Ejercicio 3

 

Ogorijijk 9. Kporfijkdos odtro voitkros ho

.

⃐ y ⃐ ikrrospkdhjodto fc cjtorfc osik`jhk. Ikdsjhoro cks voitkros  ⃐⃐ Ð ⃐   Hotormjdo oc prkhuitk iruz  ⃐ skbro ⃐.   Hotormjdo cf prkyoiijùd krtk`kdfc hoc voitkr  F.

⃐ 

= ( ,− , ) y

⃐

= ( , , − ).

   ⃐⃐ Ð ⃐    Hotormjdo oc prkhuitk iruz   



_= (6,-6,6) U= (1,6,-6) 6 −6 6

_ * U=

1 6− 6

 

= (6-(+6)) ’ ((-6)-1) +(6-1)

 

=1j + 6g + 6l

 

⃐ skbro ⃐.  Hotormjdo cf prkyoiijùd krtk`kdfc hoc voitkr 



_  U 

=

  =

  =

_ ∐U 

∯ U   ∯∯

2

 U

(6 , −6 , 6 ) . (1 , 6 , −6) ∗ (1 ) + » (6 ) +(−6 ) » 2

−2 2

∗ 2

2

2

 

=

−6

6

_  U 

  (1 6 -6)

=1 ,

−6

6

 ,

6 6

  =1,-6, 6