EOQ
Short Description
EJERCICIOS DE INVENTARIOS...
Description
INSTITUTO TECNOLÓGICO TECNOLÓGICO DE PIEDRAS NEGRAS
INGENIERÍA INDUSTRIAL ADMINISTRACIÓN DE OPERACONES EJERCICIOS UNIDAD 3 ING. GONZALO GARCÍA LUNA MARI MARIA A DE JES JESUS US TUR TURRU RUBI BIA ATE ZAV ZAVALA
N.C. N.C. 10/ 10/32 320 0
PIEDRAS NEGRAS, COAH. A 27 DE OCTUBRE DE 201
1.!L" S#$$%& G'()$'& #'(*+$$ +-" *"')" #"')+"' %$ )" +$ $-$ "4 45+$-$4 )"'")$'64)"4 • • • •
"> @> )> %>
V$-"4810 V$-"4810 )"9"4 #(' #$'4(-" C(4( %$ ('%$-8:10 #(' ('%$C"'5(4 #(' $"'(830; " "
D 520 = = 24.98 Q 20.81
=20.81
C =
Q ( H )= 20.81 ( 24 ) =249.72 2 2
%> A5+-" "'")F- $- "4 $-"4 %$ " $*#'$4" +- -)'$*$-( %$ 0; 0 +- %$)'$*$-( %$ 0;. CT =
D ( S ) + Q ( H )= 520 ( 10 ) + 20.81 ( 24 )=499.59 2 20.81 2 Q
D ( S ) + Q ( H )= 520 ( 10 )+ 10.40 ( 24 )=624.80 Q 2 10.40 2
0;
CT =
!
CT =
0;
D ( S ) + Q ( H )= 520 ( 10 ) + 41.60 ( 24 )=624.20 2 41.60 2 Q
2.!L" $-%" G'-$ M")-$ "@')" +-" 6-$" %$ #"-)"4 *$)"4 #"'" 4+4 )$-$4. A5+-"4 %$ $4"4 #"-)"4 4$ $"- $- $ -$-"'( %$ #'(%+)( $'*-"%(. U-" #"-)" $- #"')+"' $-$ "4 45+$-$4 )"'")$'64)"4 V$-"48200 " " ?+ ")('$4 #(%'6"- ()"4(-"' +$ " )(*#" D"(4 #"'" @ D820 H 83K S810
EOQ=Q∗¿
√(
2 ( D ) ( S )
P ) (C )
2 ( 520 ) ( 10 )
(36 )
=29.43
)> C+"-%( 4$ -)'$*$-" $ "*" N =
D 100000 = =38.72 Q 2581.98
)> CT =
D ( S ) + Q ( H )= 100000 (1000 )+ 2581.98 ( 30 )=42602.78 2 2581.98 2 Q
%> U- -)'$*$-( $- " %$*"-%".
.!L" H"'"% C((# ('%$-" #"&$'"4 )(- $ $*@$*" %$ " H"'"% U-$'4& *#'$4( $- $"4 #"'" $-%$'"4 $- :2 )/". %+'"-$ +- *$4 )+"+$'", 4$ $-%$1000 #"&$'"4 $4( -)+&$ (%(4 (4 $4(4 & "*" C+"-"4 #"&$'"4 %$@$ %$ ('%$-"' " C((# " " $ @> A #'($$%(' $ 5+4"'6" $"' #"&$'"4 $- "*" D 8 7=0000 EOQ=Q∗¿
√
2 ( D ) ( S )
H
=
√
2 ( 780000 ) ( 25 )
( 6.25 )
7=.3!30.=38=0.10 %$ )(4(
=789.93
