Flowcharts and Design Equations - Eurocode 2

February 6, 2017 | Author: ChineseAssassin | Category: N/A
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prEN 1992-1 (3

rd

Slab Design Flowchart

draft)

2

for fck 1.5As 9.2.1.1& 9.3.1.1(1) Distn >= 0.12% >= 0.2Asprov

Primary s = 26%fctm/fyk

bf

9.2.1.1

As >= Ascrack

1 - 2(M - M f )106 ù dé ú £ xmax x = ê1 lê hbw f cd d 2 úû ë Mf æ h ö (M - M f )æ lx ö çç d - f ÷÷ + z= çd - ÷ M è 2ø M 2ø è

[

M OR = hf cd z h f (b f - bw )+ lxbw

7.3.2 (2)

Part of top steel at supports must be spread across the width of the flange 9.2.1.2 (2)

]

For point load near support, use 6.2.2.5 or 6.2.3 (8)

M ' = M - M OR ³ 0 M' As ' = f sc (d - d ') f M -M' As = + As ' sc f yd z f yd

At d from support face VEd g s Asw A A min £ sw = £ sw max (6.7) s s zf cot q s ywk

and

Asw

s

A sw

min =

s

0.08bw f ck f yk

m ax =

(9.4) & (9.5)

n f cd b w g 2 f ywk

s

(6.9)

SHEAR

At support face b znf w = cot q + tan q = w cd VEd f ck æ where n = 0 . 6 ç 1 250 è 1 £ cot q =

where

Treat as rectangular section, substituting bf for b.

z may be taken as 0.9d

(6.8)

ö ÷ (6.5) ø

w + w2 -4 £ 2.5 6.2.3 (2) 2

1 0.18bw d k (100 r l f ck ) 3 ³ 0.4 f ctd bw d (6.2) gc As 200 r l = l £ 0.02 where k = 1 + £2 bw d d 0.7a ct f ctm (3.14) and f ctd = gc bw znf cd VRd ,max = ³ V (6.8) (cot q + tan q ) Ed

VRd ,ct =

smax,L = 0.75d (9.6) smax,T = 0.75d
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