = constant

16.

Apparent depth R t a= (where R = Real depth) = η η If there is an ink spot at the bottom of a glass slab, if appears to be raised by a distance

(a) (b)

x=t–a=t– (c)

 1 t = t 1 −  , where t is the thickness of the glass slab η  η

If a beaker is filled with immissible transparent liquids of refractive indices η1, η2, η3 and individual depths t1, t2, t3 respectively, then the apparent depth of the beaker is: t t t a= 1 + 2 + 3 η1 η 2 η3

18.

1 η For a luminous body at a depth d inside a liquid: Radius of bright circular patch at the surface d r = d tan iC = η2 − 1

19. 20. (a) (b)

For optical fibre: sin i ≤ Prism: i+e=A+δ r1 + r2 = A;

17.

(c) (d)

Total internal reflection: Critical angle iC is given by: sin iC =

[(n

2

]

/ n1 ) − 1 2

 A + δm  sin    2  At minimum deviation: i = e and r1 = r2. Hence, η = A sin   2 For small angle prism: δ = (η–1) A

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Formula Booklet – Physics XII

21. (a) (b)

Dispersion: δred < δviolet because ηred < ηviolet Angular dispersion: θ = δV – δR = (ηV–ηR)A

(c)

Dispersive power: ω =

(d)

Dispersion without deviation: (i) δC + δF = 0

δ V − δ R ηV − ηR ηB − ηR (In practice) = = δY ηY − 1 ηY − 1

or

(η − 1) AF =− C AC (η F − 1)

(ii) Also, angular dispersion, θ=AC (ηC–1) (ωC–ωF) (e)

Deviation without dispersion: (i) θC + θF = 0 (ii) Also,

or,

AF η − ηCR = − CV AC η FV − ηFR

δ ωF = − CY δ FY ωC

22.

Principle of superposition: y = y1 + y2

23. (a) (b) (c)

Superposition of waves of equal frequency and constant phase difference Resultant wave amplitude, a = √(a12 + a22 + 2a1a2 cos φ) Resultant wave intensity, I = I1 + I2 + 2√(I1I2) cos φ 2 If a1 = a2 = a0, and I1 = I2 = I0, then a = 2a0 cos (φ/2) and I = 4I0 cos (φ/2)

24. (a)

Constructive interference conditions: φ = 2nπ ≡ 0, 2π, 4π, 6π,….. or, ∆ = nλ ≡ 0, λ, 2λ, 3λ, ……

(b) (c) (d) (e)

amax = a1 + a2 2 Imax ∝ (a1 + a2) 2 Imax = I1 + I2 + 2 √ (I1I2) = (√I1 + √I2) Imax = 4I0 ; If I1 = I2 = I0

25.

Destructive interference

(a)

conditions: φ = (2n –1) π ≡ π, 3π, 5π,…… or, ∆ = (2n–1)

(b) (c) (d) (e)

amin = a1 – a2 2 Imin ∝ (a1 – a2) 2 Imin = I1 + I2 – 2√(I1I2) = (√I1 – √I2) Imin = 0 if I1 – I2 = I0

26.

Young’s double slit experiment 2π 2π Phase difference, φ = (S2P – S1P) = x path difference λ λ A = 2a0 cos (φ/2) and I 4I0 cos2 (φ/2) Position of nth fringe on the screen: nDλ (i) for bright fringe, x n = d ( 2 n − 1) Dλ (ii) for dark fringe, x n = 2d

(a) (b) (c)

27.

