Ejercicios Complementarios

 

KCKRLELEN\ LN@]JK@KAXDREN\ KCKRLELEN 4

 Dltudj`katk sk vkahka 8.=== katrdhds hk leak l eak d ua prklen hk $ ; lldhd dhd uad. Jd kjdstelehdh “ prklen hk jd hk`dahd hk katrdhds hk leak ks efudj d 4. 4) Ldjlujk ka quk pnrlkatdck hkbk rkhulersk kj prklen hk jds katrdhds, se jns prnpektdrens hk sdjds hk leak quekrka vkahkr ;.=== katrdhds. ; 01 x 0 - 4.=== . ; Kk  0 T k  . ]k  01 4 0 4===  ]k Tk - ]k 8.=== 4 . 8.===   ] k

0 - ;.=== 0 -4,2; 8.===

]nrlk ]nr lkatd atdck ck 0 -4,2; . 4== 0 - 2; % Hkbk rkhul rkhulerer kj prklen prk len ua 2;% ; 2) Hkhuler jd iualeüa hk hk`dahd. H= 0 Th -  T . ] H= 0 8.=== + Th 0 H= + T . ] 4.=== x ;

]

H= 0 8.=== + 8.=== Th 0 ?.== ?.==== “ 4.== .=== ] 4,2;

]

4,2;

H= 0 ?.=== Th 0 ?.== ?.==== “ ?== ]

KCKRLELEN 2

\e jd hk`dahd dutüan`d hk ua eahevehun ks 8= uaehdhks, kj prklen lrklk hk d $2 y jd ldatehdh vdràd datk ksd setudleüa, ka 4= uaehdhks3 4) Hktkr`eak jd iualeüa hk hk`dahd eahevehudj Th 0 8= “ 4= ] 2 2) Ldjlujk jd tdbjd hk hk`dahd pdrd eafrksns quk vda hk = d ? hk hns ka hns.