K.! L" C((# $- $ $9$'))( 4$ %" )+$-" +$ %$@$ %$ $4"@$)$' +- -$-"'( %$ 4$5+'%"% #"'" 4+4 #"&$'"4. D$4$" +"' +- 44$*" %$ #+-( %$ '$('%$- )(+- $*#( %$ $-'$5" %$ 2 4$*"-"4. P+$%$ 4+#(-$'4$ +$ " %$*"-%" %+'"-$ +- -$'"( %$ 2 4$*"-"4 $-$ +- #'(*$%( %$ $-"4 %$ 00 +-%"%$4 & +-" %$4")F- $4-%"' %$ 20 +-%"%$4. "> + #+-( %$ '$('%$- %$@$ %$ 4"@$)$' " C((# #"'" "4$5+'"' +- -$ %$ 4$)( %$ ; #"'" )"%" ('%$- )(()"%" @> + #+-( %$ '$('%$- %$@$ $4"@$)$'4$ #"'" "4$5+'"' +$ -( *4 %$ +-" -$4$-)" ()+''" $- $ '"-4)+'4( %$ +- " +$ -$-"'( #'(*$%( $"'" " C((# #"'" $ -)4( @ -)+&" "*@(4, -$-"'( )6))( $ -$-"'( %$ 4$5+'%"% %$ 4+ '$4#+$4". %> +$ "- '$)+$-$*$-$ '("'" " C((# 4+4 -$-"'(4 " +"' (4 '$4+"%(4 %$ -)4( )
"> E #+-( %$ '$('%$- $4 %$ 2 D"(4 * 8 00 +%4 8 1.7
ᵶ
Q 8 20 R= m+ ( ᵶ∗ ṓ )=500∗( 1.7∗250 )=925
@> I-$-"'( %$ 4$5+'%"% D 8 12000 "-+"$4, ( 4$", 32,=7 / %6".
)> -$-"'( *$%(
T 8 √ 14∗250=935.41 8 1.7
ᵶ
4 8 ( 1.7∗250 )=850 830.=3
inventario medio= s +
Q 2
Q
309.83
2
2
= zxT + = 850 +
=1004.91
"(' %$ -$-"'( *$%( 8 100.128 2122.7
7.!U-" $-%" %$ "#"'"(4 %4'@+&$ +-" )$'" *"')" %$ $$4('$4 +$ $-$- "4 45+$-$4 )"'")$'64)"4 • • • • • • •
"> @> )> %>
V$-"4 #'(*$%( "-+"$4 200 +-%"%$4. C(4( %$ ('%$-8:2 #(' ('%$C(4( #(' $"' $- $ -$-"'(82; " " ROP D"(4 * 8 200/0>>83.2
=10
8 3
ᵶ
Q 8 0.1 R= m + ( ᵶ∗ṓ )=3.2∗( 3∗0.1 ) =3.5
)> E4"%( %$ " '$5" Q=
√
2 ( S )
iCD
=
√(
2 ( 25 ) .25) ( 400 ) ( 200)
=0.0025
%> C"*@( %$ $*#( %$ $-'$5" * 8 200/0>1>8 8 3
ᵶ
Q 8 0.1 R= m + ( ᵶ∗ṓ )=5∗( 3∗0.1 )=5.3
C"*@( %$ %$4")F- $4-%"' * 8 200/0>>83.2 8 3
ᵶ
Q 8 0.1 R= m + ( ᵶ∗ṓ )=3.2∗( 2.6∗.5 )=4.45
A -)'$*$-"' " %$4")F- $4-%"' %6"4 %$ $-'$5" 4$ -)'$*$-" $ #+-( %$ '$('%$- & $-$ $ *4*( )(*#('"*$-( 4 @"9".
=.!P"'" (4 %"(4 +$ 4$ %"- $- $ #'(@$*" 7. "> D$$'*-$ +- 44$*" P %$ )(-'( %$ -$-"'( #"'" +- -$ %$ 4$')( %$ ;. C")+$ (4 "('$4 %$ P & T. @> C")+$ " -$'4F- '$+$'%" #"'" $ 44$*" P & $ 44$*" %$ #'(@$*" 7 #"'" "'(4 "('$4 %$ -$ %$ 4$')(. )> P('+$ '$+$'$ $ 44$*" P +-" -$'4F- %$ -$-"'( *"&(' S(+)F- "> P & L P=
Q 10 = =.05 D 200
L8 $*#( %$ $-'$5" 8 T 8 *4 T 8 .01.K78 .K17 D(-%$ * 8 %$*"-%" #'(*$%( %$ PL PL 8 .08 .0 %"4 48 -$-"'( %$ 4$5+'%"% 4 8 Q> 4 8 1.K0.> 81.K7 @> I-$'4F- '$+$'%" P & " 7; %$ 4$')( Z81.00 I =
Q ( Z ṓ )= 10 (1.900∗.95 )= 9.025 2 2
P 10 ( 3.455 )=17.275 I = ( Z ṓ ´ )= 2 2
P"'" #8
´ =¿
1.K01.00.>83.