Fringe width:

(a)

Linear fringe width, β =

λ λ 3λ 5λ = , , ,......... 2 2 2 2

Dλ d

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Formula Booklet – Physics XII

λ d

(b)

Angular fringe width, α =

(c)

βliquid =

(d)

βwater =

28. (a)

When a thin shit is introduced in the path of one of the interfering waves: (η–1) t = nλ (η − 1) t β Shift of the central fringe = λ

(b)

β air air

ηliquid

or λliquid =

Fringe visibility: V =

30. (a) (c)

Frensel’s biprism: d = 2a (η–1) α ; (b) β = (Dλ/d);

I max − I min I max − I min

d = √(d1d2) (d) dliquid < dair, for example, dwater = dair/4  ηg − 1   βliquid > βair ; βliquid = βair   ηg − ηt   

(e)

(b) 32.

Newton’s rings: Diameter of nth dark fringe, Dn = √(4nλR) D 2n +p − D 2n D 2 − D 2n and η = n2+ p λ= 4 pR D' n + p − D' 2n Thin films: For reflected light 2ηt cos r = nλ

(Dark fringe)

1 2ηt cos r = (n– )λ 2

33. (a) (b)

ηliquid

3 βair 4

29.

31. (a)

λ air air

(Bright fringe)

Diffraction: a sin θ = nλ (a = width of slit) Half angular width of central maxima, θ = sin–1 (λ/a) 2

(c)

(d) (e)

 sin φ   Intensity distribution of the screen I = I0   φ  πa y where, φ = and I0 = Intensity at central point of screen λD 1.22 λ Limit of resolution of telescope: θ = a 1 a Resolving power of telescope = = θ 1.22λ

34. (a)

Spherical mirrors: Focal length: ƒ = (R/2)

(b)

Mirror formula:

(c)

Newton’s formula: ƒ2 = xy

1 1 1 = + ƒ v u

(x and y are the distances of the object and image from the principal focus respectively)

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Formula Booklet – Physics XII

I v ƒ ƒ−v =− = = o u ƒ−u ƒ

(d)

Linear magnification: m =

(e)

Longitudinal magnification: m = −

35. (c)

Spherical lenses: A single spherical surface: η 2 η1 (η 2 − η1 ) − = [For an object placed in a medium of refractive index η1] (i) v u R η1 η 2 (η1 − η 2 ) − = [For an object placed in a medium of refractive index η2] (ii) v R u R (iii) First principal focus: ƒ1 = where η = η2/η1 (η − 1) ηR (iv) Second principal focus: ƒ2 = (η − 1) v / η2 (v) Magnification: m = u/η1

(d)

Lens Maker’s formula: (i)

 1 1  η2 1   or, = − 1  −  ƒ  η1 R R 2  1

v2 u2

 1 η1 η1 1   − = (η2 − η1 )  −  v u R R 2  1

[When medium is same on both sides of the lens] (ii)

η3 η1  η 2 − η1   η3 − η 2 + − = v u  R 1   R 2

  

[When different medium exist on two sides of the lens] (e)

Biconvex or biconcave lens of the same radii for two surfaces:

(f)

Linear magnification: m =

(g)

Power of lens: P=

(h)

Lenses in contact: (i) (iii)

I v ƒ−v ƒ = = = O u ƒ ƒ+u

1 ƒ

1 1 1 ; = + ƒ ƒ1 ƒ 2

(ii)

P = P1 + P2

For lenses separated by a distance d =

1 1 1 d = + − ƒ ƒ1 ƒ 2 ƒ1ƒ 2

(i)

Achromatic lens combinations: Condition of achromatism,

36.

Silvering at one surface:

(a)

1 2 (η − 1) = ƒ R

1 1 1 1 2 2 (η - 1) = + + = = F ƒl ƒ m ƒl ƒl R

ω ω' =− ƒy ƒ 'y

R η Fig. 1

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Formula Booklet – Physics XII

(b)

(c)

η

1 2 1  (η − 1)  2 2n = + =2 + = R F ƒl ƒ m  R  R

R

Fig. 2

η

R1

 1 1 2 1 1  2 + = + = 2(η − 1)  +  F ƒl ƒ m  R1 R 2  R 2

R2

Fig. 3 37. (a)

(b)

(c)

