Ejercicios Resueltos Fluidos Ii
July 27, 2022 | Author: Anonymous | Category: N/A
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.-GNGMZLH>
Gi ui kbibl kbibl dg khikr khikrgt gth, h, gl torb torbit itgg gs dg ,0 ,0: : m y gl baub eluyg eluyg b ui uibb vglhkodbd mgdob dg 0,4: m/s, fbstb ui kogrth puith, dhidg, dg`odh b uib kbídb,, lb vglhkodbd kbídb vglhkodbd sg glgvb glgvb b 0,:: m/s, m/s, rgdukoïidhsg rgdukoïidhsg gl torbit torbitgg b :,5: m. dgsp dg sprg rgko kobi bidh dh lb lbss ph phso so`l `lgs gs pï pïrd rdod odbs bs ph phrr er erok okko koûi ûi,, DGT DGTGP GPMOI MOIBP BP LB DOEGPGIKOB DG IOUGL GITPG LB[ DH[ ZBPTG[ DGL KBIBL. ----------------------------------------------------------------------------------------------------------
[hlukoûi> [g togig gi kugitb qug gs ui kbibl y sg dgsprgkob lbs prgsohigs gi lhs dhs puiths. Z=:
Dbths> [gkkoûi 2> v2= 0.4: m / s y 2=2.0: m
^ =¸ _ =8 ¸ a¸ m / s 2
?.62
sgkkoûi 0> v 0=20 m /s y 0= 0.4: m /s z 0= : f e =:
Zlbitgbmogith.
U=vglhkodbd gi m/s
a=arbvgdbd gi m/s0
z=doegrgikob dg iovgl rgspgkth b khtb :
Bplokbidh lb gkubkoûi dg @grihullo gitrg lbs sgkkohigs 0
0
U 2 U + y 2+ z2= fe + + 0 + y0+ z 0 0a 0a
y0
…...….(*)
Pgmplbzbidh vblhrgs gi lb gkubkoûi………………..……. 0
( 0.4: m / s )
+ 2.0: m + z = fe + + 2
0
0 ( ?.62 m / s
+ :.5: m + z
0
0 ( ?.62 m / s
)
0
( 20 m / s ) )
y z =:
o fe=:
0
0
0
( 20 m / s ) ( 0.4: m / s ) + :.5: m+ : + 2.0: m + z = : + 0 ( ?.62 m / s ) 0 ( ?.62 m / s ) 0
2
0
:.;: + 2.0: + y = 1.4: + :.5:
y = 6∐2.7: y = 5.7: m
∴ lbdoegr lbdoegrgik gikob obdgl dgl iovgl iovgl gitr gitrg lhs dhs pb pbrtg rtgss dglkbibl dglkbibl
sgrbdg 5.7: m .
0
(*)
0.-GNGMZLH>
Dg ui dg dgpû pûso soth th arbidg arbidg eluyg eluyg ba baub ub dg .0 .0:p :pog ogs; s;/s /sga ga ph phrr ui sostgm sostgmbb dg tu`gríbs, khmh sg bprgkob gi lb eoaurb . KBLKWLG LB KBITODBDD THTBL DG GIGPAOB RWG [G ZOGPDG GI GL [O[TGMB DG@ODH B LB UBLUWL UBL UWLB,K B,KHDH HDH[ [ GIT GITPBD PBDB B DG TW@ TW@GP GPOB[ OB[ _ EPO EPOKKO KKOHI HI DGL ELW ELWODH ODH.. ---------------------------------------------------------------------------------------------------------
[hlukoûi>
[g togig gi kugitb qug gs uib tu`gríb tu`gríb y sg dgsprgkob lbs lbs prgsohigs gi lhs dhs puiths. Z=:
Dbths> [gkkoûigs> R= 2.0: pogs ; / sga ^ 2=¸ 20¸ z 0=2;
a¸ ?.62m / s 0 f L =8
Zlbitgbmogith.