)> P(' + 4$ $ 4+*" $ -$-"'( %$ 4$5+'%"%. .! L" S+'$5'# T'$ C(*#"-& $" $ -$-"'( %$ )$'( #( %$ -$+*)(4 )(" 45+$-$ )"'")$'64)" • • • • • •
V$-"4 #'(*$%( "-+"$4800 -$+*)(4 C(4( %$ ('%$-8:0 #(' ('%$C(4( %$ -$-"'(82; " " C(-'( %$ -$-"'( #"'" 44$*" $- +- )$'( #( %$ 4$5+'%"% #"'" -$$4 %$ 4$')( %$ =, 0, , 7 & ; D 8 000 -$+*)(4 "-+"$4, ( 4$", 20 -$+*)(4 / %6". * 8 20 %6"4 %$ %$*('" 8 =0 T 8 √ 4∗1= 2
R= m + z∗T =¿
R1 8 =0 1.03 2 8 =2.07 -$+*)(4, #"'" +- -$ %$ 4$')( %$ =;. R2 8 =0 1.30 2 8 =2.K0 -$+*)(4, #"'" +- -$ %$ 4$')( %$ 0 ;. R3 8 =0 1.K 2 8 =3.30 -$+*)(4, #"'" +- -$ %$ 4$')( %$ ;. R 8 =0 1.0 2 8 =3.0 -$+*)(4, #"'" +- -$ %$ 4$')( %$ 7 ;. R 8 =0 2.37 2 8 =.7 -$+*)(4, #"'" +- -$ %$ 4$')( %$ ; )> + -$ %$ 4$')( $4"@$)$'6" +4$% )(- @"4$ $- " 5')" %$ " #"'$ @ )(*$-$ N.S. I-$-"'( *$%( V"(' %$ -$-"'( 0.= 8 1.03 2 K3.2/2 8 33.K +-%"%$4 33.K : =0 8 : 2K.20 0.0 81.300 2 K3.2/2 8 3.22 +-%"%$4 3.22 : =0 8 : 2737.K0 0. 81.K0 2 K3.2/2 8 3.2 +-%"%$4 3.2 : =0 8 : 273.K0 0.7 81.00 2 K3.2/2 8 3.2 +-%"%$4 3.2 : =0 8 :2=33.K0 0. 82.370 2 K3.2/2 8 3K.3K +-%"%$4 3K.3K : =0 8 : 20=.=0
Valor del Inventario Medio VS Nivel de Servicio %
nivel de servicio %
100 98 96 94 92 90 88 86 84
$2,800.00 $2,600.00 $3,000.00 Valor deInventario Medio
nivel de servicio %
E -$ **( %$ 4$')( &" +$ -( $4 "- 45-)"-$ " %$'$-)" $- )(4(4 $" )(*#"'")F-. 10.! P"'" (4 %"(4 %$ #'(@$*" . "> A )")+$ " '(")F- "-+" )(*( +-" +-)F- %$ -$ %$ 4$')( @> S "4 $-"4 4$ -)'$*$-"'"- +- 0;. +$ ()+'''6" )(- " '(")F- $- +-$ %$ 4$')( %$ ; "> R(")F- "-+" Í-%)$ %$ '(")F-8 $-"4$4 %$)' %$*"-%">/-$-"'( *$%( IR =
Demanda inventario medio
Ir ( 85 ) =
Ir ( 90 ) =
Ir ( 95 ) =
5000 33.69 5000 34.22 5000 34.92 5000
Ir ( 97 ) =
Ir ( 99 ) =
35.42 5000 36.36
=148.41 =141.11 =143.18 =141.16 =137.51
@> I-)'$*$-( $- " $-"4 %$ 0; " -$ %$ 4$')( %$ ; EO -)'$*$-( %$ 0; D"(4 D 8 700 S 8 0.00 H 8 PC 8 0.00 .2 8 10 2 ( D ) ( S ) 2 ( 7500 ) ( 40 ) EOQ= = =244.94 H ( 10 )
√
√
N.S. I-$-"'( *$%( V"(' %$ -$-"'( 0. 81.K0 2 2./2 8 12.77 +-%"%$4 12.77 : =0 8 : 100K1.K0
Ir ( 95 ) =
7500 125.77
=59.63
E 6-%)$ %$ '(")F- "+*$-" )(- '$4#$)( " " $-" %$ 000 +-%"%$4 $- $ 45+$-$ #(')$-"9$
I . r . ( 95 ) para 7500 unidades − I . r . ( 95 ) para 5000 unidades I . r . ( 95 ) para 5000 unidades
59.63 −143.18 56.63
8
=−1.48∗100 =148
C(-)+4(-$4 P"'" +- -$ %$ 4$')( %$ ;, +- -)'$*$-( %$ 0; $- "4 $-"4, #'(%+)$ +- %$)'$*$-( #(')$-+" *"&(' $- " '(")F- %$ -$-"'(4, $- $ ('%$- %$ 1=;.