Optical Instruments Astronomical Telescope: ƒ0 ƒe

(i)

For normal adjustment: m =

(ii)

For near–point adjustment: m =

ƒ0  ƒ  1 + e  ƒe  D

Simple Microscope: D ƒ

(i)

For normal adjustment: m =

(ii)

For near–point adjustment = m = 1+

D ƒ

Compound Microscope: (i) (ii)

D    ƒe  v  D For near–point adjustment: m = 0 1 +  u0  ƒe 

For normal adjustment: m =

v0 u0

I do not ask to walk smooth paths, nor bear an easy load. I pray for strength and fortitude to climb rock-strewn road. Give me such courage I can scale the hardest peaks alone, And transform every stumbling block into a stepping-stone. – Gail Brook Burkett

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Formula Booklet – Physics XII

MODERN PHYSICS CATHODE RAYS AND POSITIVE RAYS 1. (a) (b)

Cathode rays Thomson identified cathode rays as an electron beam. 11 Specific charge q/m as measured by Thomson is: (q/m) = 1.759 x 10 Coulomb/Kg

2. (a) (b)

Positive rays Positive rays were discovered by Goldstein. (q/m) for positive rays is much less than that of electrons.

3. (a) (b) (c) (d) (e) (f)

Motion of charge particle through electric field (Field ⊥ to initial velocity) 2 2 The path is parabolic: y = (qE/2mu )x The time spent in the electric field: t = (L/u) The y–component of velocity acquired: vy = (qEL/mu) 2 The angle at which particle emerges out tan θ = qEL/mu The displacement in y-direction, when the particle emerges out of the field: y1=(qEL2/2mu2) 2 The displacement on the screen = Y = (qELD/mu )

4. (a) (b) (c)

Motion of charged particle through magnetic field (Field ⊥ to initial velocity) The path is circular with radius: r = (mu/qB) Momentum of the particle: p = qBr The deflection on the screen: X = (qBLD/mu)

5. (a)

Mass spectrographs Thomson’s mass spectrograph (i) Traces on the screen are parabolic in nature (ii) Inner parabola corresponding to heavy M white outer parabola to light M. (iii) The upper portion of parabola is due to small v ions, while lower portion is due to high v ions. (iv) Only v = ∞ ions can reach vertex of parabola. 2 2 (v) Equation of parabola: X = (B LD/E) (q/M) Y = K (q/M) Y

(b)

Brain bridge mass spectrograph (i) Velocity selector: v = (E/B) (ii) Other relations: r = (Mv/qB’) = (ME/qBB’) (whre B’ is the magnetic field in dome); d =2r; (d2 – d1) ∝ (M2–M1) ; M1 : M2 = d1 : d2 [where d1 and d2 are the distances of traces 1 and 2 from the slit S2 of velocity selector].

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Formula Booklet – Physics XII

PHOTOELECTRIC EFFECT 6. 7.

Work function W = h h c hc hc Threshold wavelength: λ0 = = = v 0 hv 0 W

Threshold frequency: v0 =

(To calculate λ0, use hc = 1240 (eV) (nm) = 1.24 x 10–6 eV) (m) 8. (a) (b) 9. 10. (a) (c) 11. (a) (b) (c)

12.

Maximum kinetic energy of emitted photoelectrons 1 Kmax = mv2max = eV0 2 1 1   Kmax = hv – W = h (v – v0) = hc  −   λ λ0  h Slope of (V0 v) graph = e Energy, momentum and mass of a photon hc Rest mass of photon = 0 (b) E = hv = λ E h E h p= = (d) m = 2 = c λ cλ c Number of photons:

(

)

Intensity Watt/m 2 hv Power (Watt ) number of photons incident per second, np = hv number of electrons emitted per second = (efficiency of surface) x number of photons incident per second. 2 number of photons per sec per m , np =

(a)

Compton wavelength: h =2.426 pm λc = m0C

(b)

Change in wavelenth, (λ’ – λ) = λc (1– cos φ)

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Formula Booklet – Physics XII

ATOMIC STRUCTURE 13. (a)

Rutherford’s α–particle scattering 4 N(θ) ∝ cosec (θ/2)

(b)

Impact parameter, b =

14.