0
Z 2 Z + U + U + ^ 2 2 + F B ∐ F P∐ F L = 0 + ^ 0 0 _ _ 0a 0a
0
GK……. (2)
GK……. (0)
GK……. (;) ^ = BLTWPB
FBLLBIDH LB UGLHKODBD
U=
R
B
0
R= .0: pogs;/ s0 Zbrb dgtgrmoibr lb vglhkodbd tgigmhs qug fbllbr gl ârgb >
( ) ( ) 0
0
D ; = ϊ =1.:5 B = ϊ 4
4
Khivortogidh b pogs puga= :.:5? sga0 B= 1.:5V:.:5?¸ :.:4? pogs0 ;
R 2.0: pogs v 0= = x sga B0
0
2
:.:4? pogs
=04.4 pogs / sga
0
v 0= 04.4 pogs / sga
Khivortogidh lb arbvgdbd dg m/s b pogs a = v
?.62 :.;:46
0
0
=;0.26 pogs / s 0
0
0a
=
( 04.4 ) pogs sga
0
0
x
sga
0
( 0 )( ;0>26) pogs
=?.07 pogs
Pgmplbzbidh vblhrgs gi lb gkubkoûi………………..……. GGK … .. ( ; )
F L=( ^ 2 ∐ ^ 0 ¸ v 00 / 0 a F L=07 pogs∐ ?.07 pogs F =27.17 pogs L
∴ lb pgrdod pgrdodb b dggigraob dggigraob x eroko erokohi hi gs 27.17 pogs
(*)
GNGPKOKOH ;>
Grgs du Grgs dugò gòh h dg ui rg rgst stbu burb rbit itgg y gs gstâ tâss oi oivg vgst stoa oabi bidh dh iu iugv gvbs bs eh ehrm rmbs bs dg gitrgabr `g`odbs b tus klogitgs. Wib prhpugstb gs uib tu`gríb qug llgvbrâ kgrvgzbb dg rbíz dg dgisod kgrvgz dgisodbd bd ,:?:
ca ;
m
b trbvïs dgl rgstburbitg. Wib sgkkoûi
dg lb tu`gríb sg mugstrb b khitoiubkoûi. Lhs plbihs gstb`lgkgi qug lb vglhkodbd y lb prgsoûi mbihmïtrokb dg lb kgrvgzb dg rbíz gi gl puith shi ;.:: m/s y 0,;::Zb rgspgktovbmgitg. rgspgktovbmgitg. Lb kgrvgzb dg rbíz rbíz gi gl puith 0 gstââ .0: m mâs blt gst bltbb qug gl eluo eluodh dh gi gl puit puith h y vobnb vobnb b uib vglh vglhkod kodbd bd dg :.17:m/s. Gl iþmgrh pbrb lb prgsoûi gi gl puith 0 ih sg vg klbrbmgitg.
Z2 +
2
ςv
0 2 0
2
0
+ pa f =Z0+ ςv + pa f 0 2
2
0
0
2
2
0
Z0= Z2 + ςv 0+ pa f2- ςv 0+ pa f0 0
0
Gi gstg puith dg`gmhs gskhagr lb blturb f=: dg rgegrgikob. Gskhagrgmhs f=: b lb blturb dgl puith 2. Gsth gstb`lgkg qug f2=: y f0=2.0 m Bl sustuor gsths vblhrgs pbrb lbs blturbs, h`tgigmhs
2
2
2
0
Z0= Z2 + ςv 0+ pa ( : m )- ςv 0+ pa ( 2.0: m) 0
0
Ihs phdgmhs dgsfbkgr dgl tïrmoih khi gl kgrh y sustuor lhs vblhrgs iumïrokhs dg lbs htrbs vbrob`lgs pbrb h`tgigr, 2
Z0=20,;:: Zb+ (2,:?: 0
ca
ca ca 0 0 ∐ ∐ 02(2 , :?: (2 , :?: )(;.:: m/s )(:.17: m/s ¸ ¸ ; ; ; )a(2.0: m) m m m
Z0=4,:6: Zb
GNGPKOKOH 4> ¸kubl gs gs lb prgsoûi prgsoûi gi gl hkïbih b uib uib prheuidodbd prheuidodbd dg 7::m suphiogi suphiogidh dh
qug>
b. Gl baub sblbdb gs oikhmprgso`lg (λ :=2:07
ca ;
)
m
`. Gl baub dg mbr gs khmprgso`lg y togig ui pgsh gspgkíeokh gi lb supgreokog ; λ h=2:07 ca∐ e // m y ui mûdulh dg glbstokodbd vhlumïtrokh> @= 1 ; 02 Ñ 2: ca ∐e // m [HLWKOHI b)
dp =+ ςa =λ dz dp =λdz
IHTB> p
Khmh> λ = λ h =ktg←
p= λ h f =2:07
∣ dp= λ ∣ dz
eu euod odh h
gs khistbtg g oaubl gi thdhs
h
sus puiths>
h
ca∐ e Ñ 27:: m ; m
p=27;17:: ca ∐ e / / m
th thdh
oikhmprgis oikhm prgiso`lg o`lg lb dgisodbd dgisodbd
f
h
Gi
∴ khmh ς
=ktg←λ =ktg
0
7
p=27.;17 x 2: ca ∐ e // m
0
ς ) ih gs khistbitg phr `) Khmh gl uodh uodh gs oikhmprgis oikhmprgiso`lg o`lg githik githikgs gs lb dgisodbd dgisodbd( ς lh tbith gl pgsh gspgkíkh tbmphkh gs khistbitg dp dλ ← dp = λ ………(O) @= λ dλ ← oitgiarbmhs >
←Z
p
λ
h
λ h
p
λ
ph= :
λ h
∣ dp =@ ∣ dλ λ
∣ @ li∣ ← p ∐k = @ (liλ ∐ li λ ) h
← p = @ li ( λ / λ h )………(OO) Khmh dp =λdz …….(OOO)
Iûtgsg
qug
^
modg fbkob b`bnh
sg
dλ dλ Dg (O) = (OO)> λdz = @ ← dz = @ 0 λ λ f
λ
← f∐: =@ ∣ dz =@ ∣ dλ λ 0
h
λ =
λ H
S ] 2
∐
2
λ λ h
λ .@ … … … . ( OU ) @∐ λ . f
(OU) gi (OO)>
Z= @ li
(
)
@ ca∐ e =27.4;2 Ñ 2:7 0 @∐ λ H f m
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