12.! L" )(*#" ?C+ $4 $ $$)( 4(@'$ $ -$'"( %$ ('%$- " )"*@"' $ )(4( %$ -$-"'( 2, 30 & 3; "> I-$-"'( F#*( %$ ('%$- $- %6"4.
D"(4 P8 D8 300 C8:= S8 :20 2 DS
C
=¿
√
2 S
CD
Q 1 P = = √ ¿ D D
2 ( 300)( 20 ) 8
=¿
√
2 ( 20 ) 8 ( 300 )
Q 1 P = = √ ¿ D 300
P=3.33 = 38.72+ .13
P=38.85
@> ?C+-( %$ )"%" #( %$ "(*@'" 4$ ('%$-"'6" $- )"4( %$ )(()"' +-" ('%$- )(*@-"%" A 300 K> 81=00 B 200 10>8 2000 C 100 => 8 =00 )> ?C+ $4 $ $$)( 4(@'$ $ -$'"( %$ ('%$- " )"*@"' $ )(4( %$ -$-"'( " 2, 30 & 3; 1=00 2; 8 0 2000 30; 8 K00 =00 3; 8 2=0 %> ?P(' + -( 4$ #+$%$- ('%$-"' $4"4 "(*@'"4 *$%"-$ +- 44$*" P('+$ )(- $ 44$*" de P se obtiene un resultado fjo
13.! S+#(-5" +$ +4$% $4 $ #'($$%(' %$ " )(*#". S+#(-5" +$ $ )(4( %$ -$-"'( $4 %$ 30; & (4 ('(4 %"(4 4(- (4 +$ 4$ %"- $- $ #'(@$*" 12. "> +$ "*" C(*( )(-4"'" +4$% (4 "*" C"-%"% %$ #$%%( 0! :=0.00 0 :7K.00 D8 20 )"9"4 #(' " ?C+ $4 $ "(' **( %$ -$-"'( D"(4 8 %8 2 #"-)"4 20 %6"4 %$ '"@"9( " " D8 00 P"-)"4 S8 :1200.00 P8 20; C8 :2.00 R8D D8 D$*"-%" A-+" %8 T"4" %$ %$*"-%" %"'" IMA8 I-$-"'( M*( "> ?C+ $4 $ "*" ?C+ $4 $ "(' **( %$ -$-"'(
[ ]
I!" = 1−
[
I!" = 1−
d Q ∗¿ R
2 500
](
489.89 )
I!" = [ 1 −0.004 ] ( 489.89 )
I!" = [ 0.996 ] ( 489.89 )=487.93 Uds
17. U- #'(%+)(' %$ )(*#(-$-$4 $$)'F-)(4 %$4$" (*"' $- )(-4%$'")F"-( " "4" %$ #'(%+))F- )(*( $ '*( %$ " %$*"-%" #"'" %$)%' (4 "*" ?C+ $4 $ "*" S 4$ 5-('" " "4" %$ #'(%+))F-, ?C+ 4$'6" $ "*"
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