Distance

15.

Bohr’s atomic model nh L = mvr = 2π hc hv = Ei = Ef = λ Radius of nth orbit:

(a) (b) (c)

of

(Ze )cot (θ/ 2) , 2

(4 π ε 0 ) E

closest

approach:

(where E =

r0 =

1 mu2 = KE of the α–particle) 2

2 Ze2 (where (4π ε0 )E

(iii) (iv)

Ratio of radii: r1:r2 : r3 = 1 : 4 : 9 ; rN : rHe+ : rLi++ = 1 :

rn ∝

n2 , Z

=

1 mu2 2

=

KE

(ii) rn =

1 1 : =6:3:1 2 3

Velcotiy of electron in nth orbit: 2π Ke 2 1 Z c  Z (where α = = = fine structures constant) (i) vn =  = αc n  137  n ch 137 1 1 (ii) v1 : v 2 ; v3 = 1 : : = 6 : 3 : 2 2 3 st (iii) v1 = velocity of electron is 1 orbit of H–atom = (c/137)

(e)

Total energy of electron: 2 (i) Potential energy, U = – (kZe /r) 1 (ii) K = mv2 = (kZe2/2r) 2 2 (iii) E = K + U = – (kZe /2r) = (U/2) = –K (iv) K = – (U/2) or U = 2K = 2E

(f)

En = –

13.6 Z 2

the

n2 Z

(d)

(v)

of

α–particle)

  h2    4 π 2 m ke 2    2 2 2 Bohr’s radius: a0 = (h /4π mke ) = 0.529 Å

(i)

E

eV = –

Z 2  2π 2 m k 2e 4 

h2 n2 n 2  2 Ionization energy = – E1 = + (13.6Z )eV (i) For H–atom, I.E. = 13.6 eV + (ii) For He – ion, I.E = 54.4 eV ++ (iii) For Li –ion, I.E. = 122.4 eV

(g)

Ionization potential: (i) For H–atom, I.P. = 13.6 V + (ii) For He ion, I.P. = 54.42

(h)

Series formula (wave number v = 1/λ

 

=−

2.18 x 10-18 Z2 n2

J

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Formula Booklet – Physics XII

 1 1 1  = RZ 2  2 − 2  n  λ  1 n2 

(i)

2π 2 m k 2 e 4 ch

3

= 1.097 x 10 7 m -1

Series formula for H–atom (i)

Lyman series:

1 1   = R 1 − 2 , n = 2, 3, 4, ......∞ λ  n 

1 1   1 = R  2 − 2 , n = 3, 4, 5....∞ λ 2 n   1 1   1 (iii) Paschen series: = R  2 − 2  , n = 4, 5, 6....∞ λ n  3 1 1   1 (iv) Brackett series: = R  2 − 2 , n = 5, 6, 7….∞ λ n  4 1 1 1   (v) P–fund series: = R  2 − 2 , n = 6, 7, 8 ….∞ λ n  5 Series limits (λmin) (i) Lyman: λmin = 912 Å (ii) Balmer: λmin = 3645 Å (iii) Paschen: λmin = 8201 Å

(ii)

(j)

where R =

Balmer series:

16.

Number of emission lines from excited state n = n(n–1)/2

17. (a)

Time period of revolution Tn ∝ (n3/Z2) ; (b) T1 = 1.5 x 10–16 sec ; (c) T1 : T2 : T3 = 1 : 8 : 27

18.

