First maximum when n = 1: First λ 656 × 10 9 = 0.328 sin θ = = sin d 2. 0 × 10 6 so, t = sin−1 0.328 = 19.1° so, −
−
Distanc
[1] [1]
Second maximum when n = 2: Second sin θ = sin
The dashed line represents the resultant wave. [2]
3
[1]
(Your diagram should show a good (Your attempt to sum the two waves.)
b
Wavelength is the same as that of the longer wa wave. ve.
a b
2λ d
=
2 × 656 × 10 2. 0 ×10
9
−
6
=
−
0.656
[1]
−1
8
sso, o, θ = sin 0.656 = 41.0° [1] a Superposition is the algebraic summing of the displacements [1]
of two (or more) wa waves. ves.
[1]
b
λ = D
More rounded
[1]
Even flatter
[1]
leading to λ D 590 ×10 9 ×1.8 ×12 = a = x 16.8 ×10 3
ax
[1] [1]
−
4
5
6
Radio waves have a long enough wavelength, wa velength, up to 1 km, that they can diffract round the hills.
[1]
TV T V waves have very short wavelength (centimetres or millimetres), so cannot diffract round the hills. a
Using ax ax = ld
1.5 1.2 = 0.225 m ≈ wavelength λ = ax = 8.0 d 0.23 m [1]
a = 6.3 × 10−4 m
c
i
More fringes seen on screen or fringe brightness decreases less from middle to edge of screen [1]
[1]
Less bright
[1]
[1]
ii ii
Fringes wider / farther apart
[1]
Same brightness
[1]
b
λ; 330 = f v = f f f × 0.225
[1]
f = 1470 Hz ≈ 1500 Hz
[1] [1]
They T hey gradually go out of phase, and when they are in antiphase, the sound is at its quietest. [1] The T he waves waves gradually come back into phase and become loud again. [1]
1
[1]
×
When the waves are in phase, they add up to give loud sound.
−
9
[1]
a
Coherent: constant phase difference
[1]
Monochromatic: very small or no Monochromatic: range of wa wavelengths/frequencies velengths/frequencies
[1]
b
i
First order produced by waves with path difference of one wavelength wavelength [1] Second order produced by waves wa ves with path difference of two wavelengths
Thank you for interesting in our services. We are a non-profit group that run this website to share documents. We need your help to maintenance this website.