Ejercicio 2

 

TUMEFOCN 59 O` of lbrlubtm so tbo`o u`n lan`lngmrn, u` gbstrbeubgmr ?4%, fn znrn`gn os go gmefo pbsm, of  prbcor pbsm go cnffn >‒‒ y of soju`gm go cnffn ¶‒‒. Gotorcb`o fn lnrjn lbrlufn`to tmtnf U< y of Enfn`lo go cntorbnfos go tmgm of lbrlubtm. Lm`sbgoro quo of pbsm suporbmr go fn znrn`gn os >44% ohblbo`to pnrn tncnþms c ¶‒‒9

ENFN@LO CNWOUBN JO@OUNF9

 O`trngn  O`trng n 3 \nfbgn  7  H 3W  7 Enfn`lo o` fn cnffn >9

 H + U < 3 U >+ W > Enfn`lo o` fn cnffn 59

W > 3 U 5 + W  5  5 O`tm`los9 3

 U <  U >

+

 U 5 5

 

Goebgm nf gbstrbeubgmr9

W 5 + W < 3 W   7 7 

↕

 U 5  < 3 W  < 5

Uosmfvbo`gm9 \nebo`gm quo fn ohlbo`lbn go fn cnffn > os >44% o`tm`los pmgocms golbr9

W > 3>44∕>>.> 311.2 11.2 % \b smfm sb o` fn cnffn >9 >443

( h ∕>>.> )√>44 √>44 ( >44∕>>.> )√ h 

h 3>44 Lnflufn`gm fn ohlbo`lbn go fn cnffn 59

 O 3

( 11.2 ∕< )√>44 √>443 22.8>% ( >44 ∕< )√11.2

Fn rofnlbü` go lnrjn lbrlufn`to9 Tnrn fn C59

( >∕4.228> )√11.2  U 3 ll 53 3 4.>>8  H  < O`tm`los9 Go (5)9

 U 5  U 5 3 4.>>8↕  H + U < ∕ U >3 W >  ↕  U + W > 5 Uoocpfnzn`gm9  U 5

 U 5

 H + U > +

5

3

4.>>8

 U >

∕

Gosnrrmffn`gm to`ocms9

 U 53>5. Uosmfvbo`gm9

W 5 +

 U 5 5

3

W 7

W 5 + >5. 3>44 5

(5)

 

W 5 32 3>5.+ 2 3>48,>8 Hb`nfco`to lm`sbgorn`gm U>34 goebgm n quo fn cnffn o`o u`n ohlbo`lbn gof >44%9 Lnflufncms fn lnrjn lbrlufn`to U< os9

 U