Frequency of revolution

(a)

vn ∝ (Z2/n3);

19. (a)

Current due to orbital motion 2 3 In ∝ (Z /n ) ; (b) I1 = 1 mA

20. (a)

Magnetic field at nucleus due to orbital motion of electron Bn ∝ (Z3/n5) ; (b) B1 = 12.5 Tesla

21. (a) (b)

Magnetic moment: Mn = (eL/2m) = (nhe/4πm); –24 2 M1 = (eh/4πm) = µB = Bohr Magneton = 9.27 x 10 Am

22.

Magnitude of angular momentum: L = √[l(l+1)] (h/2π)

23. (a)

Angle of angular momentum vector from z–axis cos θ = [ml√{l(l+1)}]; (b) the least angle is for ml = l i.e. cos θmin = [l/√{l(l+1})]

24.

Magnitude of spin angular momentum

(b) v1 = 6.6 x 1015 Hz ; (c) v1 : v2 : v3 = 1 :

S = √[s (s+1)] (h/2π) =

25. (a)

3 (h/2π) 2

1 1 : 8 27

X–RAYS

Continuous X–rays: vmax = (eV/h) ; (b) λmin = (hc/eV) = (12400/V) Å

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Formula Booklet – Physics XII

26. (a)

28.

Characterictic X–rays: λKα < λLα < λMα ; (b) vKα > vLα > vMα 3cR Frequency of Kα line : v (Kα) = (Z–1)2 = 2.47 x 1015 (Z–1)2 4 2 2 Wavelength of Kα line: λ(Kα) = [4/3R(Z–1) ] = [1216/(Z–1) ]Å

29.

2 Energy of Kα X–ray photon: E(Kα) = 10.2 (Z–1) eV

30. (a) (b)

Mosley’s law: 2 5 v = a (Z–b) , where a = (3cR/4) = 2.47 x 10 Hz For Kα line, b = 1; (c) √v α Z

31.

Bragg’s law: 2d sin θ = nλ

32.

Absorption formula: I = I0 e

33.

Half–value thickness: x1/2 = (0.693/µ)

34. (a) (b) (c) (d)

For photons: E = hv = (hc/λ) ; p = (hv/c) = (E/c) = (h/λ) ; 2 2 m = (E/c ) = (hv/c ) = h/cλ rest mass = 0, charge = 0, spin = 1 (h/2π)

35.

Matter waves:

(a)

de Broglie wavelength, λ = h = h =

(b)

(i)

For electron λe =

(ii)

For proton, λp =

(iii)

For alpha particle λα =

27.

–µx

MATTER WAVES

(c)

p

(g)

V 0.286 V

h 2m E

=

h 2mqV

[Q E =

1 2

mv 2 = qV ]

Å

Å 0.101 V

Å h 3 m KT

3    E = kT  2  

For neutron or proton: λ = (25.2/√T) Å [if E = (3/2) kT, average energy] 30.8 Å [if E = kT, most probable energy] but λ= T

The wavelength of electron accelerated by potential difference of V volts is: λe =

12.27

Å v Hence, accelerating potential required for obtaining de Broglie wavelength for as electron is: V=

(e) (f)

12.27

For particle at temperature T : λ = (i)

(d)

mv

150.6 λ2e

volt

Condition for obtaining stable orbit: 2πrn = nλ The phase velocity of a de Broglie wave of wavelength λ and frequency v is Ε h mc 2 h c2 = = i.e. v p > c. v p = vλ = x x h mv h mv v Group velocity, vg = (dω/dk). It is found that group velocity is equal to particle velocity i.e., v g = v

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Formula Booklet – Physics XII

RADIOACTIVITY 36.

Decay law: (a) (dN/dt) = – λN ; (b) N = N0 e λ ; (c) (N/N0) = (1/2)

37.

