Energy balance on separator
April 20, 2019 | Author: hisham | Category: N/A
Short Description
PositiveQ...
Description
V-100
Stream 25 18.84 mol H2O (v)/s 0.57 C2H2F2(g) P = 4.44 atm
T = 138.
℃
Stream 23 4.23 mol H2O (l)/s 0.010 mol C14H10O4 (l)/s 0.0051 mol !aCl2H25 (l)/s 0.57 C2H2F2(g) 0.010 P"#F (l) P = 4.35atm
T = 141.4
℃
Stream 2$ 75.3 mol H2O (l)/s 0.010 mol C14H10O4 (l)/s 0.0051 mol !aCl2H25 (l)/s 0.010 P"#F (l) P = 4.44 atm
T = 138.
℃
Inlet-outlet enthalpy table : References: C2H2F2(g, 141.4 ℃ , 4.935 atm), PVDF(l, PVDF(l, 141.4oC, 4.935 atm), H 2 (l, 25!C , 1.!! atm), C14H1!"4 (l, 141.4!C , 4.935 atm), #aCl2H25"4 (l, 141.4!C , 4.935 atm).
"$%stance
n&n (mol's)
^
H
('m
&n
ol)
no$t (mol's)
^
H
o$t
('mol)
^
H2 (l)
94.23
H2 ()
-
C14H1!"4 (l)
!.!1!
H
#aCl2H25"4 (l)
!.!!51
H
C2H2F2 (g)
!.5*
H
PVDF (l)
!.!1!
H
^
Calculate H
H
-
1
/
V∆ ^
P
∆ P
p
1
/
1000
(4.935-1.!!)
/ !.!!39 'mol 141.4
^
H
/
23,1%
∫ 25
0.0754
0t
^
2+,2
^
2+,3
^
25,2
^
2+,4
H
^
23,3
/!
!.!!51
H
^
23,4
/!
!.5*
H
^
23,5
/!
!.!1!
H
H ! H2 (l, 141.4 C, *.4!2 atm) /
25,1
H
!.!1!
^
23,1a
^
1.4
/!
H ! H2 (l, 25 C, 4.935 atm)
^
2+,1
H
23,2
Reference state: H2 (l, 25!C, 1.!! atm)
H
^
*5.39
^
23,1
^
23,1
/ !.!*54 (141.4 25) / .** 'mol
^
H
23,1
^
/ H
23,1a
^
H
23,1%
/ !.!!39 .** / .* 'mol
^
Calculate H
26,1
Reference state: H2 (l, 25!C, 1.!! atm)
^
H ! H2 (l, 25 C, 4.44 atm)
^
H ! H2 (l, 13.9 C, *.4!2 atm)
^
H
V∆
/
1
/
P
^
2+,1a
∆
p
P
1
/
(4.44-1.!!)
1000
/ !.!!34 'mol 138.9
^ H
/
2+,1%
∫
0.0754
0t
25
/ !.!*54 (141.4 25) / .5 'mol
^
H
2+,1
^
/ H
2+,1a
/ !.!!34 .5 / .591 'mol
^
H
2+,1%
^
Calculate H
25,1
Reference state: H2 (l, 25!C, 1.!! atm)
^
H H2 (l, 1!! C, 1.!! atm) !
^
H ! H2 (, 1!! C, 1.!! atm) H ! H2 (, 13.9 C, 1.!! atm) H
^ ^
H2 (, 13.9!C, 4.44 atm) 100
^ H
/
25,1a
∫ 0.0754
0t
25
/ !.!*54 (1!! 25) / 5.+55 'mol
^
H
/
Δ
25,1%
H / 4!.+5+ 'mol
0.03346 +¿
^
H
138.9
∫
25,1c /
¿
!.+ 1!-5 !.*+!4 1! -2 3.593 1!-123 0t
100
138.9
/ !.!334+ (13.9-1!!) (!.+ 1!-5
3
138.9
3
−100
3
)
138.9
(3.593 1!-12
/ !.1++ 'mol
4
− 100
4
4
) 0t
2
2
−100
2
)(!.*+!4 1!-
^
H
/ V∆ P ^
2+,10
/ ! 'mol
^
H
25,1
^
/ H
25,1a
^
H
25,1%
^
H
25,1c
^
H
25,10
/ 5.+55 4!.+5+ !.1++ ! / 4+.4** 'mol
^
Calculate H
26,2
Reference state: C14H1!"4 (l, 141.4!C, 4.935 atm)
^ ^ H
H C14H1!"4 (l, 141.4!C, 4.44 atm) C14H1!"4 (l, 13.9!C, 4.44 atm)
^
H
V∆
/
^
2+,2a
1
/
∆
p
P
P
1
/
(4.44-4.935)
1330
/ - 3.*2 1!-4 'mol 138.9
^
H
/
2+,2%
∫
108.52
141.4
0t
/ 1!.52 (13.9-141.4) / -2*1.3 'mol
^
H
2+,2
^
/ H
2+,2a
^
H
2+,2%
/ - 3.*2 1!-4 (-2*1.3) / -2*1.3! 'mol
^
Calculate H
26,3
Reference state: #aC l2H25"4 (l, 141.4!C, 4.935 atm)
^ ^ H
H #aCl2H25"4 (l, 141.4!C, 4.44 atm) #aCl2H25"4 (l, 13.9!C, 4.44atm)
^
H
V∆
/
^
2+,3a
1
/
P
∆ P
p
1
/
(4.44-4.935)
1010
/ -4.9 1!-4 'mol 138.9
^
H
/
2+,3%
∫
218.59
141.4
0t
/ 21.59 (13.9-141.4) / -54+.4*5'mol
^
H
2+,3
^
/ H
2+,3a
^
H
2+,3%
/ -4.9 1!-4 (-54+.4*5) / - 54+.4'mol
^
Calculate H
25,2
Reference state: C2H2F2 (g, 141.4!C, 4.935 atm)
^ ^ H
H C2H2F2 (g, 141.4!C, 4.44 atm) C2H2F2 (g, 13.9!C, 4.44 atm)
^
H
v ^
/
25,2a
∆
P
/! 138.9
^
H
∫
/
25,2%
7.55
141.4
0t
/ *.55 (13.9-141.4) / -1.*5 'mol
^
H
25,2
^
/ H
25,2a
^
H
25,2%
/ ! (-1.*5) / - 1.*5 'mol
^
Calculate H
26,4
Reference state: PVDF (l, 141.4 !C, 4.935 atm)
^ ^ H
H PVDF (l, 141.4!C, 4.44 atm) PVDF (l, 13.9!C, 4.44 atm)
^
H
/
2+,4a
1
/
p
V∆ ^
∆
P
P
1
/
1780
(4.44-4.935)
/ - 2.* 1!-4 'mol
138.9
^
H
/
2+,42%
∫
0.0228
141.4
0t
/ !.!22 (13.9-141.4) / -!.!5* 'mol
^
H
2+,4
^
/ H
2+,4a
^
H
2+,4%
/ - 2.* 1!-4 (-!.!5*) / -!.5*3 'mol
∆´H /
∑ n´
o$t
^
H
o$t
-
∑ n´
&n
^
H
&n
/ (*5.39)(.591) (1.4)(4+.4**) (!.!1!)(-2*1.3) (!.!!51)(-54+.4) (!.52)(-1.*5) (!.!1!)(-!.!5*3)6 (94.23)(.**)6 / 15!*.9+ 2*.151 / +!.35 'mol
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