EXAMEN - U2 - Administracion de Operaciones 1 - 2018

 

DATNFNBOK F AB^QFKNBF ADWFSQFIDKQO AD BK@DKBDSÉF BKAT^QSBFJ FAIBKB^QSFNBOK AD OWDSFNBOKD^ 6 TKBAFA 3 Koicrd5________________________________________________________Nfjbl.5_________ Jos sb`ubdktds aftos iudstrfk jfs vdktfs ad uk proaunto adtdribkfao dk jos õjtbios 63 idsds. Ids 

\dktfs

6

677

3 >

634 667

1

674

4

27

<

637

0

614

=

617

2

677

f)  Wroidabo Iþvbj ad > idsds c)  Wroidabo Iþvbj Wokadrfao nok uk pdso ad , prokostbqud pfrf jos sb`ubdktds idsds. Adsvbfnbþk Fcsojutf idabf IFA nok uk ζ97 .6 y ζ97.>  ζ97.>  Drror Nufarætbno Idabo I^D nok uk uk ζ97 .6 y ζ97.>  ζ97.>  Drror porndktufj fcsojuto idabo IFWD ad jf ideor adj IFA Dvfjuâ nufj ds dj ideor prokþstbno ζ97 ζ97 .6 y ζ97.> y adsnrbcf dj por quâ? Sdfjbnd uk ^ufvbzfibdkto dxpokdknbfj dxpokdknbfj nok feustd ad tdkadknbf (Wrokostb (Wrokostbno no adj prbidr ids lud ad 9663 y dj feustd nok tdkadknbf bkbnbfj ds 967 y jfs nokstfktds ad sufvbzfao sdjdnnbokfao sok γ97.1 γ97.1 ζ9 ζ97.3 7.3 Qdkadknbf LBQ Wroydnnbþk ad tdkadknbfs pfrf jos idsds 67, 66 y 63