Half life and decay constant: (dN/dt ) ; (b) λT = log 2 or T = (0.693/λ) λ=− e N

(a)

– t

t/T

or λ = (0.693/T)

38. (a)

Mean life: τ = (1/λ) or λ=(1/τ);

39. (a) (e) (g)

Activity: – t t/T R = |dN/dt| ; (b) R = λN ; (c) R = R0e λ ; (d) (R/R0) = (1/2) ; 10 1 Becquerel = 1 dps ; (f) 1 curie = 1 ci = 3.7 x 10 dps; 6 6 1 Rutherford = 1Rd = 10 Rd = 10 dps

40.

Decay of active mass:

(a)

m = m0 e

41.

Radioactive equilibrium: NAλA = NBλB

42.

Decay constant for two channels: (a) λ = λ1 + λ2 ; (b) T =

43.

Gamma intensity absorption: (a) I = I0e

–λt

(b) T = 0.693τ or τ = 1.443 T

; (b) (m/m0) = (1/2)t/T ; (c) N =

6.023 x 10 23 x m A

–µx

T1 T2 T1 + T2

; (b) Half value thickness, x1/2 = (0.693/µ)

NUCLEAR PHYSICS 44.

Atomic mass unit: (a) 1 amu = 1.66 x 10–27 kg ; (b) 1 amu ≡ 1u ≡ 931.5 MeV

45. (a)

(c)

Properties of nucleus 1/3 where R0 = 1.2 fermi Radius: R = R0A 4 4   3 3 Volume: V αA Q V = 3 πR = 3 π R 0 A    17 3 Density: ρ = 2.4 x 10 Kg/m (ρ is independent of A)

46.

Mass defect: ∆M = Zmp + (A–Z) mn – M

47. 48.

Packing fraction: ƒ = ∆/A = mass excess per nucleon [∆ = –∆M = mass excess] 2 Binding energy: ∆E = BE = (∆M)c

49. (a) (b) (c)

Binding energy per ncuelon: BEN = (BE/A); BEN for Helium = 7.1 MeV/nucleon BEN for Deuterium = 1.1 MeV/nucleon

(b)

ELECTRONICS 50. (a) (b) (c)

Richarson equation 2 –W/KT where A = 60 x 104 A/K2m2 J = AT e 2 11600 W/T –23 –5 J = AT e [∴ K = Boltzmann’s constant = 1.38 x 10 J/K = 8.62 x 10 eV/K Hence, 1/K = 11600 kelvin/eV] I = AT2Se–W/KT

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Formula Booklet – Physics XII

3/2

51.

Child’s law: Ip = KVp

52. (a)

Diode resistance –1/2 (iii) Rp ∝ I −p 1 / 3 Static plate resistance: (i) Rp = (Vp/ Ip); (ii) Rp ∝ Vp

(b)

Dynamic plate resistance: (i) rp = (∆Vp/∆ Ip); (ii) rp ∝ v −p 1 / 2 ; (iii) rp ∝ I −p 1 / 3 .

53. (a)

Triode Constants:  ∆Vp   rp =  ;  ∆I p    Vg = constant

(b)

 ∆I p gm =   ∆Vg 

(c)

 ∆Vp µ=   ∆Vg 

(d)

µ = rp x gm ; (e) rp ∝ Ip

  ;   I p =consant

[K = constant of proportionality]

–1/3

55.

Vp    Plate current equation: Ip = K  Vg + µ   Cut off voltage: Vg = – (Vp/µ)

56.

Triode as an amplifier:

(a)

Ip = (µVg/RL + rp); (b)

54.

(c) 57.

  ;   Vp =cons tan t

3/ 2

A = (µRL/RL + rp) rp   ; (d) µ = A 1 + (e) A = µ/2 if RL = rp Amax = µ;   RL  Conductivity of semi conductors − E / 2 KT

(b)

Intrinsic: (i) σ = e (neµe + nh µh) ; (ii) σ = σ0e g Extrinsic: (i) n–type : σ = eneµe; (ii) p–type : σ = enhµh

58. (a)

Transistor: IE = IC + IB

(a)

(b)

(IB